The trig integral of your dreams (or nightmares)

[@ΙΗΣΟΥΣΧριστος-θ2γ]

OMG 8:33 the moment i realized how you used the tangent addition formula and that the integral would simplify I was fucking blown away. That is truly some anime type tricks right there by kamaal.

[@CM63_France]

Hi, Nice formula : tan^-1 ( (1-z) / (1+z) ) = pi/4 - tan^-1 z . And I realized that I had already discovered this formula a few months ago. "ok, cool" : 3:51 , 4:38 , 11:25 , "terribly sorry about that" : 9:26 , 9:40 , 12:44 , 13:04 .

[@Jocularious]

In my msc in physics I derived a Hamiltonian for atom-light interactions for a quasi 1D system in terms of gamma(1/4), so the Lemniscate constant has "real world" applications

[@nizogos]

16 is 4^2 so in the final result you have something*((1/4)*Γ(1/4))^2 which simplifies to Γ(5/4)^2

[@worldnotworld]

"The best way to simplify things is to make them more complicated." Yip!

[@stefanalecu9532]

This has been a wild integral, kamaal was playing 4D chess with that addition formula

[@holyshit922]

I played with substitutions like x = arctan(sin(theta)) u = 4x v = Pi-u w = Pi/2-v y = 1/2w and i have got result in terms of Elliptic integral Pi/4*EllipticF(Pi/4,2)

[@yoav613]

When i started watching,it looked like a nightmare,but at the end this integral is adream!💯

[@tzovgo]

this is actually life-changing

[@Mathematician6124]

Hey friend 😊. I did it just the same way. It was a nice one.

[@Spiderp-p1l]

Weierstrass has yet to disappoint me:)

[@neg2sode]

Amazing substitution tricks!!

[@MrWael1970]

It is very interesting result and innovative solution plan. Thank you.

[@slavinojunepri7648]

Excellent

[@Jalina69]

arctan tan connection is the best thing I saw today

[@xxxx015]

Harikasınız hocam

[@shubhammeghani8232]

Solve this integral : (ln³x)/(x²+2x+2) Limits being 0 to +♾️

[@KramRemin]

4:40. Wow! Talk about non-intuitive! Weierstrass sub hit that integrand like a cluster-bomb!

[@sidhantmohanty5256]

Also do try integral 0 to pi/2 of arctan(0.5sinx) dx

[@SussySusan-lf6fk]

A much more interesting result intgrl 0 to pi/2 arctan( a * sinx) dx. {at lim a tends to infinity} = pi^2 /4 I'm not joking. As of your integral, it's pretty impossible as we have to solve int 0 to 1/2 ln(a + sqrt(1+a^2)) /(a sqrt(1+a^2)) da, it's not possible by Feynman or anything. But for my integral it becomes int 0 to infinity ln(a + sqrt(1+a^2)) /(a sqrt(1+a^2)) da This is easy if you use a=tanx and then split up the ln term. Finally after applying Feynman in one integral and applying geometric series in another, you get pi^2/4.

[@MugdhoDas9]

What's the app name

[@dthez4768]

Impressive. I like the cut of your jib!

[@satyam-isical]

Jee advanced(india) exam 5 days left From watching your integrals to getting a slap from chemistry,i came a long way

[@shamgermedad9560]

Hahahaha 1:36 . It happens when I practice Cal question

[@omkarjoshi9137]

Sooo I was playing on wolfram and found out that int ( 0 to infinite of x^ln(1/sqrt(x))) is exactly sqrt(2epi). You have any approach or reason for this?? Also written like that cuz is fun but better way is prolly x^((lnx)/-2)

[@SussySusan-lf6fk]

It's not very hard Substitute, lnx=t int -inf to +inf, (e^t)^( - t/2) e^t dt int - inf to +inf, e^( - t^2/2 +t) int - inf to +inf, e^( 1/2 - ( t/sqrt2 - 1/sqrt2 )^2) dt Take t/sqrt2 - 1/sqrt2 =u 1/sqrt2 dt = du, dt=sqrt2 du int -inf to +inf, e^1/2 e^(-u^2) sqrt 2 du Apply gaussian integral result sqrt(pi) * sqrt(e) * sqrt(2) sqrt(2epi)

[@toufikakkak8459]

Hi, I hope you do vidéo about : int from 0 to 1 for (ln x)²/(x²+1) cuz its equals = pi³/16, i solved its by séries, btw Nice video

[@vascomanteigas9433]

I solve with a x=1/t substitution, and combine to use the Residue Theorem.

[@giuseppemalaguti435]

Con lo sviluppo in serie della arctg e la beta function trigonometrica risulta I=(1/2)Σ((-1)^k/(2k+1))β(k+3/4,1/2)..poi..???

[@Anonymous-Indian..2003]

Ok Cool !

[@Akhulud]

noice

[@barakathaider6333]

What do you mean when you said (third world ciuntry)? since you are solving a scientific math problem, probably some people not like these kind of expression to be used while you are talking math... My dear

[@joelchristophr3741]

Hey bro (I'm who was calling you master) I have one new challenge for you! Int 0 to 1 [ ln ( 1-x² ) ] dx This is my today's mock test question 🌟

[@maths_505]

Factorise the argument of the ln function and then apply log properties. You'll get the sum of 2 integrals. Then go for integration by parts.

[@joelchristophr3741]

OmG 😂 But they've used ln expansions and some ultimate series simplification in given solution You're legend bro (Master )

[@maths_505]

@@sarahakkak408 indeed it doesn't 😂

[@SussySusan-lf6fk]

He could have meant floor function by [ ]