Mantissa and Exponent in Floating Point

[@SinKeongTong]

After 50+ years of programming in COBOL, Pascal, Assembler, Python, C and now Python, I finally understand floating Point, Thank you very much before I bid farewell.

[@kcvinu]

I lost the flow at 02:18 when you say 10 bits for mantissa and 6 bits for exponent. Because, how do computer know that ? You didn't said that in video.

[@thenobody8037]

It depends on the os and hardware architecture. I used a small instance of the problem so it would be easier to grasp the idea.

[@HarpreetSingh-ke2zk]

Simple and straightforward.

[@aritheee]

nice video best part 5:30

[@FawkesR]

i m not understanding the last example.... why six?

[@amrali6388]

-8 + 1 + 0.5 + 0.25 (sorry for answering a year late)

[@zetovicfabio]

Very good video, thank you ❤

[@sarkersaadahmed]

5:24 -7.75

[@Kusanagi64]

Only the first number (to the complete left) is a negative number, so: -8 plus 1 = -7 -7 + 0.5 = -6.5 -6.5 + 0.25 = -6.25 -6.25 is the correct answer there. It seems you added the 0.5 and 0.25 and went back to minus, but you’re already below zero so adding makes the number go closer to 0

[@AsifImran]

Thanks

[@elainemaellacuna4819]

Thank you sir

[@ghattassaliba4910]

isn't the last example -7.75??

[@NetFreak]

true

[@cathy-annlindsay7024]

I understand why you ask this question ... Towards the end the calculation was not done to return the mantissa to the positive two's complement value. ie. 1001.11 is (- 0110.01) ... That is then -6.25

[@sashkopejovski782]

​@@cathy-annlindsay7024thanks!

[@thenobody8037]

1001.11 = -8 + 0 + 0 + 1 + 0.5 + 0.25 = -6.25. You can check this as well by applying 2's complement. 1001.11 = -(0110.01) = -6.25 Sorry late reply..

[@christopherbarredo2512]

Thank you sir 💯

[@simplelife6802]

Thank you po sir

[@KenLorenzSendaydiego]

👍

[@sahrali4186]

Plz solve 3/8 how to find exponet

[@bemsorcaabay8509]

0.375 so this becomes 375 x 10^-3 in decimal. In Floating point binary, this can be written as 0000000011 111010

[@johnisaacdelgado7765]

Thank you sir

[@jamesabalus4261]

Thank you sir

[@armanvicente6845]

Thank you sir