I would like to compliment the camera man for his fine work. Also whoever is responsible for recording the sound did a great job. It's so important to be able to hear and see these lectures clearly. My thanks also to MIT for making this content available.
@davidBeekman-c5q3 ай бұрын
im 13 and the way he teaches and breaks it down is truly magnificent and fascinating how everything works
@Boist-qv1pb2 ай бұрын
Exactly
@Trey-x6f2 ай бұрын
I’m 15 and I agree with you 100%! Keep going and don’t give up when things get tough, things will get better and it is very rewarding.
@stephenanastasi7483 жыл бұрын
I love this form of explanation. It is so complete. And I love that the facts and reasoning are explained in a human-centric simple form, where so many others throw a bunch of fact at the screen. Thank you! I will use this information in the most powerful way. I have tried to wrap my head around the supposedly simple idea of linearity for a long time. Somehow this shifted me over my preconceptions.
@SanDiego_J7 жыл бұрын
Thank you MIT OCW and all MIT staff!
@mjackstewart4 жыл бұрын
There are some people who are perfect communicators of complex subjects. My calculus teacher, Martha Kasting, was one such person. She would smile the entire time as she described Green’s Theorem, or she would say, “Isn’t that a pretty equation?” Dr. Zwiebach is another.
@cidorodrigues60875 жыл бұрын
I'm Sido Rodrigues Brazil I really like Quantum Physics Classes. Very important to know quantum physics. Teach everything the universe knows and you gain self-knowledge about everything. Great series of really useful lectures on quantum mechanics. I am also very grateful to MIT OpenCourseWare and Barton Zwiebach... etc...
@axis_8 Жыл бұрын
I feel illuminated. A clear and concise lecture by a lecturer who comes across having an authentic passion for learning and understanding. Thank you 🙏
@homerodaniel_007 Жыл бұрын
This is actually an excellent class. It worth's its length in Gold. Thank you very much
@chrisl39875 жыл бұрын
As someone who works in (classical) fluid mechanics, I can confirm that it's very very nonlinear.
@chuuuu11315 жыл бұрын
Can you give an example?
@frun5 жыл бұрын
Does it look like electromagnetism? I think he meant classical mechanics.
@LifeForAiur5 жыл бұрын
@@chuuuu1131 Not him, but in fluid mechanics, to quantify the deformation of a fluid particle in a continuous medium you need something called a stress tensor, which is a 3 by 3 matrix describing the direction of the stress imposed and on which "face" of the fluid particle it is acting on. Check out the Navier Stokes Equation expanded out.
@MrMathjordan5 жыл бұрын
Agreed.
@هذاأنا-ذ3ث3 жыл бұрын
True. Many applied mathematicians research in the field of fluid mechanics.
@prabudeva25479 ай бұрын
I'm from India.... great thank you mit gives the online courses...little tweak are arises...but most of the phenomenal are not predicted..which means my life time scenario is the one of the examples...some atoms are vibrated...but no losses. After some times the illusion are visible... 🤔
@anywallsocket3 жыл бұрын
First time I’ve ever heard the process of QM explained outright, every professor I’ve ever had on the subject just jumps right in and it’s hard to grip without foundational information.
@karthigamanivannan79224 жыл бұрын
thank you MIT AND ALL FACULTIES FOR PROVIDING INTERESTING LECTURES ON QUANTUM MECHANICS...
@RomanBraixen5 жыл бұрын
Nearly 200,000 views on the first video, and the second video only has a quarter of that? Shame so many people gave up already
@HighestRank4 жыл бұрын
Brandon Smith maybe it was just a review which they needed, I myself got this only as a recommendation even though I’m not a subscriber to OCW, and wouldn’t have expected anyone who didn’t realize there is a second part because they weren’t told in the video to go looking for it or to recognize it if it had bit them in the nose.
@MegaFunkysoul4 жыл бұрын
They were looking for pseudoscience
@abrarfaiyaz65034 жыл бұрын
Maybe they moved on to the ocw site.
@wassupari22946 ай бұрын
benedict cumberbatch in disguise
@Shooo1175 ай бұрын
Bruh😂
@MikeDbean4205 жыл бұрын
Thank you. Great teacher. Easy to follow.
@Anb-ng2ou5 жыл бұрын
How is called this teacher pelase?
@ZapytajRedditPolska2 жыл бұрын
@@Anb-ng2ou what are you doing here if you have problems with reading description?
@nichokind52337 ай бұрын
@@Anb-ng2ou Dr. Barton Zwiebach
@FredBakker4 жыл бұрын
Mister Zwiebag, you absolutely rock! Explaining complex stuff simple is a trait of true genius!
@fujiexia25153 жыл бұрын
Very excellent open course on QM, thanks MIT professor!
@SurprisedDivingBoard-vu9rz7 ай бұрын
Within 25 years you have to get a PHD. Only then by 30 you can get a job and support anyone. Just because your life is 100. And atleast relax for some time. Mostly when you get to an industry it is all apps of the learnt. Whether you remember or not is not much of an issue because you can recall most.
@123string42 жыл бұрын
Why is the Schrodinger equation linear when the Hamiltonian depends on V(x), and earlier he said that V(x) can be arbitrary? The quantum harmonic oscillator is a perfect example of a nonlinear potential and as far as I know you need special techniques like Hermite polynomials to solve it.
@commonlistener875 ай бұрын
Linearity depends on the dynamical variable you’re solving for. In the example the lecturer presents for Newton’s equations, you are solving a second-order differential equation for the “variable” x (which is a function of time). The equation is nonlinear *with respect to x* whenever V’(x) is nonlinear with respect to x. In the case of Schrödinger’s equation, by contrast, you are solving a partial differential equation for psi (the wavefunction), not for x. You’re right that the Hamiltonian has a potential term V that depends on x (often nonlinearly), but V doesn’t depend on psi, and it’s psi that you’re solving for.
@nikhilgoyal78145 жыл бұрын
This professor is amazing.. Though my stream is not linked with this subject but then also i have seen the whole video :)
@arushaacharyya63763 жыл бұрын
Where and how does the non-linearity get introduced in classical mechanics when quantum mechanics is all linear?
@tarunpurohit65223 жыл бұрын
What a great intro
@retepredlef52126 ай бұрын
Phantastic lecture!
@lepidoptera93375 ай бұрын
Not really. I am beginning to wonder how this guy made professor at MIT. ;-)
@khaledal-homam64824 жыл бұрын
You are great.
@cedriccappelle20364 жыл бұрын
For some reason I keep watching this guy even though I don't understand ßhit of this
@geoffrygifari33773 жыл бұрын
hmmm i guess quantum mechanics is linear because the potential operator is applied ("multiplied") to the wavefunction, instead of the potential being an arbitrary function *of* the wavefunction, as in classical mechanics
@FreezerBurn.5 жыл бұрын
I think I am going to treat myself to hotdogs in my mac and cheese tonight.
@spencersabet86013 жыл бұрын
I respect that. Have fun
@ProgressiveTeen3 жыл бұрын
How evil. Torturing animals for your tongue's evil delight.
@FreezerBurn.3 жыл бұрын
@@ProgressiveTeen ... kind Sir, sadly you are mistaken. Mac and Cheese is not an animal.
@ashtondavis3235Ай бұрын
@@FreezerBurn. 3 years later and I'm still laughing at your comment. well done kind sir.
@nayemabdullah76274 жыл бұрын
I am from Bangladesh Love Quantum mechanic
@mohammednour15347 жыл бұрын
MUCH THANKS MIT
@geoffrygifari33773 жыл бұрын
If schrodinger's equation is linear in any case by default, is it not possible to observe nonlinear behavior in quantum system?
@deepakkumarravi92174 жыл бұрын
Thnx to mit n your staff to spread your valuable contribution in enhancing the concept in worldwide.. Respect n love to you all guys.....
@ramonasosna Жыл бұрын
Great teaching ❤
@beenishmuazzam5 жыл бұрын
Thanks
@yordygarciamalca34875 жыл бұрын
Thank you so much!
@java_Marcelo-xx5nw7 ай бұрын
Thank you for share!
@CharlesSmith-vk8co5 жыл бұрын
You can aquire all thie knowledge for free.You may even sit down in the lecture und visit all classes and pass the exam.But if you want that piece of paper which says that you did all of that you have to pay thousands of dollars.
@emersonfranzuaaldanagavarr2314 жыл бұрын
thank you
@abdulbaqui94994 жыл бұрын
Good lecture
@i.m.Q.22 жыл бұрын
Thanks for confirming something I've been wonderimg about for some time now! You've got no idea what you just helped me out with. 👍😁
@Mystic0Dreamer4 жыл бұрын
@ 9:30 he talks about Schrodinger not knowing what the wave function is. How did Schrodinger come up with this equation in the first place. Professor Zwiebach doesn't offer an explanation of how Schrodinger came up with this equation. But Schrodinger must have had reasons.
@greatquux4 күн бұрын
I actually just found a Reddit thread that discusses this based on your comment and the fact that they didn’t tell me in school either! But basically it was an inspired / educated guess based on previous wave mechanics equations.
@LRahmanGrandUnifiedModelLRahma Жыл бұрын
L. Rahman Grand Unified Model
@rezokobaidze85013 жыл бұрын
hamiltonian has potential energy inside and why it is linear?
@AbhishekSachans3 жыл бұрын
Because potential energy is not a function of the 'wave function'- the independent variable in schrodinger's wave equation (or its derivatives); unlike in Newton's equation of motion in which P.E. WAS a function the independent variable(s) e.g. x in general.
@antoniolewis10167 жыл бұрын
@MITOCW Is this the same room where they did the old 2013 QM course, but renovated??
@mitocw7 жыл бұрын
Good eyes! Yes, this is the same room where they did the 2013 version of the course. :)
@farahsalam18874 жыл бұрын
thanks sir for this amazing lectures but can any one give me the notes of the course please?
@mitocw4 жыл бұрын
The lecture notes are available on MIT OpenCourseWare at: ttp://ocw.mit.edu/8-04S16. Best wishes on your studies!
@abubakarejaz55394 жыл бұрын
Hey U a physics student too?
@ryogakaydc70174 жыл бұрын
Ojala algun dia regrese Barton a la Fiee para para una clase de estado solido 🙌
@timmy181355 жыл бұрын
It is linear iff a linear relationship exists
@ahmedessam14267 жыл бұрын
this continuous montages and cuts through the video made my upset because i want to know everything he says like the real lecture :(
@mattmurdock22595 жыл бұрын
free knowledge hooray
@Adam-cn5ib5 жыл бұрын
why pay when you can not pay? right?
@SphereofTime11 ай бұрын
Dynamic quantum variable, wave function
@RonPaulOrDie6 жыл бұрын
Whatever it is it's non-linear, and it is the easier explanation. Maybe he says this later Im 30 seconds in.
@kaushaljain59994 жыл бұрын
5:13 how is Hamiltonian operator linear? Since it also contains potential energy term which need not to be linear.
@zacharythatcher73284 жыл бұрын
Kaushal Jain the potential in the Hamiltonian can be thought of as a set of values that span relevant space (a normal line or surface over space) that the wave function will be multiplied by at every single one of those points individually. So the wave equation (the input) will be transformed in essentially a multiplication style operation. Multiplication is linear, and so is the “potential operator”. If the potential was somehow squaring or logging the wave equation, that would be nonlinear, but that is impossible. The potential isn’t that weird. It just multiplies the wave equation by its own predetermined values, which you could do before or after multiplying by a constant and get the same result.
@aryasingh81734 жыл бұрын
@@zacharythatcher7328 wow
@abcdef206910 ай бұрын
QM(quantum mechanics) is linear? where is the laws of physics that says it is, we dont truly know if QM is linear, but the probability representation of psi or ANYTHING is ALWAYS linear, because we MADE it linear so that it could be solvable, this is the ONLY way we could even TRY to solve for the slightest bit. "it is linear" and "we MADE it linear" are two different things. the initial value problems of non-linear classical mech is the SAME as the boundary problems of linear probability representation in quantum mechanics.
@lepidoptera93375 ай бұрын
It is linear because the quantum mechanical ensemble consists of statistically independent experiments. That's an assumption. Since we do not have an actual ensemble in real life but only the repetition of the same experiment, the statistical independence of the data set that it produces has to be tested. It will usually work out fine for e.g. the photon flux from a thermal light source, but it will show very strong temporal correlations for a laser source. So you are not completely false in saying that "we made it linear", but the naive assumption that every quantum mechanical system obeys that linearity is incorrect.
@MS_PrithwirajMaity2 жыл бұрын
CLASSICAL MECHANICS IS NONLINEAR AND QUANTUM MECHANICS IS LINEAR THEN HOW CLASSICAL MECHANICS IS APPROXIMATON OF QUANTUM MECHANICS.
@mohammadaminmasoomi35972 жыл бұрын
I'm from Iran.I love quantum physics and the other parts of physics and absolutely I go to the MIT university.
@smartscience53054 жыл бұрын
Wow , great lesson Sir. I am 12 years old and I am learning quantum gravity,string theory , Electromagnetism, thermodynamics and other lessons . but your lesson was great also the another lesson of relativity
@lamaquinadelainformacion826 Жыл бұрын
At your age I was learning basic astronomy, you know where I ended up, studying geological engineering, I'm in my first cycle, I like physics although it's a bit difficult to understand, but what I don't understand much is chemistry, I'm from Peru.
@offYears7 жыл бұрын
Why can we assume the Hamiltonian is a linear operator? Isn't it another measure of potential, and theoretically could be made some non-linear result?
@LusidDreaming5 жыл бұрын
I don't know enough about the Hamiltonian to directly answer this, but in general an operator is linear if it satisfies the following two conditions (O is an operator): 1.) O(f + g) = O(f) + O(g) 2.) O(c*f) = c*O(f)
@frun5 жыл бұрын
@@LusidDreaming yes. I think that's the definition.
@fredrikj84915 жыл бұрын
The difference is previously your solution was in terms of x(t) and the potential depends explicitly on x. Now your solution is in terms of the wave function, of which the potential is not a function. The Hamiltonian is a linear operator on the space where the wave function lives. The potential is not a function of your wave function.
@ericsmith18014 жыл бұрын
@@LusidDreaming So there cannot be time compression to satisfy linearity... experiments seem to suggest that in addition to spatial nonlocality there is temporal nonlocality involved in entanglement. I doubt that changing the inertial frame of reference will get rid of such nonlinearity.
@timetostudy64433 жыл бұрын
Yes professor, I found the tutorial irrelevant since I’m no where near being a physician.
@debanujchatterjee27684 жыл бұрын
The Hamiltonian operator may contain a potential term. So how is the Hamiltonian always linear?
@Jeremymautino3 жыл бұрын
Orgullo peruano
@pmcate23 жыл бұрын
Aren't maxwell's equations only linear for some materials?
@diegofernando42776 жыл бұрын
I don't get it, he says that classical mechanics ain't linear because of the potential energy, but the Hamiltonian it's the sum of the kinetic and potential energy, so, how can the classical mechanics be non linear, but the wave function that also depends of V(x, t) be linear?
@ogoshi6 жыл бұрын
Yeah, I'm also a little confused by this argument
@andrewstallard69276 жыл бұрын
Notice in the classical equation, m x'''(t)=-V(x'(t)), the potential is a function of the derivative of the position. While the derivative itself is linear, we don't know what the unknown potential function "V" is so we can not say with certainty that V(x'(k*t))=k*V(x'(t)). By contrast, in the Schrodinger equation the potential V is multiplied by the wavefunction psi, so V*k*psi=k*V*psi
@UnknownBeast415 жыл бұрын
The potential function is arbitrary, in most scenarios we approximate it to be harmonic (proportional to x^2) but it can be generally non linear. Alternatively H-hat is the Hamiltonian operator which is basically a constant time the 2nd derivative with respect to position i.e its linear. Its not the Hamiltonian itself, its an operator named after the Hamiltonian.
@mike4ty45 жыл бұрын
The quantum Hamiltonian operator acts on the state variable differently than the potential/kinetic energy (classical Hamiltonian) does in Newtonian mechanics. In particular, "x" in the potential energy function is just a parameter, not the present particle state being plugged into the function like it is in the Newtonian case with Newton's second law or Hamilton's equations, because in quantum mechanics position, momentum, etc. are not actually numbers, but "fuzzy" quantities described by probability distributions (which corresponds to reduced information, as per Shannon), and they are all wrapped up in the linear state vector, |psi>. That state vector is not a real number, but (effectively) an infinite number of them, and hence could not be inserted into the potential energy function anyways, which is expecting only one real number as input. Instead, the potential energy function _becomes_ an operator on the state vector by first considering it in the form of the positional wave function psi_x(x), which is a "basis expansion" (effectively the same thing as vector components of ordinary vectors, but with infinitely many components) and then you multiply this wave function by the potential energy function to get another wave function (i.e. form psi'_x(x) = U(x) psi_x(x)), which then represents, by going backwards through that expansion, the resulting new state vector. Since multiplication is distributive, hence linear, you get a linear action of this operator.
@michaelsadek4449Ай бұрын
i am not a student any more, neither physics student i was, but i am just curious about physics that is why i am here :D
@AlexBlade27 Жыл бұрын
I have a question, isn't Hamiltonian operator also a non linear operator, because it also contains Potential term which may be quadratic or cubic depending on the condition. Thus, isn't then Quantum mechanics also, non linear in nature. Please, explain if I am wrong.
@sylvenara Жыл бұрын
While the potential energy term in the Hamiltonian operator of quantum mechanics can be nonlinear, the dynamics of quantum mechanics are fundamentally described by a linear equation, the Schrödinger equation. Therefore, quantum mechanics is considered a linear theory.
@AlexBlade27 Жыл бұрын
@@sylvenara ok understood. Thanks for the help😊
@eternapesadilla23555 жыл бұрын
Arent you the dean of the university of architecture in copenhagen?
@gustavodeoliveira7023 жыл бұрын
In what extent can someone assert that classical mechanics or quantum mechanics is linear or not? Is in regarding to the description of fundamental interactions and not merely idealized models? Because a classical harmonic oscillator is a linear system inside classical mechanics and systems that respect Ginzburg-Landau equation are non linear examples in quantum mechanics. Why those aren't consider counter-examples to the thesis defended in the video?
@dougiev92875 жыл бұрын
Newton's is non-linear because potential could be non-linear function; ok! But Maxwell's is linear...couldn't potentials A and V be non-linear?
@HighestRank4 жыл бұрын
dougie v yes, Aa is easy to see, but Vv will always be made using straight lines.
@nsudhir_here4 жыл бұрын
Can someone explain what is potential V of x? I'm noob in quantum physics. Does it mean a kind of potential which is providing force?
@bencegabor92284 жыл бұрын
Potential V(x) is a classical quantity, whose negative derivative is force. For example: en.wikipedia.org/wiki/Gravitational_potential or en.wikipedia.org/wiki/Electric_potential#Electric_potential_due_to_a_point_charge
@nsudhir_here4 жыл бұрын
@@bencegabor9228 thank you sir
@hadlevick6 жыл бұрын
Can you catch the sensation of simultaneity, can you do 1+1...
@انتشفن5 жыл бұрын
Good
@kaushaljain59994 жыл бұрын
Explain 0:56 to 1:05 by example
@pranjalsharma33703 жыл бұрын
Amazing👍 Can anyone say whether these are graduation or postgraduation classes? Or anything else?
@pranjalsharma33703 жыл бұрын
@pippo Thanks!
@abhijeetbhattacharjee61856 ай бұрын
3:31 What is V(x) ?
@Inserthandle-ff6jw5 ай бұрын
Velocity along the x axis
@liplayz61313 ай бұрын
X is the Particle moving in 1d under potential v
@lepidoptera9337Ай бұрын
The classical potential. The Schroedinger equation is a quantization procedure that goes from classical quantities to quantum mechanical ones.
@sagarwadhwani16104 жыл бұрын
Can't we use linear qm to solve 3 body problem
@posthocprior Жыл бұрын
Somewhat vague definition of the difference between linear and non linear.
Why is 2nd law for newton not linear wrt Potential? Partial derivatives are linear and so are the normal derivatives...
@AbhishekSachans3 жыл бұрын
Because, say for one dimension, x is an independent variable of which potential energy is generally a function so that gives you a non-linear differential equation. That's it!
@surendrakverma5552 жыл бұрын
Excellent lecture Sir. Thanks 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
@amirhidri83924 жыл бұрын
Nothing is linear or non linear, it depend on how you consider it., observation,. When you see as human being you will try to explain like all excited scientist.
@benwincelberg96844 жыл бұрын
?
@sharptongue29725 жыл бұрын
Han Solo is now a physicist? Damn...
@kaushaljain59994 жыл бұрын
explain 0:53 to 1:07 by example
@uTubeNoITube2 жыл бұрын
You don't need any of this. Just go to Vegas on weekends and play black jack.
@Greato_ Жыл бұрын
Wtf
@infinity-and-regards4 жыл бұрын
9:35 How did Schrodinger come up with his equation before there was any physical interpretation for the wave function? What did he try to derive? What was his starting point?
@durgeshgaikwad7414 жыл бұрын
When de Broglie proposed the idea of matter waves, Schrödinger tried to find an equation which could describe these matter waves and hence came up with the famous Schrödinger equation
@lambda26932 жыл бұрын
it is quite easy. you just have to prove that what the classical operators become in qm. like p=-ihbar d/dx or E=ihbar del/del t
@infinity-and-regards2 жыл бұрын
@Lambda that doesn't sound easy at all, could you elaborate?
@lambda26932 жыл бұрын
@@infinity-and-regards look finding the operators is tough but the derivation of the equation is very easy if you know the operators. okay look i will derive it for you but i will assume the operators if you want the proof for why the operators are equal to what i am assuming you will have to look it up as the proof is very long. E=KINETIC ENERGY + POTENTIAL ENERGY KE= P^2/2M. PE=V(X,) LET US QUANTIZE THIS EΨ=P^2/2M Ψ +VΨ NOW EΨ=Ih/2π dΨ/dt. and p=-ih/2πd/dx Ih/2π dΨ/dt=(-ih/2πd/dx)^2/2m Ψ+VΨ Ih(ΒΑR)dΨ/dt=-h(BAR)^2/2m d^Ψ/dx^2+VΨ AND YOU HAVE DERIVED THE SE. YOU CAN DERIVE ITIN OTHER FORMS BUT THE PROCESS IS SAME. THE REAL CHALLENGE COMES IN PROVING THE ASSUMPTIONS AND YOU TO USE BRA'S AND KET'S FOR THAT. ALTHOUGH THE PROOFS ARE GIVEN IN SOME TEXTBOOKS BUT ARE VERY COMPLEX. EVEN GRIFFITHS DOES NOT GIVE THE PROOF
@timmy181355 жыл бұрын
Chaos theory is non linear. Nullo space is linear
@kostasargiris748 Жыл бұрын
Very good teacher!! I have a question : 3:34 Why x squared is not a linear function?
@mateusmarinho72 Жыл бұрын
f(x) = x² f(a + b) = a² + 2ab + b² f (a) + f (b) = a² + b² So f(a+b) is not equal to f(a) + f(b), therefore it's not additive. So it's not linear.
@kostasargiris748 Жыл бұрын
@@mateusmarinho72 yes, okey, thank you very much!
@urpisarmiento53858 ай бұрын
@@mateusmarinho72muchas gracias, entendí la explicación.
@hadlevick6 жыл бұрын
The size of simultaneity...
@Abyss_Hole_Records3 жыл бұрын
👁️
@czitels18563 жыл бұрын
Interesting thing. First video has 2x more views than second :D
@hadlevick6 жыл бұрын
Hamilton?
@SarojKumar-lt8qy6 жыл бұрын
Sir can a wavefuntion determine the dynamics of a macrobody?????or it is just applicable in cases of microbodies
@farooq88976 жыл бұрын
It can.. But Classical Mechanics is a good approximation and easy to use..
@atmonotes2 жыл бұрын
for a second there i thought he was Harrison Ford
@achintyajai29343 жыл бұрын
alright he reminds me of dr. peyam
@ahmedafifkhan4 жыл бұрын
Can anyone elaborate a bit from @2:20 to @2:33. What did he mean? Where did that graph came from?
@NoName-vq6cg4 жыл бұрын
Graph of potential energy over time. (Potential energy meaning the work that force has to do. Force × distance) The derivative is the force acting on it at a specific time. Like if a ball is rolling down a hill, hes basically just saying that because there's mass, gravity would be pulling it down, and it loses potential energy as it gets closer to its destination and force is used. So the force is the negative of the derivative of potential energy.(someone correct me if I'm wrong)
@kaushaljain59994 жыл бұрын
9:22. Why is one wave function unable to explain both spin up and down state of e-?
@benwincelberg96844 жыл бұрын
Initial conditions aren’t given
@riturajanand71335 жыл бұрын
sir how force is equal to the derivative of potential...Sir as I know the force is equal to -du/dx (rate of change of potential ENERGY W.R.T X) not potential.....
@mysteriouspandey34505 жыл бұрын
Pehle basics clear karo Bhai baadme quantum ki lectures samjhoge
@riturajanand71334 жыл бұрын
@@mysteriouspandey3450 Thanks sir for your advice, please answer to bta dete doubt ka
@itsDhiran4 жыл бұрын
The capabilities of human brain.. I am not even 1% of it
@kaushaljain59994 жыл бұрын
4:39 Is time is dynamical variable? what is definition of dynamical variable?