Load Assignment on Roof Trusses - RF Series 2/4 - Tagalog

This video is a series of my previous Roof Framing layout. It covers calculation of loads such as Dead load, Live load and Wind load using NSCP 2015 edition.

[@BadzMaranan]

napakahalagang topic po ito sir salamat sa paghare ng inyong kaalaman madami kaming matutunan dito

[@ibrahimjafaru6031]

Love how you calculate the load .. I appreciate..

[@silvinocardozo224]

gud day sir, educational po un mga topic nyo, lalo sa amin na limot na mag design, gusto ko sana ma I explain kung paano kayo nag derive ng values nyo sa

[@Monasampulna]

nice one sir!..mejo nalito lang paanu pagka arrive ng values components ng inward [34,30,20 at -18].🙂

[@el-sh4hy]

paano nasolve yan?

[@Pecksman01]

kahit ako hanggang ngayon di ko parin gets

[@angillomartin28]

Structural Engineer 👏🔥

[@muahri3199]

Tamang tama to na topic kasi madaming nasirang roof trusses sa nagdaang bagyong Odette dito sa Cebu.

[@JakeZaraTV]

Happy New Year po Engr. watching po. thanks! at malaking bagay tong info ninyo.

[@danicacapuno9435]

Happy New Year, Sir❣️ More blessings to come. 🙂

[@cortezetal.]

good eve po sir, paano nyo po nakuha yung 20 and -18 sa windward at leeward sa horizontal force?

[@DazzSpace]

Thank you for sharing this video

[@christopherdevidomingo9462]

Sir, ang ginamit po ninyo na 0.80 at 0.70 as multiplier applicable po ba siya kahit anong slope? Or may table po iyan?

[@joelp.costillas1789]

Ung total deadload po ay kasama po ba ang purlins at roofing sheet sir?

[@vincentvaldez8306]

Sir saan galing ung horizontal load na 20 sa windload?

[@norjannahlanto7099]

Hello, sir. new fan po. pwede malaman ang name ng book?

[@silvinocardozo224]

salamat po and happy new year

[@joelp.costillas1789]

Sir tumatangap pa rin kayo ng structural design..magkano po kaya?

[@lorenzglenn00]

Thank you sir

[@rhenieorbeta8489]

Sir, pano na kuha Ang 3kN na joint liveload? Kung [0.60 x (5.8x3.75)]/8 ?

[@jsdesign_engineeringtv3633]

8 yung divisor natin therefore you need to consider the whole roof, (0.6)(5.8x3.75)(2)/8 = 3.26, rounded off lang kaya 3. Sorry for the confusion. Thanks

[@atoac1804]

@@jsdesign_engineeringtv3633 clarification lang po sa value na 2. san po ito galing? Thanks po.

[@vinzpranza5844]

Yung 5.8 po ay sa kabilang top chord lang. Times 2 niyo po

[@vincentvaldez8306]

​@@atoac1804 (0.6KN/m^2)(5.8m)(3.75m)/4=3.26KN... liveload(tributary area)/#joints at tributary area...

[@rolandmontemor1088]

Happy new year sir thanks for this vedio

[@jsdesign_engineeringtv3633]

Happy new year too! Thanks

[@markedisonvillaceran8580]

2.23*5.8*3.75 = 48.5Kn/m yan po ba ung sa inward pressure?

[@zidemoto9485]

salamat po

[@badriaabdul8161]

Good day, Sir Engineer. Meron po ba kayong video para sa calculation ng rain load?

[@jassemliday]

Hello sir. WIND LOAD CALCULATION book by ASEP po ba yung source book niyo sa wind load parameters?

[@jsdesign_engineeringtv3633]

Nscp 2015 ang reference ko dyan. Thanks

[@shamamba02]

good day engineer, paano po loading analysis pag nag install ng industrial hvls fan sa truss? additional Liveload po ba yun na point load?

[@jsdesign_engineeringtv3633]

Yes, point load sa bottom chord, if you know its weight add 15% for vibration. Thanks

[@shamamba02]

@@jsdesign_engineeringtv3633 salamats ng madami engineer. !❤️

[@multiverseinfinite777]

Thanks po...

[@soo_nybnr2565]

Sir, kahit ano po bang iassign na initial section para sa pagkuha ng dead load?

[@jsdesign_engineeringtv3633]

Yes, but I suggest use at least 75x75x6mm angle bar as preliminary size. Thanks

[@icaneatapackofchipswithout3488]

Good day, sir. Paano po nakuha na yung unit na kN sa Dead Load. Yung given po kasi na unit weight is expressed in kg/m. Bale kung i-multiply yung unit weight na kg/m sa linear meter, magiging kg po.

[@christajoycedoria522]

multiply niyo lang po sa 9.81x10^-3 magiging kN/m na po siya

[@glennmanat4289]

@@christajoycedoria522 grabe kana doria ahahahaha

[@angelaidos8277]

@@christajoycedoria522 pano po gawing kN na lang ang dead load?

[@jamesclaridad4394]

Mga kaibigan paano po nakuha ung 12KN? Total length ng bottom chord, top chord , web , etc... multiply ng weight(kg/m)? tama po ba or may kulang?

[@jamesclaridad4394]

sa DL po

[@FuyuAkiGameplay]

Yung pinakita niyo pong Table 2-J Combined height, Exposure and Factor Coefficient di ko po mahanap sa NSCP 2015 or di ko lang makita... saan po siya nakuha

[@jsdesign_engineeringtv3633]

We might be using different edition, use yours if that is the latest. Thanks

[@bertox101]

Hello po engr. good day. Clarify ko lang po yung Y component na 34 sa inward wind load nakuha niyo po ba yan gamit ang concentrated normal force na 2.23*3.75*5.8*8 po? Salamat po God bless and More Power.

[@jsdesign_engineeringtv3633]

That is correct, Thanks

[@ejoep]

Happy new year

[@dansteventolentino2614]

Good day po, sir! Tanong ko lang po yung about sa horizontal force, yung sa wind load. Hindi na po ba siya imu-multiply sa 0.5? Kagaya nung sa bottom chord na dead load na nakamultiply sa 1.2? Salamat po!

[@zidemoto9485]

multiply by 0.8 para maging vertical ung load

[@el-sh4hy]

​@@zidemoto9485 idol pwede pa explain kung paano nakuha ung 5kn at 4.5kn? hindi ko mapalabas eh

[@maymiranda9633]

Hello, pano po nakuha yung 12 na total weight?

[@jsdesign_engineeringtv3633]

As mentioned in the video, get total member length x unit weight per meter. Thanks

[@ibrahimjafaru6031]

I love your teaching.. but some of us are from other countries. And we don't understand the language.. please can you explain in English

[@santosalvin2139]

Engr. Yung sa Wind load po ba na 5kN(inward) and 4.5kN(outward) Sa horizontal component po talaga ibabase? Hindi sa vertical?

[@jsdesign_engineeringtv3633]

Nature kasi ng wind is always horizontal sa nalalaman ko. We just need to resolve it into 2 components. Thanks

[@santosalvin2139]

@@jsdesign_engineeringtv3633 thank you po engineer. Last po Yung sa paglalagay po ng dead load sa bottom cord yung 1.2DL = 1.2(1) = 1.2 Wala na po ba talagang 1.2 kN dun sa mismong joint ng support? Tig kalahati po ng 1.2?

[@jsdesign_engineeringtv3633]

We just simplify the complexities of multiple forces at support Actually even 1 single force (total DL) applied at the centre will give you the same support reaction right?, the more joints loads you have the less magnitude it will give you.

[@akpvdensolartv3389]

Good Day Engr. Pano kapag open structure same parin po ba approach sa winward at leeward don po sa coanda effect?

[@jsdesign_engineeringtv3633]

Yes pareho din ang concept except yung factor for inward 0.8 and leeward 0.7 will change. Check recommended value from nscp. Thanks

[@akpvdensolartv3389]

@@jsdesign_engineeringtv3633 Thank you Engr

[@ronaldgorre4732]

Tnx sir

[@cristina5095]

hi po Sir..bakit po naging 2.23 yung wind pressure? 0.76 x 3 po kasi nasa 2.28kn.m po nalabas sa calculation ko.. at panu po naarrive yung 5 at 4.5 sa wind load ?

[@crystalaurora9278]

Same question dito sir

[@SuperBenjo19]

Sir saang book nyo po nakuha yung value ng GCp na may table? Sa NSCP 2015 po ba?

[@jsdesign_engineeringtv3633]

Yes 2015. Thanks

[@vanrashirabdukaras2441]

pahelp naman pano nakuha yung 3kn sa live load. 1.36kn kasi sa calculation ko

[@jsdesign_engineeringtv3633]

Its from total liveload divide by number of top chord joints

[@pablojuan8896]

sir pwede gawa po kayo video tutorial design ng beam trusses mga 15 meters span simply supported kung ano ang detail ng beam top/bottom and materials na gagamitin depth ng beam double angle ba o hindi at ano sizes ng members at top bottom sana po makakagawa kayo sir salamat po

[@jsdesign_engineeringtv3633]

kzbin.info/www/bejne/mnSWl4tqrKt7kLMsi=YTBvIG9xnbVJegFT part 1 of similar topic.

[@jsdesign_engineeringtv3633]

kzbin.info/www/bejne/d3iXqGieqrmJitksi=efIAuo5WGqxYq7bl part 2

[@motalibaluyodan8616]

.pki.nman un actual calculation ng trusses 20m span, ng isang covered court na parallel cord ang gamit, makapal sa support then maliit sa gitna... kng meron man... ..kc karamihan sa bina.blog ay common figure lamang..

[@christopherdevidomingo9462]

Engr, good day po. Paano po nag arrive sa 30, 20, -30, -18?

[@jsdesign_engineeringtv3633]

Which part did you see that please? Thanks

[@christopherdevidomingo9462]

@@jsdesign_engineeringtv3633 Good day, engr. Sa segment 25:10 po. Na break down niyo po into two commponents and WL.

[@ianrosal1235]

250km/h is 69.444444m/sec sir 🙂 pwde na rin 70 hehehe malapit lang nmn😅

[@nepitsspinesnyere2438]

Pano po naging 3kn/m2 yung sa stagnation?

[@jesnaz517]

😂 hindi ko din makuha

[@JaxBallestar]

q = 0.613 (70)² N/m² yan kaya divide by 1000 para maging KN/m²

[@markedisonvillaceran8580]

sir paano po nakuha ung sa inward and outward pressure

[@rubenrana9812]

😂

[@lizardo1444]

Sir ask lang po. Paano nakuha yung 34

[@jsdesign_engineeringtv3633]

Which part from my video is 34 (please indicate time) sorry I can't remember. Thanks

[@lizardo1444]

Wind load po sir inward. Yung breakdown into components, 34/4 joints po.. paano po yun nakuha sir yung 34.

[@jsdesign_engineeringtv3633]

Design wind pressure x tributary area x 0.80 (for inward), or 0.70(for outward)

[@frankitecttv3828]

rafter type naman sir

[@nicanorarviola3655]

hapi new year po, Pw=2.23kn/m2 x Ta(5.8x3.75)=48.5kn, paano sir ma brake to coordinate

[@jsdesign_engineeringtv3633]

Design pressure x Ta x 0.8 (inward) or 0.70(outward). That is concentrated (normal force for each). Now resolve into vertical and horizontal component. Then distribute or divide by number of joints on top chord. I hope that helps. Thanks

[@nicanorarviola3655]

ok sir thaks po

[@nicanorarviola3655]

gud am sir ask ko lang po, yung variation ng joint vertica load sa series 2 & 3 na 10.25kn to 11.06 is it due to additonal dead of purlins And roofing or due to the loads of hip truss 1,2,3 acting on joint EL

[@jsdesign_engineeringtv3633]

@@nicanorarviola3655 yes correct, that is due to Ht3 reaction, Ht3 carries rafters

[@silvinocardozo224]

gud day sir, un P NORMAL perpendicular po ba sa ROOF?

[@jsdesign_engineeringtv3633]

Yes perpendicular

[@silvinocardozo224]

@@jsdesign_engineeringtv3633 thank you sir♥️♥️♥️

[@jfkciakennedy8557]

good evening po. papaano nakuha ang leeward force na 0.8 and 0.7 sa diagram po?

[@jsdesign_engineeringtv3633]

Specified ng code, check mo nscp. Thanks

[@dansteventolentino2614]

Good day po, sir! Tanong ko lang din po kung anong specific section sa NSCP 2015 matatagpuan itong 0.8 and 0.7 for windward and leeward? Salamat po!

[@silvinocardozo224]

WL na 5K inward, 4.5 outward

[@jsdesign_engineeringtv3633]

Calculated wind pressure (P) x tributary area(TA) x 0.80 (inward) or 0 70 (outward) That is normal force, you need to break it out (horizontal and vertical component) Then, distribute or divide it into number of top chord joints. Thanks

[@silvinocardozo224]

@@jsdesign_engineeringtv3633 thank you sir, SALUTE PO SA INYO, PARA MA REFRESH MGA STOCK KNOWLEDGE SA ENGINEERING

[@el-sh4hy]

​@@silvinocardozo224 Paano po nasolve yung 5 at 4.5kn? Pwede pa-explain po nang ayos, hindi ko kasi magets kung paano napalabas yun

[@jordangayutin9850]

teacher