Math Olympiad Algebra | How To Solve Algebraic Equation With Radicals The Easy Way.

[@upeindrakumarsingh]

Very nicely explained a complex problem

[@starspreandprimaryschools3075]

Yes I am still learning, at the age of 60, I still love maths.Thank you brother.

[@mustaphaballaji4628]

Think you for the good explanation

[@opulence3222]

Wonderful steps men. This video is super great, keep on the good work sir.

[@tyronekim3506]

Very good lesson. Thank you.

[@mallikarjunaraokotikalapud4828]

Excellent. Thanks for educating us.

[@rosariomayorga8471]

Congratulación. Excelente way to solve equation!!!!

[@manojkantsamal4945]

Respected Sir, 🙏. Fantastic elaboration.......

[@onlineMathsTV]

Thanks a million for the acknowledgement sir. We love you sir...💕💕💖💖

[@AbdulBasit-b8d]

Smart teacher 😮n

[@EhsanZia-Academi]

thank you sir for this great and easy explanation. Good job

[@AbdulBasit-b8d]

Smart teacher 😮

[@wesalfahad4910]

Thank you🎉🎉🎉🎉🎉

[@exoplanet11]

Well done. After seeing the answer a strategy dawns on me: since sqrt(2) is irrational, the exponents must be even numbers. Look for powers of 2 whose difference is 504.

[@Thebrightestgem]

brilliant method sir

[@muhammadtasleem959]

Very nice

[@scotguitar]

Always, you're my favo

[@matole906]

My friend, you are the best. Your reasoning has driven you to the right solution. Thank you for your dedication to teaching your audience.

[@jamesonzere5201]

From 2^k-1 =63 we can determine the value of k and p.

[@therichcircle.8819]

❤❤❤

[@danielfranca1939]

Wow!!! You will never ceased to impress me with your skilful and detailed explanations. You the best maths tutor sir. Thanks for this video clip mr Jakes.

[@ebenezereric-gj3zh]

Your explanation are easy to understand and reliable. Thanks so much 😊😊😊

[@squeet6831]

Damn, that question was way harder than I initially thought it would be.

[@rajesh-dh3dl]

Write 504 as (512 -8) or ( 2 power 9 - 2 power 3) or power will be double ie 18 and 6 if base will s replaced with sqrt(2). Now compare LHS with RHS Then sqrt(x) = 18 And sqrt (y) =6 Ans x = 324 and y = 36

[@manojkantsamal4945]

Sir, x=324, y=36 (hit & trail method )

[@demellomarcelo]

Parabéns mestre! Soudo Brasil! 🎉

[@VIP-vs3dc]

هل البرازيل جيدة❤

[@huseyngamerbs]

ilk

[@onlineMathsTV]

Thanks for being the first to watch and comment. You are amazing sir. Much love 💕💕💖💖😍😍

[@huseyngamerbs]

@@onlineMathsTV ♥️♥️♥️♥️

[@ykishore4340]

It's not an easy problem. But explained nicely 😊

[@danielfranca1939]

Hahahaha...😂😂😂

[@moisesdf5014]

👍

[@charlesmitchell5841]

Interesting q. The sticking point for me would have been to see how you can equate the left side to the factors of 504. You are a very good teacher. Love your videos!

[@aszasq3150]

sir, can you explain square numbers?

[@prollysine]

Two variables, many solutions are possible , let u=(V2)^(Vx/2) , u^2=(V2)^(Vx) , let v=(V2)^(Vy/2) , u^2=(V2)^(Vy) , u^2-v^2=504 , for example , 504=36*14 , (u+v)(u-v)=36*14 , let u+v=36 , let u-v=14 , u+v+u-v=36+14 , 2u=50 , u=25 , u^2=625 , 625=(V2)^(Vx) , ln625=Vx*1/2*ln2 , Vx=2*ln625/ln2 , x=(2*ln625/ln2)^2 , x=(4*ln25/ln2)^2 , v=u-14 , v=25-14 , v=11 , v^2=121 , u^2=(V2)^(Vy) , 121=(V2)^(Vy) , Vy=2*ln11/(1/2)*ln2 , Vy=4*ln11/ln2 , y=(4*ln11/ln2)^2 , test , (V2)^(4*ln25/ln2) - V2^(4*ln11/ln2) = 625-121 --> 504 , same , OK , one solution out of many possible ones , x=(4*ln25/ln2)^2 , y=(4*ln11/ln2)^2 ,

[@onlineMathsTV]

Thanks for the detailed works sir.

[@prollysine]

@@onlineMathsTV Thank you very much for your review!

[@mateushenriquecoutosilva433]

queria uma tradução dessa aula :(

[@КатяРыбакова-ш2д]

(324; 36) Верно?

[@dimitriskyriakopoulos1984]

Why are the numbers p,q integers ???

[@slimanebenlala2622]

Why you doesn't use the k value from 2^k-=63 which imply k=6 and then p=3+6=9

[@DonRedmond-jk6hj]

Why are p and q positive integers? If they aren't then ubeque factorization is not warranted.

[@onlineMathsTV]

That is the domain for this solution because we have infinite solution to p and q. Thanks a million sir.

[@user-qr7dw4hk6x]

запросто можно ответ подобрать за пару минут, а не тратить на это 17

[@lechaiku]

Very nice explnation. But why don't use the students the simplest way to solve this problem and teach them simply logical steps. If x and y are positive integers the solution is very easy. √ 2^√ x - √ 2^√ y = 504 √ 2^√ x - √ 2^√ y = 512 - 8 √ 2^√ x - √ 2^√ y = 2^9 - 2^3 √ 2^√ x - √ 2^√ y = (√ 2^2)^9 - (√ 2^2)^3 √ 2^√ x - √ 2^√ y = (√ 2)^18 - (√ 2)^6 ----> the same bases, then comparing the exponents √ 2^√x = (√ 2)^18 and √ 2^√ y = (√ 2)^6 √x = 18 --------------------------- √y = 6 x = 18^2 -------------------------- y = 6^2 x = 324 ------------------------ y = 36

[@onlineMathsTV]

This approach is well detailed and brief. Thanks for sharing the idea of conserving time in order to save the student's time and become smart at math sir. Your suggestion is noted sir. Much love ❤️❤️💕🙏🙏

[@lechaiku]

@@onlineMathsTV You're welcome.

[@lechaiku]

@@onlineMathsTV You're welcome.

[@АннаСивер-г8м]

It doesn't take that much time to solve this(solved it in my head): 1)Only if the power of root 2 is even,the number is integer(only than you can group the roots into pairs and get twoos). 2) that's a difference of 2 powers of 2,obviously-9th and 3rd(can't proof they are the only,but 1st thing to occur to me) 3)3×2th and 9×2th are powers of 2(roots of x and y).² them and you'll get the answers. Not native English speaker I am,sorry.

[@ДмитроМиколайович-ь7п]

Where is the proof that another p and q (irrational) don't suit us?

[@anatoliibatura2385]

It was a task initial condition - numbers - are integer. Irrational answers - can be infinite number of solutions of course

[@theupson]

you're right of course; excellent question and one i overlooked. i solved the problem by looking at 2^p - 2^ = 504 in binary. from the representation of 504 we can see that whatever the noninteger part of p (in base 2), it must be, shifted, duplicated in q (in base 2). that gets us that said noninteger part is repeating, making p rational.

[@samuelbenet007]

Au départ tu dis P > Q, puis plus tard P = Q, du coup, je suis perdu🙄

[@samuelbenet007]

En revoyant cette vidéo aujourd'hui, j'ai compris pourquoi : c'est écrit p = 9, le 9 anglais ressemble au q français ^^