Class 9 Maths Chapter 2 | Polynomials Solutions | Exercise 2.3 Q1 to Q5

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46:31 Home work Ans:- (y+1)(2y+1)(y-1) Thanks sir

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35:29 ( in the third step it would be (x-1) (x-2) ( x+1) ... But you wrote (x+2)

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(Y+1)(2y+1)(y_1) thanks sir

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Q5(i) ans ❌️ right ans is (x-1)(x+1)(x-2)

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(2y+1) (y+1) (y-1)

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34:33 sir kindly tell u that yaha pe (X-2) middle me hoga

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5.) question me (I) wla ka ans= (x-1) (x-2) (x+1) hoga

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(2y+1),(y-1),(y+1) is a right ans

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(y+1) (2y²-3y+1) (y+1) [y(2y-1)-(2y-1)] (y+1)(2y-1)(y-1) Bahut aasaan chapter hai 46:30 46:30 46:30 46:30 46:30

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46:39 h.w. p(y) = (y+1) (y-1) (2y+1) thanks

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(y-1) (2y+1)

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Part 5 (i) your answer is wrong the correct answer is *( x-1 ) ( x-2 ) ( x+1 )* but your answer is *( x-1 ) ( x+2 ) ( x+1 )* 35:33

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35:33 Sir 5 ka first number ka question me (x-1)(x-2)(x+1) correct Answer hoga shayad se lekin aapka (x-1)(x+2)(x+1)

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Ans. (y+1) (y+1) (2y-1)

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19:19

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