You are the only channel that goes into details concerning robot thank you
@CivilEngineeringEssentials Жыл бұрын
Hi there, thnx a lot for the great comment. I am happy that my deeper dives help you understand robot better. If possible, could you suggest this channel to your friends? it helps a lot. Regards, CEE
@BA-gp7sr Жыл бұрын
@@CivilEngineeringEssentials all ready did I shared your channel with my colleagues.I was wondering if you are going to make a full playlist about RCS modling and analysis.
@CivilEngineeringEssentials Жыл бұрын
It is the next project after the current warehouse design series.
@tukangsipilofficial1362 Жыл бұрын
alhamdulillah Thank You Civil Engineering Essentials
@CivilEngineeringEssentials Жыл бұрын
I am very happy you liked those my brother ^_^ Stay tuned, CEE
@yusuffmusbau11407 ай бұрын
You are the best in this. Thank you much
@CivilEngineeringEssentials7 ай бұрын
you are most welcome ^_^ stay tuned for more content. Also, if possible, please consider sharing this channel with your friends.
@AliAsad-w8p8 ай бұрын
best explanation !!
@CivilEngineeringEssentials8 ай бұрын
thnx a lot, I am honored. Stay tuned for more content. If possible, plz consider sharing those videos with your friends. It helps a lot.
@canal8222 жыл бұрын
GREAT VIDEOS!! BEST ON THIS "ROBOT" TOPIC. GG!
@CivilEngineeringEssentials2 жыл бұрын
thnx a lot. help the channel grow by suggesting it to your friends 🙂
@mwirigimarete22312 жыл бұрын
I really like your videos thanks alot
@CivilEngineeringEssentials2 жыл бұрын
Glad it helps. Most welcome
@engcivil8275 Жыл бұрын
Amazing ..
@CivilEngineeringEssentials Жыл бұрын
Thank you very much. Stay tuned for more content.
@civilengineeringwitharas4776 Жыл бұрын
Can we release the moments partially ? like for the semi rigid connects ?
@CivilEngineeringEssentials Жыл бұрын
Yep, you can by checking out the "Linear Release" or even a "Non-Linear" release when defining one. In a linear-release case, the release is replaced with a rotational OR linear spring based on the released direction and the spring constant that you provide during the definintion. In a non-linear release, you would define the full force-displacement or moment-rotation curve. If I remember correctly, robot might ask you to enable some higher order calculation options in case you are using non-linear hinges (if those options are disabled in your robot at the moment). I think I should provide a video about that issue to talk about the underlying theory and how robot does model those linear releases, but I wanted to answer your question first. Hope it helped, stay tuned for more content, and - if possible - please suggest this channel to your friends, it helps a lot. Regards, CEE