Mechanics of Solids | Principal Stress and Strains | Direct Stresses combined with Shear Stress |

[@ManasPatnaikofficial]

Please make a correction at 31:16, the max shear stress formula written at the center of White board will not have (1/2) fraction outside. Sincere apologies. That's the downside of teaching infront of a camera, it cannot intervene and make the necessary correction.

[@CarlJohnson-tr1lm]

A teacher is that person or a personality who turns difficult problems or scenarios into easy and approachable solutions. That's you sir. Really you are very hardworking, talented and skilled tutor that can make above statement justifiable. Thanks sir soo much. 😌😌

[@ManasPatnaikofficial]

Thats really motivating Carl.....Thank u so much.....I wish you all the very best in future endeavors.

[@BCS-IshtiyakAhmadKhan]

This is the best explanation i have ever came across

[@onkarsabnis60]

Sir,An additional 1/2 is not needed outside the expression of max shear stress(t=31:24)

[@ManasPatnaikofficial]

You are right Onkar....... That's my mistake.,... Do ignore.......

[@anushreedutta5097]

So clear and beautifully explained the subject. Thank you so much sir.

[@kulasekarans5428]

I feel very blessed to be your student sir. Your teaching method with your level of dedication and efforts is truly awesome and inspiring. I've always wanted to learn concepts deep and in an understanding way. I was never able to understand these concepts in college. But now that problem has been solved. I wish every teacher could be like you. 😊

[@ManasPatnaikofficial]

It's my pleasure and i wish you all the very best in life. And do share this with your friends and juniors also so that they can also benefit.

[@hritiksingh3870]

superb teaching style..i understood all the concepts and derivation of formula for determining stresses in an oblique section by analytical method....u are the best...other teachers teach and if there is mistake they dont correct it ..that means they themselves dont watch their videos ...you correct your mistakes ...and this dedication of yours is much appreciable...keep us inspiring sir...thank you

[@rupendrachandaluri9327]

No one can expressive in this clear way except you,its a wounderful lecture.great.taq.

[@Harsha_-ly7nh]

I understood each and every concept ....you are an awesome tuitor .....thank you sir🥰

[@nandipatisai]

sir,1) what is active shear stress. 2) At 32:48 also we can multiply and divide again with +,- na as u did at 20:5

[@zishanahamed1170]

Sir, Why there is 1/2 at max. Shear stress equation at 30:39....its already inside the square root.

[@ManasPatnaikofficial]

You are right Zishan......

[@aashidm]

What at lecture, liked it a lot sir wonderful!!!!!🎉🎉🎉🎉🎉🎉🎉🎉

[@nunfeli7145]

Most probably the best explanation sir!!!! BIG THANKS!!!!!!!!

[@VedSurendraThakurBME]

Very Good Video....Amazing Teaching....neatly understood everything

[@sunillambert431]

Great video ! Your enthusiasm and effort is inspiring. Keep it up. Thank you

[@vaisakhktharakan5366]

Great. Keep it up👍

[@ganeshshenoy1344]

So neatly explained!! Awesome 👍

[@ManasPatnaikofficial]

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[@suhailmhmd3117]

Sir u r awesome.😍

[@mariosa6741]

28:04 great beat !!

[@ritesh.5160]

Respect sir 🙏🏾

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All the best and do share this channel with your friends and classmates, so that they can also benefit. Download the Manas Patnaik app now: bit.ly/3wMRxoc

[@pradgadagkar8557]

Well explained Squire

[@harshithvarma6583]

thanks a lot sir .the topic is crystal clear now.thanks a lot once again.

[@jairadhegovindji]

very good explanation...

[@kuldipdhokiya7733]

It was very great video sir 👌 keep doing sir

[@saravanajogan1221]

Good job sir

[@alekul2020]

Neatly done ✅ you nailed this topic!

[@ManasPatnaikofficial]

cheers and all the best

[@VickyLenzer]

Great Job:)

[@motvo1430]

do it just consider the rotation of normal stress in the 1 direction, right, i think we should consider both normal strss in 2 direction x,y

[@poojanshah4782]

Amazing explanation sir

[@balaganapathy6869]

am doing self preparations sir and ur videos are so helpful......keep up.

[@ManasPatnaikofficial]

All the best bala....

[@manpreetsingh7005]

Thnks alot 💯

[@sahilpandey288]

Sir in case 4 if the shear stress is not applied then the tangential stress would be negative as it would rotate clockwise according to mohr circle but if I use this same equation I wouldn't get a negative value of tangential stress.. How is it possible sir?

[@BCS-IshtiyakAhmadKhan]

Excellent sir but we can find max. Stress directly. The max. and min Value of Acosx+Bsinx=+_✓(A^2+B^2)

[@SatyajeetSingh]

Sir,,do you prepare ppt of strength of materials,, please let me know

[@CURRENTWORLD2.0]

Great sir

[@aniketsharma7412]

Loved the way you teaching whole stuff.... Jjust want to tell you A very very thankyou so much... Instead of it .....I have some queries....I think 1/2 should not be there in max. shear....

[@ManasPatnaikofficial]

Yes u r right.....that was an error on my part....

[@hritikvasuja6250]

Complex Chapter made pretty easy

[@hanumantborate994]

sir if u have an angle of rotation clockwise ( with respective CB reference plane) +ve and same drawn with mohr circle then 6t value is becomes negative but by analytical method it is positive. plz reply ..... also one request please solve one problem by both analytical and graphical method

[@shaniba3113]

What is active shear stress sir and also complementary shear stress.?sir pls clear. Your classes are so interesting and can be understood very easily.thank u sir .🙂👌👌

[@zhsana4611]

Thankyou so much

[@ManasPatnaikofficial]

All the best 😀Do share this channel and its playlist with your friends. 1. Engineering Drawing Playlist (ENGLISH): kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Drawing Playlist (HINDI): kzbin.info/aero/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU 3. Engineering Mechanics Playlist (OLD): kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 4. Engineering Mechanics Playlist (NEW 2023-2024): kzbin.info/aero/PLIhUrsYr8yHxeypEyVdWeGNxWHjNxU_JP 5. Mechanics of Solids Playlist: kzbin.info/aero/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 6. Theory of Machines / KOM / DOM Playlist: kzbin.info/aero/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 7. AUTOCAD Playlist: kzbin.info/aero/PLIhUrsYr8yHyLArdiiSDLa0Fmz8YKIy7G 8. Machine Drawing Playlist: kzbin.info/aero/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w Visit Main Channel Page(@manaspatnaikmech) for Playlists on specific topics. Second Channel for Hindi Audience: @btechplus Download the Manas Patnaik App for Premium content : bit.ly/3wMRxoc

[@savagedeuterium374]

Manas, lengths cannot be negative and hence how can you take two scenarios of positive and negative. Pythagoras theorem. ♥️

[@vikramdas4688]

Good explanation sir

[@ashishkunwar1533]

Sir I have a question.how you found the triangular section.plz solve it.

[@samratduttaroy2533]

Sir if possible kindly make videos for ies aspirants 🙏.

[@lakshman3609]

Sir u said principal stresses are normal stresses without shear but why we are considering always shear plz explain sir I getting totally confused sir...plz rply

[@balasreebindu8282]

Sir in 31:35 sigma max. =-√((sigma y -sigma x)/2)²+tau² hoga app ek extra 1/2 kardiye

[@eknathnishad8779]

Aaj mera subjects hai sir thanks

[@shadanjaved8827]

great sir ! but one of the formula you have written is wrong,there is an extra 1/2

[@ManasPatnaikofficial]

You are correct...... That's a mistake on my part.....

[@shivamsharanlall672]

Thanks!!!!

[@mryellow5294]

Please make videos on torsion

[@ManasPatnaikofficial]

need some more time Mr. Yellow.... Working on acceleration analysis right now.

[@ssrivatva1188]

Thanks sir

[@karthik239]

Tau max should be corrected ,there is no (1/2) extra in that expression all you guys should make it clear .... THANK YOU

[@ashishkunwar1533]

And plz make us understand practically and tell us its' real life use

[@pranavjadhav1987]

For manufacturing components and analysis in civil and mechanical components

[@bituponboruah9175]

Board ko thora zoom krke dikhna sahiye

[@daddy5315]

love u

[@ManasPatnaikofficial]

All the best

[@sunils122]

To be frank,, it's a complete lecture for those who are very much into solving the problems and not getting much involved in the actual concept......the concept which u tried to explain can be interpreted from just looking into book derivatives...it's that simple... The thing is, u didn't try to explain exactly all thoz terminologies out Ter like principle planes, principle stresses and theres lot of angles associated with the very concept of getting the direction of the actual principle plane that u should have convered thru some good examples. Watevr...!!!!!!