Lecture 6: Pressure

  Рет қаралды 1,996

Vincent Meunier

Vincent Meunier

Күн бұрын

Пікірлер: 9
@mathletics6287
@mathletics6287 Жыл бұрын
Thank you so much for your lectures. but can you please include your lecture 7(effusion) in this playlist? That knudsen flow is confusing me.
@vincentmeunier7873
@vincentmeunier7873 Жыл бұрын
I'm planning to complete all the missing lectures of the first part of the book by December 2023. I'm also working on lectures on theoretical mechanics...
@mathletics6287
@mathletics6287 Жыл бұрын
but can you tell me why did we integrate from 0 to π/2 to find pressure from the expression (1/2)nvcosθvf(v)sinθdθdv?
@vincentmeunier7873
@vincentmeunier7873 Жыл бұрын
Yes, it is best understood from page number 95 where the solid angle is drawn. You see there that theta sweeps 0 to pi/2 for a solid angle of "theta" opening
@mathletics6287
@mathletics6287 Жыл бұрын
@@vincentmeunier7873Then Why did we neglect other side of the sphere? Is it because the pressure will add up to zero?
@mathletics6287
@mathletics6287 Жыл бұрын
@@vincentmeunier7873 Thank you so much for your lectures. but can you please include your lecture 7(effusion) in this play list? That knudsen flow is confusing me.
@ilyassoujaddi4569
@ilyassoujaddi4569 2 жыл бұрын
Why does the momentum transfer equal 2mvcos@??? I dont understand where did 2 come ?
@vincentmeunier7873
@vincentmeunier7873 2 жыл бұрын
It is the change in momentum. It is initially -mv \cos \theta and then mv \cos \theta after the molecule hits the wall. Thus, the change in momentum is thus 2 mv \cos \theta
@ilyassoujaddi4569
@ilyassoujaddi4569 2 жыл бұрын
@@vincentmeunier7873 thanks a lot ... ur fan from morocco. Je sais que vous êtes belge et ainsi vous parler le français ...ça se voit surtout sur ton accent... vraiment vous faites un trop honneur pour votre pays ...
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