LOOPS IN SAS - 2 | Iterative Do Loop in SAS | Do Index Loop in SAS | Do Loop in SAS

This video emphasizes on one of the the Do Loop type and provides you clear understanding in such a way that you could be in position to:
► Explain What is Do Loop or Iterative Do Loop or Do Index Loop in SAS
► Create a Counter Variable in SAS Using Do Loop or Iterative Do Loop or Do Index Loop
► Apply Do Loop to Simplify the Works Like Creating Multiple Statements
For Introduction of do loops, check out the video on below link:
• LOOPS in SAS - 1 | Int...
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Download the excel files for practice data:
GitHub ► github.com/LEA...

[@domadordedromedarios]

Very helpful content! Thank you for sharing this knowledge!

[@learnerea]

Glad it was helpful!

[@sachingaikwad5580]

thank u sir share very useful information looping statement...

[@learnerea]

So nice of you

[@shwetajaiswal777]

very helpful content

[@learnerea]

Glad it was helpful!

[@ombirsingh802]

very very nice content and I really appreciate your hardwork. keeep doing. some videos dont have sound pls check.

[@learnerea]

thank you for watching, we are ensuring to not repeat the sound issue in all of our upcoming videos... unfortunatly we cannot improve the sound in already uploaded videos

[@gauravrajole6655]

great explanation

[@learnerea]

Glad you think so!

[@srikanthreddy3454]

In 1st do loop example ,if we don't use output statement between do and end,we are getting different output why,can u please explain control flow of those

[@learnerea]

Output statement instructs to print each of the iteration individually while if it's not given, each iteration gets overwritten by the later one and hence at the end you will see the output of only last iteration. Hope this clarifies

[@chandanchaurasiya348]

Hello @learnerea Sir, I wanted to keep the Serial number (Sr_no) column at the beginning so I set it first but in the output in the first observation the Sr_no 1 is missing. Don't know why and there is no error showing on the log Below is the code for my output. data numbers; do Sr_no=1 to 19; output; end; run; data class; set numbers; set sashelp.class numbers; run; looking forward to hear from you soon. Thank you

[@learnerea]

In the second set of code you are appending the data sets one below another (also sashelp.class is fine not sure why you have written "numbers") while your requirement is to simply have a serial number for each of the record in your class data, if so try below - data testing; set sashelp.class; if _n_ = 1 then sr_no = 1; else sr_no +1; run;

[@vaibhavbhadane2451]

I got some error to execute a programme like expecting a format name

[@learnerea]

can you please put the error message over here..

[@CGDminds]

Why didn't you use 'output statement' in if then do loop????