Light NumericalS Top 20 || Science || Chapter 10 Class 10 In One Shot

[@atharvgolam]

v = 30cm h' = -10cm m = -2 cm nature : Real & Inverted image

[@jasleen819]

Your ansr is correct... But m=-2 hoga bs.. cm nhi lgega.. magnification ki unit ni hoti ..

[@joker73612]

@@jasleen819 correct

[@RaushanKumar-fk5qy]

Mera bhi same aaya but M=-2 hoga bass Unit nhi

[@rohitgugjar2831]

👍

[@harshitmeena4493]

@@jasleen819 correct

[@cookiecake6187]

Image Distance (Position): 30 cm Height of image: -10 Magnification: -2 Therefore, the Image is Real and Inverted

[@07FS]

Also add it is diminished

[@cookiecake6187]

@@07FS it's not diminished Because the Magnification is 2 , By the rule of magnification the image is enlarged because it's greater then 1 if the magnification is less then 1 then we can say that the image is diminished 😊 Therefore, the Image is Real Inverted and Enlarged

[@TARWITZ]

Yes I also got the same answers

[@07FS]

@@cookiecake6187 ok thx 😁

[@ScorpioXD6969]

@@cookiecake6187 its -2 not +2

[@abeertodi1608]

49:20 Answer no. 10 Focal length = -20cm mirror - concave (it has a converging nature ) Nature of the image formed is real and inverted and is enlarged in size.

[@bhawanatomer8494]

Yeah same here n m checking m I right or not 🤣 and when I came to know this is right 😄 this is satisfaction of another level 😁

[@abeertodi1608]

@@bhawanatomer8494 isliye toh dala he taki sabki help ho jaye . lage raho bus 👍

[@abeertodi1608]

@Pooja Pritee Ayush welcome

[@hy-re7kx]

Correct answer 😀 yes !!!!

[@hy-re7kx]

Didi but apne idhar nature of image bataya jo pucha nhi apne nature of mirror batana tha yani concave or convex 😅

[@abeertodi1608]

24:29 Answer of ques.3 :- V=30cm (position of the image ) m= -2 Size of image = -10 cm Nature of the image- real and inverted, enlarged and the image will be formed beyond 2F2.

[@dhavalbadiyani4027]

How is magnification-2 if the h' is-10?🙂

[@AryanRaj-vt7cz]

@PRIYANSHU SINGH same here

[@radhakrishnadas676]

@@dhavalbadiyani4027 same bro.. Please explain me🙏❤️

[@dhavalbadiyani4027]

@@radhakrishnadas676 h' is -10, and and h is 5, so they h'/h = -10/5 Hence it will be'-2'🙂

[@deven805]

Size double hoga

[@simranghadwe338]

For People who know all the formulas, here you go save some time... first 5 questions: 15:16 question 1 19:29 question 2 23:16 question 3 25:07 question 4 31:01 question 5

[@ZER-in9hs]

Thx

[@xiddhimx]

Thnkewwww

[@daksh-nikunjpal5727]

Thanks uncle ji

[@ColourfulCanvas10]

Thanx

[@batman.mp3]

Messiah

[@ranjanagupta8181]

Fun fact- KZbin ads- What does Sara do? Me- Disturbing me while studying from KZbin 😂😂😂

[@vivekchand8197]

🤣🤣🤣🤣🤣🤣🤣🤣🤣

[@girlayesha7432]

Sara wear a mask🤣🤣🤣🤣🤣🤣

[@YTbooiii]

try brave no ads

[@SushilKumar-xt9ns]

@@YTbooiii but, mera ads agaya

[@Fuckerbitch1266aa]

@@SushilKumar-xt9ns idiot brave is a web browser 😂😂

[@vanshikarani5457]

24:01 V =30 Hí= -10 Nature of image Real and inverted Englarged

[@adi00712]

Enlarged nhi diminished aayega mam

[@ishusrivastava2579]

Mera bhi same h🤗

[@asadraqib]

@@adi00712 bro diminished nhi hoga enlarged hoga cause magnification is more than 1

[@piyush6142]

@@asadraqib m=-2

[@satyakushwaha3351]

@@asadraqib bro -10 hai 1 se chotta isliye diminished hoga

[@GaneshKumatole...]

49:24 1)converging mirror 2)f=-20cm

[@Muscle_Mind_Mastery]

Correct

[@Tf_srt]

Yes

[@Aim-UPSC123]

00:00 (Introduction ) 01:00 (Formula ) 12:20 ( Sign Convension ) 15:15 (Practice Questions) Edit : Kal pakka Exam he 😄

[@WiLDbEAsTGameSHere]

@@RameshKumar-he5js RIP Ramesh

[@SureshYadav-qf2ki]

It's wasting time 😁

[@kizivashu3664]

Thanks Yaar

[@SureshYadav-qf2ki]

@my world I am sis 😁..... Anshu Yadav 😊

[@SureshYadav-qf2ki]

@my world lol but you don't mention unknown in your comment

[@ompandey9127]

24:40 - 1. Position = 30cm 2. Nature = Real and Inverted 3. Size = -10cm 4. Magnification = -2

[@rrxrowdyyt9086]

U are right

[@namitanamdeo2428]

great

[@hy-re7kx]

Same 😀

[@Ajajshdhdh]

can i olso capy poste this

[@Jiyarisian]

Mujhe ye jana hai ki -10 kise aya mera 10 aaraha. Hai

[@uniquesahilff5225]

Answer no. 3→ h=5 cm f=10 cm u= -15 cm Lens formula =} 1/f = 1/v - 1/u =} 1/10 = 1/v - 1/(-15) =} 3-2/30 = 1/v =} 1/30 = 1/v =} |V= 30 cm\( position of the image) Magnification =} m = v/u =} m = 30/-15 =} m= -2 ( the image is real, inverted and enlarged ) because when magnification comes with negative sin i.e. image will be Real, Inverted, enlarged. m= n > 1 enlarged m = n < 1 diminished m = n = 1 same size # if magnification came with positive sin i.e image will be Errect, virtual ....😁 Thanku for reading my comment

[@kushalrt2007]

Op brother

[@smrizwan5203]

FANTASTIC BRO...............

[@oNY_X_]

-10 ayegi m

[@evilgaming4015]

@@oNY_X_ bro vo height ha -10

[@AK_POPA]

Size -10cm

[@geetanjalisinha625]

v=30 m= -2 height of the image =-10 nature = real and inverted size= enlarged answers of question 3 Thank you🙏

[@loveshpal]

Sahi

[@Anitasharma-bp3kg]

Size enlareged nahi ho ga

[@khushijain7270]

43:24 Sir for virtual image v is always positive...hence m=1/4 and this is case for convex mirror as concave mirror gives enlarged virtual image

[@RohitKUMAR-np8qd]

Bhai Yh Wala smjha Nahi M.....Isme Mujhe convex lag rhA H Bhai ..pr Reason nahi Hai....Can YOU Explain me

[@gamerjii3749]

@@RohitKUMAR-np8qd bcoz convex mirror give diminished image nd image form is 1

[@RohitKUMAR-np8qd]

@@gamerjii3749 I'm in 11 now ....so don't need this

[@FuXioN_7777]

@@RohitKUMAR-np8qd lol 🤣

[@sutapasur6834]

@@RohitKUMAR-np8qd convex hai because there it is given erect so it's virtual also so v=1 and u=-4 magnification will come out to be 1/4 that means image is diminished which shows that image is virtual erect and diminished which makes it clear that it's convex mirror

[@AmanGupta-mq7zh]

24:47 v 30cm , height of the image -10 cm and magnification -2 cm

[@RakshitGarg06]

Don't use cm in magnification

[@karishmasingh7068]

@annu priya thanks

[@MithleshKumar-nu1sj]

@@karishmasingh7068 m=h'/h=v/u => h'/5=30/-15 =>h'=-10 Thnks me later🙂

[@dynamic8377]

Bro magnification has no unit 🙂

[@snehilsinghal6312]

Correct✅

[@karunamishra4093]

24:46 the position of image is 30cm, h'=-10, the nature of image is real and inverted and the size of image is enlarged

[@bollywoodmasala3436]

Wah bhai

[@adarshkumar8542]

Same...

[@Gattugamerfacts912]

I also got this

[@shahabdulla7501]

No image will be diminished because minus 10 is less than one ok

[@nidhichauhan7784]

I also got the same answer

[@RajeshSingh-rr1bc]

24:44 The answer is:- v=+30cm m=-2 Nature of image:- Real and inverted, Also twice in size than the object. h'=-10cm.

[@SAMEER_RATHER_001]

Legendary

[@SAMEER_RATHER_001]

🥵🥵

[@wildsoulgaming3662]

Bro mera m=2aaya plz yar bata de -2kise aayega??

[@AADILSTECH]

@@wildsoulgaming3662 i will help u bro..m= v/u m= 30/-15 m=2/-1 m= -2 cm.. If ur confused (there is negative sign in denominator it goes to numerator ) U got it?

[@wildsoulgaming3662]

@@AADILSTECH yess bro after 2 mins I got it

[@mayankbro6237]

Answer 3 : position of image =30cm, nature of image =real and inverted ,size =diminished Answer 10: focal length of concave mirror is -20 ,image formed on screen real and inverted .Sir but iam not sure for this answer please tell the correct answer

[@aspirantmemories2106]

Sahi ho bhai

[@rajrish]

The image is not diminished, in fact, the image is 2 times magnified. The size of the image is -10cm. And the magnification is of -2

[@ashubhaicomedydala]

@@rajrish yessss sahi kaha

[@akshitajain2096]

56:35 focal length=20cm Height of the image = -6 cm

[@yashmaurya4229]

Question no. 4 ----> Nature- Real& Inverted Size-> -10cm Position- 30cm m=-2....

[@dineshmahto8788]

Yes sir phir se bataeye q no.3

[@mirmuneeb3704]

Right 👍

[@vashu_vv]

👌

[@YuvrajSingh-tw7fi]

Wrong hai bro position not -30 it's only 30 check it bro

[@faqlodeon69]

Oye yash lucknow nhi aya yrr tu bahut time se

[@latifmd3047]

49:26 FOCAL LENGTH -> -20CM

[@tarachandtribhuwan3477]

Hi Do you have the light and reflection notes of edumantra

[@SankalpChandra.02]

Ur ans is ryt!👍🤟

[@urjitchauhan7737]

@@tarachandtribhuwan3477 mere pass h bhai

[@armaan7194]

@@urjitchauhan7737 kahan se mile

[@preranapatil5076]

Bhai mera ans to -30 aa raha hai 😭

[@AlexS_2902]

49:24 F = -20 Concave mirror 😉👍

[@legionx8099]

Same here But -20cm Unit imp

[@aryanbhadoria601]

Bhai image ka distance 30 diya hai na yani v =30 ??

[@AlexS_2902]

@@legionx8099 ha 😅 unit bhi lagana chahiye tha, bhul gaya 😅

[@legionx8099]

@@AlexS_2902 hota h , hota hai

[@legionx8099]

@@aryanbhadoria601 no dist. Of obj diya h U= -30cm

[@rohanchavan8817]

Sir for Q8= 41:22 In both cases v = +ve Therefore, m=-v/u Thus, m= -1/-4 Thus, m=1/4 Here we can clearly see that image is smaller than that of the object. So, case of concave mirror can't be get satisfied as it forms larger image than that of the object. So it is convex mirror. Ans: m=1/4 And mirror = convex Is it correct??? 🥲

[@sudipapaul56]

Ya it's totally correct👍

[@saanviisharma]

yes

[@shaikmujahid25]

I too got the same!

[@nooreopro2292]

You are right

[@MOHITSharma-qn6qx]

24:36 v=30. Height of image=-10. (Below 👇 principal axis ) Real and inverted

[@devotionalladki215]

👏

[@rajrish]

Correct

[@tanishqdaksh]

3rd ques v=30 h'= -10 Nature real and inverted image

[@btvbanjara7658]

@@dazaisama3214 bro formula lagao m= h'/h=v/u h'/5=30/-15=-10

[@prasanshalodhi3781]

@@dazaisama3214 v/u= -2 ( R and I, Magnified) now, h'/h= -2 h'= -2*5 h'= -10cm

[@dti6866]

Right

[@sharakhan6821]

Nd m= -2

[@pujasharma1065]

40:22 Distance of IMAGE from the OBJECT is asked. So I think it should be 0 cm because 50 cm is the distance of IMAGE from the POLE of mirror. 🤔

[@pawankumarsingh4715]

56:37 It is a CONVEX lens since its forming a real image Focal length is +20cm and size of image will be -6cm

[@thelostmann]

Can u explain dude?

[@arnavsingh0852]

@@thelostmann he iss wrong

[@ShreyaSingh-rq9uu]

@@arnavsingh0852 no he is right

[@akshatjajoo584]

Height of the image will be +6cm

[@holyhumane]

Correct 👍

[@sanketbasu3591]

Sir at 40:26 the distance between the image and object should be zero. V is the distance of the image from the pole of the mirror. Please make a correction sir. Thankyou.

[@Uditshastri00]

You're right brotha, even i got confused there. It's mirror not lens

[@prabhasharma7554]

Image distance from the mirror should be 100cm

[@class10namja9]

Yeah u r right but i think that he got confused and thought that what is the distance between mirror and screen

[@saijagtap7742]

24:43 Q3 Image distance (v) : 30 cm Height of image : -10 Magnification : -2 So, the image formed is enlarged, real and inverted.

[@reshmabagum9595]

V is positive so it should be virtual and errect know

[@nakiyasadikot1632]

@@reshmabagum9595 it happens in mirror... This is lens numerical U should draw ray diagram first of all then u will be clear

[@Aishwaryadey17]

@@nakiyasadikot1632 How does on the screen means real and inverted??

[@aryan4899]

May also student get 97%+ marks in board 2021

[@flutemelodiesbyraj3942]

Sahi pakre hai

[@piyushbhardwaj5811]

Thanks dips sis

[@Naturlove1]

🤟🤟🤟🤟

[@Saurabh_Rao_1111]

Thanks dipa

[@rohitrar9311]

Thanku

[@ishasachan7749]

49:31 ques no.. 10 focal length -20 cm and nature of mirror is concave mirror because image form in image form on screen then its show the property of real image

[@preranapatil5076]

Kese nikala bhai ans

[@iitianabhi62]

Sahi hai

[@hs_mannhs_mann4057]

Wrong it's -60

[@pranavforstudy9985]

I know these you tube teachers are fantastic.. but never forgot to respect your offline teachers.. Yesterday one of our teacher cried.. and said that after this corona , students didn't give respect to us.. it made a mind set that offline teachers don't know better than you tube teachers.. but they are also fantastic.. just try to listen their lectures.. and you will get

[@dereshishishishidereshishi4676]

Even offline teachers work hard but students have developed a mindset that KZbin teachers are better. People often ignore their offline class lectures and come here saying that our teachers in school aren't nice. People really need to concentrate on their offline classes instead of going online most of the time. Believe me , school teachers + ncert books are literally enough for understanding every concept in the syllabus.

[@mTrader1]

@@dereshishishishidereshishi4676 students are made to study forcefully by offline teacher on a particular time whereas they can study whenever they feel like they should or whever they want to

[@hakaishinbolte158]

@ Well Chess Player , discipline is very important in life . If you only study when you feel like it , you will never succeed in life .

[@gursimrankaur7034]

56:42 Focal length =20 cm Height of image =(-6)

[@RahulBhatt01]

Mera bhi yehi aara hai😀

[@yashwardhansinghsikarwar7074]

@@RahulBhatt01 kyuki yahi hai isiliye aa rha hai😅

[@ashokshakyawar6491]

Mera bhi yehi answer aaya he🤧

[@DeepakSahu-fb9px]

40:27 sir distance of image from object is 0, -50 is the distance from mirror

[@MonekyDluffy692]

Exactly !!!

[@trippleleggy4451]

Finally someone who studies and felt the same as me

[@umpking5955]

I understand but 0 kaise aya

[@MonekyDluffy692]

@@umpking5955kyuki image object ke saath hi bana hain(one above the another). Jaise main tere saath khadha (chipak ke) hun to, hum dono ke bich ka distance kitna hua- 0

[@pratiksha4258]

Hey there! Can you explain me how -1 will be the same size as the object cause it's less than 1 right but it will be the same size of the object only if it's equal 1? Like I'm confused a bit :(

[@divyajamwal1343]

44:36 magnification= -v/u (in case of mirror ) Therefore m= -(1)/-4 = 1/4 Since magnification is 1/4 image formed will be virtual errect and diminished (It is only possible in the case of convex mirror ) hence the type of mirror is convex and the magnification is 1/4

[@surbhirawat272]

44:55---> v is positive because virtual & erect image is always formed BEHIND THE MIRROR, means positive direction. Then, m= 1/4 It is CONVEX MIRROR because image is DIMINISHED. 👍👍👍

[@abeertodi1608]

56:30 focal length = 20cm m= -2 Type of lens - Convex Height of image = -6cm

[@PD22119]

I am happy with your answer

[@fiendfnm2828]

36:25 we can use m=f/(f-u) *OR* m=(f-v)/f ; where u=obj. dist. and v=img. dist. and f=focal length :D

[@akshitajain2096]

1:00:10 focal length = -8 cm

[@ritikroyrk2310]

Sir l hope that all student will get more than95 %👌🏾👌🏾

[@Pushpagaming229]

No not 95% we will get full

[@anishpatwardhan1023]

@@Pushpagaming229 we will get 99.99%

[@kingstar3396]

Not 90 but 70

[@thenikhilnain]

@@anishpatwardhan1023 that's not actually possible Even if you lose only 1 mark it will be 99.8

[@anishpatwardhan1023]

@@thenikhilnain 99%👍

[@anmolbharti9148]

If someone in an hurry and do not want to revise formula then Questions start at 15:17

[@kuldeepverma2232]

Thank u so much bro🙏🏻🙏🏻

[@anitapanwar2072]

If someone is in a hurry....... Then he/she will surely not come here to explore all the stupid comments......✌️✨✨

[@aainfos3023]

Thanks bro

[@lohitadityanaik9260]

@@anitapanwar2072 😂😂😂🔥 true bro

[@sanatani.by.heart-]

@@anitapanwar2072 kyu jhada rhi ho didi

[@AAdityaAvinabKumar]

At 24:40 v=+30cm , m= -2 , h'= -10 cm. Image is real and inverted. Thankyou sir.

[@princyparmar363]

Bhaiya apne h'kaise nikla

[@NeerajYadav-qu3mk]

Right....but i have a doubt....how to solve h'i.....?

[@samar7529]

Height of image = -10 cm Magnification = -2 Nature of image= Real and inverted Size of the image = diminished Position of the image = 30 cm

[@ot4138]

Size of the image will be enlarged na, cuz 2 is greater than 1 and as sir have told us ,when we see the digit we have to avoid the sign for that time.

[@rayyeras77]

@@ot4138 yup

[@Jeonjunkook307]

@@ot4138 yes👍

[@YashSingh00011]

Yes 👍

[@Gymmer_Youth_OFFICIAL]

No baruda Samar is right because -2 is less than 1 see..... - 2 ,-1 ,0,1 , 2 ,3

[@gunjanchaudhary1412]

24:47 v = 30 Height of the image is = - 10 Magnification = -2 Nature of the image is real inverted and larger than the object

[@muskanpandey5101]

I also got the same answer...

[@anshujoshi2162]

Same

[@sqln7515]

23:00 Height of image :- -10cm Nature :- real and inverted Size :- magnified

[@nikita6069]

I think Ho is -2..

[@GautamsChannel]

V= -12 I think 😢😢

[@sidhyanandapradhan748]

@@nikita6069 yes you are absolutely right

[@ankitapoetry8951]

Height -10 kaha sa aaya ?

[@gaurav7142]

24:40 Nature of image Real Inverted and Diminished Size of image -10 cm Position of image is 30 cm Magnification is -2

[@munirvohra9421]

Shouldn't it be Enlarged image since the value is more than 1 and we don't see the the sign it is only the number which is considered, let me know if I am right...

[@suparibhai3287]

@@munirvohra9421 but the magnification is -2 that is smaller than 1

[@munirvohra9421]

@@suparibhai3287 Brother The Image will be Enlarged or Diminished on the basis of the number not on the sign. For example if m=-5 the image is enlarged (-) sign doesn't give the value of the number. It's to check whether it is real or virtual... Let me know if I am right? This is what I learned in School

[@laxmipandey6359]

@@munirvohra9421 i too

[@NOTycyborg]

@@munirvohra9421 yes you are right buddy…… he’s dumb ignore him…….

[@kunalchandrakashyap3712]

mage Distance (Position): 30 cm Height of image: -10 height of image: -2 Therefore, the Image is Real and Inverted

[@allenmano]

m = -2

[@dharmendrabairagi1835]

Vro (30cm) he to virtual and erect hogi 👆

[@ghanshyamsingh6511]

@@dharmendrabairagi1835 yes sir

[@vanshajnirwal5825]

44:27 Sir Virtual And erect Image is Always formed behind the mirror therefore image distance will always be positive

[@Pinnacle_07]

36:28 sirji maine sirf ek hi case nikala tha and one doubt, Agr pencil ki height dugni thi to enlarge hai Vahi iski height highly Enlarge kab hogi

[@jhakanishka]

24:41 Firstly it is asking about the position means its asking about v =30 Next it's asking about the size means its asking about h'=-10 Since the size negative show the nature will be real and inverted Lastly its asking magnification v/u=30/-15=-2 Wrote this magnification part in some detail because at last I was forget to find the magnification so if someone else also forget it how to find so then my answer will be helpful for him or her

[@RashmiKumari-qo3ot]

How yaar how the image is real and inverted since image distance is positive? Does the image depend upon only magnification or position of the image

[@pragati4174]

@@RashmiKumari-qo3ot since the image height is coming negative it means that the image must me inverted and with inverted image is always real

[@pragati4174]

@@RashmiKumari-qo3ot u will see that magnification is negative then image will be real and inverted

[@RashmiKumari-qo3ot]

@@pragati4174 but why position of image is positive?

[@suchitrakambi7192]

Great 👍 this is correct 💯

[@ragegaming2823]

23:14 V= 30 Size= -10 Magnification= -2 Nature= real and inverted

[@rehankevlog376]

Magnification -10

[@tapashyasahu2335]

Magnification is 2

[@ragegaming2823]

@@tapashyasahu2335 check it twice🙌

[@tanmaysharma582]

33:23 SIr hint is given in the front of the mirroe in the question so the case taken will be real and inverted and magnification will negative of 2.

[@kartikdevnani8624]

no bro, look in both the cases the pencil is in front of the mirror as the distance is negative, so we HAVE to check for both the cases, i.e, one where magnification is +2 and another where m is -2 (and that hint is for object distance not for image distance and obviously we cant place object behind the mirror... I hope now u understand. 😇 )

[@aryankasundra9808]

Bro current

[@latifmd3047]

24:29 》REAL AND INVERTED 》DOUBLE THE SIZE OF OBJECT 》POSITION -> 30CM

[@restrings1393]

Enlarged image right??

[@flakeyt5940]

24:30 1/f=1/v-1/u 1/10-1/15=1/v 30=v M=hi/h=v/u hi=1/-10 Position=30 Size=diminished Nature=Real & Inverted

[@KhushalKotendra-pu8ok]

your v is wrong

[@shortsking4108]

Same m = -2 Bhaiya ap to 11th mai ho 😅

[@vsp3290]

40:24 sir (ii) ans is 0. Because both image and object is at Centre of curvature

[@angadsinghsandhu1489]

Yess that's what I was thinking

[@Tanishkagaur13]

But sir said it's -50?

[@manasmayank5082]

This is India's luck that genius teachers like Sanjeev Pandey Sir are teaching the students

[@manasmayank5082]

Yes it is

[@anish1246]

@@manasmayank5082 you are commenting on your own comment😝

[@mayanksrivastava7540]

@@manasmayank5082 my name is mayank and my brothers name is manas. What a coincidence!

[@manasmayank5082]

@@mayanksrivastava7540 bro my name is Manas. my brother's name is Mayank. My father made this KZbin ID by the names of both brothers. What a coincidence, you have the same pair of names 😃😃

[@mayanksrivastava7540]

@@manasmayank5082 yup! Surely a funny coincidence 😄

[@gulrajjain3585]

24:45 V=30cm H'=10cm M=-2cm Plz just apply formula same as above one

[@Wtfxshivam]

Bro hi = -10

[@sid1x1.]

@@Wtfxshivam yes bro

[@dineshbhosale2383]

Ya..The u is -15 so u'll get -10..

[@channelclosed218]

@@Wtfxshivam yes

[@raghavsharma1697]

Plz tell the position of image

[@varshajindal1951]

24:42 Distance of image = 30 cm Nature = real and inverted Height = -10 cm Magnification = -2

[@MDRASHID-xo4fb]

U r right

[@yadunathsingh5646]

Same bro

[@dpurple07]

Just got ur Channel recommended and trust me I have exam after some hours 😭 and this chapter is already a fuss but u Made it crystal clear we'll be always grateful to you with pure Gratitude🙇✨

[@catlol...]

V = image distance

[@mdzanyn3730]

Ohhhhk

[@rajkumarvlog6965]

40:22 there is asked the distance between object and image that is '0' but you told told the distance between mirror and image that was '-50'.

[@AbhayKumar-hw7ld]

it is 0.50

[@anish1246]

Yes

[@sanikainamdar2236]

v= 30cm, h1=-10cm, nature= real and incerted, magnification=-2 sir your videos are helping a lot! guyes exam ke pehle inke vids dekho full marks guranteed !!!!!!!

[@mohammadnaved7371]

Bhai ye vedio kal ke exam ke lie helpful hai ma

[@mohammadnaved7371]

Na*

[@anaszakir261]

@@mohammadnaved7371 numerical ke liye to ha but thoda jaldi jaldi karna padega

[@mohammadnaved7371]

@@anaszakir261 are bhai 2x pe laga ke dekenge na

[@s.fgaming209]

Same ans

[@lakshayvohra3346]

I wish all student across 95%+ marks 🙂 in 2022 because 2021 board are cancel 😂😂

[@mr.divyajain1268]

Kashhh

[@simranseerwani8784]

Thnx but it is rarely possible

[@AL-Shams-vy7ld]

Kassh esaa ho jaee

[@gymbeast8180]

Same to you bro, you also got 99.9% / 1st rank on class 10th CBSE

[@zunairamasood4944]

Ameen

[@paragdas7244]

40:23 ,2) I think the answer should be 0,as the question asks about the distance of the image from the object.

[@_aryanmishra_]

@@paragdas7244 you are right bro

[@jennnly]

Sir 40:20 Question is asked about the distance of image from *object* not Pole It's Zero

[@yashwardhansinghsikarwar7074]

Mai bhi wahi soch rha hu sir ne to from mirror bta diya

[@skm3840]

Jenni You Follows dear sir for maths, Science for edumantra 😂😂😂 me too

[@ljustice5905]

S

[@jennnly]

@@skm3840 yes❤ And Shobhit bhaiya for motivation 🤣

[@skm3840]

And bkp for sst 😂😂 shobit bhaiya notes our choices matches😂

[@shraddhapatel4087]

48:09 Nature of image = Real,Inverted Focal length= -20 Enlarged image

[@Beingmyself33]

Bro its called enlarged not inlarged.... Disclaimer- not here for correcting english...but can cost you in exam..😊 take positively

[@ruchikakaushik3510]

good

[@shraddhapatel4087]

@@Beingmyself33 thanks

[@Beingmyself33]

@@shraddhapatel4087 😊

[@kashifabbasi1077]

Ans. 3 v= 30 cm, size=-10 cm, nature= real and inverted, m= -2 cm

[@youtuber7960]

Yes bro same 😀😀😀😀😀😀

[@rdxgamer8128]

🤟

[@shreyamishra863]

Nature : real and inverted Position : 30 cm Size (img) : -10 Magnification : -2

[@adityarajsahu3204]

Correct

[@krittikaaa_18]

also the image formed will be enlarged

[@Kiyopon0]

Bro how? If the position of the image is real and inverted, how can it be on the right side of the lens?

[@beastayaan-2007]

@@Kiyopon0 nope

[@mr.skumar4407]

Size :-diminished, nature :-real &inverted, magnification:- -10cm, position(v):- 30cm

[@Aman.._yadav]

Correct

[@shobhitsinha9347]

@@Aman.._yadav kya correct galat likhha hai magnification is -2 and

[@vanshikamishra6798]

Magnification??

[@shobhitsinha9347]

@@vanshikamishra6798 seriously , that -10 is h dash value

[@vanshikamishra6798]

@@shobhitsinha9347 okay

[@proboyayushofficial7712]

24:44 , v= 30 , h' = -10 , m=-2 , real and inverted image which is enlarged

[@Hotliner_gamerz]

Correct and thank u for making me confident that I had done it correctly 😂

[@proboyayushofficial7712]

@@Hotliner_gamerz lmao and you're welcome

[@hyperop899]

How this is enlarged

[@proboyayushofficial7712]

@@hyperop899 Its enlarged because magnification is greater than 1 , when magnification is greater than one ( irrespective of sign) the image formed is enlarged

[@akshatisback]

Right anwer

[@surbhirawat272]

Q.3- Answer: POSITION: 30cm BEHIND THE LENS SIZE: 10cm tall, i.e. double the size of object NATURE: REAL, INVERTED & ENLARGED MAGNIFICATION: -2

[@rttech7627]

thank you brother

[@ZXSAMOP]

i have a doubt how do we find size and nature of object by finding these values please help :(

[@satyagautam659]

24:45 question 3 , V=30cm , m= -2 , h' = - 10cm Nature = real ,inveted and enlarged

[@_MOTIVATIONAL40]

1:05:10 Sir we only have to find height not a focal length by magnification we will find our answer -30 easily.

[@_MOTIVATIONAL40]

Sorry Image distance.

[@rageboyankit9762]

@@_MOTIVATIONAL40 yes right 👍

[@whbazaz]

Yes right Singh sahab!

[@pratyakshbhardwaj6195]

At 41:30 sir said convex mirror by seeing the diagram. I will try to tell be theory concept : u=-4 metres v=+1 metre ( Reason: both spherical mirror always forms the erect image at right side so +sign) Using magnification formula: m=-v/u =-1/-4 =1/4 (which is smaller than 1) Diminished image is formed which is only possible in the case of convex mirror. Therefore answer is m=1/4 and convex mirror.

[@rachitgarg4712]

Me bhi yahi soch ra tha😅😅

[@varunkushwaha69]

Same bro 😁

[@akmotivation5053]

Q.no.3 Ans: v = 30 Real and inverted h' = -10 m = -2

[@arkojotibhowmick5983]

Boht badiya same hai mera bhi

[@arkojotibhowmick5983]

Kitna syllabus ho gaya bro?

[@akmotivation5053]

@@arkojotibhowmick5983 Now only i have started to study I think 10% over What about you ?

[@arkojotibhowmick5983]

All done doing sample papers and all that stuff

[@memeshub6001]

Thanks

[@SangeetaDevi-eo4fl]

Tomorrow is my exam and thanku so much sir the helping me through this video 😇😇

[@prakashpujara6184]

24:32 this numerical's answer is v=30cm h'= -10cm Image is real, inverted and enlarged

[@madhavkhandelwal9621]

It is diminished not enlarge

[@schooltags4470]

Question number 3 ( sir told to comment and say the answer) v= 30 cm Nature: Real and inverted Size : Enlarged, -10 cm Magnification= 2

[@shahidkham548]

Magnification is minus 2

[@anuragupadhyay5010]

M negative na aayega 30 ko _15 se divide karoge to _2na aayegy to diminished na hoga

[@komalkapri3004]

Answer of 3rd question : Nature=Real and inverted Position=30 cm from lens Size = -10, Enlarged Magnification =-2

[@rowdygaming6201]

Good job 😘😘❤️

[@pokemonworldfanclub7467]

Very nice day due your lecture

[@NCSMUSIC.7]

Mera bhi aagya answer👍👍👍🙂🙂🙂

[@ManpreetGill-fc2zq]

Image distance:30 Height of image :-10 Magnification:-2 Nature:real and inverted ..

[@youtubeuser-9432]

Height of image - 10 lamao 🤣👀

[@sohamtaneja412]

40:23 Sir the distance of image from the object should be 0 cm and not -50cm. Am I correct?

[@dsmeena116]

Correct

[@kkbfansasphitlerhater2494]

Yes,Ur correct..It should be 0 not -50..

[@SankalpChandra.02]

This was a mistake from the side of sanjeev sir! Please correct it everyone! 🙇🏻‍♂️🤟

[@harshitavishwakarma9868]

Sir question no. 3 Nature- real and inverted Position = v = 30 CM h ' = -10 cm m = -2

[@sompalsingh2617]

Thnks I have just cross checked from your ans. Thnks a lot.

[@vigourpunt9864]

bro yes but nature real and inverted and size diminshed

[@harshitavishwakarma9868]

Yes,thank you 😊

[@sompalsingh2617]

@@vigourpunt9864 yess

[@badboy_productions]

Oh... Is ur name also harshita.... Ummm..

[@Vanshiikaaaaa]

In Question-3 Position (V)=30cm, Nature=real and inverted Size=enlarged or magnified Magnification(m)= -2

[@vansh1659]

My Answer is also same

[@hrmndeeprp-2584]

How enlarged?

[@hrmndeeprp-2584]

Magnification is -10...as...h'/h=V/U ...putting values..it gives h'/5=30/-15 i.e h'/5=-2....h'=5×-2=-10

[@Vanshiikaaaaa]

@@hrmndeeprp-2584 you're right but see h' is -10. If we'll solve this further for the magnification as....h'/h= -10/5 Then the magnification will be -2

[@hrmndeeprp-2584]

@@Vanshiikaaaaa oo thanku sis❤️..but r these both answers right?

[@akshatisback]

24:45 Iska answer Nature-real inverted Size-(-10cm) Position- 30cm

[@ayushkaintura3607]

Sir, Vo magnetic effects of current ke important questions bhi krado🙏

[@Priyanka-ke4zu]

24:45 The answer is:- Nature of image =Real & inverted Position = +30 Size of image = -10 Enlarged Magnification = -2

[@anshikasingh4334]

Answer = Nature of image = real & invested Position = -30 Size of image = -10 Magnification = -2

[@anshikasingh4334]

Sir it is right or wrong

[@anshikasingh4334]

24:47 ques no 3

[@Priyanka-ke4zu]

@abhishek pandey11 If u slove v/u with theri value you'll get the answer...

[@Priyanka-ke4zu]

@abhishek pandey11 So what u want to ask?? Sorry I didn't get ur question!! I think I get confused...

[@NITJSAURABH]

24:46 nature(Real inverted), height (-10cm), position of object (30cm)

[@STudyTaleS3]

thanks....I rechecked and mine is also correct

[@Adarshpandey94712]

Galat 30 or -2

[@krivikashyap]

Just for ur information magnification is -2

[@STudyTaleS3]

@@krivikashyap yup....mine is also that

[@aryaatkari9169]

@@Adarshpandey94712 yes you r wright adarsh its -2

[@RISHABHAGARWAL-jm8vz]

In some questions i faced problems but more than seventy percent questios i was able to solve Thank you sir for your help ♡

[@khallasplayz]

I never forget you in my life 😭😭😭Thank you sir 🙏🙏🙏

[@sandipkr.2292]

You are the most hard working man this time.......love u sir❤️❤️

[@gopika4534]

Sir, aapke classes attend krne ke kaaran mere science ke marks mein 20 marks ka boost aaya hai. Pehle toh mein science mein A1 laane ka soch bhi nhi sakti thi. Par ab meri boards ke acche results ki ummeed badh gyi hai. All thanks to u sir :)

[@Harshmaheshwari9028]

Same yr mere bhi 68/80 mese aaye pehle 50 tak kabhi kabhi aate the🙏🙏👍

[@sagarsway2277]

@@Harshmaheshwari9028 👍👍👍 nice bhai keep it up

[@avdheah6162]

Yaah absolutely right 👍👍

[@yasmin2679-d6f]

Magnification is -2 Size of Image -10. Position of image 30cm

[@study6360]

bhai same yhi aya mera bhi 💝

[@abhishekchauhan896]

Magnification -2 kaise aayi??

[@abhishekchauhan896]

Baki sb toh sahi aayi but magnification m mistake h

[@study6360]

@@abhishekchauhan896 bhai mera yh aya eo baar me wapis solve krta hu

[@nathaniel5091]

Size of the image -10 kaha se aaye? .please explain me ! ?

[@Krishnarastogi_7]

24:40, _Image Position(v)_ = *30cm* _Nature:-_ *Real & Inverted* _Size:-_ *10cm*

[@pawankumarsingh4715]

Bro it should be -10 cm

[@pawankumarsingh4715]

Since it is real and inverted

[@Krishnarastogi_7]

@@pawankumarsingh4715 Yes that's correct too but mine is neither wrong, the negative sign just denotes that the image is real and inverted which i already mentioned in _Nature_

[@pawankumarsingh4715]

@@Krishnarastogi_7 ya ya bro ✌️

[@vshny_kshh7566]

Magnification ?

[@Dr-vp4yo]

1:00:11🕐 The focal length = + 8cm Best 💗 TEACHER 💗 Ever

[@pankaj_gmch]

Concave mirror focal length will be in negative

[@kavitaawasthi3341]

solve krke bhi negative hi aa rhi h focal length .

[@funnycliper5370]

focal length negative aaye gi bro

[@princepandey9468]

24:45 the answer is, Position of Image- 30cm. Nature of Image- Real & Inverted. Size of Image is -10cm.

[@Ani_]

how the value is negative bro?? Position of image is = +30 or -30?

[@princepandey9468]

@@Ani_ arrey wo negative nhi hai wo = ka symbol hai

[@Ani_]

ohh dude, you didn't added up gap, no problem then my answer was correct :)

[@Mayank-fe9ev]

Sir in 1st question I think so the m = 3 cm by the formula m=v/u . You can check it on google also 😀.

[@harshitsangwan30]

Who wants to score 96% above 🖤🤔🙌 and you also deserve this 🎯

[@nehakakkar5452]

@@suhani9885 I also

[@virpalkaur8736]

Me want ❤️❤️❤️👍👍❤️❤️👍 god bless us all

[@yashchaudhary3200]

I want

[@kaminisinha4215]

I want

[@yashdeeptehlan3889]

@@virpalkaur8736 english 😂

[@Priyanka-ke4zu]

1:00:02 Answer :- Focal length of the mirror = -8cm

[@yogawithkuldeep3671]

Bro galat hai

[@alokkumar096]

-8 hoga

[@sharique2006]

Is it -8?@@yogawithkuldeep3671

[@girleditor3819]

-8cm

[@girleditor3819]

@@sharique2006 hn...

[@sharanyaahire7299]

Sir Q.3 ans v= 30cm(position), h' = -10cm (nature = inverted and real) and size = -2cm (diminished) sir is magnification in this question same as size? By the way sir I am new student of batch 2021-22

[@shreyaskhare2712]

Yes I got same

[@a2motivational654]

Same

[@aaryamanjain2204]

Q. A 5cm tall object................................find its magnification. Ans :- f = 10cm u = - 15cm v = 30cm m = - 2 h = 5cm h' = 10cm

[@lokendrapandey4812]

Answer of question asked in 24:40 Q3: Position of image(V) :- 30 cm from the lens. Magnification(m) :- -2 Height of image(h') :- -10 cm Size:- 2 times that of the object Nature:- Virtual and erect

[@Arya-pq8hm]

Real and inverted

[@itzz_me_viru9104]

Real n inverted

[@deadofedit7403]

It's virtual

[@unknownxyz694]

Bro,nature real n inverted hoga.........

[@THE.CR.OG.7]

Real and inverted

[@baleepahade5929]

24:48 Ans of Q.3 v= 30cm h= - 10cm m= - 2cm The image is Real and Inverted

[@TanishqMishra_IIT-R]

Enlarged or diminished?

[@TanishqMishra_IIT-R]

M= 2 So image will be enlarged

[@sristibisht3980]

44:49....sir yhn pe hume image distance aur object distance given h to hum usse focal length find krenge aagr focal length positive hoga to vo convex mirror hoga or agr negative focal length hoga to concave...✌ And focal length positive 1.33 aya h so ye convex mirror h.....

[@prarabdhanamdeo6960]

No you are wrong focal length is -20 cm

[@prarabdhanamdeo6960]

@@sristibisht3980 see 1/f =1/v+ 1/u... 1/f = 1/-60 + 1/-30 ... 1+2/(-60)... So 3/-60 and as you know 3×20 is 60 so here f = -20

[@sristibisht3980]

@@prarabdhanamdeo6960 bro app kon se que ka ans btare ho ye.......que to ye hh.....An obj is kept at a distance of 4m in front of sperical mirror, which forms its erect image at distance of 1 m from the mirror. What is magnification? Is the mirror concave or convex...... Here in this que u =-4m and v=1m

[@sristibisht3980]

@@prarabdhanamdeo6960 bro jo timestamp diya h maine uspe click kro vo h que ussi ka ans di hu mai.....✌✌