Mathematical Representation of Signal Waveforms (Shortcut)

Signal and System: Mathematical Representation of Signal Waveforms (Shortcut)
Topics Discussed:
1. The mathematical representation of signals using the combination of ramp and step signals.
2. The mathematical representation of signals with no discontinuity.
3. The mathematical representation of signals with discontinuity.
4. Homework problem on mathematical representation of signal waveforms.
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Music:
Axol x Alex Skrindo - You [NCS Release]
#SignalAndSystemByNeso #Signal&System #MathematicalRepresentation

[@rupambanik5556]

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[@manshimuskan1636]

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[@makindeolalekanmonsuru5349]

You are saving a career, thanks so much for these wonderful classes

[@uniteUsk]

Wow I must say am so grateful for your lessons in this unit. Am taking signals and systems this semester and have found your content very much understandable much thanks. If I score an A I owe it to you Neso Academy and the entire team

[@sabiyanaikwadi641]

thank you so much neso academy...... lots of love.... I ll recommend this channel to all of my frnds definitely...

[@amvkarthik]

You are a life saver! I can't appreciate your efforts in words. Thank you sir. My ans. For the H.W problem I am getting 2 ramp( t + 2) - 4 ramp( t) - 4 ramp ( t - 2)

[@mkbgaming222]

Bro starting lo 2 mundu minus vastadhi ga (4/-2=-2)

[@Player-pj9kt]

need to add 4 ramp(t-3) as well so the signal remains at 0 when t goes to infinity

[@engineeringduniya3922]

I liked your video so much because these are really helpful for me to pass my semester examination😊😊

[@PoojaKumari-jr1jh]

best video on waveform synthesis,thanks

[@familyzone7369]

Thank You, Sir, That was great ! But I think ..... i ) 0 + 2r(t) - 2r(t-1) + 2u(t-1) ,

[@Mehraj_IITKGP]

The answer to the homework problem is: 2r(t+2)-2r(t)-4r(t-2)+4r(t-3) NESO ACADEMY IS GREAT💖

[@duchoang3635]

@sarthak gupta at t = 3 the slope tends to upward when compared with 4r(t-2), so should we add the 4r(t-3) signal?

[@JEEVANA-j6k]

@meharj bro, last term its -4r(t-3)

[@medhakumari7301]

no it's +4r(t-3)

[@Player-pj9kt]

same thing I got and I checked with desmos nice

[@Innocent3DModel-cf8pn]

5:40 horizontal lines don't have slope why do use 2??

[@venkateshsharma3180]

I finally got the correct and easiest method only from u.Tnq sir.

[@cristernicolhmanabat2798]

Thank you so much sir. Hope one day I can be as good as you :)

[@ELECTRICALENGINEERINGCONCEPTS]

thank you so much for this video. i have been waiting for this...

[@MOHD_JUNAID_19]

H.W. answer: 2r(t+2) - 2r(t) - 4r(t-2) + 4r(t-3)

[@HM42162]

Thank you so much for this wonderful explanation 🙏

[@adityajain2502]

sir please make a video of laplace transform of waveform

[@ABHISHEKKUMAR-ym5fq]

while going from 5 to -2 U just substract 5-(-2) means initial -final but in other cases U just substract final - initial

[@sibaprasad1803]

already the sign is taken negative as the signal is undergoing downward shift . if you want to follow the "final-initial" then do not take the negative sign beforehand. so either way you will get the negative sign. so do whatever you are comfortable at. good luck.

[@dani_dupae]

thank you so much, this was very eloquently explained :)

[@OMAR-jb6xt]

You saved me , thnx a lot NESOoo

[@c.ksharma6435]

2r(t+2)-2r(t)+4r(t-2)💯

[@abdelkadermoussidene9139]

2r(t+2)-2r(t)-4r(t-2)+4r(t-3) i guess

[@magjoy_6]

@@abdelkadermoussidene9139 This is the correct answer 👍

[@PoluBalaji]

@@magjoy_6 at t=3 in 4r(t-3), I guess we hve to take amplitude as 4/3 right (slope)..????but y you hve taken 4..??

[@PoluBalaji]

@@abdelkadermoussidene9139 can u explain y u hve taken 4 in 4r(t-3).???

[@magjoy_6]

@@PoluBalaji If you see the diagram clearly, at t=3 the diagram is not going down to the 4th quadrant but -4r(t-2) is representing the diagram towards down(4th quad). So, we have to change the slope to 0 at t=3 by adding +4r(t-3). Actually '+4' is the slope value. If you don't add this 4r(t-3) term at t=3 the diagram would be different.

[@myonlynick]

4:11 is it correct to say : +ve sign when turning anticlockwise, -ve sign when turning clockwise for all 360 degrees?

[@ojastewari]

the change in slope would be zero so it wouldn't matter.

[@Chauhan_Jayrajsinh]

X(t) = 2r(t+2) - 2r(t) -4/3 r(t-2) - 4/3 r(t-3)

[@kurono1822]

This channel is great

[@AxelmadQ]

as usual ,life saveur

[@roshniyadav1539]

I want to watch all vidoe from this accademy can any one tell me how can I get it .....this vidoe are superb i can't express in words...dear neso can u help me i want to study every subject full course from your channel.....i belong to ECE branch and preparing for gate pls help me ... eagerly waiting for your reply..

[@opharoon7789]

HomeWork Answer is 2r(t+2)-2r(t-0)-4r(t-2)

[@muchinamunthali8888]

Thank you for this video

[@mangeshkumar1901]

God bless you sir

[@toluwasesetemi1028]

Please which textbook are you using for signal... I really love your videos

[@mohamedfallaha3794]

its very helpful, thx very match

[@arkelamahathi3435]

I need Fourier series representation of continuous periodic signals

[@-ECE-LOHITHKUMARGURRAM]

In the 1st example also the signal is changing from 0 to 2,then why it is not discountinuity

[@arasibrahem4274]

thanks 👍👍👍

[@harshgarg3978]

THANKS

[@jayantshakya6777]

thanks sir

[@marcvenna4031]

Thank you sir for this clear and nice explanation :), I need to plot the following function: Hw(tau)=H[Cw(t-tau)-r],could you please help me to plot it?Thanks again :)

[@RahulGupta-ox7gh]

Love from J.Yan ELEC 221 section :D

[@parassharma7784]

Thanks

[@srialekhya7248]

0+2r(t+2)-2r(t-0)-4/3r(t-2)+4/3r(t-3)

[@azmeerClicks]

no need of zero at start. and after the 2 term all are having wrong amplitudes

[@johnnydevvn]

thank you!

[@srideviias3856]

2r(t+2)-r(t)-4r(t-2)

[@imsourobh]

+4r(t-3)

[@BSFMSTU-EEE]

10:45 why (5-(-2))? New level - old level is (-2-5)

[@kaustavchakraborty6400]

2r(t-2)-2r(t)-4r(t-2)-4r(t-3)

[@sagarshrestha5453]

2r(t+2) - 2r(t)-4r(t-2)

[@jeremiegibangokantin1941]

@@sagarshrestha5453 this look incomplete there's no term with r(t-3) already

[@CorporateCat]

Grade saver! God bless y'all ✌

[@tanmoytalukder5791]

Correct answer ✅✅ 2r(t+2)-2r(t)-4r(t-2)+4r(t-3)

[@muwaffaqelbadawi]

2r(t+2)-2r(t)-4\3(r-3)

[@saicharanteja8869]

Wrong

[@samuelosagie-aruya923]

Beautiful How I wish I can give you a big hug right now.

[@kollatiyuvaraju2570]

2r(t+2) -2r(t) -r(t-2) +r(t-3)

[@anonnymetoto8343]

what if thre are 3 type of signals ? ramp exp and unite step

[@benish7515]

Homework problem answer: 2r(t+2)-2r(t)-4/3r(t-2)

[@guddankaur9511]

Magnitude of 3rd term is -4 not -4/3 and also there will be one more term at t=3 bcs slope is changing there also

[@UECDishaKhattri]

super

[@ravivarma3800]

2r(t+2)-2r(t-0)-4/3(t-2)+4/3(t-3) right or wrong ???????

[@KasirajanSembodai]

At 10.13 . How do u simplify the last two terms as 2t u(t-1) pls reply as soon as possible..

[@yurifan2537]

Since it's downward, so -ve sign is used, then original level - new level, 5-(-2) =7

[@azmikhoo1367]

2r(t+2)-2r(t-1)-4/3 r(t-2) +4/3 r(t-3)

[@mrmkkryt6485]

Why does the first signal have no dicontinuity

[@kamalasiwal5516]

4r(t+2) - 4r(t) - 4r(t-2) + 4r(t-3) Sir please reply is it correct or not??

[@navdeepsingh6368]

In my opinion... 2r(t+2) - 4r(t) - 4r(t-2) + 4r(t-3).. there will be 2r(t+2) in place of 4r(t+2). reason............... for the calculation of slope, we use>>>> (4-0)/(0-{-2}) = 4/2 = 2

[@zeachter9356]

whats the answer pleaseee

[@trusted_owners]

2.r(t+2)-2.r(t)-4.r(t-2)+4.r(t-3)

[@ishitalai4877]

Why neso academy don't provide the solution of the hw problems???????????????? Website is also not showing the answers, please provide the answers.

[@kaustavchakraborty6400]

pls post the answer sjr

[@maheryagub]

2 (t + 2) u[t + 2] - 2 t u[t] - 4 (t - 2) u[t - 2] + 4 (t - 3) u[t - 3]

[@AmeerHamza-os6sk]

2r (t+2)-2r (t)-2r (t-2)-4r (t-3) is is correct or not sir please tell me

[@zeachter9356]

2r(t+2)-2r(t)-4r(t-2)-2r(t-3)??

[@Hiyori___]

the correct answer is x(t) = 2r(t+2) - 2r(t) - 4r(t-3) you can plot it on Matlab and check it is right. here's the code: t0=-2:0.01:0; x0=2*(t0+2); t1=0:0.01:2; x1=4*ones(size(t1)); t2=2:0.01:3; x2=-4*(t2-3); t=[t0 t1 t2]; X=[x0 x1 x2]; plot(t,X,'linewidth',2) xlabel('time') ylabel('amplitude') grid on

[@rksingh489]

2r(t+2) - 2r(t) - 4/3 r(t-2) *** sir right or wrong

[@imranshaikh-vy9ke]

4r(t+2) - 4r(t-0) - 4r(t-2) - r(t-3)

[@harendrakumarjatav6726]

2r(t+2)-4r(t)-4r(t-4)+4r(t-3)

[@ayeshaali6462]

if it is 3u(t)u(t-4), how to represent it?

[@Channel_Math_and_Physics]

As 3(t-4)

[@SupermanSuperb]

Tu Feku

[@mohammadtawfiq7115]

2r(t+2)-2r(t)-4r(t-2)+4(r-3)

[@dipeshverma29]

mohammad tawfiq ri8

[@HappyDestinations]

mohammad tawfiq correct

[@twinklebose9759]

*4r(t-3)

[@srialekhya7248]

Wrong

[@HemantYadav-tt2ry]

2r+(t+2)-2r(t)-4r(t-3)

[@siddharthrajesh8345]

its t-2, not t-3

[@md.saiyedchowdhury2545]

Thanks

[@anupkumaryadav1562]

2r(t+2)-2r(t)+4r(t-2)

[@satyamverma05]

Bhai please bta de wahan 4 kaise aa rha hai mera 4/3 aa rha hai

[@sayan486]

2r(t+2)-2r(t)-4r(t-2)+4r(t-3)

[@ujjawal1366]

Shi hai tera

[@keerthanajospin2874]

Last slope is decreasing so it must be - 4r(t-3) right?

[@ujjawal1366]

@@keerthanajospin2874 true its mistake.

[@ujjawal1366]

@@keerthanajospin2874 you are from which country?

[@keerthanajospin2874]

@@ujjawal1366 im an indian

[@souravgoyal5675]

2r(t+2)-2r(t)-4r(t-2)

[@suryakants7037]

2r(t+2)-2r(t)-4r(t-2)+4r(t-3)

[@pulisampath8093]

2r(t+2)-2r(t)-4r(t-2)+4r(t-3)

[@advikmaniar5783]

How is last term 4r(t-3)

[@sparshkatiyar8909]

@@advikmaniar5783 it changes to zero after t=3

[@yurifan2537]

@@sparshkatiyar8909 Hello sir, can you elaborate on that?

[@kera2403]

Wrogn

[@dakbabu]

@@yurifan2537 Without that term the signal continues in the -ve direction after crossing 0 at t=3, which isn't the case in the ques, so to terminate the signal we add the 4r(t-3) part.

[@snehanagulapati38]

2r(t+2)-2r(t)-4r(t-2)

[@alphasatari]

2r(t+2)-2r(t)-4r(t-2)+4r(t-3)

[@rajchaudhary1727]

2r(t+2)-2r(t)-2r(t-2)

[@UtubeShorts1729]

2r(t+2)-2r(t)-4r(t-2)+4r(t-3)

[@godishelping]

shouldn't it be- x(t)= 2r(t+2)-2r(t)+4r(t-2).

[@santanumandal5455]

no, because there are 4 transitions.So there must be 4 terms

[@chakrialluru5633]

Santanu Mandal BRO SLOPE MAY COME 4/3

[@PRASHANTKUMAR-wm8kk]

you are right

[@AMITKUMAR-fp1ut]

2r(t+2)-2r(t)-4r(t-2)+4r(t-3)

[@vinaypant557]

2r(t+2) - 2r(t)-4r(t-2) +4r(t-3)

[@kiyoboss2424]

* -4r(t-2) because at pont 2 singal is downword turn and down turn consider to be - ve and slope is 4 = 4-0/(3-2) , and the pont of turning is 2 so we take r(t-2) and not r(t-3)

[@ujjawal1366]

2r(t+2)-2r(t)-4r(t-2)+4r(t-3)

[@kiranojha9409]

Please explain

[@JEEVANA-j6k]

2r(t+2)-2t-4r(t-2)-4(t-3)

[@Sumitkumar-el8gs]

2r(t+2)-2r(t)-2r(t-2)+2r(t-3)

[@devansh_0012]

2r(t+2) - 4r(t) - 4r(t-2) + 4r(t-3)