A mesmerizing result

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Maths 505

Maths 505

Күн бұрын

A beautiful iterated integral with full solution development leading to a closed form with this awesome linear combination of zeta functions.
My complex analysis lectures:
• Complex Analysis Lectures
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Пікірлер: 52
@stefanalecu9532
@stefanalecu9532 3 ай бұрын
Bro had a football fan moment before proceeding to jump to an integral You're something special
@orionspur
@orionspur 3 ай бұрын
Ohhhkaaay cool!
@alielhajj7769
@alielhajj7769 3 ай бұрын
If we make it a triple integral with the same structure you will get two additional zetas and and additional -2, the generalization is pretty cool and I think the limit as we increase the dimension of integration is convergent and it is actually equal to -1 + the sum from n=2 to infinity of zeta(n)-1 !!! Really cool and worth investigating
@CM63_France
@CM63_France 3 ай бұрын
Hi, "ok, cool" : 1:55 , 5:24 , 8:03 , 8:43 , "terribly sorry about that" : 2:05 , 2:44 , 4:34 , 8:20 , 9:35 .
@leroyzack265
@leroyzack265 3 ай бұрын
The final results with ascending coefficients of zeta is really cool. "We enjoyed the video. Thank you see you next time". Oops I'm using some one's words.
@jonsmith8579
@jonsmith8579 3 ай бұрын
Logarithms
@arkadelik
@arkadelik 3 ай бұрын
Logarithms
@maths_505
@maths_505 3 ай бұрын
Logarithms
@nox_ell1549
@nox_ell1549 3 ай бұрын
@@arkadelik Logarithms
@Dedicate25
@Dedicate25 3 ай бұрын
Logarithms
@stefanalecu9532
@stefanalecu9532 3 ай бұрын
Logarithms
@julioguilarte9438
@julioguilarte9438 3 ай бұрын
No wonder you are a sigma with this talent you have when it comes to solving these kinds of integrals. I hope I will someday become as good as you, meanwhile, keep up this amazing work :)
@ayushrudra8600
@ayushrudra8600 3 ай бұрын
portugal played well but they porbbaly won't win the whole thing - my guess is a quarter final exit
@archinsoni1254
@archinsoni1254 3 ай бұрын
Please integrate x^a*cosnx*e^(-kx)
@txikitofandango
@txikitofandango 3 ай бұрын
Sir you are a poet
@slavinojunepri7648
@slavinojunepri7648 3 ай бұрын
Cool result
@giuseppemalaguti435
@giuseppemalaguti435 3 ай бұрын
I=-Σ1/((k+1)(k+2)^4)...poi bisognerebbe sintetizzare con zeta function..
@داریوشسروری
@داریوشسروری Ай бұрын
لوتللت
@داریوشسروری
@داریوشسروری Ай бұрын
‏‬‏505
@داریوشسروری
@داریوشسروری Ай бұрын
اَلسَلامُ عَلَيْكُم وَرَحْمَةُ اَللهِ وَبَرَكاتُهُ‎
@داریوشسروری
@داریوشسروری Ай бұрын
اَلسَلامُ عَلَيْكُم وَرَحْمَةُ اَللهِ وَبَرَكاتُهُ‎
@داریوشسروری
@داریوشسروری Ай бұрын
اَلسَلامُ عَلَيْكُم وَرَحْمَةُ اَللهِ وَبَرَكاتُهُ‎
@PeterParker-gt3xl
@PeterParker-gt3xl 3 ай бұрын
Hope to learn about Zeta fn. of odd powers apart from Euler's even powers. He loved using ln. to "lessen the labor".
@aravindakannank.s.
@aravindakannank.s. 3 ай бұрын
bro rest well bro i think you pulled an all nighter to watch football.
@3manthing
@3manthing 3 ай бұрын
2:13 Have you seen the new Oppen-adder movie? "Now I have become the sigma, the summator of the series."😅😁
@maths_505
@maths_505 3 ай бұрын
Nah haven't seen that one but damn that was cool 😂
@xizar0rg
@xizar0rg 3 ай бұрын
Can this be extrapolated out with more integrals? Like integral over unit cube of lnx*lny*lnz*ln(1-xyz) being (guessing result if it continues as before) eta2 +eta3 + eta4+ eta5 - 5? Or generally N Integrals_01 of Product(ln(x_n), 1, N) = Sum(eta(n), 2, n+1) - (n+1)? (I probably fucked up some notation there, but hopefully what I mean is understood.)
@BridgeBum
@BridgeBum 3 ай бұрын
On notation: zeta, not eta. On the concept: seems worth exploring!
@kgangadhar5389
@kgangadhar5389 3 ай бұрын
I was wondering the same. If its the case then Its can give some insight on Zeta and its distribution.
@maths_505
@maths_505 3 ай бұрын
Oh yeah it's definitely gonna carry over thanks to symmetry.
@lizardwithahat4862
@lizardwithahat4862 3 ай бұрын
I tried to find a solution to the general integral: ∫...∫ln(x1)•...•ln(xN)•ln(1-x1x2...xN)dxN... dx1 (with all the integrals going from 0 to 1) and got this: I = -2N + sum{j=2 to 2N}Zeta(j)
@username-ur6dq
@username-ur6dq 3 ай бұрын
I looked at numerical answers for these integrals, and it seems there is a factor of -1 multiplied for each n for the solution you provided​@@lizardwithahat4862
@Nottherealbegula4
@Nottherealbegula4 3 ай бұрын
May I ask what app you use for your videos?
@MrWael1970
@MrWael1970 3 ай бұрын
Thank you very much.
@yoav613
@yoav613 3 ай бұрын
Sport and math perfect!😊💯
@insouciantFox
@insouciantFox 3 ай бұрын
Who you got for the Copa? Also I dare you to use ξ as a variable
@maths_505
@maths_505 3 ай бұрын
Argentina
@felipematus3021
@felipematus3021 3 ай бұрын
Greetings from the Czech Republic.
@maths_505
@maths_505 3 ай бұрын
Greetings
@felipematus3021
@felipematus3021 3 ай бұрын
@@maths_505 I knew there was something weird with my comment 🤣🤣🤣
@serdarakalin2209
@serdarakalin2209 3 ай бұрын
Perfect
@satyam-isical
@satyam-isical 3 ай бұрын
I thought we're gonna find the value of zeta2 zeta3 zeta 4😂
@hizon525
@hizon525 3 ай бұрын
2:13 Kamaal your sigma dad joke literally sent me hysterically laughing across the house. I have to thank the Gods i am home alone right now. Ive never been more comedically t-boned before in my life 😂
@GearsScrewlose
@GearsScrewlose 3 ай бұрын
Sweet result.
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