Lecture22: All about Char Arrays, Strings & solving LeetCode Questions

[@sahilanand30]

Very few KZbinrs can maintain such consistency with such quality content 🔥

[@inter3988]

great video whenever you show a new problem, I spend at least 30 min or more trying to solve it. Then if I can't or after solving, I see the solution you provide. Never thought problem solving would be this addictive

[@incnomercy6573]

did you solve this problem 57:15 if yes please share the code

[@sahilanand30]

The best thing about this course is, it covers wide range of topics which is helpful for beginners as well as advance programmers!

[@mdwaqar7401]

Finally Completed this Video after 5 days. Have to say this was the Toughest to Digest and Code and Understand so far in the journey But Worth every Second. Now I am much confident with String. Thanks Bhaiyya !! Onto the next video.

[@dEviL_bIsWaJiT]

*Key Differences Between Character Array and String* A character array is a collection of variables which are of character datatype. String is a class that is instantiated to declare strings. Using index value you can access a character from a character array. On the other hand, if you want to access a particular character in a string, you can access it by function string’s_name.charAt(index). As an array is not a datatype similarly a character also is not a datatype. On the other hand, String being a class act as a reference type hence, it can be said String is a data type. You can not apply any operator on a character array whereas, you can apply operators on String. Being an array character array has a fixed length and its boundaries can be easily overrun. Where String does not have any boundaries. Array elements are stored in a contiguous memory location hence that can be accessed faster than string variable.

[@AbhishekKumar-nz9dn]

thanks for this bro🙏👍

[@prathamsharma5016]

Very informative thank you

[@sagarbiradar1104]

Mast kam karta hai tu

[@shivashiskar8421]

ok rana bhaiii

[@dEviL_bIsWaJiT]

@@shivashiskar8421 😅

[@SandipDas-bd2pt]

This is my favourite channel. I especially like it when you explain everything so nicely. I wish you a lot of success with the channel and happy life.

[@shubhamaths]

4 din lag geya 🥲🥲 Complete karne me.

[@harshitverma2707]

Ek din ka kaam hai bhai ye to

[@rishabh_pant]

We keep trying :) 💪

[@suxsfulrecovery7161]

​@@harshitverma2707 nah bhai humse ek din mai na hu paiga

[@gauravbisht504]

Chota bachcha h kya😂

[@shivakashyap5017]

Bhai mujhe 5 din lag gaye complete karne me , kyu bhai jab problem khud se apna 100% dekar solve karne than lete h to time lagta h , 5 minute dekar hamse na ho payega ye soch kar solution dekh lene se kiya phayada phle 2 se 3 ghante do problem ko nahi hua to phir solution dekho or uske bad bhi khud se karo

[@mlkgpta2869]

In this 2 hours of lecture i learnt about 10 hours of content by going through other optimized solution in discussion section, refering different stl libraries for new function, learning from errors...

[@ayushkushwaha171]

took me like 2 days to complete this video. really enjoyed it. thanks bro

[@anishtripathi3800]

Bhaiya ye video maine 3 din me complete ki hai... Lekin ek ek explaination ko 2- 3 baar dekha, implement kiya.. aur cheezein samajh aane lagi. Thank you bhaiya.

[@Gungun-ce4ox]

are you also learn string 1st time?? i am following this playlist and all videos i understand easily but that particular video i didn't understand

[@subrinasirajee2109]

Hi Mr. Love Babbar. Your content is just amazing. Thank you so much from Bangladesh.

[@sambhavsharma2780]

for converting upper case to lower case simply add ( ch+32 ) and for converting lower case to upper case simply subtract ( ch-32 ).

[@pranshul40]

Please explain me the code when the string is 'aabbBcD' , then output is 'b' because maximum occurrence in string is b

[@scoc55vora15]

Amazing

[@gurtegsinghsohi411]

​@@scoc55vora15 can you provide answer of 57:15

[@adityakant9736]

Because 'a' - 'A' is 32🐘

[@deepanshusingh3623]

mere code me error de rha tha esa krne pe ....

[@sayanmukherjee1445]

This is a really good course and more better than many premium courses of DS & Algo. Thank you is not enough for this course.

[@codewithmames]

hello bro

[@Aatifkhan-pq6kv]

Present bhaiyya, I am on 1:00:45 timestamp........ To be honest, by far the best video ever watched on these topics❤️❤️ absolutely loving the way u mould us to solve any problem. You are a gem 💎

[@arnobbaiga309]

bro 1:47:28 why he did char[ansindex++]?

[@ravishekhawat5958]

@@arnobbaiga309 quki char ko store krne k baad ans vector ka index bgi increment krna pdega ... Tbhi to uske next index pr ya to char ya bhi uski occurrence daal payenge

[@Raj_Tanvar]

I don't care about length I care only about content which is fantastic 👌

[@apurbakumarmajumder9478]

Me too bro Length doesn't matter, Quality is all that matters. And more over we have to learn this topics may not today then tomorrow but we all have to understand this topics so why not today.

[@arnobbaiga309]

bro 1:47:28 why he did char[ansindex++]?

[@darshanbhaiya8711]

after comparing it will atomatically increase the pointer @@arnobbaiga309

[@saurabhvishwakarma9616]

Best solution for Remove all Adjacent Duplicates 1:39:00 string removeDuplicates(string s) { string res; for(char ch : s){ if(!res.empty() && res[res.size() - 1] == ch) res.pop_back(); else res+=ch; } return res; }

[@Anonymous-ng5dw]

FOR MY REFERENCE:- A character array is a collection of variables which are of character datatype. String is a class that is instantiated to declare strings. Using index value you can access a character from a character array. On the other hand, if you want to access a particular character in a string, you can access it by function string’s_name.charAt(index). As an array is not a datatype similarly a character also is not a datatype. On the other hand, String being a class act as a reference type hence, it can be said String is a data type. You can not apply any operator on a character array whereas, you can apply operators on String. Being an array character array has a fixed length and its boundaries can be easily overrun. Where String does not have any boundaries. Array elements are stored in a contiguous memory location hence that can be accessed faster than string variable.

[@yashkum095]

A character array is actually different from cstring, the thing he was using here was a cstring and not character array, try declaring a character array explicity by yourself as if it was an integer array, you'll see

[@Vikram-Sharma-]

HW - 3 Auxilary space O(0) for space replacement with @40 problem string replaceSpaces(string &str){ // Write your code here. int l = str.length(); string rep = "@40"; for(int i = 0; i

[@mohitbansal222]

str.replace(i,1,rep); esme 1 kis kiya likha ha

[@ishratkaur1605]

@@mohitbansal222 Probably because we have to replace a space of size 1 with the string rep.

[@mohitbansal321]

@@ishratkaur1605 thanks

[@avibirla9863]

@@mohitbansal222 i,1 ..specifies range of indexes i.e till which range you have to replace

[@rameshmalhotra9525]

kzbin.info/www/bejne/qnK0en6bZbp6fpY

[@muatasimahmed2343]

Seeing you consistent My brains demands consistent from ...Ajj ka attendance laag gya😃 Thanks Bhaiyaa ☺️

[@arnobbaiga309]

bro 1:47:28 why he did char[ansindex++]?

[@aadityakumar8604]

ch-'A'+'a' ------> ch+32 likh sakte hai ( to convert capital to smallest) Or ch-32 for vice versa

[@themindtreatment]

very few youtubers can maintain such consistency with such quality content good job brother

[@gurtegsinghsohi411]

Can you provide answer of 57:15

[@md.ualiurrahmanrahat2400]

You are like a superhero to us. Consistency is unbelievable!! You are a man of words Vaiya. You're keeping your promises. Salute.

[@arnobbaiga309]

bro 1:47:28 why he did char[ansindex++]?

[@abhishekmaurya6594]

@@arnobbaiga309 actually he is storing the old character in ansIndex and than post incremented

[@artifice_abhi]

42:46 Valid Palindrome Apne jo approach check palindrome m btai usse kaafi asan hogya ... mne kaafi complex kardi thi approach class Solution { public: string toLowercase(string s){ string ans; for(int i = 0; i= 'A' && s[i] = 'a' && s[i] = '0' && s[i]

[@imPriyansh77]

The way you broke down the problem in 3 steps at 54:58 is just awesome ! Thanks Bhaiya :)

[@CentristPerspective]

He misunderstood the question, the question doesn't states that

[@shadprakash]

@@CentristPerspective true, i also read the question, and it says to reverse the words, not the letters. eg :- input --> the sky is blue output --> blue is sky the He didn't pay it much attention and just read the title that's why he might've misunderstood ig, that's why there were no submissions as well lol, cuz he mistook that question for some other question.

[@ravishsingla4454]

what a dedication this man has recorded the video from about 3:00 am to morning 6:40 am, Hats off to you. 🔥🔥

[@satyamgoenka6287]

mai bhi itti hi dedication ke saath pubg khelta tha bro..kabhi🥲

[@BOSS55]

ha yyar @@satyamgoenka6287

[@043-h-subhashreebastia7]

thoda tough tha questions par bhaiya do baar dikhne se samajh aa rhi h thank you bhaiya☺

[@newhope5729]

Didi please reply I request pleeees

[@akashverma5880]

#include #include using namespace std; int main() { string s = "my name is akash"; int start = 0; int p = 0; for (int i = 0; i

[@MyAnish22]

Akash, my code looks similar but it isnt working, can you review? #include #include using namespace std; void reversewordsinaString(string str){ int len = str.length()-1; int i = 0; int j = 0; int s = i; while (i

[@ananyapandey8162]

@@MyAnish22 bhai tune getline to declare Kiya Hua hai but utne koyi function ESA initialize hi nahi kiya jisme getline ho

[@Mohddanish-ly4yx]

Thank you

[@aashutoshsathe8078]

thank you bro this was very helpful

[@8BitGamerYT1]

can we do without losing the O(N) time complexity?

[@ABHISHEKRAI-n9k]

sir maja hi aa gaya question ban ja raha h jab aap acha sa samjha da raha h and kabhi kabhi 50 to 60% ma khud hi soch pa raha hoon jabki sirf 5 days hi hua h apki video dekha hua

[@kailashdaata8610]

I love this series, Thanks for providing this content. One feedback, plz explain the code by more dry run(specially permutation question), also 30-40 min video length will be good.

[@sagarbiradar1104]

I thought you put photo babbar than i realized on closer look that its not babbars photo but maybe your photo😁

[@RAHUL-pe7jv]

@@sagarbiradar1104 😀

[@AnujTiwari-g8o]

bhaiya aapki 2 ghante ki video mere liyea poora din hota .... code samajhne me bhi time lagta hai..... apne end se errors aajae to unhe bhi solve karna hota hai ..... but i will never stop learning ....

[@anuragpandey8165]

Completed - 1:53:19 Great explanation.

[@technologytrends645]

//Happy that I am able to solve it //Homework - Remove All Adjacent Duplicates In String string removeDuplicates(string s) { int i=0; while( i < s.length() ){ if(s[i] == s[i+1]){ s.erase(i,2); if(i > 0){ i--; } } else{ i++; } } return s; }

[@only_for_fun1234r]

Difficult for me, me studying string for 1st time but maja boht aya 🔥🔥

[@tanishgupta7505]

reverse of a string using stl is way simple : string babbar = "babbar"; reverse(babbar.begin() , babbar.end() ); cout

[@sharedme4471]

💡 HomeWork 1:17:12 - replace space [O(1) space solution] : for(int i=0;i

[@cuteanime2]

well done bro 👌

[@kms8320]

What is the time complexity of this? Is it O(N^2) ?

[@sharedme4471]

@@kms8320 O(N), bcs here is only one loop

[@lateshbansal7801]

iska output sai nhi aara

[@devangsingh2950]

actually this will become O(N2) in complexity because making substring in c++ will take linear time not constant time, also using insert will cause also O(N2), as it was given in cpp site that these operations are linear in T.C.

[@Listenup831]

sir, aapke charno me mera shat shat naman, bahut lecture dekhne ke baad, aaj aapse string clear hua

[@sherebanoburhani8939]

Present bhaiya. I am still on lecture 8 (just busy with all my assignnents and internals of college😩😩😩) It's going to be an amazing video I am sure of that.

[@RahulKumar-wt9qc]

Don't worry , try to manage time and never give up, best of luck 👍👍👍👍

[@rameshmalhotra9525]

kzbin.info/www/bejne/qnK0en6bZbp6fpY

[@sourabhsingh5941]

1:23:00 why are we checking this condition -> s.find(part) < s.length() what is the reason plz help

[@rahulrastogi5312]

Just finished the video...Haven't seen better way of teaching than this..#TheProblemSolvingWay... really grateful bhaiya ..one of the best videos of this course till date ❤️🙏🏻...1hr+ content really helps in many ways specially understanding

[@shreyansh_yadav]

Just abhi poori vid complete hui, Mza aaya bhaiya

[@anjanimittal9313]

Reverse Words: Code: #include using namespace std; void reverse(string &s, int x, int y) { while(x

[@ankitsahu1575]

Thank you for your answer Anjali, it helped me a lot.

[@ayushmanagarwal4323]

nice work

[@Arcgamerz27]

could you explain how: y=i-1 and x=y+2 came.

[@ultrondanger1208]

nice

[@champ-kx9lb]

Thank you @anjanimittal9313 for your answer as this q was lock for non premium members!! can you explain me pls how first word is reversed? it will help me alot

[@RohitKannaujiya-i1r]

Aaj mja aa gya padhne me bas ab hamaari baari khud se solve karne ki inn sab question ko ❤ Ab aur mja aayega bhaiya❤❤❤🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉

[@priyapandey8951]

@Babbar Bhaiya, Homework at 1:17:12 it can be done in-place using replace method also:- string replaceSpaces(string &str){ // Write your code here. for(int i=0;str[i]!='\0';i++){ if(str[i]==32){ str.replace (i,1,"@40",0,3); } } return str; }

[@anmol3]

@Hiranmay Formal can you provide me with the link to real solution, without using inbuilt functions. Thanks.

[@anmol3]

@Seekersbay thanks a lot brother

[@nityamtiwari8502]

bhaiya yaar "Remove all occurrences of substring" mei jo approach lagai aapne , wo tagda tha , maja hi aa gaya sahi mein.

[@awais_ansarii]

Present bhaiyya, TBH, by far the best video ever watched on these topics❤❤ absolutely loving the way u mould us to solve any problem. You are a gem 💎

[@GAURAVKUMAR-rt4gd]

most occurrence char wala question me sbse phle string sort krke fir while loop lagake conditional statement use krke ho jayega....... NEW APPROACH

[@017_indrasen9]

At 1:18:00 we can use "str.replace(i, 1, "@40");" for any space occurence

[@vishalrajiwade6964]

03:22 Understanding and using character arrays and strings 13:35 Understanding character arrays and string manipulation 17:32 Understanding char arrays, strings, and solving LeetCode questions. 23:56 Understanding different types of character arrays and their applications 26:49 Understanding the process of subscribing and subscribing to a channel. 36:03 Understanding character arrays and string manipulation 40:24 Understanding char arrays, strings and solving LeetCode questions 46:58 Discussion on subscriptions and useful content 51:29 Understanding char arrays, strings, and LeetCode problem-solving. 58:25 Usage of char arrays and strings in coding. 1:01:17 Understanding char arrays, strings, and solving LeetCode questions 1:07:21 Understanding char arrays and strings in C++ 1:11:00 Understanding char arrays and strings 1:16:46 Understanding the solution for specific lengths and balancing 1:20:34 Understanding char arrays, strings, and LeetCode questions. 1:27:01 Understanding char arrays and strings in C++ 1:30:15 Understanding array operations and processing strings 1:35:53 Understanding and solving char arrays and strings 1:38:25 Understanding Char Arrays and Strings 1:44:05 Cleaning and maintenance of char arrays and strings 1:47:43 Understanding account management and settings 1:52:40 Understanding the size of a tractor

[@siddhishitole3986]

Thank you sir for effort and time ur taking out for us.. Motivating us to do more ✨🙂

[@abdxlive]

52:00 TBC Insha-Allah | Thanks Bhaiya Ji ❤️

[@Name-f9v1n]

It's 1:40 Am 6/10/24 , Alhamdulillah ❤ i completed this long and tough lecture.

[@AjaySharma-gg8dv]

bhai mera aaj hua , ek saval tha bhai ki apna college walo ka bhi dsa aa gaya hai u tube per , vo follow karu ya yahi

[@52hsrah]

String Handling Input: std::string s = "ab\0cd\0"; Behavior: The string will contain all characters, including the null terminators. The length of the string will be 5 (including the null characters). Printing the entire string will show all characters. Size and Length: s.size() will return 5 s.length() will also return 5 Iteration: Iterating through the string will include all characters, including nulls. Substring Extraction: Extracting substrings will preserve null characters. Char Array Handling Input: char ca[] = "ab\0cd\0"; Behavior: The char array will be terminated at the first null character. Only "ab" will be considered part of the string. The second "\0" and "cd" will be ignored. Size and Length: strlen(ca) will return 2 sizeof(ca) will return the total size of the array (likely 6) Iteration: Standard string functions like printf("%s", ca) will stop at the first null character. Substring Extraction: Attempting to extract substrings beyond the first null will result in undefined behavior. Key Differences Null Terminator Handling: Strings can contain null characters; char arrays treat them as terminators. Length Calculation: Strings calculate length including nulls; char arrays stop at the first null. Memory Usage: Strings allocate memory dynamically; char arrays have fixed size. Flexibility: Strings offer more flexibility in handling special characters. Compatibility: Char arrays are compatible with C-style string functions; strings require C++ methods.

[@chandrabhanthakkangar8380]

Maine puri video dekhi hai bhaiya.. Sachme bhaiya dilse kaha raha hu pahle muze dsa problems ko tackle karna bahot hard lagta tha jabse aapka KZbin channel dsa ka series follow kiya na bhaiya sachme ekdam tagda aatama-vishvas bahot jyada high ho raha hai.. Thank for such awesome series bhaiya ❤.. Mai abtak 22 lecture dekh liye hai bhaiya...

[@vanshmehan8634]

❤‍🔥Easy Code for 01:23:30 - Permutation in String ❤‍🔥 #include using namespace std; #include #include bool checkPer(string s1, string s2){ while(s1.length()!=0 && s1.find(s2)

[@ankushraj9583]

does it work? where is it calculating for all permutations. from what I am understanding it's just checking from original order and a reverse.

[@vanshmehan8634]

@Ankush Raj yess you r right!! I understood the question wrong!! Thanks buddy👍🏻

[@smarthgarg6305]

very well explained ,Ik I'm bit late but loving the videos till now. Each concept is cyrstal clear till now.

[@Abhinav_2060]

In last question of the video dont forget to add chars.erase(chars.begin()+ansIndex,chars.end()); return chars.size(); at the end or the existing elements of the chars array will also be there ,leading to incorrect ans.

[@umangpatel4202]

1:10:29 bhaiya agar is code mein jo ki maximum occuring character ka hai. agar ismein input string "zac" ya esi ho jis mein koi character repeat nahi ho raha tab bhi is code mein jo character alphabetically pehle aa raha ho vo print hoga jab ki sabki occurence 1 hai to ese case mein kuch bhi print nahi hona chahiye. to iss ke liye return 'a' +ans; ke pehle aap ye if statement le sakte hai if(ans

[@tanmayghosh8311]

1:17:39 str.replace(index, 1, "@40 "); this will help

[@shubhamlingwal5054]

it willl not work we need still extra space in string .Can you please share soln if it worked .

[@devanshusahoo]

Dil se accha laga yeh video. thank you very much.

[@sudhanshuprasad8508]

homework code given at 42:39 #include using namespace std; string reverse(string x){ int i = 0; int j = x.length() - 1; while(i

[@garvmit]

thnx

[@kathanadalaja4990]

V.push_back(reverse(x)) durai baar kyu likha bhai

[@1hokage8]

in the question it was mentioned without allocating extra space we need to do.

[@RohitRana-tz2lr]

Bhut mja aara h bhaiya aapse different different question ko solve krne ki approach ko samjne m... puri video dekhi bhaiya.. keep doing it bhaiya... Thanks for everything

[@muneebjaved3940]

1:17:34 string replaceSpaces(string &str){ for(int i = 0; i < str.length();i++){ if(str[i]== ' '){ str.replace(i,1,"@40"); } } return str; }

[@snehagupta3479]

saw the full video in 2 days bhaiya and reffered this link to all my friends !! best video i have seen!!

[@kirtigupta9983]

01:17:12 QUES: Replace space in the original string.... SOL: string replaceSpaces(string &str){ // Write your code here. string s="@40"; for(int i=0;i

[@DominiK037]

sir told us not to use second string and you created this xd | string s= "@40" | Instead it's just | str.replace(i, 1, "@40"); | inside if loop :)

[@8BitGamerYT1]

@@DominiK037Not just that, s[i] is supposed to be a character right? We can't place a string in that position. Canw e?

[@rishikumar-uf7tu]

47:32 GOOD PALINDROME QUESTION REFER FOR FUTURE ALSO TIMESTAMP IN PERSONAL PPT 1:24:00 permutation in string also included in personal ppt

[@KR1SH05]

send that ppt :D

[@adityasinghrawat6664]

me too please

[@seemantkamlapuri36]

Salute your hard work sir 👍... & Thanks for the easiest explanation 🙏

[@aryanmahendru772]

literally cried at 1:20:23 it took .5hr to me to get the approach and bhaiya,you did with these, in build functions in just 3-4 lines!😫😩

[@vanshtyagii3498]

string replaceSpaces(string &str) { int spaceCount = 0; // Count Number of Spaces for(int i = 0; i < str.size(); i++){ if(str[i] == ' '){ spaceCount = spaceCount + 1; } } // Store thr current length of the string in a variable. int len = str.size(); // Find the new length. int newLength; newLength = len + (spaceCount * 2); // Resize the current string. str.resize(newLength); // Index to end of string. int index = newLength - 1; // Fill string from end. for(int k = len - 1 ; k >= 0; k--){ if(str[k] == ' '){ str[index] = '0'; str[index - 1] = '4'; str[index - 2] = '@'; index = index - 3; } else{ str[index] = str[k]; index = index - 1; } } // Return string. return str;

[@abhiinavv.pullss]

good approach

[@swatisinha5037]

this man is a gem, your explanations are soo good!

[@vijaysaharan3382]

1:17:53 string rep = "@40"; for(int i=0 ; i

[@bhawargujral3574]

Always providing quality content 👌

[@infernogamer52]

Key Differences Between Character Array and String ------------------------------------------------------------------------------------ 1. A character array is a collection of variables which are of character datatype. String is a class that is instantiated to declare strings. 2. Using index value you can access a character from a character array. On the other hand, if you want to access a particular character in a string, you can access it by function string’s_name.charAt(index). 3. As an array is not a datatype similarly a character also is not a datatype. On the other hand, String being a class act as a reference type hence, it can be said String is a data type. 4. You can not apply any operator on a character array whereas, you can apply operators on String. 5. Being an array character array has a fixed length and its boundaries can be easily overrun. Where String does not have any boundaries. 6. Array elements are stored in a contiguous memory location hence that can be accessed faster than string variable.

[@ayushsoni7823]

18:24 Length of string We can directly print 'i' instead of creating count variable

[@741ibrahim2]

i+1

[@themindtreatment]

the best thing about this course is it covers wide range of topics which is helpfull for beginners as well as advance programe

[@kishanprajapati3327]

57:42 question 6 #include #include using namespace std; int main(){ //string s ="s","k","y"," ","t","h","e"; // char s[8] = {'s','k','y','\0','t','h','e','\0'}; string st = " sky the is blue "; int s = 0; int e = st.length()-1; while(s

[@sureshmakwana8709]

But this leetcode question got locked for Premium users now 🥲

[@im_sks]

wrong in o/p->we want "yks eht si eulb"

[@kishanprajapati3327]

@@im_sks yes but if you don't take space at the beginning and the ending it will give the wrong answer.

[@aizajsamani8894]

Kamaal karte hain bhaiya ji, itna bada video😰...Khair dekhna toh padega hi😁 Thank You bhaiya ji🙂

[@GauravSharma-ze4cu]

55:27 question 5 is little different btw great video

[@rohanmahajan6129]

Bhaiya time to laga puri video dekhne m, but truely mazza bht aaya, and specially jo questions kr k confidence mila...🔥🔥🔥🔥, thank you bhaiya..!!!

[@devvarshney1144]

Inplace solution of question "replace an space with @40" string replaceSpaces(string &str){ int l = str.length(); int i = 0; while(str[i] != '\0') { if(str[i] == ' ') { str = str.substr(0,i)+"@40"+str.substr(i+1,str.length()-1); } i++; } return str; }

[@kenguvaabhinav2200]

it should be substr(i+1,s.length()) as the end index is not inclusive, isn't it?

[@akashpatel-jp4gh]

Reverse words in a string we have to Change the position of word instead of reverse the word Example: "my name is love" Incorrect - "ym eman si evol" Correct - "love is name my" Like you helpful ❤

[@tausifahmad2007]

1:23:06 code:- string removeOccurrences(string s, string part) { //while(s.find(part)!=-1){ s.erase(s.find(part),part.size()); } return s; }

[@jasonjackson8557]

can you pls explain? why -1?

[@jaivishavbhaskar7776]

At 42:46 Question Valid Palindrome my approach is a lot more easier and i wuld say the best: class Solution { public: char tolowercase(char ch){ if(ch>='a' && ch

[@rehanhussan]

Sir Your teach us Like a Brother, Quality content and I follow all your words.

[@arnobbaiga309]

bro 1:47:28 why he did char[ansindex++]?

[@BombSquadHindiTipsTricks]

54:56 the question which Love Babbar bhaiyya is talking about is reverse word in a string III not II so guys search question no.557 in leetcode

[@VishalGupta-xw2rp]

Wow... This is just Gold 🔥🤩

[@codedByAyush]

Wow Bhaiya, apne joh Palindrome ka approach bataya, woh toh akdam 🔥🔥 hai!

[@aakashprajapati4836]

Quality Content ++ ❤❤ Thank you sir for effort and time ur taking out for us 🔥🔥

[@gurtegsinghsohi411]

Can you provide answer of 57:15

[@usernamewhatsoever4557]

Bhaiya aaj pehla question leetcode pe khud se solve kra, bahut garv mehsoos ho rha hai Aapke videos ne bohot help kari

[@karthik53r35]

1:39:08 Homework with Runtime: 85 ms, faster than 30.06% of C++ online submissions for Remove All Adjacent Duplicates In String. Memory Usage: 9.7 MB, less than 96.17% of C++ online submissions for Remove All Adjacent Duplicates In String. string removeDuplicates(string s) { int i=0,j=1; while(i0){ if(s[i]==s[j]){ while((i>0 && j

[@parthhh3589]

time complexity kya hai?

[@mradultiwari9864]

@@parthhh3589 O(n square)

[@mradultiwari9864]

string removeDuplicates(string s) { int i=0; while(i

[@satyam8334]

​@@mradultiwari9864 Try this:- class Solution { public: string removeDuplicates(string s) { int sl=s.size(); int i=0; while( i0) i-- ; sl=sl-2; } else{ i++; } } return s; } };

[@mradultiwari9864]

@@satyam8334 thanks

[@manashvardhan9965]

bhaiya is video ko ek hafte se padh rha hu samjh samjh kar😎 thankU

[@jayeshmandavkar9837]

Attendance Marked Bhayya try to make videos till 1hr only because HW + attendance + Implementation is going beyond 3.5hrs going great in this course Hope we will be getting videos on daily basis...!! Thank You so much...

[@HardikKrPatel]

yes that's true✋

[@SumitSingh-wz3wt]

isme to 5 hour lag gaye

[@munnakrish3572]

Replace string question string replaceSpaces(string &str){ // Write your code here. string temp = "@40"; for(int i = 0; i < str.size();i++){ if(str[i] == ' '){ str.replace(i,1,temp); } } return str; }

[@rajkasat5804]

for adjacent duplicates: class Solution { public: string removeDuplicates(string s) { int j=0; int i=0; while(i+1

[@sonicboom6635]

Thank you bro sharing this code

[@raushansingh8618]

bro can u explain while(i+1

[@aviralkumarsingh639]

Ye lecture mera upr se gya 😵‍💫

[@sureshbhardwaj9998]

Log kehte the aapko coding nhi aati roadmap dete ho. Job se nikal diya.. Kya tamacha maara sbke mooh pr aapne..well done Poori duniya me itna detailed content nahi h filhal

[@hitececourses4062]

Replace Spaces: inplace solution string replaceSpaces(string &str){ for(int i=0; i

[@prajjwalsingh2009]

BRUH TOO GOOD

[@visheshkumar15]

why 32 can u explain me plz

[@prajjwalsingh2009]

@@visheshkumar15 32 coz its the ascii value for space

[@parthdeshwal4419]

9 hrs lage khud question try karte hue is video ko dekhne me

[@NamanSingh_142]

at 1:22:00,suppose there is no such part remaining in the string now,then .find() will return -1 and hence the condition becomes -1

[@sunpreetsingh3797]

Best solution to Remove all Adjacent Duplicates 1:39:00 void removeAdjacentDuplicates(string &str) { int i=0; while(str[i] != '\0') // OR we can use -> while( i

[@gulmuazzamfaize6020]

It's not working

[@harmanjeetsingh4973]

@@gulmuazzamfaize6020 int i=0; while(i>=0&&s[i]!='\0'){ if(s[i]==s[i+1]){ s.erase(i,2); if(i!=0){ i--; } } else{ i++; } } return s; This will work. he missed when i=0; then i will be decremented to -1, so code was showing compilation error

[@AyanSohail-oq7vk]

for Maximum occurring character solved using mapping with time complexity of O(n) and space complexity is O(1) which is the most optimal solution: the code is down below --> class Solution { public: char toLower(char ch){ if(ch>='A' && chmax){ max = it.second; maxchar = it.first; } //to handle characters lexiographically else if( it.second == max && it.first< maxchar){ maxchar = it.first;// s= 2 , t=2 , e=2; } } return maxchar; } hope this helps : -) .