De Broglie Hypothesis | De Broglie Wavelength

[@Mmpoyalo]

λ = h / p where h is Planck's constant. Since kinetic energy (KE) is related to momentum by: KE = p^2 / (2m) where m is the mass of the electron, we can express the change in kinetic energy as: ΔKE = (p2^2 - p1^2) / (2m) Given that the kinetic energy increases by 96%, we can write: ΔKE = 0.96KE1 where KE1 is the initial kinetic energy. Substituting the expression for KE in terms of momentum, we get: (p2^2 - p1^2) / (2m) = 0.96(p1^2 / (2m)) Simplifying, we get: p2^2 = 1.96p1^2 Taking the square root of both sides: p2 = √1.96p1 ≈ 1.4p1 Now, using the de Broglie equation, we can find the change in wavelength: λ2 = h / p2 = h / (1.4p1) ≈ 0.71λ1 So, the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).

[@desmonderickson2232]

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Congratulations!! Great to hear that you did in your Physics paper! Do share our channel with your friends!

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[@franklinemix8048]

God will continue to bless you as long as you exist both you and your family and generations.

[@Daily_Wit]

Thanks 🙏 from Bangladesh 🇧🇩. Does that means that all object r high Frequency least wavelength? 2. All objects r frozen light?

[@franklinemix8048]

Change in wavelength is (9x10-¹¹) that's exactly 27.3% decrease. This when you truncate the numbers while solving. But, when you decide not to truncate, estimate or approximate. The percentage change is 28.57142857143% exactly.

[@franklinemix8048]

The wavelength originally is 3.3×10-¹⁰m but as K.E(2.202x10-¹⁸) increased by 96% it changed the wavelength down to 2.4×10-¹⁰m that's a difference of 0.9×10-¹⁰ in correct standard form 9.0x10-¹¹. 23.7%. K.E is 1/2mv² where m(mass) is 9.1x10-³¹kg and v(velocity)=2.2x10⁶m/s.

[@anthonymckinney8173]

Let's dive deeper into the concept of "systems" and their role in the context of de Broglie wavelengths and quantum mechanics. What is a system in physics? In physics, a system is simply a collection of objects or entities that we choose to focus our attention on. It's a way of mentally separating a part of the universe from the rest, so we can analyze its behavior and interactions more easily. Types of Systems * Isolated System: No exchange of matter or energy with its surroundings. A perfectly isolated system is an idealization, but some systems come close (e.g., a well-insulated thermos). * Closed System: Can exchange energy but not matter with its surroundings (e.g., a sealed container with a hot liquid). * Open System: Can exchange both matter and energy with its surroundings (e.g., a living organism). Why Systems Matter in Quantum Mechanics When we talk about a particle's de Broglie wavelength interacting with a system, we're essentially talking about how the particle's wave function interacts with the potential energy landscape or boundaries defined by that system. * Confinement: Systems can confine particles to specific regions of space, altering their wave functions and energy levels. This leads to phenomena like quantum confinement in nanostructures, where the particle's behavior is strongly influenced by the system's boundaries. * Scattering and Diffraction: When a particle interacts with a system, its wave function can be scattered or diffracted, revealing information about the system's structure. This is the basis for techniques like electron microscopy and neutron scattering. * Tunneling: In quantum mechanics, particles can "tunnel" through potential energy barriers, even if they don't have enough classical energy to do so. The probability of tunneling depends on the particle's de Broglie wavelength and the shape of the barrier, which is often determined by the system's properties. Choosing the Right System The choice of system depends on the specific problem or phenomenon we're interested in. * Single Particle in a Potential: We might consider a single particle (e.g., an electron) interacting with a potential well or barrier created by some external field or structure. This allows us to focus on the particle's wave function and energy levels within that specific environment. * Many-Particle Systems: In more complex systems, we need to consider the interactions between multiple particles, which can lead to collective phenomena like Bose-Einstein condensation or superconductivity. * Open Systems: In some cases, we need to account for the exchange of matter and energy with the surroundings, which can lead to decoherence and other effects that influence the quantum behavior of the system. Key Takeaway The concept of a "system" provides a framework for analyzing the behavior of particles in quantum mechanics. By defining the system and its boundaries, we can understand how a particle's de Broglie wavelength interacts with its environment, leading to a wide range of quantum phenomena. Let me know if you'd like to explore any specific examples or aspects of systems in more detail. I'm here to help!

[@kottekotravikumar8906]

It's energy that was thought to be continuous, not matter.

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[@bhaktabachalabehera2654]

I wanna become quantum scientist thanks sir for this video

[@ManochaAcademy]

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[@OG_Solar_Edit]

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[@sunilrai500]

I guess you don't know the dot of quantum. Sir ki video toh khud sur confuse lag raha hae. Theory is not physics it's understanding.

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[@sriritwikshastry9603]

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[@24dipika]

the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).

[@simegnewtesfaye4455]

If we let the first kenetic energy is KE1 and The second kenetic energy is KE2 then the answer will be -0.2hKE1m h =Planck's constant m=the mass of an electron KE1=the first kenetic energy I hope you will give me a correction if I'm wrong 🙏 Thanks for the video I swear this video is so amazing

[@MukulSaini-iv7fr]

bro answer is -.03 aa raha h mera to kya tum bataoge kaise kiya tumne

[@RasheduzzamanRuhid]

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[@shiekh366]

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[@adityalokhande6484]

Sir the answer would be 5.01×10^-19 .

[@iron-cut6436]

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[@ManochaAcademy]

Glad to hear that

[@AnicheIjeomaJennifer]

5.0127×10^-19

[@srinivasanv7951]

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[@AvishekYadav-j6m]

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[@ManochaAcademy]

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[@deku_ik_7]

Change in wavelength=2/5 and %change in wavelength= 40%

[@nathanakpome6401]

Sir Please do a video on electromagnetic induction

[@ಅರ್ಪಿತಾ-ತ4ಷ]

Are number of electrons reduced when metal was exposed to light ?

[@vaibhavprajapati1835]

Wavelength will decrease by 28.5 % Sir please pin if ans is correct ❤

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[@fathimahafsausman]

Clear explanation sir :) Sir can i please know the answer for the homework question? Thanks in advance sir.

[@gotobawa]

28.57% dicreases

[@rupalipatel2603]

how to find

[@KumarUtkarsh-u2y]

Great explanation❤ liked this video

[@zakmatew]

The fact that the energy levels are quantized doesn’t mean that there are particles. Rather, it is all waves but “quantized waves” as I call them. They give the false impression of particles but do account for the so called “dual nature of particles”.

[@MARADONA_20]

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[@m.rakeshroshan9601]

What is Quantum sir ? Is it something like quantified or will it can be other way said as made into mathematically expressible once Sir ?

[@maheshwarisingh6295]

1.58×10^-15

[@panthaganiniharika3208]

the percentage change in wavelength is 2.14%.

[@srinivasanv7951]

Amazing🎉

[@Chemysterious10]

Sir from which website you use simulations like you use photoelectric effect in this video ??

[@SayaniChattaraj]

Thank you.... your explanation is crystal clear

[@dank3470]

what is the answer for the question? please help ?

[@anshu4102]

7/5

[@umeshkumartiwari9431]

0.13383×10-34

[@divyaanji2361]

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[@BhaskarGupta.]

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[@Lily20008]

Sir is the change in wavelength 92.8%

[@oluwajobaOkewole]

27%

[@AvishekYadav-j6m]

❤❤❤❤❤

[@ManochaAcademy]

Thank you!

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[@AtemkengSonna-im6rg]

Please can help me on how to identify colour in chemistry 9:55

[@KieKie-lj8ks]

I got 51%....i.e the wavelength decreases by 51%

[@Sigma__Mathematics]

Sir please Give tha answer of last Question

[@Sigma__Mathematics]

Is this KEf=kei+96%(ke) i

[@ayushkumar27703]

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[@ManochaAcademy]

Most welcome!

[@DanielIhueze]

0.287 decrease

[@nitasharma8308]

The answer is: 1.4 times the initial wavelength. i.e., Final wavelength=1.4 initial wavelength or, λ'=1.4λ. Hope it's true. Please let me know.

[@ShyamaliWijesinghe-t1o]

71.428% increase in wave length.

[@k2creation481]

98% decrease

[@SHURPARMAR]

kk

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First

[@ManochaAcademy]

Thanks for watching so fast :)

[@sholaadeyemi6846]

This is awesome. How can I have to these topics in physics that difficult to explain theoretically

[@milandjordjevic2408]

Decrease 28.571428571 %