A very interesting integral with aesthetically pleasing solution development

  Рет қаралды 14,723

Maths 505

Maths 505

Күн бұрын

Пікірлер: 64
@maths_505
@maths_505 8 ай бұрын
If you like the videos, feel like you're learning something and would like to support my efforts: www.patreon.com/Maths505 You can follow me on Instagram for write ups that come in handy for my videos: instagram.com/maths.505?igshid=MzRlODBiNWFlZA==
@noobymaster6980
@noobymaster6980 8 ай бұрын
I love when he said ”it’s integral time” and integraled all over the integral. Truly one of the integral moments of 2024.
@edcify8241
@edcify8241 8 ай бұрын
You're the only one who didn't get a heart
@CalculusIsFun1
@CalculusIsFun1 8 ай бұрын
@@edcify8241you just had to jinx it.
@lyonkang7402
@lyonkang7402 8 ай бұрын
I thought we were done with this
@CM63_France
@CM63_France 8 ай бұрын
Hi, "ok, cool" : 1:06 , 5:27 , 6:37 , 7:37 , 8:12 , "terribly sorry about that" : 2:20 .
@boranxiii
@boranxiii 8 ай бұрын
damn this video was so beautiful that i lost my edging streak.I love math.
@maths_505
@maths_505 8 ай бұрын
Yup KZbin is definitely recommending my videos to the right audience.
@BenDover69831
@BenDover69831 8 ай бұрын
bro
@NavyaMenon25
@NavyaMenon25 7 ай бұрын
guys i think he likes likes math
@askandpushpaltiwary8537
@askandpushpaltiwary8537 8 ай бұрын
you should try the book of almost impossible integrals. Its a joy to solve those!
@josephlorizzo8997
@josephlorizzo8997 8 ай бұрын
WOW, what a cute ODE, i loved how you used the feyman trick there, i couldn't wait for you to mention the gaussian integral for that -u² on the e ahahahaha
@ieee12345
@ieee12345 8 ай бұрын
It feels like it'd be a ton easier writing cos(x) = Re(exp(ix)), packing the exponentials, completing the square and then invoking some mild holomorphic property to make the imaginary shift in the integration variable. After that it's just gaussian integrating. You could even do that at the step before, changing the sin into a complex exp. Still, watching Feynman's trick at work is always nice, keep it up.
@lakshay3745
@lakshay3745 8 ай бұрын
Or you could just use the complex definition of cosx and then complete the square in both Integrals and create two erf functions which solves the integral in like 2-3 lines
@aryaghahremani9304
@aryaghahremani9304 8 ай бұрын
can you explain the holomorphic shift? what i get when completing the square is Re(exp(-(x^2-i/2)), how do you turn this back into a normal guassian without invoking complex integrals
@ieee12345
@ieee12345 8 ай бұрын
@@aryaghahremani9304you should get something like exp(-(x-k*i)^2) inside the integral, for some k I can't tell right now. Then you'd want to do the change of variables u = x - k*i, to get back to the normal gaussian integral, but to do so you must note that the 2 "line pieces at real infinity" integrate to 0 and that the integrand is holomorphic. You can also just do the change, replace the limits and hope it works, but to justify it you need this very mild complex analysis, which is what I was referring to.
@djconnel
@djconnel 8 ай бұрын
@@lakshay3745 I agree: I felt as if the use of Fenyman's trick was strained. My first reaction was to express the cosine in complex exponentials, as you suggest. But maybe because I never learned it in school so I find it non-intuitive.
@Sugarman96
@Sugarman96 7 ай бұрын
And at that point it's just the Fourier transform of the Gaussian evaluated at 1
@utuberaj60
@utuberaj60 5 ай бұрын
Hi Kamal I've been watching your amazing 'integral' videos, and the more I watch, the more I love them, and I see you using that amazing Feynman's trick that's really cool. Indeed you make my 'integral moment' today at sunrise here in India
@lolcollol212
@lolcollol212 8 ай бұрын
Free okay cool buttons: 1:05 5:27 6:36 7:37 8:11
@MrWael1970
@MrWael1970 8 ай бұрын
Very impressive integral. Thanks for featured solution.
@acelm8437
@acelm8437 4 ай бұрын
I liked how the e^(-u^2) term kept absorbing the u's
@dukenukem9770
@dukenukem9770 8 ай бұрын
Both the solution and the technique are beautiful.
@aryaghahremani9304
@aryaghahremani9304 8 ай бұрын
ODE is smart, i love how feynman's technique is becoming an actual method of solving integrals rather than just a cool trick these days i solved the cosx e^(-x^2) integral by letting cosx=Re(e^ix) though which is pretty cool as well i guess
@holyshit922
@holyshit922 8 ай бұрын
Integration by parts Change of variable u=sqrt(-ln(x)) Series expansion for cosine Change order of integration and summation Change of variable v = u^2 , to get Γ function (Γ function can be also expanded)
@cameronspalding9792
@cameronspalding9792 8 ай бұрын
@ 4:49 for this part I would have used the complex expression for cos(u) and then used contour integration to get the rest of the answer
@zealot4325
@zealot4325 4 ай бұрын
Thank you!
@leonmancaj3690
@leonmancaj3690 8 ай бұрын
Great thank you Sir
@Jalina69
@Jalina69 8 ай бұрын
Counting how many times bro said "cool".
@sasukeuchiha1320
@sasukeuchiha1320 7 ай бұрын
Ok cool!
@lucasbeaumont5762
@lucasbeaumont5762 8 ай бұрын
people say im weird cause to me this is fun, i think their werid for not understanding that this was fun
@trelosyiaellinika
@trelosyiaellinika 3 ай бұрын
Really cool! 😊
@emilien2555
@emilien2555 22 күн бұрын
I got it alone ! it was nice and actually easy
@YassFuentes
@YassFuentes 8 ай бұрын
Beautiful one!
@HighlyEntropicMind
@HighlyEntropicMind 8 ай бұрын
I liked how we never needed to go back to the original
@SamLindskougMBGY
@SamLindskougMBGY 8 ай бұрын
First time i accually manage to solve one of your monster integrals, lets go
@maths_505
@maths_505 8 ай бұрын
I'm proud of ya bro
@nickyhekster2974
@nickyhekster2974 8 ай бұрын
Very cool.
@federicoformaro
@federicoformaro 8 ай бұрын
one of the few times i could've solved it by myself
@illumexhisoka6181
@illumexhisoka6181 8 ай бұрын
I have read about norms the other day (barely understood anything) But I got wondering how to find a general formula for the integral from 0 to 1 of The nth root of (1-x^n)
@GiornoYoshikage
@GiornoYoshikage 8 ай бұрын
Substitute `x^n = u` and notice that you get a kind of beta-function
@BadrBoutara
@BadrBoutara 6 ай бұрын
hi please why did you plug in ln c rather than c
@giuseppemalaguti435
@giuseppemalaguti435 8 ай бұрын
Io ho fatto così...t=√(-lnx)..risulta e^(-t^2)cost integrata da 0--->inf...poi feyman I(a)=..cosat...risulta,in sintesi I=√π/2e^(-1/4)
@toufikakkak8459
@toufikakkak8459 8 ай бұрын
Hi bro, can you do the intégrale from 0 to 1 for "ln(1-ln x)"
@maths_505
@maths_505 8 ай бұрын
Aight
@sciencelover-c2j
@sciencelover-c2j 8 ай бұрын
When you get in the next step, please put some explanation between steps. Because we need to get the clearance solution. we are not all proficient .thank you
@maths_505
@maths_505 8 ай бұрын
So you weren't listening to the audio???
@sciencelover-c2j
@sciencelover-c2j 8 ай бұрын
@maths_505 Absolutely, because mathematics is a language in itself, so l asked you, we need more steps before you get in another step,
@maths_505
@maths_505 8 ай бұрын
@@sciencelover-c2j to waste more time??
@sciencelover-c2j
@sciencelover-c2j 8 ай бұрын
@maths_505 Why do you think that 20 minutes is not enough ??
@maths_505
@maths_505 8 ай бұрын
@user-zg8ny5tp4g I just think that rambling on about basic algebra is gonna be extremely boring. The level of math here is something that my target audience is sufficiently familiar with.
@yoav613
@yoav613 8 ай бұрын
Nice😊
@igorbatkovich3856
@igorbatkovich3856 8 ай бұрын
Без Фейнмана не обошлось))
@Ivan-mp6ff
@Ivan-mp6ff 8 ай бұрын
Why not complement it with a graph? In most math calculations, a graph speaks a thousand words and can be very intuitive. Thank you all the same.
@KarthikDasari-g5q
@KarthikDasari-g5q 8 ай бұрын
i thought you sove it by complex nos
@maths_505
@maths_505 8 ай бұрын
Keepin it real this time
@albert3344
@albert3344 8 ай бұрын
Ooooook coooool!!!
@edmundwoolliams1240
@edmundwoolliams1240 8 ай бұрын
Beautiful aesthetically pleasing result, use of differentiation under the integral sign which led to a lovely first order ODE 😍 Exactly what I needed on my Friday morning. Could you find and do a beasty integral that evaluates to Digamma(G/sqrt(phi))?
@maths_505
@maths_505 8 ай бұрын
Wow that is some request! I'll try my best.
@edmundwoolliams1240
@edmundwoolliams1240 8 ай бұрын
@@maths_505 I know that's a very tough request. 😂 I don't expect you to get very far with it; as far as I'm aware crafting a (non-trivial) integral to yield a specific result is some near-impossible guesswork. I suppose that's why it's extra-special when beautiful results DO come out 😊
@davidblauyoutube
@davidblauyoutube 5 ай бұрын
Ah, but is the final result irrational?
@2739D
@2739D 8 ай бұрын
mane wtf😭😭
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