I literally went from "I don't have a single clue what's going on" to a passable understanding in under 20 minutes. Hat's off.
@Ulikela Жыл бұрын
Even though u hv a 2 hours lecture, it's still have no clue what's going on
@VictorianoOchoa4 жыл бұрын
The way you casually laughed at your mistake at 2:30 makes this video that much better.
@anonymousmask42242 жыл бұрын
8 Years and still best explanation ever on Why to use specific connectives for quantifiers. Kudos to you.
@macestarwalk24744 жыл бұрын
Oh my god for the first 2 and half minutes of the video I was confused AF because you wrote that he was immortal. I was trying to figure out how the heck that contradiction could possibly make sense 😂
@zyansheep3 жыл бұрын
I just justified it to myself saying that the proposition "Socrates is immortal" is false based on the previous propositions.
@lutfilutfi33103 жыл бұрын
brilliant video man. Builds the need of why you need predicate logic instead of just handing out the formulas
@hannahbogahi46842 жыл бұрын
If you understand can you help me out
@lutfilutfi33102 жыл бұрын
@@hannahbogahi4684 sure which part dont you get?
@hannahbogahi46842 жыл бұрын
Both the negations and the predicate part
@lutfilutfi33102 жыл бұрын
@@hannahbogahi4684thats a bit too long of a long explanation , do you have a discord
@hannahbogahi46842 жыл бұрын
@@lutfilutfi3310 no I don't have any disagreement but it is just too tough
@tiptoe14135 жыл бұрын
Immortal? you caught it.
@weijie75 жыл бұрын
Hello, question. at 16:00, shouldn't Hx be 0 as your population has x that are sad too (not knowing they are men or women)? I know in the end the first conditional rule will still be true, but just to clarify this detail
@isawilraen98162 жыл бұрын
At around 13:00 and onwards where you were showing why we use different connectives for different quantifiers: You showed that, when MarkIsHappy, SteveIsHappy, JocelynIsSad, we get 0->1=1, and 0^1=0, respectively. So, Mx here means that x is a man. That will ofc be 0 for each. But, Hx here seemed to expressly mean that "man is happy"... which is 1 for each, yes, and thus the above statement =1, while the below one =0. So it checks out. But, it just seems confusing to think that Hx here means "man is happy" instead of "x is happy". I mean, for every object (x) that we check in our universe of xs, sure, Mx won't be true, so it's 0. But it seems strange that Hx is always 1. Like, how do we remember that Hx only checks whether the men are happy? Because there is afterall an x (Jocelyn) that is not happy. It feels much more intuitive to just think about it as follows: IS IT TRUE THAT IN THE CASE OF EACH x ie object in that universe 1) WHENEVER x is a man, x is also happy? Yes. 1) x is a man, AND x is happy? No. It is not true that in the case of each object in that universe x is a man and x is happy. The latter feels more intuitive, like I said, but of course, if what Hx MEANS is happy man, then that is correct as well. It's just that the meanings seem rather arbitrary. But this makes me wonder if I've missed something necessary, or if I'm just looking at convention that happens to be confusing to me.
@mhdfrb9971 Жыл бұрын
Are you just assume their gender?
@tomasmateus175 жыл бұрын
I still cant get this shit 🙃 im going to fail so hard
@bonbonpony6 жыл бұрын
00:31 You meant Socrates is MORTAL, right? Proving otherwise would be an indication of an error :q BTW how about introduction and elimination rules for these quantifiers?
@unh0lys0da165 жыл бұрын
Apparantly he didnt understand them so he didn't cover them
@johantitulaer10525 жыл бұрын
He wrote it wrongly because he was talking. He meant to say: "a mortal" but it sounds similar to immortal.
@alvin38324 жыл бұрын
Maybe Socrates is in fact immortal?
@deborahiranezereza60403 жыл бұрын
This might seem random, but thank you!! U just saved my life😭… my book was not doing a good job. God bless you!
@faiza.s65094 жыл бұрын
Thank you!!! I was so stuck over predicates and this really cleared things up! Thank youuuuu
@georgejerry15454 жыл бұрын
15:17 wouldn’t Hx still be 0? Isnt Hx symbolizes all x (not men) are happy? If that’s the case, then since Jocelyn is sad, then Hx is 0, no? Well, if that’s the case, it’s still fine since the antecedent Mx is false, making the statement still true, right?
@arpi60543 жыл бұрын
you’re literally a life saver
@eliwidd8 күн бұрын
crazy good teaching
@NghiaNguyen-lp1us6 жыл бұрын
very clear, thank you!
@mohammedal-shaboti79393 жыл бұрын
The examples at the end help a lot, Thanks for sharing :)
@PizzaPunt993 жыл бұрын
Thanks!
@rxrider14512 жыл бұрын
Really helped with intuition. Thanks!
@timmeeyh6523 Жыл бұрын
2:29 I was looking forward to an awsome proof by contraposition of some kind!
@ThisIsNotMyHandle8 жыл бұрын
Excellent job!
@proggenius20242 жыл бұрын
man you are teaching math like a book! Keep it up.
@mamtasingh83734 жыл бұрын
Is general language different from language used in logic in terms of precisely defining things.
@affumcollins33753 жыл бұрын
Easy understandable 👍😀👍😀
@farah-bq3rg5 жыл бұрын
you are amazing
@aizazkhan5439 Жыл бұрын
You are a great teacher. If not for this, I would have to spend a full day looking into Predicate Logic. Thank you so much. **P.S: university lectures are dog shit.**
@kamenzhelyazkov85752 жыл бұрын
2:26 I just suggested that you are starting with the opposite, proving that it is wrong ;D
@oskaraltman2 жыл бұрын
at 15:54 Does Hx mean x is happy for all x because of the quantifier? Because it doesn't make sense to me that Hx is true for all x even though Jocelyn is sad. It doesn't change the truth of the implication or the conjunction, however i am confused why Hx is true in this case.
@oskaraltman2 жыл бұрын
unless Hx means something like if x is a man then x is happy or x is happy or a woman or something.
@kyejocham483 Жыл бұрын
Amazing!
@marinastamou42465 жыл бұрын
could you create a video explaining the problem of improper definite descriptions? Thank you!
@wecros32493 жыл бұрын
Hi, thanks for the video. Could you elaborate on 15:15, please? If Steve was pointing to Sad, meaning Mark is happy and Steve sad, would that mean that ∀x(Mx -> Hx), where Mx is 0 and Hx is 0, means "All men are happy", even though they are not judging by common sense? Thank you!
@PizzaPunt993 жыл бұрын
Did you ever find the answer, I am stuck on this too
@wecros32493 жыл бұрын
@@PizzaPunt99 I passed the exam, that's all I remember now :D But go with your guts on this one, I think I was onto something here though.
@PizzaPunt993 жыл бұрын
I believe the answer is that when the left side of an implication is false we can just assume that the right side is true as it doesn't matter anymore because the statement we are making a conclusion out of is false
@PizzaPunt993 жыл бұрын
@@wecros3249 just had my exam, hope I passed
@Logos592 жыл бұрын
Actually the truth tables say this is true. Even if Mx is 0 and Hx is 0; "All men are happy" is true. I think the same as you; although by common sense you would say is false, the conditional says is true. This is actually troubling in my mind. I'm obsessed with logic but there are cases like this that make me mad. It's like is not connected to our reality.
@apataoyinlade30333 жыл бұрын
Thanks a lot for this
@computerscience9018 жыл бұрын
When we use universal quantifiers for all ∀x , does that mean everyone in our domain of discourse of discourse is "x" ?
@Trevtutor8 жыл бұрын
It depends what follows it. If we say "∀x Dog(x)", then that means everything in our universe is a dog. If we say "∀x (Dog(x)->Happy(x))", then that means that every dog in our universe is happy. ∀x is just like a variable statement, "for every x".. then something.
@computerscience9018 жыл бұрын
Wow. Didn't expect the GREAT TrevTutor to respond to my comment. (bows down) . Thank you for your awesome response. One follow through question: ∀x Dog(x)->Happy(x) V ∀y Penguin(y)->Happy(y) What does this mean in respect to our domain of discourse ? Does that mean everyone in our domain is some form of hybrid penguin/dog ?
@computerscience9018 жыл бұрын
∀x (Dog(x) -> Happy(x)) V ∀y (Penguin(y) -> Happy(y)) . For some reason the formula to the previous question go crossed off. (Formula above is for the previous question)
@Trevtutor8 жыл бұрын
This means that "Every dog is happy or every penguin is happy". These are variables stating something like "For every x, if x is a dog then x is happy. OR. For every y, if y is a penguin, then y is happy." The conditional means "if-then", so we should treat it like "if variable satisfies this first part, then the variable also satisfies this second part."
@vigneshkumar45463 жыл бұрын
At 10:08 why can't we take cake and pie as a single unit?
@Logos592 жыл бұрын
Cause of the word "and" which is the ^ operator. It separates it in two.
@paurushgargtube4 жыл бұрын
thnks
@speconcloud92 жыл бұрын
Tahnk you :)
@timbarnbou3723 жыл бұрын
Amazing
@liamtaylor55233 жыл бұрын
Thanks for the video, question: how do you define Existential quantifier (backwards E) as “some” when it can also represent a single item having that property only which wouldn’t be some.
@ajricherson10993 жыл бұрын
think of it as "there exists some value(s) ..."
@madhavi1203 жыл бұрын
A is brother of B if A is a male, A has father F and mother M and B has the same mother and father as A does. Translate these facts into formulae in predicate logic
@alahuakbar44424 жыл бұрын
man pls answer my question, all men like cake and pie can also be written. by “Ax(M(x)->Lx(c^p))?
@alahuakbar44424 жыл бұрын
“?*
@paque-music4 жыл бұрын
no you cannot
@alahuakbar44424 жыл бұрын
Sven explain man
@alahuakbar44424 жыл бұрын
why not becoz the statement “Lx(c^p) is also men like cakes and pie
@hypotheticallyspeaking4 жыл бұрын
∀x [(Mx -> (Lxc V Lxp)]. For every x is such that if x is a man, then x likes cake or a pie or both.
@mamtasingh83734 жыл бұрын
Help professor,this doubt is eating me up for days, Does dog refers to class/group of all animals satisfying dog properties or refers to every individual satisfying dog conditions
@yoroo3000 Жыл бұрын
blessings
@oOJw9gKX8YOTz8BHSdlmDg6 ай бұрын
Bruh I thought I was tripping until 2:30
@rumi22455 жыл бұрын
Thx
@nathanvanlent94072 жыл бұрын
Sorry but isn’t scocrates mortal if he is a man and all men are mortal?
@CaesarInVa2 жыл бұрын
Caught it about 2 seconds before you mentioned it.
@efbdvtfbrt70274 жыл бұрын
I now learned men likes pee
@lekoicy3 жыл бұрын
Lojban
@mastermind29712 жыл бұрын
Its pie not p
@mastermind29712 жыл бұрын
Lol
@BlightHeart4 жыл бұрын
I am not a happy man that's for sure.
@leetheee Жыл бұрын
all men aren't happy
@lederpsta423 жыл бұрын
You get a lot wrong in this.
@zaccalvert73418 ай бұрын
Lucky he made this video 9 years ago. Him changing the name "Mary" to a "mans name" Mark? Dude would have been cancelled af
@Trevtutor8 ай бұрын
In 2024 anyone can be any gender so really I was just super progressive in hindsight 😉
@rastisdiq41428 ай бұрын
@@Trevtutor That is bull*it. If you have an xy chromosome you ARE a man. And If you have an xx chromosome you ARE a woman. That's simple biology
@Salamanca-joro3 ай бұрын
@@rastisdiq4142damn 🥷🏾 its a joke
@mamtasingh83734 жыл бұрын
Help professor,this doubt is eating me up for days, Does dog refers to class/group of all animals satisfying dog properties or refers to every individual satisfying dog conditions
@supernenechi4 жыл бұрын
I am by no means an expert, but from what I gathered he meant that for absolutely everything you can point to in the universe, if it is a dog then it satisfies that condition. It depends on the universe you're looking at. Your universe could be filled with only animals, or filled with mostly osmium atoms. If you pick a point, any point, and it's a dog, then it satisfies that condition