27.03 Hammett Substituent Constants Defined

  Рет қаралды 7,409

Michael Evans

Michael Evans

Күн бұрын

Deprotonation of para-substituted benzoic acids as a model reaction for substituent donating/withdrawing strength. Defining the para Hammett constant. Defining donating and withdrawing groups in terms of the Hammett constant.
00:00 Measuring Electron Donating or Withdrawing Strength
01:00 Deprotonation of para-Substituted Benzoic Acids
02:37 Electron-donating Groups and Acidity
05:33 Electron-withdrawing Groups and Acidity
07:06 Effects of Donating and Withdrawing Groups on Acidity
08:06 Derivation of the Hammett Constant
12:00 Meaning of the Hammett Substituent Constant

Пікірлер: 5
@esoto1386
@esoto1386 2 жыл бұрын
Its awesome that these videos are available, and so well explained! Thank you for your work!
@mubarakayinla
@mubarakayinla 3 жыл бұрын
You made it easy to understand. Thank you 😊
@janvisagie231
@janvisagie231 2 жыл бұрын
Great vid, though I have to say, this is the first time I see someone using blue color code for electron poor positions and red for electron rich positions XD
@mevansthechemist
@mevansthechemist 2 жыл бұрын
Really?! 😂 I swear it's not just me. Thanks for watching!
@ahmedhegazy6080
@ahmedhegazy6080 3 жыл бұрын
Dear doctor, i have two questions in organic chemistry and i hope that you help me answering that questions the first one regarding reactivity of phenol and anisole why phenol is more reactive than anisole even methyl group is an electron donating group that will increase electron density on phenyl ring and hence increases reactivity towards electrophilic substitution such as the case of aniline and di methyl aniline and the second one regarding possibility of hydroysis of ortho cyano alkyl benzoate which i have read that it strongly dependent on PH of medium if the ph of medium is lower than 2 the rate increases five times its intial value so what happens at lower ph that increases the reaction rate dramatically is it associated with cyanide hydroysis i hope that you help me doctor thank you so much
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