Math: Partial Differential Eqn. - Ch.1: Introduction (21 of 42) 1st Order PDE (2 Partial Deriv.) Ex

[@ajj7794]

Ok so in 20/42 video dp=0=dx/A(x,y)+dy/B(x,y) thus should dx/A(x,y) = -dy/B(x,y) thus dx/X = dy/2y Since -(dy/-2y) Thanks for your time. i love how f(p) is litraly the constant haha thats makes everything very clear and nice.

[@daniwinckler5354]

In the previous video you had the form dx/A(x,y) + dy/B(x,y) = 0 but in this video you have dx/A(x,y) = dy/B(x,y) which means that you have changed the sign of the dy/B(x,y) term. Should it be written as the first or the second definition?

[@MichelvanBiezen]

In this video we have A(x,y) = dx and B(x,y) = dy therefore A(x,y)/dx = B(x,y)/dy

[@jason1682]

isn't it y^-1 instead of y^1 from the Equation in previous video lecture

[@curtpiazza1688]

😊

[@MichelvanBiezen]

🙂

[@PaulQuelet]

This is the exact same as the previous video. Double upload.

[@MichelvanBiezen]

These are different parts of the same problem. (thanks for bringing it to our attention)