Best teacher , and the best channel to learn astronomy
@sunetamendis52624 жыл бұрын
Great video. Oddly satisfying to watch this...
@theworldofspace86203 жыл бұрын
i wanted to learn how to calculate the magnitude of a star and now I know, thanks for the explanation.....Beautifull explanation
@MichelvanBiezen3 жыл бұрын
Happy to help
@homo_spider56073 жыл бұрын
Sir, my favourite subject is history and I start reading astrophysics recently. I find your video easy to understand. Thanks
@MichelvanBiezen3 жыл бұрын
You are most welcome
@manisky90263 жыл бұрын
Teacher Mattersssssss... Thank you for the awesome explaination.
@MichelvanBiezen3 жыл бұрын
Glad it was helpful!
@manisky90263 жыл бұрын
@@MichelvanBiezen Thank You :)
@ezasuddy45584 жыл бұрын
Where do you get the number 2.512 from when doing the brightness difference calculations? Great video btw 👍🏻
@MichelvanBiezen4 жыл бұрын
That number was chosen (not by me) so that 2.512^5 = 100 by design.
@alexiapickens34284 жыл бұрын
How do you find the flux ratio if you are only given the magnitude of one star? Im trying to solve this question and am very confused. If we have a two identical stars and one is twice as far, and the close stars apparent magnitude is +5 how do we know the magnitude of the other star? I don't understand how I should find the flux ratio if I'm only given one apparent magnitude. The apparent visible magnitude of the closer star is +5. What is the apparent visible magnitude of the more distant star?
@MichelvanBiezen4 жыл бұрын
They are identical stars so they have the same absolute brightness. If one is twice as far, the intensity will be 1/4. Then you take 2.512^m = 4 (for the close one being 4 time brighter). Take the ln of both sides and you get m ln(2.512) = ln (4) solve for m and you get 1.5 That means the far star has an apparent magnitude of 5 - 1.5 = 3.5