Loop Azimuth Computations

[@habtiemelke7966]

When I first heard your voice, I said he should be a journalist however after I saw your explanation, I understand why you’re a teacher. Absolutely clear and interesting explanation, thank you!

[@Brendiinhaandrade]

Thank you so much for this video! I was stuck in a question of my surveying assessment for days, and you basically saved me! your video is fantastic, clear explanation and an easy way to explain the details, I wish you were my examiner.

[@karinajarzen2633]

Thank you so much for this video! It is saving my surveying grade!

[@fireballz7]

Can you please provide a link to the azimuth and interior angle work sheet in the comments?? Thanks!!!

[@AT-wx2bw]

Todd's free videos are much more valuables than many paid ones, for Special CA PE Surveying courses.

[@ALIEUFSAMAH]

How to pre-determined the Known Azimuth? Please I want to understand.

[@FloWayDaGoatWay6]

I wish I could print that worksheet out

[@stevebr2888]

Where can you download the form shown in the video?

[@victorb22622]

It again remembered my engineering college days

[@alvaroguerra3627]

sir i am punching in the numbers on my calculator as you speak and im getting different answers by one .....ive concluded either im doing something wrong or you didnt make some rule clear to us......

[@Strikekiller9]

Me too...

[@shine763]

I think the only mistake in the video is subtracting 385 degree from the negative 112 degree, and the answer should be 273 instead 272 degree.

[@Jeez_Peets]

I was confused for a while but my boss who's a surveyor helped me figure out the issue so I'll break it down and try to clear it up. Begin calculating Right to left starting at the seconds and carry over into the minutes then minutes carry over into degrees. So 25 27' 53" subtracted by 112 54' 17". Again begin with the seconds 53"- 17" = 36". So now we have 25 27' 36" subtracted by 112 54' 00". Now we subtract the minutes 27'- 54' but think of it as a clock going backwards and there's no negatives on a clock. We then get to 25 00' subtracted by 112 27' which then becomes 24 33' subtracted by 112 00'. So now we're at 24 33' 36" minus 112 00' 00" which then equals -88 00' 00". An Azimuth is 0-360 degrees so we take -88 + 360 = 272 degrees. And now we have our answer of 272 33' 36". 25 27' 53" 25 27' 36" 25 00' 36" 24 33' 36" -88 33' 36" -112 54' 17" --> -112 54' 00" --> -112 27' 00" --> -112 00' 00" --> +360 00' 00" = 272 33' 36" is our answer. I hope this clears things up a bit.

[@TheCamillejr]

Are you able to do a corridor video? thank you!

[@lauraharvey7424]

do you have a calculation sheet that can be printed out?

[@amyvalentine4783]

I understand how to get the degrees, but the minutes and seconds, i don't. Im confused how you subtracted 27 with 54 and came up with 33, but with 53 - 17 it came out correctly, as 36. Just a bit confused there.

[@jonathansanchez2854]

same with me here

[@faiqazharabbasi6209]

Hey there! Idk if it'll help you or not but I found how he did that. So basically it was 25°27'53'' he added 360°00'00'' to it making it 385°27'53''. The interior angle is 112°54'17''. So basically if you do the regular math and subtract 112 from 385, 54 from 27 you'll get wrong answers. If you have a scientific calculator there is a button through which you can enter values in degrees second minutes. In your calculator put (385°27'53'') - (112°54'17") you'll get 273°33'36'' Hope this helps:)

[@sylvestreedmondharoldtraor5548]

Thank you so much sir. Extremely helpful video.

[@RAAYY1515]

Why can’t you go counter clockwise ?

[@Feecofinated]

me a architecture student who sees this at after the finals of surveying 😭 next is mec statics of rigid bodies and mechanics of deformable bodies

[@tylerhansbury4409]

how is it 51- 40

[@freedomhillbilly348]

I've generalized the process to eliminate the need for a worksheet, eliminate the need to determine +/- 180 each step, and eliminate the problem of negative angles. it is also more amenable to automation via programming or spreadsheets. Here it is: Label all points in the direction of the traverse numerically from 1 (so 1, 2, 3... instead of A,B,C...) For Clockwise (CW) direction and Left Hand Angles (LHA) use the expression: A(n) = [A(n-1) - LHA(n) + 540]MOD360 Where An is the nth Azimuth, LHA(n) is the nth Left Hand Angle and MOD360 is the modulo operation (i.e divide by 360, throw out the quotient and keep the remainder. In simple terms, keep the the final angle result within the primary 0-360 degree circle.) For Clockwise (CW ) direction and Right Hand Angles the equation is: A(n) = [A(n-1) + RHA(n) +180]MOD360 A similar pair of equations can be derived for the complementary operation of finding the angles of turn given the Azimuths. I've confirmed they work for angle turns > 180 as well. These equations are elegant, closed form, and eliminate the plague of errors due to trying to keep track of all those sign changes etc. I'm sure I'm not the first to figure this out, but it's odd to me that everyone seems to teach this as you have. I understand that it's useful in cementing what the underlying mechanics are, but for real work, it's much too laborious. Maybe that's just me.

[@guanzhongshi6414]

very easy, simple and smart method

[@hawit1377]

wehave to see the picture of question to solve the problem with u ?? do't u think? ........make everythingg clear fr!!!!

[@weygheoncaldeen]

Could you please email me a copy of that Worksheet?

[@nyonymousphuck4783]

Very helpful 🔥🔥🔥

[@minervamunoz4607]

Thank u so much!!! This is really helping me review for my surveying final☺

[@dareen6451]

Thaank you thank youuuu Youre yhe besttttt

[@dareen6451]

MAANNN you rescued meee!!!

[@dlinzikri1766]

Thank you

[@sayedirshad1479]

Life saver

[@TheCamillejr]

You're the best!!!

[@dawodahibrahim6961]

your lesson of the computation is in other