Every time he says tech talk i hear "TED talk", thanks Brian.
@ogunsadebenjaminadeiyin27294 жыл бұрын
Hello Brian. Very well taught. Thanks a million times.
@timothydavis25682 жыл бұрын
great video, really helped me out
@seetllee Жыл бұрын
I did not get the "re-label where we call zero" part. It looked like you made Hbar = 0, but then you took the square root of it n the slope term, making it result in -a/4A. It looks mathematically inconsistent, to consider Hbar to be zero only at one part. Could you explain? (Or someone that got this)
@sierramikekilo6925Ай бұрын
(Answering 1 year after, but I hope it helps someone) Yes, looks inconsistent, but you can interpret it as: You re-label what you consider zero in another variable, an auxiliary variable, not exactly the same as considering Hbar = 0. The operating point is still at the original H = 4, a point where there's no discontinuity. The value of the slope is calculated at H = 4 and fixed (The slope is still -a/4A). Only then you re-label it. But I agree with you that maybe another variable should be used, an auxiliary variable, to represent this re-labelling.
@son150219925 жыл бұрын
Hello. Thanks for interesting video. Can you give more detail process about step: x-xbar->x in state space equation and how simulink model and controller connect with it will look like. Thanks you so much.
@prasadkoppal38682 жыл бұрын
Thanks Brian !!
@matlabaerospace85442 жыл бұрын
Hello, Brian if you are linearizing at H(bar) = 4 then how does H-H(bar) = H? is not H(bar) at 0
@SamRao6 жыл бұрын
Two of the links link to AEM pages within MathWorks. Please edit those. Thanks
@BrianBDouglas6 жыл бұрын
Samvith V Rao I asked Mathworks to update the links (I don’t post these so I can’t do it myself). Thanks for pointing it out!
@MATLAB6 жыл бұрын
Hi Samvith, thanks for catching that. Links are updated now.
@edgycuber92858 ай бұрын
Thank you!
@Maybe.0193 жыл бұрын
thank you
@taloqib48204 жыл бұрын
Hello Brian! in the final equation you have gotten and when I tried to substitute in value of the operating point(H_bar, V_bar), does the left side (H_dot) has to equal to zero? I tired to substitute but I have gotten nonzero value, why?
@HORIMEKABDERRAHMANE6 ай бұрын
Fantastic
@blackcat-mp7kh4 жыл бұрын
how pendulum will be at equilibrium pointing straight up ?
@louco2 Жыл бұрын
With friction forces helping/triming a a bit? Hahaha