The most memorable part was when you giggle, and my wife in the other room says "You're watching that math guy again?" As always, thank you for expanding my knowledge base.
@piratesofphysics41004 жыл бұрын
😂😂😂
@douglasstrother65844 жыл бұрын
When she hears all of the profanity, she knows you're watching Flammable Maths!
@christiaanbalke4 жыл бұрын
Same over here :)
@teleny24 жыл бұрын
His giggling always sounds like Dr. Strangelove to me. Man, Peter Sellers was a great actor.
@douglasstrother65844 жыл бұрын
@@teleny2 Gen. Turgidson: "'Strangelove'? That ain't no kraut name." Aide: "His original name was 'Merkwürdigliebe'. He changed when he became a citizen." Gen. Turgidson: "Huh. Strange."
@shivambiswas57904 жыл бұрын
Any divergent series: *exists* Ramanujan: Allow me to make it convergent.
@456MrPeople4 жыл бұрын
Ramanujan summation is powerful but it is also very picky. For example if I add 1+2+3+4+... and 0+1+2+3+4+... under Ramanujan summation they would have completely different values! Even if I add the numbers in a different order they would have different values. A small price to pay given the ability to sum divergent series.
@przemysawkwiatkowski26744 жыл бұрын
@@456MrPeople It's not so strange that order of summation changes the sum... It might happen even for convergent series. :-) Well... Actually it *does* happen for convergent series, except the absolutely convergent ones. :-)
@Noname-674 жыл бұрын
@@456MrPeople that's the normal problem of infinity
@sharpfang4 жыл бұрын
...to something that is not even close to where the series goes.
@EdoTimmermans4 жыл бұрын
It would like to see how TREE(1)+TREE(2)+TREE(3)+... can be made convergent. 😉
@bernyelpro19064 жыл бұрын
Most memorable part: me losing my life after failing the “no nines sum converges”
@christianorlandosilvaforer34513 жыл бұрын
sure.. x2
@Torthrodhel3 жыл бұрын
I didn't lose my life at that part! I gamed the system, by already losing it way earlier on in the video! lmao
@ireneonajarila41383 жыл бұрын
@@Torthrodhel t
@sergiomv852 жыл бұрын
I lost my life too!
@PC_Simo4 ай бұрын
If you had collected 1000 Coins (or more), in Japan; then, it’s no problem. 🙂
@Fun_maths4 жыл бұрын
"Are we there yet?" "No just 1+1/2+1/3+1/4+... more minutes."
@Mathologer4 жыл бұрын
:)
@johnchessant30124 жыл бұрын
In a similar vein, a mathematician advertises a lottery in which the prize is an infinite amount of money. Lots of people pay for tickets, but when the winning ticket is announced, the mathematician explains the mode of payment: "$1 this week, $1/2 next week, $1/3 the week after, ..."
@MGSchmahl4 жыл бұрын
@@johnchessant3012 Given the common assumptions about compound interest and the time value of money, this prize can actually be funded with a finite amount of money. (The assumption is that $1 today is worth $e^(rt) at time t for some constant r.) A neat puzzle is to figure out how many "now dollars" that prize is worth. (Hint 1: If the prize was $1 every week, and assuming a realistically small interest rate like 1/52% per week, you would only need about $5200.50 to fund the prize.) (Hint 2: I don't know how to solve this by hand. I cheated and used WolframAlpha.) (Hint 3: It's surprisingly small! Less than $10.)
@Fun_maths4 жыл бұрын
i just realized that that means that they are pretty close to their destenation, about half a minute away
@Jooolse4 жыл бұрын
@@MGSchmahl In today's world, 1% is actually a high interest in USD: the Fed Funds effective rate is only 0.08% (annually).
@jzieba02044 жыл бұрын
The most suprising part for me was the "terrible aim" the fact that odd/even is never an integer is so simple yet i would have never thought about it
@PC_Simo Жыл бұрын
Yes. Simple, indeed: In order for a fraction to be an integer, the prime factors of the denominator must form a subset of the prime factors of the numerator; but, in odd/even, the denominator always has the prime factor: 2, which the numerator never does, in odd/even; thus, P(denominator)* is never a subset of P(numerator); and thus, odd/even can never be an integer, in disguise 😌. *P = Prime factors.
@whatby1014 жыл бұрын
Undergraduate mathematician here. The better I get at math, the more I appreciate your videos. These videos give a great visual experience which is generally not taught in proof courses. My favorite chapter was probably Chapter 5, reminded me of some of the concepts discussed in my analysis course.
@n0nam3given4 жыл бұрын
As an adult who barely survived "New Math" back in the 60s, I grew to *hate* math with a purple passion, though I loved it with an equal passion. I gave up, finally, in high school at algebra 1, with the only "C" I've ever received in all my school years. I guess they were trying to tell me that math is not my shtick. Today, that hatred has melted away and my love and curiosity shine again. I never miss any of your videos. I love your humor and your enthusiasm!! The most memorable part? The searching for and recognition of patterns. That is so delicious!
@Mathologer4 жыл бұрын
That's great, your comment made my day :)
@dennisbell96394 жыл бұрын
My wife viewed this lecture,I made her,and just called you the biggest nerd on the planet.But that is good for she has been calling me the biggest one for 37 years I gladly pass the title over to you.I thoroughly enjoyed it and love your enthusiasm.I'm self-studying figurate numbers and would enjoy any lectures on this subject matter.Thank you
@ИмяФамилия-е7р6и2 күн бұрын
her iq level imagine?
@apbmes76904 жыл бұрын
Most memorable part: In university Mathologer apparently came up with an original finiteness proof for Kempner's series, and the grader failed the homework because they couldn't be bothered to check a solution that was different from the one on the answer sheet.
@IoEstasCedonta3 жыл бұрын
We've all had those graders.
@snowstarsparkle3 жыл бұрын
[i
@stopthephilosophicalzombie90173 жыл бұрын
I had a similar experience in topology in undergrad. I did an unconventional proof and even my professor didn't understand it but he found another professor who said it was correct.
@jetzeschaafsma12113 жыл бұрын
How often do you imagine an answer different from the answer sheet is actually correct?
@Meta73 жыл бұрын
@@jetzeschaafsma1211 In math, more often than you think.
@Meepmows4 жыл бұрын
The most memorable part for me might be the idea of that gamma value: especially the super quick visual proof that it had to be less than one by sliding over all the blue regions to the left
@chessnotchekrs4 жыл бұрын
Yeah that was really mind-blowing. Also, to answer Mathologer's question, Gamma is more than half because each time we slide over the blue part, there is a corresponding white part, but the blue part has a "belly", or it bulges into the white part, so they're not equally divided triangles. There are infinitely many blue-half/white-half pairs, and in each the blue part has a "belly" so adding the area of all the blue "halfs" should yield a sum slightly more than half. This is just a visual approximation though, I don't know how to prove how much more than half it is.
@atimholt4 жыл бұрын
@@chessnotchekrs Yeah, that was a fun one to just suddenly get (though, like he said, it was “obvious”).
@johnchessant30124 жыл бұрын
24:30 It's "obvious" because 1/x is concave, meaning between any two points the graph is below the secant line connecting those two points. Dividing the 1x1 square into rectangles in the obvious way, the blue areas include more than half of each rectangle and hence more than half of the 1x1 square.
@Mathologer4 жыл бұрын
Exactly :)
@MonsieurBiga4 жыл бұрын
Finally something I had seen myself with my very low level of maths
@anthonycousins8534 жыл бұрын
That makes sense! Good explanation, I got it without any visuals! Haha.
@jisyang87814 жыл бұрын
You mean convex. You triggered one of my pet peeves.
@moritzalshuth72394 жыл бұрын
The secant lines partition blue triangles as a lower bound for gamma, triangles add up as a telescoping sum 1/2*((1/1-1/2)+(1/2-1/3)+...-1/n) = 1/2*(1-1/n) = 1/2 in the limit
@sergeboisse4 жыл бұрын
Mathologer video series are definitely better than any Netflix series. They surprise me anytime.
@Achrononmaster2 жыл бұрын
With a small amount of effort one could probably get Mathologer onto Netflix. It's just filling in forms and checking video quality and whatnot.
@BritishBeachcomber2 жыл бұрын
Netflix? No comparison. Mathologer wins every time, and it's free.
@manelmanolo71952 жыл бұрын
Mathflix. The best series (Taylor, MacLaurin, armonic, ...) (Seen in his t-shirt)
@TravisTellsTruths2 жыл бұрын
Exactly true 👍
@jean-francoistremblay77444 жыл бұрын
Clearly, the highlight of the Euler-Mascheroni constant is a splendid part of the video...the sum of no 9's animation is very impressive.
@zacharystark55204 жыл бұрын
Most memorable: that the harmonic series narrowly misses all integers by ever shrinking margins
@TheM0JEC4 жыл бұрын
I agree that an infinite number of non intergers is quite amazing.
@MasterHigure4 жыл бұрын
I mean, any diverging series with ever smaller terms will have ever shrinking margins (as long as it doesn't actually hit any integers).
@landsgevaer4 жыл бұрын
@@MasterHigure I don't think so. For example, consider the sequence x_0 = 9/4 and for all n > 0: x_n = 1+(1/3)^n; form a series by summing these terms. The terms are ever decreasing, the series is divergent, and never hits any integers. Yet the partial sums never come closer than 1/4 to any integer, which it hits at the very first element a_0 alone.
@MasterHigure4 жыл бұрын
@@landsgevaer You're right. The terms need to converge to 0. I done goofed.
@parkershaw85294 жыл бұрын
It also managed to miss infinitely more and infinitely denser all irrational numbers as well. THAT seems even more impressive!
@dragifire4 жыл бұрын
Your teaching style is just so good! I think it's a combination of the interesting topics, your smooth as heck animations, giggles, and the quick glances you give at the end of each chapter to summarize (it's especially nice for note-taking!). Not even to mention the fact that you don't give direct answers to questions you bring up, but instead direct the viewer to introductory terms and topics to look up and gain knowledge themselves. I wish I could attend one of your lectures, but until then this will have to do!
@dEntz884 жыл бұрын
The most memorable proof is the original proof of the harmonic series' divergence simply for the fact that this probably the only proof I could present to my year 10 math class and most of them would understand it.
@Mathologer4 жыл бұрын
Would be interesting what your kids would make of the animation of this proof :)
@dEntz884 жыл бұрын
@@Mathologer Maybe I'll use it in my "Mathe AG". :)
@morodochable4 жыл бұрын
The fact that the number of fractions summing to one in that doubled every time hinted at the logarithmic relationship, although I was thinking log base 2.
@peter_p_r_zhang4 жыл бұрын
Most memorable part: derivation of γ. As in high school we learn about the approximation of the area under the 1/x curve but not many actually focus on the 'negligible part of the area' which in fact adds up to something trivial to the whole field of number series. 24:23 Sinple proof for γ>0.5: All the tiny little bits of that blue areas are a curved shape. By connecting the two ends of that curve line we can see each part is made up of a triangle and a curved shape. The total area of those infinitely many triangles equals to 0.5 so the total area of the blue sharpest be greater than 0.5.
@Mathologer4 жыл бұрын
That's it:)
@youssefm12 жыл бұрын
Why is the total area of those triangles 0.5?
@Ohhelmno2 жыл бұрын
@@youssefm1 it’s basically because the largest non-integer in the series is 1/2 and every subsequent one is half again, so the first few get you very close .5 and every one after that is less and less and therefor as the sum gets closer to infinity the area above the curve gets closer to .5 but never over. This is mainly because there are an even more infinite set of fractions between 1/2 and 1/∞ than integers between 1 and ∞
@youssefm12 жыл бұрын
@@Ohhelmno , thanks. My son made me realise that the sum of the vertical lines (heights) of all the triangles = 1 so the areas of the triangles (being half the area of the rectangle of that height) = 0.5 and since the blue part was larger than the triangle, its area > 0.5.
@williamrutiser14852 жыл бұрын
Don
@valeriobertoncello18094 жыл бұрын
24:40 the sum of all the triangles that lower-approximate the blue areas is: 1/2*(1*(1 - 1/2) + 1*(1/2 - 1/3 )+ 1*(1/3 -... = = 1/2*(1 - 1/2 + 1/2 - 1/3 + 1/3 -... = 1/2*(1)= 1/2
@vik24oct19914 жыл бұрын
you have to also prove that the left over portion is greater than area of triangle.
@sadkritx62003 жыл бұрын
@@vik24oct1991 yes, that's why he said lower approximate. The left over portions are convex. So thinking of them as triangles, there's some area left. That's why the total area is greater than 1/2.
@vik24oct19913 жыл бұрын
@@sadkritx6200 That was my point , you don't need to calculate the sum of the area , if you prove that in each part the curves are convex then that implies that at the sum of the leftover is greater than half, no matter how the parts are divided.
@justsomeguy56284 жыл бұрын
The weirdest thing you showed is definitely the unusual optimal brick stacking pattern.
@maze74744 жыл бұрын
Why is that optimal stack optimal? Those 3 bricks on the top right look like you could extend them more to the left and thereby push the whole center of gravity to the left and thereby the tower to the right
@ramenandvitamins4 жыл бұрын
@@maze7474 moving a few bricks would necessarily shift the entire stack's center of gravity by a smaller distance. Since the blocks you're proposing to shift include the rightmost one, you'd lose more overhang than you'd gain.
@maze74744 жыл бұрын
@@ramenandvitamins sorry, typo from my side.I meant top left, those 3 that are stacked exactly over each other
@ramenandvitamins4 жыл бұрын
@@maze7474 I suspect they'd no longer suffice to hold down the second-rightmost block if they were moved any further left.
@noobita49834 жыл бұрын
@@maze7474 those 3 blocks have centre of mass at the middle of them which is at the edge of the block on which they are sitting, so if you try to shift left they will fall.
@mitchkovacs13964 жыл бұрын
24:35 You can construct a right triangles out of the corners of each blue region. The base of each is 1 unit while the height is 1/n - 1/(n+1). The sum of the areas of these triangles yields a lower bound for γ. We can see that this area is (1/2)*(1 - 1/2) + (1/2)*(1/2 - 1/3) + (1/2)*(1/3 - 1/4) + ... which is a telescoping series so we can cancel everything except 1/2*1, so 1/2 is a lower bound for γ
@Mathologer4 жыл бұрын
That's it. Of course, you can also just skip the algebra :) Having said that it's nice in itself that all this corresponds to a telescoping sum when you turn it into algebra.
@danield13034 жыл бұрын
For me, the "no integers" part was the most memorable, but honestly the whole video was of great quality (as expected).
@davidgustavsson40004 жыл бұрын
I liked your evil mathematician back story, with the teacher refusing to grade the "wrong" proof.
@amadeus19404 жыл бұрын
I didn't like it. Second hand annoyance. grrr
@ummerfarooq53834 жыл бұрын
When you get to that age when you want your students to tell you a bedtime story of the old days via math proofs. It would be gracious of us to do so just like when we were little kids asking mommy for a bed time story. Hmm are tests care work? 👋🕊️
@moroccangeographer89934 жыл бұрын
I relate to that experience.
@rexwhitehead83464 жыл бұрын
Peter Ustinov relates that his teacher gave him zero marks when he answered "Rimsky-Korsakov" to the question "Name one Russian composer." The correct answer was Tchaikovsky.
@thek3nger4 жыл бұрын
I liked A LOT that the sum of the “exactly 100 zeros series” is greater than the “no 9s series”! It is almost unbelievable. I need to check the paper. 🤣
@imacds4 жыл бұрын
It is intuitively plausible as the 100 zeros series includes "a lot" of terms with 9s that the no 9s series leaves out.
@jackw77144 жыл бұрын
@@imacds I can't say that's intuitive to me 😂
@stephenmcateer4 жыл бұрын
First thought: Isn't the "exactly 100 zeros" series a subseries of the "no 9s" series? Second thought: No, what about the term 1/9e100? Third thought: So ... when you are dealing with *all* integers you thin out more by banning 9s than by *only* requiring 100 zeros. Mind blown. Fourth thought: Take a random billion-digit number. It will almost always have more than 100 zeros (you expect about 10 million of them, just 99 is very rare). So it's almost not a constraint at all. Although apparently enough to force convergence. On the other hand, almost no billion-digit numbers will have no nines (the probably is something like (9/10)^1e9 ~= 0 of randomly grabbing one). And almost all integers are bigger than just a billion digits. Mind now thoroughly blown.
@NoNameAtAll24 жыл бұрын
how was the paper?
@gregburnell84544 жыл бұрын
This blew my mind!
@rohitjoshi29534 жыл бұрын
Most Memorable : Every seconds of this video. I couldn't choose a single thing. I am sure that this is the best video I have ever watched in my life related to anything. Thank you so much Mathologer.
@lc72694 жыл бұрын
The most memorable was the optimal towers, as I always thought that the leaning tower of lire was the best way to stack overhangs. It looked so perfect that I never questioned if there was a better way to do it!
@lorenzmatz88704 жыл бұрын
In my opinion Kempner's proof at the end was the most fun since it's one of those proofs where one (or at least I) would have no idea where to even start, but once you see it, one suddenly realizes how obvious it is ;). Thanks for the very interesting lecture :)
@gromburt4 жыл бұрын
Wonderful video as always. The more videos I watch the more I'm convinced that Euler must've been a time-travelling Mathologer viewer who really wanted to look smart by appearing in every video
@alexgreer8784 жыл бұрын
Most memorable: If my life depended on knowing if the sum of no nines series is finite I would not be alive
@GopikrishnaC-nj3sy4 жыл бұрын
24:30 (γ>1/2 :) It is equal to proving that the blue region is strictly greater than white region in that 1square unit box... since 1/x is concave up in (0,oo).. (Means a line formed by joining any two points on the curve (chord) will lie above the curve in that region) In those each small rectangles inside the 1unit box , the curve of each blue region (which is part of 1/x graph) will lie below the chord (here diagonol of that rectangle) As blue area crosses diagonals of each of these small rectangles (whose area is actually 1/(n) -1/(n+1) ) , it is greater than half the area of these rectangle... And adding up all thsoe rectangle gives area 1...and adding up all these small blue region is our "γ" So it is greater than half the area of 1. ie: γ>1/2. -----------------------------------------------
@supercell66914 жыл бұрын
Thanks
@randombanana6402 жыл бұрын
basically their area is greater than their triangle counterparts and the triangle area is ½
@conoroneill80674 жыл бұрын
The variations on the Harmonic series were definitely my favourite - who even thought to ask such a strange question as "What's the Harmonic Series, but if you remove all the terms with a nine in them?" It would never have occurred to me to ask a question like that.
@TheGrenvil4 жыл бұрын
It's like the "Bee movie, but without bees" type of memes, I guess it's just the human nature
@gaelservignat28104 жыл бұрын
The most memorable part was Tristan's fractal. Fractals are beautiful and they always show up when you expect them the least.
@davutkavranoglu69594 жыл бұрын
Thank you very much for another excellent demonstration of the amazing beauty of mathematics! I love the 700 years old divergence proof. Also, the unbelievably slow pace of divergence is absolutely amazing.
@karateoscar4 жыл бұрын
Most memorable: The harmonic series misses all integers up to infinity
@Jack_Callcott_AU4 жыл бұрын
That got me too.
@thatssomethingthathappened98233 жыл бұрын
Yeah it must be ∞.438882647883976917983791870000364553678223... or something.
@PC_Simo8 ай бұрын
That’s my favourite / most memorable part, too; because I managed to prove it, for myself, and find the pattern, for the nth partial sum: Σ(n) = (a(n-1)*n+(n-1)!)/n!, where a(n-1) = the numerator of the (n-1)th partial sum. 🙂
@mattbox874 жыл бұрын
Most memorable: being invited to take a moment and post why it might be obvious that gamma is greater than 0.5 and then doing it. Hmm... why is it obvious that gamma is greater than 0.5? Well it didn't seem obvious... But imagine the blue bits were triangular; then there would be equal parts blue and white in the unit square on the left i.e. a gamma of 0.5. But the blue parts are convex, they each take up more than half of their rectangles and together take up more than half of the square.
@ffggddss3 жыл бұрын
Exactly how I pictured it! It also makes it obvious that γ is much closer to ½ than it is to 1. Fred
@PC_Simo8 ай бұрын
My thoughts, exactly 🎯! Articulated better, than I could have put it 😌👍🏻.
@tammylynn86324 жыл бұрын
The most memorable is your voice... the giggle you make when telling us wonderful facts. Have a wonderful life. Stay safe... ✌️
@pleinairr4 жыл бұрын
Most memorable moment was the cat going "μ".
@teleny24 жыл бұрын
Has a cat the hacker-nature? "Mew...."
@PC_Simo8 ай бұрын
As a cat-purrson, I approve 😻😌👍🏻.
@akaisekai1434 жыл бұрын
Most Memorable: getting the Mathologer seal of approval
@takeguess2 жыл бұрын
I have to say you are one of my favorite KZbinrs! And that is saying something.... Most youtubers shy away from the math, but not you. Your visual proofs are brilliant and will span through the ages, I thank you because I have genuinely been looking for this content for years. Out of the bottom of my heart thank you, I needed this...
@techdecker514 жыл бұрын
The most memorable for me has to be Kempner's proof, just due to how counterintuitive it is after seeing so many divergent series, but how intuitive the proof is.
@HyperFocusMarshmallow3 жыл бұрын
You’re so good at starting simple and yet including stuff that’s interesting for the fully initiated! Great work!
@CatOnFire4 жыл бұрын
The most memorable part for me was seeing the 700 year old proof.I I didn't pay much attention to math in school, despite the fact that I learned it easily. Math class was always boring to me because once I learned and understood an how an equation worked, I had no interest in running the same equation again with different numbers dozens of times for homework. My teachers never made the subject as interesting and engaging as the many resources I have found since graduation. But now that I have finally found an interest in the topic, I realize that I am woefully undereducated on anything past basic high school algebra. This is the reason why I liked seeing the simple proof. It was so easy that I could have done it myself with my current skills! That gives me hope that, while I may have MUCH to learn, there are still intricate problems that even I can grasp. Thank you for another great video, and have a nice day!
@pummelfee90934 жыл бұрын
Wow, ich hätte nie geglaubt, dass etwas das mit Analysis zu tun hat auch Spaß machen kann... :) Sehr cool!
@anon65144 жыл бұрын
They should have called it the 'Barely Divergent Series'
@takyc78834 жыл бұрын
is t the slowest diverging series?
@yazeed0ps34 жыл бұрын
@@takyc7883 I remember that there is no such thing as a slowest diverging series. for example 1/n diverges, 1/(n*ln(n)) diverges, 1/(n*ln(n)*ln(ln(n))) diverges, and so on. As always, there's a math stack exchange thread talking about this topic: math.stackexchange.com/questions/452053/is-there-a-slowest-rate-of-divergence-of-a-series
@tracyh57514 жыл бұрын
@@takyc7883 No. Using the ideas from chapter 6, you can actually show there is a subseries of the harmonic series that diverges as slowly as you would like. Simply take a function f(x) that diverges at a rate slower than the natural logarithm. At each integer, we will choose an entry from the harmonic series which is smaller than the one we had chosen previously. First, choose the largest entry of the harmonic series that is smaller than f(1). If this is not possible, choose the smallest entry of the harmonic series with is larger. Next, choose the largest entry possible so that the partial sum so far (just the first term and this one) is less than f(2). Again, if this is not possible, choose the smallest entry possible so that the partial sum is larger than f(2). Continue in this way and you will make a series whose rate of divergence is the same as f(x).
@neilaryaofficial Жыл бұрын
Love your work, thank you for sharing so much knowledge & quality content. Generally KZbinrs run for views, nothing more than that. You never click baits or anything that ever had made me regret clicking. You are just awesome.
@bagochips12084 жыл бұрын
Most memorable part: all I’m just constantly being mind blown throughout the whole video
@sadkritx62003 жыл бұрын
Same bro. The whole video was magnificent 👌
@Yupppi2 жыл бұрын
It's odd that while the terms get smaller and smaller, the sum doesn't converge. You look at every book in the tower being less and less over the edge and think "there must be a point where the top book moves so little that it's impossible to notice no matter how many books you pile, and the new books barely go over the edge for even microns" and at the same time think that it will always go further as far as you want it to go.
@PC_Simo3 ай бұрын
33:12 Also; because the sum of the even reciprocals is exactly 1/2 of the harmonic series, while its complement, the sum of the odd reciprocals is more, than 1/2 of the harmonic series; if these series all added to finite numbers, that would be a contradiction: n+m = 2n, where m > n.
@cheyennesadeghi4 жыл бұрын
My favorite part was when you revealed that the sum of the 100 zeroes series is greater than the sum of the no 9 series. Absolutely mind-blowing. In truth, my favorite part was the entire video you just made me pick :) Thank you!!!
@randyhavard60843 жыл бұрын
My new favorite maths channel
@jeewanjotsingh30883 жыл бұрын
This was probably one of the best video that I have seen on this topic. And the geometric limit of Gamma between 1/2 and 1 and the no-nine series proof was something I learnt for the first time.
@_kapy_4 жыл бұрын
The most memorable thing is how ugly the optimal leaning tower is
@Sn0wjunk1e4 жыл бұрын
you mean beautiful
@EdoTimmermans4 жыл бұрын
Some people say warthogs are ugly. To me they are stunningly beautiful, with their faces resembling the Mandelbrot fractal.
@tim40gabby254 жыл бұрын
If extended hugely, I guess that patterns of absent blocks will create pleasing curves.. I recall doing this with kids bored of 'Jehinga'. old uk duffer here :)
@naimulhaq96263 жыл бұрын
It was the most beautiful leaning tower.
@ammaleslie5093 жыл бұрын
i thought it was beautiful also. Glad I'm not alone. Modern concepts of "beauty" are overfocused on symmetry. Observe more natural structures to appreciate the beauty in the "misshapen" and the perfection in the "imperfect"
@michaellucas71774 жыл бұрын
Marble: Most memorable Idea: No integers among the partial sums. Your excitement is always a great feature not your presentations. And why you're my favorite Mathematics KZbinr!
@johncanfield11773 жыл бұрын
Dear Mathologer, I am so pleased whenever I run across one of your videos. As for my vote for the portion that impressed me the most, it would have to be the leaning tower of Lire. There is something so lovely in its orderliness, that I sense my head bowing, much like the old Frenchman, Oresme. Thank you for another interesting and entertaining video on the beauties of math.
@shaunsawyer82984 жыл бұрын
So much great content packed into 45 minutes! Something I’ll always remember will be that the no nines series converges, and how simple the proof was!
@aegirson28994 жыл бұрын
Most memorable: The most efficient overhanging structure being the weird configuration instead of an apparently more ordered one.
@naimulhaq96263 жыл бұрын
Most memorable: An overhanging structure with n=google bricks.
@Diadochokinetic4 жыл бұрын
Great stuff. It's always amazing how you manage to find such intuitive explanations. Most memorable is probably the "no 9s" visualization.
@pedrobress10724 жыл бұрын
My vote definetely goes to Kempner's proof, it is extremely elegant, since the concepts used are individualy simple, such as the calculation of numbers without nine or geometric series, but when cleverly combined they form this amazing result. Besides that, great video as always. Edit: typo
@cauankazama44314 жыл бұрын
I agree with you!
4 жыл бұрын
The most impressive part in my opinion was the fact that the 100 zeros sequence converges to a bigger sum than the no 9s sequence. Greetings from Germany by the way and keep up that great work. It is always a pleasure diving into your mathematical discoveries!
@I_like_math4 жыл бұрын
Most memorable part: the 100 zeros sum being larger than the no nines sum.
@PapaFlammy694 жыл бұрын
Good Stuff Burkard! :)
@noone76924 жыл бұрын
POLSTER! :)
@Daniel-ws9qu4 жыл бұрын
QWERTZ
@max-yasgur4 жыл бұрын
Yay Oily Macaroni!
@dariocardajoli68314 жыл бұрын
Omg the pufferfish meme hits differently now god bless, Papa
@toniokettner48214 жыл бұрын
@@Daniel-ws9qu Qwert Zuiopü, der Gallertprinz aus der 2364. Dimension
@ryandvyn4 жыл бұрын
Most memorable: every positive number having its own infinite sum. It’s very obvious afterwards, but I would never believe it without your explanation. Thank you for all the interesting videos!
@AndrewMooreMar4 жыл бұрын
The e^gamma equation really blew my mind. Good stuff!
@maxinator20024 жыл бұрын
Most memorable: the optimized leaning tower! Although it was very messy, I think there's a lot of beauty in the fact that the most optimal arrangement of bricks is such a mess. It reminds me of how an extremely simple physical system (like a double pendulum) can result in chaos!
@oliverave12343 жыл бұрын
Good point. The problem with I have that solution is perhaps that the original concept stipulated or assumed that the tower would lean only in one direction (which is what towers do). The recent innovative solution doesn't involve a "tower" at all. This is the problem with the "thinking outside the box" cliche. I tell you to connect the dots within a box using 2 lines and then you connect them by drawing lines outside the box. Wow, that's impressive. It's like telling your boss you can solve a problem by spending 10X the given budget.
@neomew4 жыл бұрын
Math: '*exists* Euler: "First!"
@ashtonsmith17304 жыл бұрын
so how did math work before euler?
@neomew4 жыл бұрын
@@ashtonsmith1730 The same way it always did - just in a dark room. Euler just turned on the lights to a lot of rooms.
@raphaelreichmannrolim254 жыл бұрын
When you're investigating maths, if you inspect close, there are really small notes all over the place. "Euler has been here"!
@andrewxc13354 жыл бұрын
@@ashtonsmith1730 Lots of wordy descriptions and cobbled-together notations from dozens of different people.
@davidrheault78964 жыл бұрын
@@neomew you'll never kill the real Dumbledore hehe
@ivansmitt21954 жыл бұрын
as for me its such a charm to see the Mathologer seal of approval, I really dont know, but it really made my day!! thanks for the great video!
@christosgolsouzidis12864 жыл бұрын
The most memorable part is the connection of the 'γ' and the log() function to the harmonic series! Really amazing!!
@PeterFreese4 жыл бұрын
Most memorable: the fact that gamma is the Ramanujan summation of the harmonic series.
@typo6914 жыл бұрын
No way
@AlfredJacobMohan4 жыл бұрын
You beat me to it.
@reinholdkemper34113 жыл бұрын
Mathloger THE VERY BEST MATH AND LOGIC TEACHER ON THE PLANET. I missed him already when I was a school boy without knowing him. I enjoy every clip and its so well presented and easy to understand. He*'s a NATURAL AND A PRO... go on bro
@leastsignificantbit50694 жыл бұрын
Definitely the most impressive part is the animated Kempner's proof, I've expected something extremely complicated and yet the whole thing was "nice and smooth".
@royalninja28234 жыл бұрын
A bit late on the lower bound for gamma, but... You can take every blue piece, place it into a rectangle of dimensions 1 x 1/(2^n), and split that rectangle in half with a diagonal from the top left to the bottom right. If you were to take the upper triangle from every one of these divided rectangles, you would get an area of one half of the square. Because every piece has a convex curve, it will stick slightly outside of the upper half of its rectangle. This means that every piece has an area greater than half of the rectangle, and the sum of all the pieces is greater than one half of the square. Because the square is 1x1, the area of the blue pieces is greater than 1/2.
@Mathologer4 жыл бұрын
That's it. Never too late to have a great AHA moment :)
@peteneville6983 жыл бұрын
@@Mathologer - Is it true to say that in the "No 'n's" series where we intuit that the sum converges, the sum of all the removed terms containing 'n' must itself be infinite? You have a series summing to infinity minus another series. If the thing you subtract is itself finite then you would still have an infinite series left over, ergo the subtracted series must itself sum to infinity for the remaining series to converge. Not sure if that's simply obvious or if it's also an "AHA" moment.
@PC_Simo8 ай бұрын
That is very much true 🎯👍🏻.
@RichardQuadling3 жыл бұрын
I wish I knew more. But the more I watch and try to learn, the more time I've used up getting nowhere. The dedication the geniuses have to mathematics and physics is astounding. And it is not done for reward other than the pursuit of knowledge. And that is as beautiful as the proofs the geniuses present. Thank you for the videos.
@alejandronasifsalum82014 жыл бұрын
I was already... not comfortable, but let's say "resigned"... to the fact that there exist very slowly divergent series; but the fact that there are very slowly CONVERGENT series, whose sum is impossible to approximate computationally within a reasonable margin of error, like the no nines series... was a shock!
@SzanyiAtti4 жыл бұрын
Exactly what I needed today EDIT: My favourite part was the no 9-s proof. It is just simply elegant.
@grahamking91213 жыл бұрын
Fantastic! The overhang problem is fun. The 'no 9s' result was a shock but the visual fractal illustration is very pleasing. Thank you!
@SeanBask4 жыл бұрын
Most memorable part: the visualization of the "no nines sum convergence" What an awesome way to look at it.
@MohammedAbdullah-mx1vg4 жыл бұрын
I have to vote for the Kempner's proof animation, it was simply stunning to see such a seemingly complex problem; being broken down into techniques that a school student could understand 👏
@doctortrouserpants13873 жыл бұрын
Thanks for another amazing, informative, extremely clear and well made presentation. The fact that the series explodes to infinity is one thing, how slow it happens and how many terms are needed for just a tiny increase makes my head spin.
@harrypotter54604 жыл бұрын
Proof that γ>1/2 (24:30): Replace all the blue parts with right triangles inside of them and the resulting sum is 1/2 (visually this is obvious, writing out the sum isn’t too bad either).
@davidrheault78964 жыл бұрын
I found it too, but I watched the video 2 days later than you, ahh sigh
@harrypotter54604 жыл бұрын
@@davidrheault7896 Good job!
@AdityaSharma-qi8nu4 жыл бұрын
Most Memorable: The fact that it is possible to *arrange* the bricks on the table such that the last brick can be as far as the size of *observable universe* from the table, and yet be perfectly balanced!!!🤯🤯🤯
@channalbert4 жыл бұрын
Pretty amazing, but don’t get the table from IKEA, they are bad quality.
@AdityaSharma-qi8nu4 жыл бұрын
Lol
@Fun_maths4 жыл бұрын
@@channalbert they mess with the physics of balance
@Noname-674 жыл бұрын
Imagine making a mistake and it all fall down
@eefaaf4 жыл бұрын
Wouldn't that mean that you would need a stack higher than the universe? Even if each layer was just one atom thick.
@bronkolie3 жыл бұрын
If you look this problem up in KZbin everyone says the leaning tower of Lire is the optimal solution. Very nice job finding this
@ברנאור-מ7כ4 жыл бұрын
I really enjoyed it. I guessed no 9s has finite sum by thinking about binary numbers with no 0s. that's 1/1 + 1/11 + 1/111 + 1/1111 + .... < 1 + 1/10 + 1/100 + 1/1000 + ... = 10 (=2). I most enjoyed the Leaning Tower of Liire, because they didn't teach it in my calculus course and it's simple and beautiful. Thank you Bar
@nicolascalandruccio4 жыл бұрын
I thought the same kind of thing. What happens with the values if we change the basis. Is it possible to find an expression to link the values?
@Richardstureborg4 жыл бұрын
solution to there bricks with overhang of 2 units: place one brick with overhang of 1. then place another bring on top of this one all the way to the right with its own overhang of 1 unit. clearly this will fall. now place the third brick to the left of the second, making the top layer 4 units (2 bricks) long, and the bottom layer centered around it. Done.
@canaDavid14 жыл бұрын
Summary: Cliff edge is x=0. Bricks are measured at the middle. Layer 0: a brick at x=0 Layer 1: two bricks, at -1 and 1
@l3p34 жыл бұрын
Idea: Put the left upper coin before the overhanging one. It will not fall.
@mujtabaalam59073 жыл бұрын
11:55, simple: brick one on the edge, bricks two and three on either edge of brick one. 14:48 LOL, I love the editing style! This plus the proof is enough to make chapter 3 my favorite. 24:44 all the curves are "bulging", which is to say that they have a positive second derivative, so they take up more area than a series of triangles with the same start and end points
@milan02344 жыл бұрын
Most memorable: The proof that the bishop came up with, beautiful simplicity
@elasiduo1084 жыл бұрын
This is the reason why I'm getting a PHD in mathematics: the infinite beauty of the numbers.
@JackSchytte4 жыл бұрын
Dear Mathologer, I remember doing that overhanging bricks thing for hours in the science museum in London when I was little! About 35 years ago... It looked exactly like your solution with counterweights and bridging bricks, and it set the record! I was there so long that my parents had to put a tannoy announcement out for me! Only thing is, that since bricks are three dimensional, as opposed to your two-dimensional diagram, I had turned the bricks so the overhang was based on the diagonal length of the bricks rather than the length on one side. Also, I had turned some of the counterweight bricks through 90 degrees, allowing them to be placed closer to the fulcrum, giving more stability and greater overhang potential... Like I say, hours....... Love your content. Andrew
@windturbine67964 жыл бұрын
The most memorable part was me dying because I didn't know the no 9's series was convergent
@MrTiti4 жыл бұрын
yeah, i just went for the odds and said: well it is finite, because maybe something will happen, that i cannot see now, so in contradiction i am still alive :) But... just to ask for clarity: if that grid exists with 9s, wouldt it exist with all other numbers >0 ? what about the 0 ?
@jimmyh21374 жыл бұрын
@@MrTiti The grid is the "same" with every digit, including 0. In the first 10 numbers, 1/10 contain a (insert digit) or 10% In the first 100 numbers, 1/10 for every "ten" + 9/100 (the ones starting with your digit, like 31 32 33...), or 19% containing your digit. In the first 1000 numbers we have 19 every 100, + the ones with the first digit (300, 301, 302...), or 271/1000 or 27.1% total. And so on... Every time the % of numbers containing the chosen digit keeps increasing, reaching almost 100%. Works for all 10 digits (0, 1, 2... 9).
@eruwa15504 жыл бұрын
The fact that the harmonic series misses all the integers is beautiful to me!
@Skunz024 жыл бұрын
The most difficult question to answer is what part to vote for. If my life depended on it, I would pick the “no integers in the partial sums” topic ... and surrender my life for stealing gamma. Awesome video, wonderfully addictive, as usual!
@zswu314164 жыл бұрын
"Is the no 9 series finite? You life depends on this!" Me: suspicious, has to be finite! "Believe it or not, it is finite!" Me: YAY
@zswu314164 жыл бұрын
PS this comment is a joke, I have heard about the no 9s series a long time ago
@JM-us3fr4 жыл бұрын
Survival squad for the win!
@shotgun36284 жыл бұрын
@@JM-us3fr i would reply to you but ive been executed since i got it wrong
@rokaq51634 жыл бұрын
11:50 Arrange the bricks in a two layer formation where, on the bottom layer, you place a single block with its center of mass on the cliff's edge (akin to a single-block maximum overhang position). Then, on the second layer, place both remaining blocks with their centers of mass aligned with each of the bottom block's edges. If done correctly, the block placed over the cliff should create precisely a 2 unit overhang (assuming all blocks are 2 units long), with the other brick on the same layer acting as a counterweight. We would need to assume all blocks weight exactly the same, have perfectly equal shapes and there are no external forces aside from gravity acting on the system. Below I'll try to make a small ASCII schematic to illustrate the formation ________ ________ ________ -------------| Cliff |
@dzone94912 жыл бұрын
I love your video. I have a minor in Math and never had a prof explain visually any of these concepts like you have. Thank you it has revitalized my love for math!
@angstony4594 жыл бұрын
Most memorable: Chapter 1: "Let's assume that the grey bar does not weigh anything - thought experiment - we can do this - hehe" Top notch video!
@davidrheault78964 жыл бұрын
It (the likes) was prime, I clicked and it remained prime ;p
@levmarchuk9984 жыл бұрын
Most memorable: fractal visualization of no-9's series being finite
@pixels_4 жыл бұрын
Agreed! Simple and thus memorable
@Hampardo4 жыл бұрын
Euler mascheroni constant being greater than 0.5 can be seen in the figure at 25:13 by noticing that the blue convex triangles contain straight triangles whose area sum to 1/2. Great video Mathologer.😉
@zanedobler4 жыл бұрын
For me, the most memorable part was the optimal setup for 20 bricks because it made me glad I'm not an architectural engineer.
@sebastiansimon75574 жыл бұрын
I liked the crazy optimal overhang tower the most. Didn’t expect that at all.
@richardatkinson4710 Жыл бұрын
Me too. The untidy structure called to mind Sabine Hossenfelder’s “Lost in Math: How Beauty Leads Physics Astray”. Physicists are addicted to symmetries. Dirac thought beauty was the most important (and convincing) feature of any formula in mathematical physics.
@marysawyer93354 жыл бұрын
Great video, watched with my husband! My favourite part was the visualization of the no 9s series, thank you Tristan for the idea!
@adriannillsen86804 жыл бұрын
It is really interesting how eulars comes into all these different formulas. Personal favourite was the very neat proof at the end that the sum was less than 80
@dhruvsingh344 жыл бұрын
His T-Shirt is always Unique... 👕
@lebecccomputer2874 жыл бұрын
I was about to comment on it; that’s an awesome shirt!
@ahcuah95264 жыл бұрын
And "infinitely" interesting.
@kwinvdv4 жыл бұрын
And in the video also seem to show some kind of Moiré pattern behavior.
@gcewing4 жыл бұрын
You can leave any time you like, but you'll never arrive...