There is a mistake @3:19 P(x) = x ∉ x; // wrong And object is not a member of itself, an object is a member of a set. The question should be: Does A⊆A? Because A is a set. P(A) doesn't make sense because P is applied on objects of A.
@ABaumstumpf3 күн бұрын
Huh - but why is it an ODR violation? if no conversion exists then the template provides one - so do we somehow get a second definition?
@Voy23782 күн бұрын
In Rust you can have set that contains all sets ;)