I like his enthusiasm. He is actually out of breath presenting mathematics. There is so much that is so important to present.
@christianlapointe16782 жыл бұрын
How amazing of a time we live in, where amateurs like me can catch a mere glimpse of our times greatest geniuses!!
@ryanjbuchanan Жыл бұрын
Yep
@anam.caballerowilson94214 жыл бұрын
He sounds so excited about this topic lie algebra. Good.
@joemoeller14424 жыл бұрын
At the end he mentions that the derived category of the universal Lie algebra is equivalent to the derived category of the category of functors from FinSurj to Ab. Where can I read about this?
@duckymomo79354 жыл бұрын
What you’re looking for is look up operads and universal algebra Start with P Vogel’s paper I hope this helps
@duckymomo79354 жыл бұрын
Jin Guu Northwestern paper by Eva Belmont might help (look up operads applications)
@tedward1914 жыл бұрын
Perhaps this is yet to be published material from Lurie? As I cannot find any text about this anywhere
@danyeol14 жыл бұрын
What a Nice lecture...
@joebloggsgogglebox4 жыл бұрын
I don't understand the comments at 11:30. The result of the commutator map is a loop of dimension a followed by a loop of dimension b, followed by their inverses, which is not the same as a loop of dimension a+b, right? Or am I misunderstanding something?
@joebloggsgogglebox4 жыл бұрын
@Connor Malin I think I understand the relationship between the loop space and the base space (the right hand side dimension increases by 1 not 2). It's the dimension of the right hand side when a,b>0 that I don't get. If we have a=b=1 then on the left hand side we have a pair of 2-loops, and the commutator of those 2-loops is surely another 2-loop (the first followed by the second, followed by their inverses), not a 3-loop!?
@joebloggsgogglebox4 жыл бұрын
OK, after thinking a bit more about the comments at 16:40 and reading the Wikipedia page about the Whitehead product, I think I get it; one of the dimensions is used by the commutator map for joining the loops (p, q & their inverses) together, and the other dimensions are used for identifying the particular 1-dimensional loops within each part. So he is treating the dimensions a bit differently in pi_{a+b}; they don't correspond with spacial dimensions as they could do for pi_a & pi_b when I try to imagine an example in my mind.
@noellundstrom74473 жыл бұрын
What a great talk/lecture
@hhhhhhhh60082 жыл бұрын
G cross g space to the identify put your identity in me(I know you know what the identity is)
@j1d2e3l4l54 жыл бұрын
Jacob is always good.
@kaushaltimilsina77272 жыл бұрын
Wow! Thanks very much for the really interesting talk!
@hhhhhhhh60082 жыл бұрын
Good
@perguto4 жыл бұрын
Why does this video have so many views (relatively speaking, for a maths lecture) after just a few hours? Is it just the prominence of the speaker plus the rather simple title?
@ХыуБаоВыонг4 жыл бұрын
I think it is youtube's algorithm, I came here because I saw it the first video recommended and it from IAS, so just curiosity. I intentionally want to watch another lecture :)
@PGouges354 жыл бұрын
Same here. I have viewed other videos on Lie algebras and the KZbin algorithm recommended this video to me
@harrywilson16604 жыл бұрын
IAS has 40k subs.
@johncharles23574 жыл бұрын
Jacob Lurie is currently a big name in mathematics. Check out: www.quantamagazine.org/with-category-theory-mathematics-escapes-from-equality-20191010/
@giuliocasa13044 жыл бұрын
@@johncharles2357 they should give those money and prizes to really competent people working in many technological fields. I'm a programmer and I see the mathematical concepts that a good developer like me has to apply to implement good abstractions in the working business context. There is an exaggerated worldwide marketing sponsorship for these golden positions, where one can enjoy playing with exotic topics and earn so much without any just comparison to the real market outside, with reference to other intellectual workers
@SidharthSisawesome4 жыл бұрын
At 5:35, How does the differential of the commutator map give the Lie Bracket?
Sidharth S Yes, that’s why it’s really not an interesting Lie algebra
@rtravkin3 жыл бұрын
@@duckymomo7935 To get the Lie bracket on the tangent space to a Lie group, one should take the second derivative, e.g.: [ dx/dt (0), dy/dt (0) ] = d^2/dt^2 ( x(t) y(t) x(t)^{-1} y(t)^{-1} ) for two differentiable paths x(t), y(t) starting at the identity element x(0) = y(0) = e .
@adityaekbote84982 жыл бұрын
@@rtravkin what happens to the first derivative?
@hhhhhhhh60082 жыл бұрын
Simply laced algebras
@Bagatatatoken2 жыл бұрын
From Higher topos theory to higher cosmoi muchzuki theory
@hhhhhhhh60082 жыл бұрын
Jacob is always good
@wacksparrow884 жыл бұрын
Was thinking about CubeB inscribed in CubeA. CubeA is fixed and CubeB rotates around one point. Vectors move through each cube. What is interesting to think about is that there will be at times in which the vectors can either hit the imaginary barrier. Still working on it but interesting to think about in terms of shapes, boundaries, and properties that can be applied.
@kenichimori85334 жыл бұрын
Lie Algebras Lie Lie Lie cosmotopy.
@MasterKenfucius4 жыл бұрын
Ops... wrong video...
@johnrichardson32974 жыл бұрын
The answer should be Alpha Constant
@NothingMaster4 жыл бұрын
Agitated, breathless, uninspiring, uninsightful, and regurgitative.
@waynewalls50334 жыл бұрын
But that’s enough about you, onto the subject at hand...