Electrical Engineering: Ch 13: 3 Phase Circuit (40 of 53) How to Find the Power Factor?

[@gipsyavenger8365]

Thank you so much for the video! Keep making us smarter!

[@brevinearl128]

This guy’s bow tie is my spirit animal

[@MichelvanBiezen]

It is my trusty companion.

[@tchakountehyacinthe6340]

thank you so much. I have a question: the power consumed by the motor is it the real or reactive power since the motor have both inductances and resistor coils?

[@MichelvanBiezen]

By definition, the power consumed = I^2 R The induced current will be in the opposite direction of the current that drives the motor, but the equation still holds.

[@stevebjee]

I'd recommend one small correction. You used Watts as the unit for Apparent Power (S). This would typically use VA for the units.

[@MichelvanBiezen]

You are correct. Thank you for the input.

[@amossichone9455]

How can i calculate the reading of the input power given the output power, power factor, efficiency and voltage of 3 phase

[@abdeldjalilyahi3322]

Professor, isn't it the unit of apparent power : Volt-ampere (VA) and not Watts (W)... I think you made an oblivious mistake there.

[@MichelvanBiezen]

Technically you are correct.

[@sanghairony464]

Love from Asian country Bangladesh 🇧🇩🇧🇩🇧🇩

[@MichelvanBiezen]

Thank you and welcome to the channel!

[@mamounabuabed]

Does the line current is the full load current amp of the motor?

[@liveurlyfchannel9641]

Thank you prof

[@MichelvanBiezen]

You are welcome

[@sakunthadassanayake]

Thank you very much teacher.

[@paninshonko8927]

Amazing

[@MichelvanBiezen]

Thank you. Glad you found our videos. 🙂

[@akbarhidayat5755]

thank youu

[@MichelvanBiezen]

You're welcome!

[@saifalharthi4677]

Thank you sir I have a question please I have a motor nameplate, the information given : I = 27.13 A V = 415 V Output power = 15 kw And p.f is 0.87 When i used the method which you have explain i got 0.76 p.f and it does not matching p.f which is given ( 0.87) 😅

[@MichelvanBiezen]

The power factor does depend on the load and the power consumed (I^2 R) versus the power provided (IV).

[@najamhasan4543]

Great

[@GH-oi2jf]

I don't think that ".2" is a significant digit.