Linear Algebra - 13 - Checking a subspace EXAMPLE

[@F34R303]

Spent like an hour watching other videos and reading the textbook. You actually explained it with logic I could understand, thanks so much

[@Mary-gr3mr]

I was lost but now I'm found. Thank you so much

[@Bounty_rash844]

And either

[@erikmachado4489]

This topic was so abstract I couldn't understand what was going on behind the scenes. Like I knew how to get the answer but I didnt know what I was doing. No other video explained the concept or the how. Thise videos just literally said "as long as these 3 conditions are it is a subspace". This video clarifies perfectly what it was I needed. I really don't understand why teachers try to overcomplicate everything.

[@Ellipse_is]

Dude you are the FIRST person to explain ANYTHING about subspace. Thank you, this was so much help. Every other Subspace video out there is FUCKED.

[@gizememir5801]

sakin ol amk kjshkjsafkja

[@StefaniSkurteska]

you are the only person to ACTUALLY explain the logic behind the rules. You're perfect and sent from God.

[@Yahhkult]

Thanks man! I got a final exam coming up and no videos/tutorials helped me. Your explanation was very concise and clear, thanks!

[@Lexyvil]

Very useful! Every source I checked, they did not show examples, but explained the theory, which only got me lost. But seeing how to actually test the axioms, that helps! Thanks!

[@MystyXsoul]

Much clearer than the other vids I found, tysm

[@selenav9514]

I've been struggling with this and with one video, I feel I understand it so much better

[@Youbettersaysubhanallah]

Al Salamu 'alaykom wa rahmatu Allah wa barakatuh , may Allah subhanahu wa ta'ala bless my muslimin brothers and sisters and make this knowledge beneficial for your dunya and akhira ameen ya Rabbi

[@denicapavlova2820]

So clear and understandable ! I spent an hour on other videos trying to comprehend it haha. Thank you very much !!!!

[@ImTheBoss914]

Wow, this was such a clear and quick video!!!

[@Bell.A130]

Just saved my ass. I had a quiz I was losing my mind trying to prepare for. You did this so concisely and clearly. Thank you!

[@vincentd1992]

Thanks! Why does everyone else fail to explain it so clearly? :) Great job helping me - and many others.

[@vincentlin7372]

Thank you you saved me from those complicated abstraction

[@danielwinner6394]

I agree with all the other comments. First I found that got me to understand and it did it really well

[@sanket7877]

You explained it very nicely. Thanks a lot sir . #staysafe

[@jadeclarke4116]

may god bless you eternally my friend

[@learnmathematics1115]

GOD bless you, you are good Teacher

[@vishveshsinghpal4289]

you saved me a lot of hours thank you very much

[@oscarwong666]

Very helpful, thank you very much.

[@LOLjerel]

Thank you for this!

[@arjay_2002]

THANK YA THAT WAS A VERY CREATIVE MATRIX PPPFFFTTT

[@ld8162]

Wow! Is the easiest way which I found in youtube. Thanks you a lot!

[@emersoncelestial7590]

in 2:13, should be the subspace of Row(A) = R(subscript)4?

[@rubicscube111]

I LOVE YOU THANKS SO MUCH

[@arulbalasachin2005]

What if two rows have the same element still it spans ????

[@thomasvanrooyen6689]

Thanks Brooo saved my life ...

[@TheLazyEngineer]

Thomas Van rooyen Good luck, my man!

[@mukarramhabeeb203]

@Lazy engineer, I want to ask, can W still be a subspace of R, if one or two of the three conditions does satisfy the solution? Pls I need ur reply ASAP. thanks

[@TheLazyEngineer]

Can you reword your question?

[@theirishviking_1575]

It is unknown if W is a subspace of R when, if we only test one condition and it works, we have no way of knowing that the other conditions will fail. Therefore, if one works then you must try all of the conditions until at least one fails, as then you can stop since W is disqualified to be a subspace. Alternatively you may make it through all of the conditions without a fail, which will mean that W is qualified as a subspace.

[@Chris-bb6yh]

shouldn't col(A) be R^4 and row(A) be R^4? at 2:12

[@christinejoyvibar3660]

Good day sir, can I ask if it is ok to add different vector in step two which in closed under addition?

[@huthayfa1723]

Amazing explanation thanks a lot

[@maxbradshaw8083]

0:40 "Let's get a little creative here"

[@DanTutorial]

Do you know anything about a emissary here ?

[@razzbag9237]

what about for C being irrational? e.g. Pi or does C have to be real. thanks

[@TheLazyEngineer]

An irrational number is a real number.

[@alfredolim6456]

thank you for making this video

[@ayatandiyed5483]

veryy helpful thankk you

[@organorganorganorgan]

Thank you so muchhhhh

[@richardwilliamjohnson8566]

thanks a lot this really helped

[@swiftplanner]

Thanks alot bro

[@TheLazyEngineer]

No prob. Good luck!

[@swiftplanner]

@@TheLazyEngineer again thanks for the fervent response.

[@celeryystick]

Hero

[@thasneem-566]

thanks alottttttttttttt

[@ammarparmr]

Great explanation, However, I did the same test for scalar multipliction, but your test is not enough I did It for (x^2, -x^2,0) where x€R Thanks

[@bhattaraisandesh]

Whats the software that you use?

[@TheLazyEngineer]

yolok1ng it’s called SmoothDraw

[@MadisonLenz]

you sound like chris patt :D

[@TheLazyEngineer]

I look like him too apparently.

[@coast_gaurd]

+1 to the comment below mine

[@deepika2830]

thankssssssssssssssssssssssss

[@killuazoldyck169]

i love you are u single