You literally saved me, went from a 1250 to a 1430 on the recent August SAT. Love your videos!
@RisetotheEquationАй бұрын
Problem 2 is a two-stepper in desmos. Step 1 enter the equation as is. Step 2 enter b=1 to create a slider. Set it from 1 to 100 in step 1 (step = 1 since it's an integer), and note that when b=52 one solution appears, but when b=51 the solutions disappear. So b=51 is the biggest it can be to ensure no real solutions. This took 30 seconds.
@apollon9031Ай бұрын
We need you to do a video about tricks with desmos
@ceydasunАй бұрын
You can also just exchange b for „y“ and then check the y value of the maximum and minimum that shows up on the graph :))
@miffyqqqАй бұрын
can you pleas make a video how to use desmos for sat?
@sam-no8ugАй бұрын
How do know the numbers to set it in like why is it from 1 to 100
@RisetotheEquationАй бұрын
For problem 5, let b be your free variable and assign a value of 100 in desmos by entering b=100 (it creates a slider, but you'll just leave it at 100...you can actually set it to ANYTHING since it's a free variable). Next line type a=30% of b. That gives you a=30. Next line after that type c=180% of a. That will give you c = 54. Then do a regression by typing c ~ nb to solve the equation c = nb, where n is how many times c is bigger than b. Under the PARAMETERS you get n=0.54. Done. Literally took 15 seconds.
@StrategicTestPrepАй бұрын
@@RisetotheEquation 🤩
@dankify79Ай бұрын
WOW this is awesome, thank you for commenting this I had no idea it was possible to get this problem done so easily
@RisetotheEquationАй бұрын
For problem 4, some students won't pick up on the trick that the answer has to have 7/2 in the x-coordinate. A more convincing approach with desmos is to just plot each point exactly as shown, and enter a slider for r. Only choice B will keep the point on the two lines (which happen to be the same) as you slide r.
@elle5463Ай бұрын
wdym by plotting each point ?
@RisetotheEquationАй бұрын
Problem 3 is 1 minute in desmos. Create a table and enter three points: (9,-14), (9+d,0), and (9-d,0). First point is the given vertex, and the second two points are artificially created conveniently on the x-axis d units symmetrically on either side of 9. Then enter d=1 to create a slider. Next do a quadratic regression by typing y_1 ~ ax_1^2 + bx_1 + c and finally type a + b + c to check the sum of the constants as you slide d. Notice that as you slide d in the positive (or negative) direction, it does have a sum of -12, but never quite approaches -14. So the answer is D.
@yaayyayayАй бұрын
why do we minus and plus d?
@cfgauss71Ай бұрын
To keep the points the same distance on either side of the x-coordinate 9. Remember parabolas are symmetric with respect to the vertex.@yaayyayay
@selaseamedroАй бұрын
how does the fact that it barely approches -14 mean its correct?
@NataliaMartinez-x6gАй бұрын
I had been struggling with problems like Maria's, she helped me understand very well!!
@RisetotheEquationАй бұрын
For the first problem just set up a regression in desmos to solve for p by typing in -p/3 + 3 - 3 + 8 ~ 20/3 to get p=4. The -p/3 is the solution to the first ( ), 3 and -3 for the second ( ), and 8 for the third ( ). For the third you do need to know the sum of solutions of a quadratic is -b/a = -(-16/2) = 8 to save time.
@diixlorrАй бұрын
did not we just need to make -b/a why did we do all that stuff. btw thanks for the explanation
@RisetotheEquationАй бұрын
That would take a lot of work to multiply that all out and you run the risk of making an error by hand. But, yes, in theory -b/a still applies as the generalized Vieta rule.
@vvvintagedarlingАй бұрын
Thank you so much! How does this "regression" work in desmos exactly, and are there many other problems on the SAT it would help to use? I've never used it before in desmos.
@16790AAsDАй бұрын
Can you go over tips and tricks for geometry, trigonometry, and circles thanks 😊
@mary-belled9244Ай бұрын
Struggle with probability and chart. Thx for resources.
@MashxuraKenjayeva-f8hАй бұрын
thank u very very much!!! i have got a deep regard for you. Carry on making such videos .please.
@malaikazainabАй бұрын
Hey Laura ! I hope you are doing well. Just wanted to say that there was one math question in the second module of the august math SAT 2024..... I have never seen a question like that in the past 20-25 papers and also not in the practice papers in the bluebook. Can you please solve any question like that. It was really complex too.
@shayan-fx7fnАй бұрын
What was the question exactly
@KonudulaCharviReddyАй бұрын
problem solving and data analysis
@yaayyayayАй бұрын
i genuinely don’t get the third problem, can someone dumb it down??
@nicolasduarte5123Ай бұрын
Thanks for your help!!!
@sodum8676Ай бұрын
Im confused for the second person speaking, question 21 I just pot it in desmos and did guess and check and it says 52 has one point touching the x axis at (26,0). ( I thought no real solutions means it can touch the x axis )?
@FakeSpiceАй бұрын
W title i clicked on this video instantly
@JuliaAckinsonАй бұрын
Fu ck ing pa jeet
@JuliaAckinsonАй бұрын
You are a (p a j e e t)
@StrategicTestPrepАй бұрын
Clickbait !! 😂 😉 jk
@JuliaAckinsonАй бұрын
@@FakeSpice jeet
@rickyz8839Ай бұрын
Can someone please tell me why the answer of problem 4 must include the x-intercept of the line???
@PectronixАй бұрын
The last bluebook test I gave I scored 1330 and after a lont time of Studying I was hopping that will get 1450 plus, but when I gave sat 6 bluebook test I scored 1130 this kind of sadded me deeply. I don't understand why? I got 26 wrong in total. Feeling quitehelplees. I am giving sat in october start. Is there any possible way for me now to do something to get 1500 plus on my real sat test please helpAll hope lost.......
@DreadOG-MoseАй бұрын
Wow the 4th one really threw me off! What's the mathematic approach to that one?
@olamiposi06Ай бұрын
Fr she just went around the mathematics of it and left me stranded
@puneetkaur5681Ай бұрын
If we look at the problem mathematically, you will notice that both equations represent the same line. All points of equation 1 are also the points of equation 2. To figure out which point lies on the graph of both equations, you can substitute the value of x or y in the equation 2x+3y=7 to get the value of y or x respectively. You will notice that it is only for option B where substituting y=r yields x= -3r/2 + 7/2. The method in the video is just a quicker (and tried and tested) way of doing the problem. Hope this helps :)
@DreadOG-MoseАй бұрын
@@puneetkaur5681 I just remembered this earlier!! I tried converting it into slope intercept so that r would equal x. However, one of the answers choices was so close to being right but it was a positive slope instead of a negative slope. So I tried doing x= yada yada just like you did and I figured it out! Math is so interesting