man I know you do crazy integrals but this is something else bro this is a murder
@wassimaabiyda7 ай бұрын
that's a horror movie
@mcalkis57717 ай бұрын
I do believe it's time to face your destiny and tackle the Borwein integrals.
@nightmareintegral55937 ай бұрын
Finnaly legendery integral! Next Coxeter integrals! 🖤
@TheDhdk7 ай бұрын
I did not survive... Will try again tomorrow.
@maths_5057 ай бұрын
@@TheDhdk that's the spirit 🔥
@insouciantFox7 ай бұрын
I suffered the little death, in the Shakespearean sense.
@maths_5057 ай бұрын
The important thing is you survived....just as I did
@insouciantFox7 ай бұрын
@@maths_505 It means the big O and I'm not talking about notation
@onkarsusladkar39836 ай бұрын
same here😅
@2739D6 ай бұрын
“Thank You Math 505” we all said in Unison
@stefanalecu95327 ай бұрын
Man, I remember when I watched Peyam solve this integral, you did it on 3x speed, this has been just beautiful, we should call you Magician Kamaal because you're pulling tricks left and right
@maths_5057 ай бұрын
Why am I not surprised that peyam solved it before me😂
@maths_5057 ай бұрын
Peyam is probably the most underrated KZbinr in the math space.
@aleksandervadla98817 ай бұрын
Is the integral related to the poisson kernel?
@felps3146 ай бұрын
15:09 i just finished calculus I and did not understand most of the things of the video, but i think it is pretty cool watching you solving these integrals
The same denominator of the integrand (x² +2xcosα + 1) appears in the result of the sum ∑ Rⁿcos(nθ), for n ≥ 0. (That is, if we let R=-x and α=θ) I wonder if this has any significance, of if it could be used to solve this integral in another way. edit: nevermind, after 4:00 you used a very similar argument
@zachariastsampasidis88807 ай бұрын
You could say that the quadratic was a known kernel
@maxmoedough64017 ай бұрын
Coomer series coming in clutch! 🎉
@davode761667 ай бұрын
Early in the morning and I'm watching such an integral instead of going to work!!! 😅
@maths_5057 ай бұрын
Time well spent😂
@nicolascamargo83396 ай бұрын
Como se llama el resultado en 15:36?
@MohamedElekhtiar--7 ай бұрын
I couldn't help but notice that alpha=0 limit exsit in that gorgeous answer, so I did it as a homework and got 1/2ln(e^-γ * pi/2) which is a nice bonus result for a special case of first integral at alpha=0
@MrWael19706 ай бұрын
Extremely Insane. Thank you.
@trelosyiaellinika7 ай бұрын
Breathtaking!
@maths_5057 ай бұрын
@@trelosyiaellinika and you survived!
@trelosyiaellinika7 ай бұрын
@@maths_505 Not only. I enjoyed it immensely!
@romanvolotov7 ай бұрын
at 10:30 it should be divided by 2i, shouldn't it? ik it doesn't matter but still
@euler17 ай бұрын
Will come back to this video when my math skills are better
@maths_5057 ай бұрын
@@euler1 bro this video will literally improve your math skills in one go
@euler17 ай бұрын
On a serious note tho, most of your videos actually do in some way or another and it's really enjoyable to watch you layout the solution development for such problems. I really need to sleep now but I will give it another go in the morning am sure.
@maths_5057 ай бұрын
Aight bro Sleep well and keep making those math gains.
@night95877 ай бұрын
10:42 part is beautiful
@subutaibaator62597 ай бұрын
I like Kummer series. Exciting integral!
@stenzenneznets6 ай бұрын
Hello! Is there a "simple" function whose integral has a very "complex" closed form? By a simple function, I mean a function similar to the one in the video, consisting of a few elementary functions, at most rational. By a very complex closed form, I mean expressions that involve various constants, raficals, logarithms, sums and multiplications etc. (ellipitc integrals, hylergeometric, gamma, zeta functions are not allowed, solution must be close). Thanks for any insights!
@hayksargsyan44164 ай бұрын
If I were a prof I'd put that in a test just for pranks
@ericthegreat78057 ай бұрын
1) you forgot a - sign at 14:30 in the second sum 2) If you replace cos(alpha) with cos(alpha * x) in the denominator, is this related to Coxeter's integral?
@maths_5057 ай бұрын
The negative was factored out. And I don't think this is related to any one of coxeter's integrals.
@samsonblack7 ай бұрын
I survived, but now I carry with me the weight of the experience.
@michaeldunn342 ай бұрын
Interestingly, I(a) where a = pi/2 is the result for the Vardi integral, correct?
@Akhulud7 ай бұрын
The universe is now speaking to me
@leroyzack2657 ай бұрын
This is far harder than the coxeter's integral. What makes it insane is that it's linked to geometric series, Fourier series, Laplace transform. Almost all the craziest analysis stuff where required to solve it. It was really a worthy opponent.
@maths_5057 ай бұрын
Coxeter is honestly just alot of algebra. This however is an entirely different story.
@mikecaetano7 ай бұрын
Shredder! Minor quibble. At ten minutes thirty, divide by 2i to get sine.
@BridgeBum5 ай бұрын
Thankfully we are dividing in the numerator and denominator so the constants cancel.
@Sugarman967 ай бұрын
Also, a weirdly specific conclusion is that the integral of ln(lnx)/(x±1)^2 over (1,inf) diverges
@maddog55976 ай бұрын
No! - ln(ln(x)/(x+1)^2 converges
@Sugarman966 ай бұрын
@@maddog5597 the parametrised results has 1/sin(alpha), which would suggest the integral diverges for multiples of alpha that is a whole multiple of pi.
@maddog55976 ай бұрын
@@Sugarman96 No. As alpha goes to zero, the Gamma functions cancel out leaving you with log(2*pi)^ (alpha/pi). You can bring the alpha/pi out in front of the log to give you a term that looks like alpha/sin(alpha). As alpha approaches zero, this approaches one.
@Sugarman966 ай бұрын
@@maddog5597 why can you just take the limit when the result comes from just plugging in a value of alpha? And how does that work for values of alpha that aren't zero? The gamma functions _don't_ cancel out then
@maddog55976 ай бұрын
@@Sugarman96 I was just responding to your original post, where you claimed ln(ln(x))/(x+1)^2 diverged. The main problem is that Kamaal should have put limits on alpha. The integral diverges for alpha = pi. It probably diverges for other values of alpha that make the cos go negative.
@rakib_hoque14 күн бұрын
surviving is an overstatement 💀
@willemesterhuyse25476 ай бұрын
You must devide by 2i to get sin, not 2.
@maths_5056 ай бұрын
@@willemesterhuyse2547 yes that's 2 errors cancelling out 😂
@sidhantmohanty52566 ай бұрын
Great integral man
@jupski49606 ай бұрын
13:31 dont mind me, this is just my personal timestamp
@leifhaider72806 ай бұрын
Can u cover Green's therom and scattering therom
@romanvolotov7 ай бұрын
barely survived this one
@khengari777 ай бұрын
I think I've survived
@martincuq24116 ай бұрын
Wow that was just insane
@andrewfischer-garbutt28677 ай бұрын
I really enjoyed this. But I have one question I dont understand why you wrote (2*pi)^(alpha/(2*pi)) shouldnt it be just (2*pi)^(alpha/2).
@Sugarman967 ай бұрын
At 10:26-ish, you need to divide the upstairs and downstairs by 2j, not just 2, to get the complex sine definition. Ultimately you're still multiplying by 1, but the point stands 😉
@jkid11347 ай бұрын
Wicked awesome.
@maths_5057 ай бұрын
@@jkid1134 another survivor!
@isaacsofair32636 ай бұрын
Where do you find all these integrals? Are they sent by the subscribers? I sent you two in the last few months.
@maths_5056 ай бұрын
This one was from a patreon subscriber. Sorry I haven't been very responsive to requests, I've been extremely occupied these past few months. Even this integral was recommended to me almost a year ago.
@whizgranny62037 ай бұрын
I survived it! Dr Peyam did this integral on KZbin a while ago.
@Nottherealbegula47 ай бұрын
15:05 Im... still breathing...
@adrianjanik65697 ай бұрын
You ruined my lazy Sunday. Will I survive? Greetings from Germany!
@wiwaxiasilver8277 ай бұрын
Oh wow, didn’t realize this integral would invoke the Laplace transform and the Fourier series… wow
@Mosux20077 ай бұрын
My question: WHERE would you encounter such a monstrosity???
@maths_5057 ай бұрын
Obviously in a near death experience 😂
@manstuckinabox36796 ай бұрын
Me before watching this video: the polinomial in the denominator can be computed as (x+e^itheta)(x-e^itheta). now we define I(s) = int from 1 to infinity of log(x)^s/(x-a)(x-b). applying PFD. a = complement of b a = e^itheta. I(s) = int 1 to infinity of (1/b-a) * (log(x)^s/(x-b)) + (1/a-b) * (log(x)^s/(x-b)) . we split into I1(s) and I2(s). apply u = log(x) e^u du = dx e^u *u^s/(e^u-b) = u^s/(1-b*e^-u) so using some melliny mellin magic I1 evaluates to.. iuhun I'm just going to watch the vid now.
@emanuellandeholm56577 ай бұрын
Shoutout to one of the few world famous Swedish matematicians. We also have Ivar Fredholm and 50% of Harry Nyquist. The Norwegians of course have Marius Sophus Lie, who's on another level altogether. And the Danes have all the celebrated Physics/QM guys. The Finns have lots of great mathematicians too.
@gerardomalazdrewicz7514Ай бұрын
Not to mention Niels Henrik Abel.
@qetzing6 ай бұрын
Somehow I survived and honestly… I don’t know how
@nitzan336 ай бұрын
I died, but I turned out fine as well
@edwardhuang58855 ай бұрын
why do you do this to yourself
@조현욱-e5j6 ай бұрын
Survived!
@GearsScrewlose7 ай бұрын
IDK if it was integral or the notation that killed me. :)
@maddog55976 ай бұрын
What am I missing: As alpha goes to zero, your answer approaches (1/2)log(2*pi). This is a positive number, but the integral should be negative. Huh?
@sadboy4today1877 ай бұрын
Yoooo I’m alive, but my god man
@alielhajj77697 ай бұрын
Now it’s time to prove that identity to ln(gamma)
@maths_5057 ай бұрын
@@alielhajj7769 it's that time alright....
@nathanmenezes79146 ай бұрын
Sorry Kamal but I died. However upon seeing the raw power of what killed me, Eru intervened and had me reborn
@richardbrewer29376 ай бұрын
awesome
@Schambes7 ай бұрын
Love it
@stenzenneznets7 ай бұрын
I'm okay
@xizar0rg7 ай бұрын
I didn't know Yngwie had his own integral. (This is a guitarist joke.)
@maths_5057 ай бұрын
YOU SURVIVED! HELL YEAH!!!
@arsensugar12657 ай бұрын
Again poor maskeroni canseling out😂
@orionspur7 ай бұрын
Lordy. 🏆
@maths_5057 ай бұрын
Bro you survived too!
@orionspur7 ай бұрын
@@maths_505 Dazed, but not confused. 👍
@naturallyinterested75696 ай бұрын
Anything
@sngash28 күн бұрын
Wow
@iWilburnYou7 ай бұрын
Unfortunately, I did not survive 😮💨
@maths_5057 ай бұрын
It's cool, try again tomorrow
@Calcprof7 ай бұрын
Wow.
@maths_5057 ай бұрын
You survived too!
@petterituovinem84127 ай бұрын
anything
@worldnotworld7 ай бұрын
OK COOL
@vitorbordini52467 ай бұрын
RIP my boy kamaal(I hope I am writing your name right)
@maths_5057 ай бұрын
He will be remembered especially for the reverse cowgirl formulation of integral calculus. Oh wait here I am false alarm guys 😂
@DIVA-on3vy7 ай бұрын
OK COOL❤
@maths_5057 ай бұрын
Another survivor!
@Mario_Altare7 ай бұрын
Er, I got the wrong channel
@maths_5057 ай бұрын
😂😂😂
@Tosi314157 ай бұрын
i died
@maths_5057 ай бұрын
Sadly yes...but the good news is you're alive!
@yoav6137 ай бұрын
Nice and easy😂😂😂😂😂
@maths_5057 ай бұрын
😂😂😂
@maths_5057 ай бұрын
I think it was you who recommended this to me a while back.
@yoav6137 ай бұрын
@@maths_505 no,but i'm glad someone else did,it is beautiful!
@A.Hisham867 ай бұрын
I stopped following you at 9:00 , cause I couldn't follow.