FE Fluid Mechanics Review Session 2022

  Рет қаралды 107,250

Mark Mattson

Mark Mattson

Күн бұрын

Пікірлер
@TrucNguyen-xk3ud
@TrucNguyen-xk3ud 9 ай бұрын
Thank you Mark for all of your videos! I just passed my FE exam after several failed attempts. This time I studied with you and passed it. Your videos are incredible, I appreciate how you put them together like this.
@sulimanhamed2751
@sulimanhamed2751 6 ай бұрын
What did you do in addition to the video? Lots of practice problems? Glad to hear you passed
@keiajackson7446
@keiajackson7446 5 ай бұрын
Good morning, were there alot of conceptual questions?
@curtisreidy4028
@curtisreidy4028 10 ай бұрын
Mark, just wanted to say a quick thank you for putting these videos together. I watched them a few days prior to my exam and I am happy to say I passed. THANK YOU!
@ThatWasNew
@ThatWasNew 2 жыл бұрын
Thanks Mark for your help incredible, I have passed FE
@jasonlewis460
@jasonlewis460 Жыл бұрын
what similar questions came up on your exam?
@arslankhalid760
@arslankhalid760 10 ай бұрын
Thanks Mark, I have a quick workaround for problem #10, instead of calculating slant distance for "Yc" and "Ycp" we can directly calculate the vertical distances "hc" and "hcp". Hc will be 50cm, however little caution needs to be taken when calculating "Ixc" and Area "A" of the gate, instead of using 16cm, use 8cm as a vertical dimension of the gate to calculate "Ixc" and "A". Just wanted to put this method as a comment as it reduces time to calculate vertical distance to the centre of pressure.
@shamanaveed9329u
@shamanaveed9329u 2 жыл бұрын
In question# 8 specific gravity SG =γ/γw we can directly solve this.SG*γw=γ put value 13.6*9810=γ
@mateusbernardodeoliveira7641
@mateusbernardodeoliveira7641 Жыл бұрын
To find velocity on Question #3, a faster route, although it does not explain all the concepts you did while solving, is to equate the difference in height between the two tubes to (V^2)/2g, and then solve for V. edit: Mark did explain it right after solving the first way.
@kautz00100
@kautz00100 11 ай бұрын
For the Pitot tube question you could also do v=sqrt(2gh) and get the same velocity without finding what the pressures are.
@BM4gic2010
@BM4gic2010 23 күн бұрын
yep, just use a bernoulli's at the top of both tubes h=v^2/2g
@Cdwilliams1999
@Cdwilliams1999 2 жыл бұрын
Thank you Mark! Thanks to your helpful videos I was able to pass the FE on my third attempt! P.s. Your jokes are the best!
@Fazojar
@Fazojar 21 күн бұрын
Question 8, in handbook page 7 we have 1 atm = 760 mm.Hg = 101.3kpa then the atm pressure is : (725*101.3)/760 = 96.7
@JoseLOrtiz-rf5ph
@JoseLOrtiz-rf5ph 29 күн бұрын
For question #4 they have the conversion factor for liters to meters in the reference handbook. The conversion factor is 0.001
@hulb1670
@hulb1670 2 жыл бұрын
Thanks Mark. I am using this to study for the PE and it has been very helpful.
@JoseLOrtiz-rf5ph
@JoseLOrtiz-rf5ph 29 күн бұрын
You can take the FE your last year in CE degree. Also law changed where you can take the PE after passing the FE, but before gaining your experience
@DatNguyen-wi3fs
@DatNguyen-wi3fs 2 жыл бұрын
Incredible as always Mark. Appreciate the video
@amanuelzemedhun8768
@amanuelzemedhun8768 Жыл бұрын
Hello Mark! Thank you for these videos! In question 11, why did you make P2 zero? Why not plug in the atmospheric pressure itself?
@Paul-oo6uu
@Paul-oo6uu Жыл бұрын
It may be too late for your question at this point. The reason is the 100kPa at point A is gage pressure. Gage pressure 0 is atmospheric pressure. The atmospheric pressure would need to be added if the pressure at A was absolute pressure.
@lay6787
@lay6787 2 жыл бұрын
Dear Mark, Im taking this video from korea and it's really wonderful! Just a question. From the 1:17:48, you explained about the applicable b and h if it is not the square type gate. So the h value will be derived from the shown value, e.g.16 cm as per problem and the b will be the value from page direction? You mentioned 12cm in y direction and 20cm in x direction and I suppose Ixc will be then 20 x 12^3/12 but the video says the other way. Appreciate if you can clarify. Thank you so much!
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
Hey Lay! thanks for the question from the other side of the globe :) You are totally right. It should be 20 × 12^3 / 12 if the 12 is in the direction of y and 20 in the direction of x. I flipped it when I was trying to add some clarification :( Thanks so much for pointing this out! Hopefully, the comment and response helps clarify it for you and others.
@lay6787
@lay6787 2 жыл бұрын
@@MarkMattsonPE Thanks for swift response! I really appreciate your lecture, always happy to see your smiley face on the right bottom of screen with stunning jokes from time to time :)
@lay6787
@lay6787 2 жыл бұрын
Dear Mark, I passed it thanks to you! (2months of studying with 2 hours/weekday+5hours on weekends) Could you please advise me on how to pass in PE Geotech in general? e.g.) List of books to study with, Online lecture will help, right?, sequence of study, preparation duration and etc… Thank you!
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
Congrats! For the PE, I used the CERM almost exclusively and felt super prepared.
@jace3254
@jace3254 Жыл бұрын
for question 11 why did you use 0kpa for Pb instead of using 101.3 kpa for atm pressure?
@unmaroolable
@unmaroolable 8 ай бұрын
gage pressure is measured with respect to the atmospheric pressure. Overall whenever the flow is exposed to atmosphere the pressure at that point is 0.
@usmitapokhrel9764
@usmitapokhrel9764 2 жыл бұрын
Thank you Mark.
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
So how do you spell gage/gauge? USGS and the Steel Deck Institute uses gage. However, ASTM and others use gauge. I normally associate gage with stream flow gages and steel deck, and gauge with meters used to measure a pressure. Merriam-Webster indicates gauge is preferred. Both are in the FE Reference Handbook. Thoughts?
@nabinshrestha6594
@nabinshrestha6594 Жыл бұрын
Hi Mark, In question number 7, why Pvinegar=5386N/m^2?
@dilipsaha94
@dilipsaha94 2 жыл бұрын
Can you explain why, in problem 12, the impulse momentum principle doesn't come into play? Why can we set Fx & Fy to 0? Doesn't our momentum change in both x & y directions because our V1 and V2 are in different directions? Why isn't it "P1A1 - P2A2*cos(α) + Fx = Qp(V2*cos(α) - V1)" and "Fy + P2A2*sin(α) = Qp(V2*sin(α) - 0)" ?
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
The distribution lines are are usually sized to keep the velocities relatively low in the pipes. Adding in the mass flow due to a velocity would increase the forces slightly. I probably could have defined the problem more fully by asking for the thrust due to the static pressure.
@dilipsaha94
@dilipsaha94 2 жыл бұрын
@@MarkMattsonPE Thanks for the reply. And thank you for this wonderful video series, you really do a good job of hammering home key concepts.
@jossyurael9042
@jossyurael9042 Жыл бұрын
question No.6 needs to be corrected. We should assume that the Vat is closed. otherwise, the atmospheric pressure will be added.
@danielj.berrios960
@danielj.berrios960 2 жыл бұрын
Question 12: the problem ask for the horizontal Thrust force ( forces acting in the X axis ) why is it that the answer is 2,828 Lb acting vertically ?
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
The z direction is vertical and ignored in this problem. The horizontal thrust is the resultant thrust in the x-y plane.
@crawsabi
@crawsabi 2 жыл бұрын
For problem 3, why is it that we use .15m for the height of Ps instead of .10m? would we use .10m if the problem didn't have the first pipe sticking out on the left?
@fawadraja3564
@fawadraja3564 Ай бұрын
I know this might be stupid but how did you do the 3:1 ratio for the 60 cm
@Fleur874
@Fleur874 2 жыл бұрын
Hi Mark, thank you for the FE review sessions! I find them extremely valuable! For Fluid Mechanics Problem 10, can you go over how you calculated Ixc ?
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
Ixc is the moment of inertia of the plate about its centroid. So you take the base (or width into the page) times the height cubed (length of plate) divided by 12. I hope that helps clarify. I did make a mistake when talking in the video. See the comment string from @Lay also.
@be1062
@be1062 2 жыл бұрын
Thanks, Mark!!
@ricandres1000
@ricandres1000 2 жыл бұрын
Good morning Mark I have a question on problem # 7 When you were getting Resultant 2 why did you do the average of the two pressure and why not use only the 5386 like when you got resultant 1 using 3973 only?
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
You actually do the average of the top and bottom pressures for each area... only for a triangle, the top pressure is zero, so you take (0+3973)/2, versus (3973+5386)/2 for the trapezoid. Does that help?
@ricandres1000
@ricandres1000 2 жыл бұрын
Yes, it helped Thank you very much. Question will you do a review for environmental?
@02AJO
@02AJO 2 ай бұрын
Thank you so much for the answers for these concepts. But can I ask a doubt about the question 3 about pitot tube. Since there is a height difference between the two tubes will the equation used in the video still be valid. Since his equation does not account for the additional potential energy due to the height difference Δh.
@sidhu2z
@sidhu2z 2 ай бұрын
Can someone please explain Q-10 at 1:14:10 how area is 16*16 ? , and also explain how Ix bh3/12 = how b & h = 16 ?
@5313030
@5313030 2 жыл бұрын
Thank you for these videos.
@engraghad8663
@engraghad8663 9 ай бұрын
Hi Mark! Finally I paaaaaaseeeed the FE civil exam from the second try 😍😍 I am soooo happy and want to thank you for all your videos I watched it several times Also I want to recommend the book of “ Islam “ which contains 800 questions it was also amazing and let me understand many additional things that not included in the yellow book So it was great knowledge from your videos, the yellow book, and Islam book after completing it I passed the exam 😍😍😍
@nikhildumbre4076
@nikhildumbre4076 2 жыл бұрын
In question 7, while calculating R1, what does 0.4 represent and from where did you get that
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
I believe that's the width of the vat. Please see the previous problem for the diagram showing the width.
@carultch
@carultch Жыл бұрын
@@MarkMattsonPE How do you know whether the given ratio in that problem, is a volumetric ratio or a mass ratio? Is it convention to give the ratio by volume if not otherwise specified?
@Sxciroq
@Sxciroq 10 ай бұрын
For question 3, if we know that v^2/2g represents the change in height, then why can't we use the .2m and set it equal to that equation to find our velocity? Wouldn't it be faster?
@eng_sam4850
@eng_sam4850 Жыл бұрын
q1) how did u get 1.25 ft for area?
@trellispowell1332
@trellispowell1332 8 ай бұрын
1.25=1ft & 3inches
@tundratales449
@tundratales449 Жыл бұрын
Hi Mark, Thank you for the lecture. On question 5, you multiplied the height of the raft (7.5"/12") by 6' by 8' feet to get the volume of wood in the raft, but since the raft is made of 7.5x7.5 timbers, there has to be some space between the timbers since 7.5 inches does not evenly divide into 6 feet. Only 9 of these timbers can fit into a 6 foot span, unless of course you are using a partial timber (0.6 the width of the others), which kind of defeats the purpose of telling the width dimension of the timbers, right?
@danielj.berrios960
@danielj.berrios960 2 жыл бұрын
Question 5: W= γ*V, But the problems states that the density ρ=45 lb/ft3. why are you using density as Specific weight γ ?? Thanks Matt. Keep the jokes up man!
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
You're right... gamma is unit weight and includes gravity, whereas density or rho is mass per volume. The problem should say the "unit weight of the saturated wood is 45 pcf..." Thanks!
@LeaderZ2000
@LeaderZ2000 2 жыл бұрын
Grateful you asked that question, Daniel. Just spent almost 10 minutes racking my brain on why gravity wasn't used, but you and Mark cleared it all up here.
@shamanaveed9329u
@shamanaveed9329u 2 жыл бұрын
Me to was confused, thanks for help.
@carultch
@carultch Жыл бұрын
@@LeaderZ2000 Everybody brought gravity to the party in that example. Both the surrounding water and our raft, are both affected by the same gravitational field, and buoyancy comes in proportion to the weight of the water. We'd get the same answer, regardless of what planet the problem takes place upon. So whether we use specific weight, or density, we'd get the same answer, as long as we were consistent.
@DatNguyen-wi3fs
@DatNguyen-wi3fs 2 жыл бұрын
55:49 can you explain why Pv = 0 for mercury again Mark ?
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
It's not that there's no vapor pressure, it's just really really small and can be ignored.
@DatNguyen-wi3fs
@DatNguyen-wi3fs 2 жыл бұрын
@@MarkMattsonPE roger
@linnacyzia3003
@linnacyzia3003 Жыл бұрын
Where in the link I can find V1.3
@raulc02
@raulc02 2 жыл бұрын
Tricky first question... open channel flow using the continuity equation...
@alban97
@alban97 2 жыл бұрын
I used Manning's equation and got 7.5
@MarkMattsonPE
@MarkMattsonPE 2 жыл бұрын
A correction factor (in this case, 0.9) is often to adjust average velocity and area measurements. For example, see this sample lesson/lab on finding flow in a small stream www.nps.gov/common/uploads/teachers/lessonplans/Climate%20Science%20in%20Focus%20Field%20Trip%20-%20Measuring%20Stream%20Flow.pdf
@AnailyCarbonellAlvarez
@AnailyCarbonellAlvarez Жыл бұрын
@@alban97 when I used Manning equation , i got 5.56 cfs. PLease could you tell me how many is S in this equation. For me S got 1.22
@DRM0087
@DRM0087 2 жыл бұрын
I am taking the NCEES FE Mechanical exam, would this this video still be helpful for me? Even though it's for NCEES FE Civil exam.
@Bri.Charles
@Bri.Charles 2 жыл бұрын
Yea it would still be good!
@Godloves24
@Godloves24 2 жыл бұрын
Great video.
@abrahambg6301
@abrahambg6301 Ай бұрын
Great
@musicbyverve
@musicbyverve Жыл бұрын
I don't understand why you used Q = Av to solve question #1 when the problem statement defines it as a channel. We can see it is open. Open-channel flow is manning's equation?
@nadheeralgburi5265
@nadheeralgburi5265 6 ай бұрын
First question 1.3 Should be 1.025 not 1.25
@TheColonelJman
@TheColonelJman 4 ай бұрын
1.25 is correct. 1 foot, 3 inches or 1 + 3/12 = 1.25
@noahbatterson2884
@noahbatterson2884 Жыл бұрын
question 1 is annoying. Why would you make a problem using open channel flow and then not use the open channel equation for flow rate???
@user-ww4jz7ve3l
@user-ww4jz7ve3l Ай бұрын
I also have that same question. I also understood it to be a small channel and used Manning's Equation to get 7.5 CFS which would be answer C.
@JoseLOrtiz-rf5ph
@JoseLOrtiz-rf5ph 29 күн бұрын
Last comment, I always stay for the dad jokes 😅
@thepiratebey
@thepiratebey 2 ай бұрын
10:10 my name is ish
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