Lesson 3 Logarithms, Solving Logarithmic and Exponential Equations

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Mr H Tutoring

Mr H Tutoring

Күн бұрын

Log Lesson 3
This video uses the laws and rules from lesson 1 and lesson 2.
5 exponential and 4 logarithmic equations are solved using log and natural logs.
Real life situation word problem is included also.

Пікірлер: 69
@niceplayer856
@niceplayer856 10 ай бұрын
From India but also watch your videos just because of your amazing teaching style🔥🔥
@mrhtutoring
@mrhtutoring 10 ай бұрын
Awesome! Thank you!
@user-ky5dy5hl4d
@user-ky5dy5hl4d Ай бұрын
@@mrhtutoring At 15:37 natural log of e on the right hand side is 1. That gives us 1 stil raised to power of -2t. One raised to power of -1 is 1. But what happens to t? And is 1 to the power of -2t negative 2t? Or should it be just t or -t? Let's say we have ln e to the power of 5x. So, ln e is 1 and we are left with 1 to the power of 5x. Do we multiply 5x by 1 or do we raise 1 to the power of 5x because 5x stil stays in the place of the exponent and 1 is the base. And it looks like you multipled one by -2t. Unconfuse me.
@trevorjames4619
@trevorjames4619 10 ай бұрын
Meanwhile, some student is paying an arrogant professor $10,000 a semester
@citizenworld8464
@citizenworld8464 10 ай бұрын
Once more, you render math simple and exciting. Again, thank you so much for sharing your knowledge, Mr H!
@bellemiscellaneous9417
@bellemiscellaneous9417 10 ай бұрын
Thank you for your videos! Very easy to understand!
@cristianlezama5564
@cristianlezama5564 10 ай бұрын
Your videos and the time you take to make them are truly appreciated. Thank You very much!
@iwjrbf99
@iwjrbf99 10 ай бұрын
we would like to see u solving calculus problems, huge support from hong kong😻😻
@HalifaxHercules
@HalifaxHercules Ай бұрын
I took some differential calculus courses when I was a Business student at Saint Mary's University in Halifax, Canada during the mid 1990s. While I'm familiar with limits, derivatives, and integrals, I would like to see some optimization and Law of Diminishing returns type questions.
@devonwilson5776
@devonwilson5776 10 ай бұрын
Greetings. Thanks always for sharing. Have a great day
@alphasaffi9230
@alphasaffi9230 8 ай бұрын
Thank you very much sir may God richly blessed you for the time you take to impact knowledge in our lives.
@amramjose
@amramjose 9 ай бұрын
Nicely done, professor.
@HumphreyVV
@HumphreyVV 6 ай бұрын
Hallo Mr H Tutoring, I am 80 years, and had the need to "brush off" some dust on past knowledge of your Topic. Well, after your video lessons, again ...I am on top of the subject. You have a marvellous way of making things look easy. Today is Christmas dec 26 in Holland, Merry Christmas to you, THANK YOU, and continue making things "look easy".
@mrhtutoring
@mrhtutoring 6 ай бұрын
Thank you. Merry Christmas!
@castiodette
@castiodette 8 ай бұрын
Damn! I wish you were my teacher in math when I was in school. I would have been more attentive! Lol. You make math so easy! Thank you sir!
@BWhiteHat
@BWhiteHat 10 ай бұрын
First, also again, love these videos
@andresomarlegarda616
@andresomarlegarda616 10 ай бұрын
Gracias profesor, excelente, las matematicas el lenguaje universal.
@emailinbox3260
@emailinbox3260 10 ай бұрын
You are the best. Gracias
@user-hx8dq9zn5z
@user-hx8dq9zn5z 10 ай бұрын
Good work Sir
@merc340sr
@merc340sr 8 ай бұрын
this video is AMAZING!
@drask1717
@drask1717 10 ай бұрын
You're the best
@BruceLee-io9by
@BruceLee-io9by 4 ай бұрын
Dear professor, a big greeting from Italy. Thanks for your lessons.
@Paulancar
@Paulancar 7 ай бұрын
The best!!
@alphasaffi9230
@alphasaffi9230 8 ай бұрын
Wow it amazing teacher thank you i appreciate you a lot sir i enjoying everything about you sir you have taken time to explain each step yeah
@mrhtutoring
@mrhtutoring 8 ай бұрын
You are very welcome
@baselinesweb
@baselinesweb Ай бұрын
Thank you for the great review.
@Nothingx303
@Nothingx303 8 ай бұрын
😊 thank you sir very useful questions 👍
@88kgs
@88kgs 3 ай бұрын
Thank you so much sir. Regards🙏
@user-hx8dq9zn5z
@user-hx8dq9zn5z 10 ай бұрын
I can recommend You an other channel for math Olympiad preparation
@lawrencelawsen6824
@lawrencelawsen6824 Ай бұрын
I love this guy
@newme8084
@newme8084 8 ай бұрын
Thank you ❤
@balukuchrispus4004
@balukuchrispus4004 8 ай бұрын
My teachers were hardening math. Made easy here, waiting for integration, differentiation and flow chart
@haroldjosephcollinsIII
@haroldjosephcollinsIII 8 ай бұрын
When the Bass meets the Treble i listen. When i Beat is about the nature of the Record i say "Turn it up!" I'd like to say something when i listen to a Record i am listening with an Ear to say i like it or i hate it. I don't minding thinking for you about this Lesson, but i am about the Record. I am the Owner of a Peer, but i am the CEO of Shore Entertainment Incorporated a California Corporation. ~ CEO this Record.
@terrypold
@terrypold 2 ай бұрын
In skydiving you have to account for air resistance. So, assuming that the skydiver is falling in a vacuum the calculations are correct. And, the skydiver is dead.
@thethinkinggamer1864
@thethinkinggamer1864 9 ай бұрын
Hello sir, you're method of teaching is extremely helpful, concise and clear, I'm from Canada and I'm wondering, which grade I will be using logs? Since I've just reached grade 11 and I've started quadratics.
@mrhtutoring
@mrhtutoring 9 ай бұрын
Usually in the 9th or 10th grade in the US
@henna-designs-and-paint2268
@henna-designs-and-paint2268 8 ай бұрын
We learned logs in grade 12 pre-calculus classes in Canada. I hope it helps
@apolloapollo3248
@apolloapollo3248 Ай бұрын
❤❤ beyond
@ART7N23
@ART7N23 10 ай бұрын
Sir can u do teach vector basic ( short video )
@ankitnauriyal6214
@ankitnauriyal6214 9 ай бұрын
Sir please explain under the root when can we cancel the root and when we can can't please sir make a vedio 💖
@moeberry8226
@moeberry8226 8 ай бұрын
Good video bro but I want to point out that exponential equations can have imaginary solutions if you consider x to be a complex number. For example e^x=-2 has a complex solution.
@mrhtutoring
@mrhtutoring 8 ай бұрын
x=ln(-2)? The equation you gave has no solution.
@moeberry8226
@moeberry8226 8 ай бұрын
@@mrhtutoring the equation I gave does have a solution x=ln(-2) can be broken into ln(-1)+ln(2)=ln(e^(ipi))+ln(2)=ipi+ln(2) as the principal root, this equation has infinitely many complex solutions. In general the solution is (2n+1)ipi +ln(2) where n is any integer and i is the sqrt (-1) so in our base case when n=0 we get the solution I stated 2 sentences back.
@farhanfouadacca
@farhanfouadacca 3 ай бұрын
Nice
@mayankshirali1158
@mayankshirali1158 10 ай бұрын
can you make a video about binomial theorem?? pleaseeee
@mrhtutoring
@mrhtutoring 10 ай бұрын
Will do soon
@mayankshirali1158
@mayankshirali1158 10 ай бұрын
@@mrhtutoring thank you sir
@charlieibkiss4068
@charlieibkiss4068 10 ай бұрын
Good shit professor I love it!
@josephveedock7815
@josephveedock7815 8 ай бұрын
Barbarian at the gate
@ChavoMysterio
@ChavoMysterio 8 ай бұрын
log_2(3)+log_2(x)=log_2(5)+log_2(x-2) log_2(3x)=log_2[5(x-2)] 3x=5(x-2) 3x=5x-10 3x-5x=-10 -2x=-10 x=5 ❤
@ChavoMysterio
@ChavoMysterio 8 ай бұрын
3^(x+2)=7 x+2=log_3(7) x=-2+log_3(7) ❤
@ChavoMysterio
@ChavoMysterio 8 ай бұрын
e^(2x+1)=200 2x+1=ln(200) 2x=ln(200)-1 x=[ln(200)-1]/2 ❤
@drewbanares3577
@drewbanares3577 10 ай бұрын
@10:52 Isn't something raised to the -x just the same as 1/x?
@carultch
@carultch 9 ай бұрын
No. x^(-1) is the same as 1/x. Negative exponents imply reciprocals in general, where the negative exponent becomes a positive exponent, once you move the power term downstairs. However, if x is in the exponent, instead of the base, it must remain in an exponent in some form or another. B^(-x) is not the same thing as 1/x of B/x, or anything else that only has x in the denominator. It is 1/B^x.
@silent99gamer
@silent99gamer 10 ай бұрын
This is eassy
@jmich7
@jmich7 7 ай бұрын
We are sure we can use the law of exponents, for the number was elevated to an exponent, right? There are many numbers; that elevated to an exponent allow us to use the log law of exponents. What numbers do not allow us to do so? Would we have to invent such numbers? To begin with all the numbers minus times a positive integer . We cannot take the log of a negative number...Let us start by saying that the log of a negative number is undefined........Or assuming the log of a negative number is undefined........
@ChavoMysterio
@ChavoMysterio 8 ай бұрын
log(x+2)+log(x-1)=1 log[(x+2)(x-1)]=1 (x+2)(x-1)=10 x^2+x-2=10 x^2+x-12=0 (x+4)(x-3)=0 x+4=0 x=-4 (x[>=]-2; x[>=]1) extraneous solution x-3=0 x=3 ❤
@robertjohnson1962
@robertjohnson1962 9 ай бұрын
If math were jazz, you’d be Miles Davis.
@ChavoMysterio
@ChavoMysterio 8 ай бұрын
log_5(x+1)-log_5(x-1)=2 log_5[(x+1)/(x-1)]=2 (x+1)/(x-1)=25 x+1=25(x-1) x+1=25x-25 x-25x=-1-25 -24x=-26 x=13/12 ❤
@ChavoMysterio
@ChavoMysterio 8 ай бұрын
4+3[log(2x)]=16 3[log(2x)]=12 log(2x)=4 10^[log(2x)]=10^4 2x=10000 x=5000 ❤
@ashu4315
@ashu4315 10 ай бұрын
Lesson is nice sir but try to include some tough questions
@user-fq1wj8xj2k
@user-fq1wj8xj2k 8 ай бұрын
3^(X+2) = 3^X * 3^2 = 9*3^X 3^X = 7/9 X= ln(7/9) / ln3 = (ln7-ln9)/ ln3 = ln7/ln3 - 2
@ChavoMysterio
@ChavoMysterio 8 ай бұрын
e^2x-e^x-6=0 (e^x)^2-e^x-6=0 (e^x+2)(e^x-3)=0 e^x+2=0 e^x=-2 (x>0) e^x-3=0 e^x=3 x=ln(3) ❤
@haroldjosephcollinsIII
@haroldjosephcollinsIII 8 ай бұрын
When i say i am a Dr. with no Degree i am, but i'll never say it to you Reader. I am smart, so i listen. I don't like thinking for you Reader, but i do. I am not about talking to you Reader. I am about my Doctrine. When i think about it i see it Reader. I don't like being about my Name and not talking Reader. I listen. I talk. I think, so i am Reader. When i listen Reader. I listen. When i think Reader i listen. When i talk Reader i am thinking about me Reader. This Dr. Degree is a Science Reader. And i like it. Bye Reader. ! Holder of a Science Degree. 🙂
@abijahmarshal
@abijahmarshal 2 ай бұрын
Anybody for JEE 😊
@gamer0-0girl
@gamer0-0girl Ай бұрын
你是中国人吗?
@user-fb6fl7zy6j
@user-fb6fl7zy6j 8 ай бұрын
Söylediklerinizi anlamıyorum ve buna gerek de yok çünkü yazdıklarınızı anlıyorum matematiğin dili evrensel
@starnews3551
@starnews3551 6 ай бұрын
Thank you ❤
@mrhtutoring
@mrhtutoring 6 ай бұрын
You're welcome 😊
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