The INCREDIBLE Malmsten integral

  Рет қаралды 7,868

Maths 505

Maths 505

Күн бұрын

This was awesome! One of the toughest integrals ever conjured up and so much cool mathematics smashed into one solution development.
My complex analysis lectures:
• Complex Analysis Lectures
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Пікірлер: 119
@kingzenoiii
@kingzenoiii 3 ай бұрын
this integral is zeroeth degree murder
@wassimaabiyda
@wassimaabiyda 3 ай бұрын
that's a horror movie
@JoseSanchezLopez-yf3lo
@JoseSanchezLopez-yf3lo 3 ай бұрын
man I know you do crazy integrals but this is something else bro this is a murder
@mcalkis5771
@mcalkis5771 3 ай бұрын
I do believe it's time to face your destiny and tackle the Borwein integrals.
@TheDhdk
@TheDhdk 3 ай бұрын
I did not survive... Will try again tomorrow.
@maths_505
@maths_505 3 ай бұрын
@@TheDhdk that's the spirit 🔥
@ashwinbabu1426
@ashwinbabu1426 3 ай бұрын
so early there isn't even a thumbnail
@insouciantFox
@insouciantFox 3 ай бұрын
I suffered the little death, in the Shakespearean sense.
@maths_505
@maths_505 3 ай бұрын
The important thing is you survived....just as I did
@insouciantFox
@insouciantFox 3 ай бұрын
@@maths_505 It means the big O and I'm not talking about notation
@onkarsusladkar3983
@onkarsusladkar3983 3 ай бұрын
same here😅
@nightmareintegral5593
@nightmareintegral5593 3 ай бұрын
Finnaly legendery integral! Next Coxeter integrals! 🖤
@aleksandervadla9881
@aleksandervadla9881 3 ай бұрын
Is the integral related to the poisson kernel?
@zachariastsampasidis8880
@zachariastsampasidis8880 3 ай бұрын
You could say that the quadratic was a known kernel
@stefanalecu9532
@stefanalecu9532 3 ай бұрын
Man, I remember when I watched Peyam solve this integral, you did it on 3x speed, this has been just beautiful, we should call you Magician Kamaal because you're pulling tricks left and right
@maths_505
@maths_505 3 ай бұрын
Why am I not surprised that peyam solved it before me😂
@maths_505
@maths_505 3 ай бұрын
Peyam is probably the most underrated KZbinr in the math space.
@maxmoedough6401
@maxmoedough6401 3 ай бұрын
Coomer series coming in clutch! 🎉
@davode76166
@davode76166 3 ай бұрын
Early in the morning and I'm watching such an integral instead of going to work!!! 😅
@maths_505
@maths_505 3 ай бұрын
Time well spent😂
@sadboy4today187
@sadboy4today187 3 ай бұрын
Yoooo I’m alive, but my god man
@andrewfischer-garbutt2867
@andrewfischer-garbutt2867 3 ай бұрын
I really enjoyed this. But I have one question I dont understand why you wrote (2*pi)^(alpha/(2*pi)) shouldnt it be just (2*pi)^(alpha/2).
@Mosux2007
@Mosux2007 3 ай бұрын
My question: WHERE would you encounter such a monstrosity???
@maths_505
@maths_505 3 ай бұрын
Obviously in a near death experience 😂
@arsensugar1265
@arsensugar1265 3 ай бұрын
Again poor maskeroni canseling out😂
@maddog5597
@maddog5597 3 ай бұрын
What am I missing: As alpha goes to zero, your answer approaches (1/2)log(2*pi). This is a positive number, but the integral should be negative. Huh?
@stenzenneznets
@stenzenneznets 3 ай бұрын
Hello! Is there a "simple" function whose integral has a very "complex" closed form? By a simple function, I mean a function similar to the one in the video, consisting of a few elementary functions, at most rational. By a very complex closed form, I mean expressions that involve various constants, raficals, logarithms, sums and multiplications etc. (ellipitc integrals, hylergeometric, gamma, zeta functions are not allowed, solution must be close). Thanks for any insights!
@MohamedElekhtiar--
@MohamedElekhtiar-- 3 ай бұрын
I couldn't help but notice that alpha=0 limit exsit in that gorgeous answer, so I did it as a homework and got 1/2ln(e^-γ * pi/2) which is a nice bonus result for a special case of first integral at alpha=0
@Nottherealbegula4
@Nottherealbegula4 3 ай бұрын
15:05 Im... still breathing...
@nathanmenezes7914
@nathanmenezes7914 3 ай бұрын
Sorry Kamal but I died. However upon seeing the raw power of what killed me, Eru intervened and had me reborn
@qetzing
@qetzing 3 ай бұрын
Somehow I survived and honestly… I don’t know how
@subutaibaator6259
@subutaibaator6259 3 ай бұрын
I like Kummer series. Exciting integral!
@romanvolotov
@romanvolotov 3 ай бұрын
at 10:30 it should be divided by 2i, shouldn't it? ik it doesn't matter but still
@night9587
@night9587 3 ай бұрын
10:42 part is beautiful
@leifhaider7280
@leifhaider7280 3 ай бұрын
Can u cover Green's therom and scattering therom
@hayksargsyan4416
@hayksargsyan4416 17 күн бұрын
If I were a prof I'd put that in a test just for pranks
@jupski4960
@jupski4960 2 ай бұрын
13:31 dont mind me, this is just my personal timestamp
@mikecaetano
@mikecaetano 3 ай бұрын
Shredder! Minor quibble. At ten minutes thirty, divide by 2i to get sine.
@BridgeBum
@BridgeBum Ай бұрын
Thankfully we are dividing in the numerator and denominator so the constants cancel.
@lauciansylvaranth2285
@lauciansylvaranth2285 3 ай бұрын
I died, but I turned out fine as well
@edwardhuang5885
@edwardhuang5885 Ай бұрын
why do you do this to yourself
@khengari77
@khengari77 3 ай бұрын
I think I've survived
@Akhulud
@Akhulud 3 ай бұрын
The universe is now speaking to me
@martincuq2411
@martincuq2411 2 ай бұрын
Wow that was just insane
@nicolascamargo8339
@nicolascamargo8339 2 ай бұрын
Como se llama el resultado en 15:36?
@felps314
@felps314 2 ай бұрын
15:09 i just finished calculus I and did not understand most of the things of the video, but i think it is pretty cool watching you solving these integrals
@maths_505
@maths_505 2 ай бұрын
@@felps314 thanks mate
@isaacsofair3263
@isaacsofair3263 3 ай бұрын
Where do you find all these integrals? Are they sent by the subscribers? I sent you two in the last few months.
@maths_505
@maths_505 3 ай бұрын
This one was from a patreon subscriber. Sorry I haven't been very responsive to requests, I've been extremely occupied these past few months. Even this integral was recommended to me almost a year ago.
@Sugarman96
@Sugarman96 3 ай бұрын
Also, a weirdly specific conclusion is that the integral of ln(lnx)/(x±1)^2 over (1,inf) diverges
@maddog5597
@maddog5597 3 ай бұрын
No! - ln(ln(x)/(x+1)^2 converges
@Sugarman96
@Sugarman96 3 ай бұрын
@@maddog5597 the parametrised results has 1/sin(alpha), which would suggest the integral diverges for multiples of alpha that is a whole multiple of pi.
@maddog5597
@maddog5597 3 ай бұрын
@@Sugarman96 No. As alpha goes to zero, the Gamma functions cancel out leaving you with log(2*pi)^ (alpha/pi). You can bring the alpha/pi out in front of the log to give you a term that looks like alpha/sin(alpha). As alpha approaches zero, this approaches one.
@Sugarman96
@Sugarman96 3 ай бұрын
@@maddog5597 why can you just take the limit when the result comes from just plugging in a value of alpha? And how does that work for values of alpha that aren't zero? The gamma functions _don't_ cancel out then
@maddog5597
@maddog5597 3 ай бұрын
@@Sugarman96 I was just responding to your original post, where you claimed ln(ln(x))/(x+1)^2 diverged. The main problem is that Kamaal should have put limits on alpha. The integral diverges for alpha = pi. It probably diverges for other values of alpha that make the cos go negative.
@Sugarman96
@Sugarman96 3 ай бұрын
At 10:26-ish, you need to divide the upstairs and downstairs by 2j, not just 2, to get the complex sine definition. Ultimately you're still multiplying by 1, but the point stands 😉
@vitorbordini5246
@vitorbordini5246 3 ай бұрын
RIP my boy kamaal(I hope I am writing your name right)
@maths_505
@maths_505 3 ай бұрын
He will be remembered especially for the reverse cowgirl formulation of integral calculus. Oh wait here I am false alarm guys 😂
@stenzenneznets
@stenzenneznets 3 ай бұрын
I'm okay
@naturallyinterested7569
@naturallyinterested7569 2 ай бұрын
Anything
@조현욱-e5j
@조현욱-e5j 2 ай бұрын
Survived!
@petterituovinem8412
@petterituovinem8412 3 ай бұрын
anything
@richardbrewer2937
@richardbrewer2937 3 ай бұрын
awesome
@xizar0rg
@xizar0rg 3 ай бұрын
I didn't know Yngwie had his own integral. (This is a guitarist joke.)
@maths_505
@maths_505 3 ай бұрын
YOU SURVIVED! HELL YEAH!!!
@manstuckinabox3679
@manstuckinabox3679 3 ай бұрын
Me before watching this video: the polinomial in the denominator can be computed as (x+e^itheta)(x-e^itheta). now we define I(s) = int from 1 to infinity of log(x)^s/(x-a)(x-b). applying PFD. a = complement of b a = e^itheta. I(s) = int 1 to infinity of (1/b-a) * (log(x)^s/(x-b)) + (1/a-b) * (log(x)^s/(x-b)) . we split into I1(s) and I2(s). apply u = log(x) e^u du = dx e^u *u^s/(e^u-b) = u^s/(1-b*e^-u) so using some melliny mellin magic I1 evaluates to.. iuhun I'm just going to watch the vid now.
@alielhajj7769
@alielhajj7769 3 ай бұрын
Now it’s time to prove that identity to ln(gamma)
@maths_505
@maths_505 3 ай бұрын
@@alielhajj7769 it's that time alright....
@emanuellandeholm5657
@emanuellandeholm5657 3 ай бұрын
Shoutout to one of the few world famous Swedish matematicians. We also have Ivar Fredholm and 50% of Harry Nyquist. The Norwegians of course have Marius Sophus Lie, who's on another level altogether. And the Danes have all the celebrated Physics/QM guys. The Finns have lots of great mathematicians too.
@CM63_France
@CM63_France 3 ай бұрын
Hi, "ok, cool" : 2:23 , 6:24 , 14:54 , 20:55 , 22:28 , 22:57 , "terribly sorry about that" : 11:00 , 11:36 , 14:36 , 18:42 , 26:50 , 27:17 .
@wiwaxiasilver827
@wiwaxiasilver827 3 ай бұрын
Oh wow, didn’t realize this integral would invoke the Laplace transform and the Fourier series… wow
@DOROnoDORO
@DOROnoDORO 3 ай бұрын
The same denominator of the integrand (x² +2xcosα + 1) appears in the result of the sum ∑ Rⁿcos(nθ), for n ≥ 0. (That is, if we let R=-x and α=θ) I wonder if this has any significance, of if it could be used to solve this integral in another way. edit: nevermind, after 4:00 you used a very similar argument
@adrianjanik6569
@adrianjanik6569 3 ай бұрын
You ruined my lazy Sunday. Will I survive? Greetings from Germany!
@whizgranny6203
@whizgranny6203 3 ай бұрын
I survived it! Dr Peyam did this integral on KZbin a while ago.
@jkid1134
@jkid1134 3 ай бұрын
Wicked awesome.
@maths_505
@maths_505 3 ай бұрын
@@jkid1134 another survivor!
@euler1
@euler1 3 ай бұрын
Will come back to this video when my math skills are better
@maths_505
@maths_505 3 ай бұрын
@@euler1 bro this video will literally improve your math skills in one go
@euler1
@euler1 3 ай бұрын
On a serious note tho, most of your videos actually do in some way or another and it's really enjoyable to watch you layout the solution development for such problems. I really need to sleep now but I will give it another go in the morning am sure.
@maths_505
@maths_505 3 ай бұрын
Aight bro Sleep well and keep making those math gains.
@samsonblack
@samsonblack 3 ай бұрын
I survived, but now I carry with me the weight of the experience.
@willemesterhuyse2547
@willemesterhuyse2547 2 ай бұрын
You must devide by 2i to get sin, not 2.
@maths_505
@maths_505 2 ай бұрын
@@willemesterhuyse2547 yes that's 2 errors cancelling out 😂
@trelosyiaellinika
@trelosyiaellinika 3 ай бұрын
Breathtaking!
@maths_505
@maths_505 3 ай бұрын
@@trelosyiaellinika and you survived!
@trelosyiaellinika
@trelosyiaellinika 3 ай бұрын
@@maths_505 Not only. I enjoyed it immensely!
@MrWael1970
@MrWael1970 2 ай бұрын
Extremely Insane. Thank you.
@Mario_Altare
@Mario_Altare 3 ай бұрын
Er, I got the wrong channel
@maths_505
@maths_505 3 ай бұрын
😂😂😂
@2739D
@2739D 3 ай бұрын
“Thank You Math 505” we all said in Unison
@GearsScrewlose
@GearsScrewlose 3 ай бұрын
IDK if it was integral or the notation that killed me. :)
@romanvolotov
@romanvolotov 3 ай бұрын
barely survived this one
@ericthegreat7805
@ericthegreat7805 3 ай бұрын
1) you forgot a - sign at 14:30 in the second sum 2) If you replace cos(alpha) with cos(alpha * x) in the denominator, is this related to Coxeter's integral?
@maths_505
@maths_505 3 ай бұрын
The negative was factored out. And I don't think this is related to any one of coxeter's integrals.
@leroyzack265
@leroyzack265 3 ай бұрын
This is far harder than the coxeter's integral. What makes it insane is that it's linked to geometric series, Fourier series, Laplace transform. Almost all the craziest analysis stuff where required to solve it. It was really a worthy opponent.
@maths_505
@maths_505 3 ай бұрын
Coxeter is honestly just alot of algebra. This however is an entirely different story.
@Tosi31415
@Tosi31415 3 ай бұрын
i died
@maths_505
@maths_505 3 ай бұрын
Sadly yes...but the good news is you're alive!
@iWilburnYou
@iWilburnYou 3 ай бұрын
Unfortunately, I did not survive 😮‍💨
@maths_505
@maths_505 3 ай бұрын
It's cool, try again tomorrow
@sidhantmohanty5256
@sidhantmohanty5256 3 ай бұрын
Great integral man
@DIVA-on3vy
@DIVA-on3vy 3 ай бұрын
OK COOL❤
@maths_505
@maths_505 3 ай бұрын
Another survivor!
@worldnotworld
@worldnotworld 3 ай бұрын
OK COOL
@Schambes
@Schambes 3 ай бұрын
Love it
@yoav613
@yoav613 3 ай бұрын
Nice and easy😂😂😂😂😂
@maths_505
@maths_505 3 ай бұрын
😂😂😂
@maths_505
@maths_505 3 ай бұрын
I think it was you who recommended this to me a while back.
@yoav613
@yoav613 3 ай бұрын
@@maths_505 no,but i'm glad someone else did,it is beautiful!
@Calcprof
@Calcprof 3 ай бұрын
Wow.
@maths_505
@maths_505 3 ай бұрын
You survived too!
@orionspur
@orionspur 3 ай бұрын
Lordy. 🏆
@maths_505
@maths_505 3 ай бұрын
Bro you survived too!
@orionspur
@orionspur 3 ай бұрын
@@maths_505 Dazed, but not confused. 👍
@A.Hisham86
@A.Hisham86 3 ай бұрын
I stopped following you at 9:00 , cause I couldn't follow.
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