Minesweeper oddities and their probabilities: 8, 77, 8-8; no 0,1,2 boards; 1-click boards.

[@sharpfang]

"Yes, but what about 27" - Oh, hello. Glad you asked. Don't stand up now. Under your chair there is a bomb. It will blow up if you stand up, or if the square you uncover in the next game you play is a bomb. The bomb under your chair will self-disarm if you successfully mark all the bombs on the board. Welcome to 4D minesweeper, where the highest number you can uncover is 80. Oh, also, if you ask about 81, the bomb under your chair will blow up.

[@incription]

That's childsplay: In 5D minesweeper with multiverses and time travel, you have to worry about uncovered mines in the past blowing you up. And don't even mention grandfather mines.

[@nef36]

@@incription I used to be a big fan of 5D minesweeper with Multiverse Time travel, it's too bad things like the terminator gambit, Jurassic moves, and the exile strategy have made the game stale and unfun

[@JalebJay]

What about 81? What about 243? What about...?

[@bluetom93]

@@JalebJay SILENCE MORTAL. YOU WISH TO PLAY.... D MINESWEEPER?

[@claudetheclaudeqc6600]

what about 69E^69 billionsD minesweeper

[@YoungTheFish]

I rate this video a 9 out of 8.

[@thiccnoodles6767]

I rate 27/26

[@starlii10]

81/80 for me

[@samuelthecamel]

243/242 for me

[@PhilippeAndelhofs]

Still 9/8 is higher than 27/26 etc.. 😆

[@had0j]

729/728 for me

[@rishitpant]

3D one it so cool! Gotta try my hands on it.

[@acatfrompoland5230]

Spat out my water when he said "Yes but what about the 27".

[@monsieuralexandergulbu3678]

Damn, dude even got the Putin's cat view from the back drawing on the wallpaper!

[@GamesComputersPlay]

Very keen observation. Actually, the first time I saw this "Cat. Rear view." drawing was during my school years (sometime in the 90s, a few years before Putin appeared in Russian politics). It was one of those things, sort of what memes are to modern kids, except you actually had to draw it, not retweet it. I have no idea about the origins of the picture, but if Putin knows it - it must have originated at least in the 60s or 70s, maybe earlier. These days, however, it has become, indeed, "The Putin's cat". Oh well... Not the only thing the guy ruined, not the biggest one, for sure.

[@monsieuralexandergulbu3678]

@@GamesComputersPlay Oh, interesting. I didn't know bout the origin of this За просмотром видео меня терзали смутные сомнения, я всё никак не мог избавиться от мысли "русский он или нет?🧐🤔", однако, моя неуверенность продержалась не долго, стоило лишь зайти в раздел "About" ;) По поводу же действий того, чьё имя нельзя произносить) мыслей слишком много, чтобы передать их здесь. Да, и не место им тут. Я думаю, так получается у любого мыслящего человека. В любом случае, приятно видеть, что есть мотивация делать видео, keep it going!

[@Lugiamasterbrony]

I mean they could make a separate category for 9x9 without invalidating the 8x8 records.

[@GamesComputersPlay]

Yeah, I this sounds like a reasonable solition. Not sure whay they didn't do that. I would guess 9x9 was interoduced to late, and the standard was set by then, IDK

[@hebruixe9125]

i think it would be a better game with 9s and even 10s.

[@darkveneno6155]

Isn't the chance of an 8 a bit lower because of the fact that 8s can't exist on the corners or that doesn't affect the chance at all?

[@GamesComputersPlay]

Yes you are right, you can't have 8 in the corner, but that's already taken into account: - in the simulation: well, because 8 can't appear in the corner in the simulation too, right - in the calculation: we count (width-2)*(height-2) as the number of possible places to have 8 on. This makes sure we only calculate valid positions for 8. (for example on a 3x3 field you'd have only 1 way to have 8, on a 4x4 field - 4 ways, etc)

[@chupathingy5862]

Will you bump my nerdiness up to 9.5 if I watched this while soldering?

[@EebstertheGreat]

In Minesweeper, a "9" is a 3x3 array of mines. It's not a real number you can get. However, it is exceptionally rare.

[@GamesComputersPlay]

I kinda suspected that, but never got a proof. Now, looking back, the nine questions were too persistent to be pure trolling.

[@gadgetlab7]

@@GamesComputersPlay yeah its pretty much universal to call that a 9 in the minesweeper community, its also universally hated by everyone

[@pokepress]

I assume the part where it gets really bad is where you have two 3*3 groups that have a ring of mines on the outside, but you know based on the number of remaining mines that one has a mine in the middle, and the other doesn’t, basically making you make a blind 50/50 guess.

[@valseedian]

@@pokepress expert games are highly likely to end in a true 50:50 guess. more than 50% but probably not much more. I think the linear algebra solving technique can reach 45% solve success but I'm not sure if that includes successful 50:50 guesses. my own solver will halt and start a new game if it detects any 50:50 guess, but it only looks for those if there are no detectable safe squares. but my solver doesn't detect 7s exactly (because 7s are the same color as bombs if i only detect 3 bombs or less on a board I treat them all as 7s) and won't detect 8s at all because they aren't solve probative.

[@OrangeC7]

My first thought was that you actually could have numbers greater than 9 in a minesweeper board with hyperbolic geometry

[@mallomon]

For the 8 in the shape of an 8, it made some sense to me. If you have one 8 already, you're using 8 of your mines in that 8, and these 8 mines are arranged in four edges of three consecutive mines. If you are to have another 8 on the board, starting with one of those edges gets you 3/8 of the way there, and requires you to use up three fewer of the total mine allotment. So it should be much more likely than random chance that, knowing you have an 8 on the board already, and knowing you have a second 8 somewhere, the second 8 would share an edge with the first

[@radeklew1]

Yes, two 8s involve the positions of 16 mines, while a figure 8 only involves 13 mines, but with additional constraints on position, so it mrke sense that those two effects roughly cancel each other out

[@GamesComputersPlay]

You (and other people saying they were not surprised) seem to have a well tuned probability intuition. Now, when I know the answer - yeah, I guess it makes sense. Bit when I saw the results for the first time, I was really suspicious there was a bug somewhere. Was totally in disagreement with my intuition, and even nwo it still rubs against it a little. For me it stands right next to the birthday paradox and Monty Hall paradox. (which fooled my intuition too the first time)

[@platinummyrr]

yup. The fact that 8s can re-use the same mines is why its much more likely!

[@jonathanblake831]

@@GamesComputersPlay Honestly you were already there talking about the array of 9, I think you just hadn't connected it to this occasion.

[@zuthalsoraniz6764]

Yep. Despite the fact that there are a lot more ways to arrange two 8s on an intermediate board than one double 8, the 24 free mines on 238 cells of the two individual 8s gives ~5.3*10^32 remaining mine patterns per two 8s pattern, while the 27 free mines on 241 cells of the double 8 gives ~ 4.2*10^35 random mine patterns per double 8 pattern.

[@EvilParagon4]

Back in highschool I used to always play a 83x38 custom board with 750 mines to pass the day instead of doing classwork. This was basically fullscreen minesweeper for my laptop and had a density of 23.78%, so just a little bit harder than expert. It took me a whole year to finally win a game lol. It took about 4 hours to get to the end game, but with a board and density of that size, the probability of getting way 4-6 pure 50/50 choices was basically guaranteed. It was a coinflip until you win at that point. Keep in mind you need to first get to that stage, which could have misclicks or even just a small but quick lapse in thinking could end your entire game.

[@KazyEXE]

Same but with 10 mines.

[@Ibbys_space]

my best is 99 mines and I'm a freshman haha (that also means I've pretty much beaten the Google version since there aren't custom boards)

[@MyWaifuNow]

i have ended many, many games with a miss click

[@NickSmith-zm4kw]

my middle school dream

[@CycleMantis]

​@@MyWaifuNow it's technically a bit slower, but I'm quite partial to playing minesweeper with keyboard only (especially better than a laptop trackpad)

[@Kpsla]

The 8-8 thing makes sense to me. To get two full 8's, you need 16 mines to be placed exactly right, but for one single 8-8, you only need 13 mines to be placed in the right pattern. Or, thinking about it more abstractly, once an 8 has already been placed, there are only 5 mines that need to be placed after that to make that 8 an 8-8.

[@JayTrip05]

Welcome to the club, me and Mallomon also posted on this, but I'm pretty sure none of us actually knew of the others.

[@red_rassmueller1716]

@@JayTrip05 i actually wanted to see if anybody got that first... so i'm not in the club although i wanted to post that too XD

[@doodeedah6409]

It’s more than that. Reducing 8 to 5 definitely improves its chance, but it’s really down to the limited number of available mines that makes it so likely to occur. The fewer mines available, the more likely the two 8s will have to share them. If you have few enough mines (e.g. 14) regardless of the board size, the chance becomes 100% because there’s simply no other way that two 8s can physically form on the board.

[@Jivvi]

​@@doodeedah6409with 14, you could still have them off by one, so they only share 2 mines. Also, does being aligned horizontally instead of vertically still count as being in an 8 shape?

[@doodeedah6409]

@@Jivvi Oh whoops, I miscounted, I meant 13 mines, i.e. 3 mines forced to be shared. Btw the fine print at the bottom of the video says he counts both vertical and horizontal shapes.

[@laytonspuzzle]

Actually, 27 IS possible if you're willing to up your Minesweeper game to four dimensions. In 4D Minesweeper it's actually possible to get numbers as high as 80. But what about 81?

[@R3DCODE]

5D minesweeper with multiverse time travel

[@jhawk2402]

Actually, 81 IS possible if you're willing to up your Minesweeper game to five dimensions. In 5D Minesweeper it's actually possible to get numbers as high as 242. But what about 243?

[@chandir7752]

@@jhawk2402 well, just enter the 6th dimension. But what about 729?

[@irrelevant_noob]

@Bobbeguille but is your version of 4d minesweeper using TIME as its 4th dimension? :-B

[@singadorito7802]

@@chandir7752 but what about 1024? or 16384... or huge numbers?

[@kennylex]

Lamers, 2D and 3D is sooooo 2020, today 'retro' is cool and real players do Minesweeper in 1D.

[@astrylleaf]

I would actually love to code this

[@josephhanicak7922]

I've actually had an 8 before. I was looking for it by setting the difficulty settings to max, with there being like 100 mines. Took like 20 straight minutes. Was so hyped when I found it.

[@ScowlingZebra29]

Minesweeper in VR is an absolute trip to go through, yes it's just 3d minesweeper but somehow it's immersive. I don't really say that but it's one of my favorite free VR games to use a way to pass time without having to move around to much. Kind of like putting a picture puzzle together, it's really interesting how it unfolds. I'd recommend checking it out if you're a fan of minesweeper itself.

[@ViolentShrike]

When I was a kid I used to change the settings of the game to use the biggest board with the fewest mines so I could basically “farm” one click wins. Sure it was cheating, but I barely even considered minesweeper a game and the most fun I could have with it was this way lol

[@khunphraeokha]

good

[@webrunner42]

In Super Mario 64 speedruns whenever something occurs that would make two sets of records (such as 120 vs 70 star, then 16 star, then 1 star, then 0 star) they just split the leaderboards. Super Mario World also has two common Any%s: regular gameplay vs using the Arbitrary Code Execution glitch to jump to the credits from level 1. I think minesweeper could do the same.. have a 8x8 leaderboard and a 9x9 leaderboard.

[@EebstertheGreat]

Speedrunning beginner is sort of pointless imo. As the creator pointed out, you can beat beginner in a single click with 0 on the clock. These zeroes are simply not counted on the leaderboard, because otherwise the top of the leaderboard would just be full of them. So instead, you have to click at least twice. That means people who want to grind a good beginner time just keep refreshing the board and randomly clicking twice. Each time randomly clicking twice doesn't win, they refresh. They try to click as fast as possible, maybe using a mouse that double clicks if you push the button right (usually an undesirable behavior). For instance, the minesweeper online #1 time is 0.02 seconds, apparently accomplished by dragging the mouse along the top of the board. Splitting the 8x8 and 9x9 times wouldn't change that. Beginner is just silly.

[@GamesComputersPlay]

Interesting point. I actually agree about 2-click being mostly luck. What they did about it is they introduced Beginner 3BV category that limit minimal 3BV at 10. It helps somewhat, still they have a few disqualified attempts because "there was one lucky click". Which is now a bit weird. So what, lucky click? If at the shooting competition I shoot without looking and hit bull's eye, I still get the prize, right?

[@EebstertheGreat]

@@GamesComputersPlay Yeah, it also must be incredibly frustrating to try to grind. Every top time must be "lucky" to some extent, so it feels like if you get _too_ lucky, then it just doesn't count anymore. Imagine if whenever a golfer got two holes in one in a single round, that round got disqualified.

[@andy02q]

@@GamesComputersPlay What is the chance to beat a beginner board with a 3BV of at least 10 with only random clicks? If it's less than a million, then there's a real chance to piss off some pros. :D

[@nicholasiverson9784]

The two 8s in an 8 configuration odds are actually fairly intuitive. Given an 8 on the board, there are two places (as long as it's not too close to an edge - and assuming you want them vertically orthogonally connected) where there are already 3 mines in a row. Requiring only 5 mines to be in specific places, to accomplish the goal of two 8s. Where a disconnected 8 on the same board as your 8 requires 8 specific mine placements. The reason it's only 1/3 as likely as finding a 2nd 8 floating in some unknown far off location is because there are significantly more than 2 places those 8 specific mines could be arranged than 2. But that only just over compensates for the 8th power vs. 5th power comparison.

[@justingolden21]

OOOOH because it's GIVEN that there's already an 8 and a limited number of mines and an additional 8 should be next to 8 mines

[@JayTrip05]

Me, Kpsla, and Mallomon have all also posted on this without knowing of each other funny enough.

[@Jwellsuhhuh]

@@justingolden21 no, not given, but the chance is not as small as expected because you only need 5 mines to be in a specific location instead of a whole new group of 8 mines

[@kenthemaster]

I liked that little tidbit about javelins resetting their records after some redesigning. I'm sure there are similar examples of other sports/games doing so, but it is quite refreshing to find these trivia in your vid!

[@shades909]

Yeah, the funny thing though is that I have seen that in a video I watched just a few days ago, and now I wonder if that's why I got this video in my recommendation lol

[@yuralis123]

For those interested. The javelin was redesigned since it was easier to make the javelin heavier than make every stadium larger. Therefore it became impossible to throw as far as before and thus all the records had to be reset

[@harrisonleon577]

@@yuralis123 also, it was done because someone threw too far

[@superdupergrover9857]

Hmm. I always assumed that Minesweeper solved the "first click problem" by choosing an appropriate board after the first click. It would keep randomly producing boards until a compatible one revealed itself.

[@GamesComputersPlay]

To be honest, I couldn't find any reliable info about latest minesweeper clones and how they handle it. But for old version - yes, they just move a mine. Also, I think they do create new board in "no guessing" mode in some implementations. (As just moving mine can create a guessing situation).

[@atlekristiansen4975]

I have wondered about this "What if the first click is a mine"-issue and how they solve it, when you're suppose to be safe that one time. There 's actually a Game Boy versjon of "Minecraft", which «solves» the whole problem by letting you actually get a bomb on your first click... kzbin.info/www/bejne/fl7Ufqyvjqdooa8

[@wormalism]

The best way would be to shift the whole board down and to the right to the first safe spot, wrapping the bottom rows to the top and the rightmost columns to the left.

[@valseedian]

@@GamesComputersPlay almost every "no guess mode" version tells you which first click to make. they generate these boards by actually solving them and when a situation is reached that would be unsolvable it moves mines then to currently uncleared spaces that aren't associated with a cascade and continues solving. if it can't find a place in uncleared blocks, it puts it in any space that doesn't boarder any other mine. if a move was moved in this way it begins solving again from the beginning. seeds for these states with the starting square are pre generated and stored, often by brute force. my approach is slightly different. I run a solver that doesn't guess on my home computer and note seeds and starting clicks for any win. those are innately solvable too.

[@NoxmilesDe]

It's ... Ninesweeper.

[@darkskyinwinter]

I got really good at this at one point, and I used to play a larger board. I think 24x30 with ~165 mines. I remember the cutoff was pretty sharp, where most games under that number of mines were easily solvable with good initial guesses. More than that and I had to start making too many good guesses to win. I never ran probabilities though.

[@NLnaga]

What are the odds to have both an 8 and a 3x3 clumb of mines, meaning u would end up with a 50/50 click to win the board

[@guyinacage]

I think the reason the 8 of 8s is so likely is because it shares 3 mines between the two 8s. The configuration requires only 13 mines and the remaining mines can be anywhere else, while having two separate 8s would require a whole 16 mines split into two groups. I think it is misleading to compare the chance of getting an 8 of 8s to the chance of getting two separate 8s. Instead, the 8 of 8s should be viewed as its own kind of shape, and the chance of it appearing can be compared to the chance of two regular 8s that are not joined. It would be interesting to calculate what the chance of finding two 8s that share any number of bomb tiles is compared to finding two disconnected 8s. I would bet that it'd be more likely than not that if there are two 8-tiles on the grid, that they share at least one bomb.

[@GamesComputersPlay]

hey, let me run that. I'll report back.

[@GamesComputersPlay]

ok, I ran a bigger simulations (220M), here's what I have: - just 2 eights: 122, 1/1.8M - 8s that touch each other at least in one spot: 88, 1/2.5M - 8 in a shape of 8: 71, 1/3.1M So: - Looks like my estimation of just having 2 eight maybe was a bit off in the video, it's looks to be more rare. However, it makes the "8 in the shape of 8" paradox even more prominent: difference between those are even smaller than 2 - You prediction that touching 8s are more common than non-touchin is quite true: almost 3/4 are touching each other. - estimation of 8 in the shape of eight still stands 3.1M and 3.2M - close enough.

[@JayTrip05]

Everyone is posting on this lol

[@ribbonsofnight]

@@GamesComputersPlay I bet the probability of two 8s that are immediately adjacent but don't use one set of mines in common is more like 100 or 1000 times less likely than any 2 eights. That would still use 16 mines

[@WolfieNamira]

These probabilities make me want to have all ~7 billion people on earth to play minesweeper once just to see what boards have these rare things lol

[@yeeterdeleter0117]

One time I randomly clicked and found an 8

[@andrewsauer9669]

The reason double 8 is not that much more unlikely is because it requires less mines in the formation than two 8s by themselves, allowing more leeway for the rest of the mines.

[@abearends]

I’m so glad to see this vid come out! I played a game of minesweeper in 9th grade where the very first click was an 8. I felt like I won the most useless lottery ever lol

[@Trupen]

awesome video :D

[@AlexanderBukh]

you are also awesome!

[@SaItogaming202]

i think that when you get an 8 they shouldve made it so its animated and looks like its on fire

[@sergiugrigorehandru9035]

What is The change of getting two 7 in an expert game witch are not next to each oder

[@Pilgrimman007]

What is the hardest possible board? By hardest I mean "requires the most forced guesses"?

[@Slush_]

In University I worked on a machine learning algorithm to play Minesweeper (with... mixed results, I was a rookie), and 1-click games became a serious problem. Turns out my board wasn't dense enough and they were more common than they should have been, it fed the algorithm a ton of bad habits because that click ended up with a massive reward score. That one eluded me for a while...

[@mpeterll]

I've never had a double-7, but I did once get a triple-6. I know that's not nearly as rare, but it was still a fun find.

[@ribbonsofnight]

I was thinking that's got to be more rare and then I realised 666 not 767.

[@TraceyGaming45]

Ha ha ha I got a 7 5 5 5

[@kiraa96]

Hey, I made it in this video! 4:40 :D

[@AlexanderBukh]

wow

[@UofU10]

Excellent video, I would love even brief slides showing your probability calculations but that’s just because I’m a math nerd. Love the content

[@GamesComputersPlay]

Thanks, man! There actually just some excel formulas, like this one (this is probability of 8 for expert): =(30-2)*(16-2)*(COMBIN(30*16-9,99-8))/COMBIN(30*16,99) Except I put board size, mines, and size and mines of the object in separate cells, to be able to re-use it for different things. It breaks for bigger numbers, but should work for everything in the video: 8, 9, 77, 8in8.

[@kylegrefe4399]

The double 8 thing makes sense, because it only has to have 13 mines in a set position, rather than 2 sets of 8 in set positions.

[@JayTrip05]

Lol, everyone is posting on this

[@AmyraCarter]

I've had many one-click wins; I just set the width and height to Expert and set the mines to ten! 🤣 (I also used to set the various sounds to something silly because reasons)

[@GamesComputersPlay]

1. This is childish 2. I did that too several times

[@bruh.5620]

@@GamesComputersPlay chill

[@GamesComputersPlay]

@@bruh.5620 cmon, I'm just kidding. Everybody did that, once discovered that you can set any number of bombs.

[@bruh.5620]

@@GamesComputersPlay oh ok

[@JayTrip05]

The reason the probability of the two eights being close to each other is so high is because it's easier for 5 mines with one space in the middle to spawn close to the 8 than it is for an entirely different ring of 8s to spawn. In essence, they are simply both 5s sharing 3 mines, not two completely separate 8s. As to them being on top of each other, not necessarily. The same logic applies sideways, where they could form the shape of an infinity symbol. I hope this explanation makes sense.

[@JayTrip05]

I will admit, Mallomon posted on this first, so credit where credit is due, however, I had no idea they had posted until just now.

[@EthanCowlbeck]

I mean, it makes sense. Having 2 8s anywhere on a board requires the correct permutation of 16 mines, where as when they’re bordering, you only need 13 correctly permuted mines

[@zuthalsoraniz6764]

The correct way to calculate it would be a multi-step process. First step: Calculate the total number of different mine patterns, this is [number of squares] choose [number of mines], so 64 choose 10 or 151473214816 for the old beginner board. Next, calculate how many different ways your chosen pattern fits on the board. For the 8, that is 36 different ways - the 8's center square can lie on any of the 36 non-edge squares of the 8x8 board. Then, calculate how many different ways the non-pattern mines can be arranged for each of those ways - in the case of the 8, that is 55 choose 2 - two mines remaining, and we have used up 9 of the board squares for the 8, giving a result of 1485. Multiply the latter two numbers together, and divide by the first, to get in this case 36*1485/151473214816=3.53e-7 or about 1 in 2.83 million odds. This also shows why the 9/filled 8 is so much less likely in the beginner board: It only has one additional mine left, so there are in total only 1980 patterns that give you it, vs 53460 patterns that yield the normal 8. This also means that on the new 9x9 beginner board, the chance for an 8 is 49*2556/1878392407320=1 in ~15 million - yes, there are more than ten times as many total different mine patterns on the 9x9 board as there are on the 8x8 board!

[@JohnPaulBuce]

3:25 why not make a whole new category for 9x9, just like what other speedrunning leaderboards are doing

[@sfdjk]

I think nine is a 3x3 field full of bombs

[@ThymeLost]

I used to get a mine on the first click back when I played.

[@GamesComputersPlay]

I guess it wasn't Windows minesweeper?

[@ThymeLost]

@@GamesComputersPlay I was the windows that came with windows 98 I think. I didn't play none windows minesweeper. Sometimes I'd start in the corners and the first click would be a mine. Sometimes it would happen in the middle of the field. It might have been windows95.

[@henryginn7490]

I love this kind of stuff. Finding out the answers to these "what if" questions purely for the sake of being curious and the programming pleasure

[@pleaseenteraname1215]

4d chess ❌ 4d minesweeper✅

[@BrenoKretzer]

How to have a 100% chance of getting an 8 1. Set the board size 3x3 2. Click on the middle and there you go

[@karlrovey]

I'm pretty sure I've lost on the first click before.

[@TatharNuar]

12:22 I immediately guessed that the conditional probability was going to be very likely, considering that it would only need an additional 5 mines for the second 8, instead of 8 for fully-separate 8s. You could also have 8s that share one or two mines, and I would expect either of those probabilities to be greater than fully-separate 8s too.

[@JayTrip05]

Everyone is posting on this lol

[@prich0382]

I still find Minesweeper is pure rng if you can win, using all the known tricks, usually at the end it comes down to a 50/50 pick or a 1/3. So stupid, I've only ever finished 2 games and gotten to like 90% every other time

[@valseedian]

with proper solving technique and a little math practically any 1/3 chance layout can be reduced to a 50:50. I think I've seen exactly 1 true 33%:33%:33% setup and it involved a corner and a few random guesses to reach.

[@prich0382]

@@valseedian Still not good enough, it's so BS seeing those fast game sequences where people solve each game 1 by 1 with no mistakes. You just can't be that lucky

[@bkCheezburgor]

6@6h6°h+h°v✓b+✓b+=h;=+=+j=+=+=j({jJ(jJ;✓£😊

[@endofpixel3712]

12:25 it actually makes sense since youre only looking at five additional mines as oppossed to 8 entirely seperate ones. I honestly thought that it would be slightly more likely then not but 1 outta 3 aint bad

[@GamesComputersPlay]

More careful simulation showed that it is closer to 1 out of 2. I agree, it makes sense to me now, I did get used to it. But my first reaction was pure disbelieve.

[@JayTrip05]

Lol, everyone is posting on this

[@rosejuliette9180]

I had a 3 click loss on expert. Click 1: 6 (Guess I should click on the other side of the board.) Click 2: 8 (Wtf well I guess the rest of this board must be pretty sparse.) Click 3: 💣

[@noobandfriends2420]

It's funny when thinking about 4D minesweeper, it occurred to me that if you play two 3D games at the same time, alternating turns on each board, you can conceptualize that they're the same board taken at different times where the mines have moved. You can even play some Schrodinger's cat with the boards by only placing mines once you've progressed on the other board because those internal spaces aren't available until you clear deeper into it.

[@ProfessorThock]

Me: watches 16 minute video about minesweeper probability Video: calls me a nerd Me: fine, I’ll subscribe.

[@maxmyzer9172]

i got a 9 once.. yes in 2d. also 4d minesweeper is fun disclaimer: the time i got 9 was when i did changed an open source minesweeper to include it

[@laurynastruskauskas6586]

Lol, i once got a circle of mines and i was so happy that i got an 8 which up to that point i thought was somehow prevented from happening. So i pressed it and there was a mine there, it really pissed me off, but now i know that it was even rarer and i got a screenshot of it so yayy i guess.

[@godlyvex5543]

0-8, consecutively, all in a line. I was playing a minesweeper game that had a bunch of wacky items that did various things, and managed to slightly manipulate some mines to create 0-8.

[@oskain]

not possible

[@naphackDT]

@@oskain Of course it's possible. 1-2-3-4-5-6-7-8 Of course, 12345678 is not possible because the 7 and 8 touching means that the 8 can never be fully surrounded by mines. (the smallest consecutive line of numbers that are touching is 1-7)

[@Michaelonyoutub]

for 1-7 X X X X X X X 1 2 3 4 5 6 7 X X X X X where X is a mine, so it needs 12 mines You can actually also save a mine if you zig zag the line at 4 and 2

[@oskain]

@@naphackDT I was talking bout 12345678

[@godlyvex5543]

@@naphackDT I more meant 12345678, with it being possible to have a mine on a number spot. Obviously impossible if every number has to be visible. I posted an imgur link with what I did, but I guess youtube auto-deleted it? that's kinda annoying. I'll try posting it again. if you don't see another post with the link then just know that it was deleted for some reason.

[@Vexy93]

I actually did lose a lot of minesweeper games at the first click when I was a child...

[@blank6989]

All fun and games till you get a nine

[@jayvw9597]

I got an 8 once on google minesweeper in class. Took a screenshot but then my computer got wiped and I couldn't save it. Was quite upsetting now that nobody believes me.

[@randomperson5579]

Someone needs to make 5d minesweeper with multiverse time travel, just 5d minesweeper you could get a 242 tile, but with the added multiverse time travel, well that number would probably skyrocket.

[@Sonlirain]

9 would probably be also possible in a non euclidean minesweeper. But good luck comprehending that mess.

[@hoppygrob3590]

There is no 9 because seven ate nine

[@GamesComputersPlay]

That's the kind of joke I should have thought of. Alright, here I go: But why did it ate nine? Because it needed three square meals a day!

[@bkCheezburgor]

Bro i Had to delete this joke

[@MonoCentennial]

that 3d minesweeper is a real thing it is especially amazing if you can play it in vr and i personally find it very fun

[@krystofkarda7395]

I Once got two 8-8 next to each other And i was JUST "wow thats neat" And continued

[@Mishigck]

Just got an 8 right before watching this video😂

[@kuwejtyt1680]

suggestion: what about a 2x2 square of 5's?

[@B3Band]

When I think of "9" I think of a bomb surrounded completely by other bombs. So you would have no way of knowing what's in the middle until the very end of the game.

[@GamesComputersPlay]

Yeah, turns out it is a slang name for that.

[@TaIathar]

Wonderful video. Now I'm curious what the odds of getting a 2x2 box of 5's is.

[@GamesComputersPlay]

Impossible in Beginner, 220M in Intermediate, 1.9M in Expert. (calculated, not simulated) Hm, interesting, not too improbably in Expert, actually.

[@TaIathar]

@@GamesComputersPlay Interesting... And thank you for the answer.

[@jackthehacker05]

I got a 6 a couple weeks back and was shocked, but an 8? Now THAT is rare.

[@3141minecraft]

12:44 think of it this way: if you have 2 eights in a shape of an 8, that only forces 13 mines but having 2 eights on somewhere far away forces 16 mines. That makes the 2 eights generating in a shape of an 8 a little bit more likely.

[@Therevengeforget]

What about 7-7-7, or boards with numbers only higher than 4? A 4x4 square of mines? 4's in a square? 5's in a square? A chain of 8's? What if the numbers average out to approximately pi, or e or golden ratio? How likely is it to get the same board twice in a row?

[@IIGrayfoxII]

3D minesweeper is what a vulcan child would play

[@Liggliluff]

The highest digit in any dimensional minesweeper is 3ⁿ-1 where n is the dimension. So in 2D this is 3x3-1=8, and in 3D this is 3x3x3-1=26. The highest number in 12D minesweeper is 531'440. The highest number in 1D minesweeper is 3-2=2. The highest number in 0D minesweeper is 1-1=0.

[@patrikcath1025]

You utter fools, discussing four-dimensional Minesweeper, I play 5D Minesweeper with multiverses and time travel. It allows for numbers up to 242. *But what about 243?*

[@machtharry]

The rarest thing i ever found (in about 50k Expert games) was a board with at least one of each number.

[@GamesComputersPlay]

Checked, looks like it is somewhere at 1 in 75-80k. Nice! Also, 50k!!! How many years did it take?

[@machtharry]

@@GamesComputersPlay :-D It took a while. About 7 years. Thats on average 20 games a day. Seems about right to me. I try to play for speed (My record is 82 seconds) but my winrate is only 6%. So most games are done in under a minute because i simply lost very quickly. I would guess that i play 15 to 20 minutes a day.

[@bkCheezburgor]

​@@machtharrystats: -81

[@blazingkite8983]

"first click is always safe" Well given that windows seems to have different versions for minesweeper throughout the years I dont know if this is also a version case but I do have actually hit mines first click essentially found cuz I was bored and just click once and start new board just for the hell of it.

[@KiraSlith]

4:50 "What else are we going to do, switch to 9x9 and reset all the records?" let me respond to your rhetorical question with my own. Is adding a separate "Beginner (9x9)" table to the scoreboards all that difficult?

[@user-tLOL1374bruh]

i used to be 20*20 ~ 30*30 grid + 432 mines 😎 tip: (432/(30*30))^8 = 0.28% or 1 in 357 chance to get 8

[@khachuli]

*"Hold on to your hats"* **Me who isn't wearing a hat"*

[@devilishjester7718]

People discussing if a beginner board is 8x8 or 9x9, then there's google over there with a easy board that is 6x11

[@NotKnafo]

how many mines there should be on a board so the majority of the games become impossible the board may be at any size you wish

[@GamesComputersPlay]

Generally, around 25% density solvability goes to almost zero. Still possible but only with quite a bit of luck.

[@NotKnafo]

thanks for answering me

[@rgvozdikov]

Сразу слышно земляка) спасибо за офигенный видос, мало такого годного контента по сапёру

[@MCB_GS]

Тоже услышал русский акцент

[@chibz1790]

did people genuinely think you can get a 9 in minesweeper

[@GamesComputersPlay]

After reading all the comments, I'd say no. Mostly no, at least. I think it was 70% a question about 3x3 mines formation, that, apparently is called a "9" (a name I strongly disagree with). And 30% trolling.

[@MorriganQueen451]

everybody gangsta until you get a 27 on 4D minesweeper

[@GamesComputersPlay]

Actually, in 4D minesweeper it goes up to 80. Im not sure how to play it. Basically you play 8 interconnected 8x8x8 3D minesweeper games. And this is just the beginner.

[@siegeking9949]

In my years of playing minesweeper, every first click was a 0, not just not a mine.

[@GamesComputersPlay]

Yes, there are implementations that guarantees openings on first click. But the classic one is just "not mine"

[@ChallengeSpaceYard]

I believe the trend of opening with a 0 in Microsoft Minesweepers started with Vista. Some 3rd-party apps do this, too.

[@TheWeco]

Only gotten 8 on first click in 24x30/210 but it was amazing.

[@DarkFrozenDepths]

Now I'm curious on how possible it is to have all mines in the shape of a grid... for example, 10 mines lined up as a 2x5 grid... or 40 mines lined up as a 8x5 grid.

[@etourdie]

To anyone who actually doesn't realize why there can't be a nine, each spot is surrounded by 8 tiles. If it were a nine, that would mean that you clicked on a mine that was surrounded by 8 mines

[@egwenealvereiscool7726]

12:45 Its because getting 2 8s next to each other uses less than 2x the number of mines; The total number of mines is not sixteen, but eight (from the first) plus five (eight from the second minus the overpap), so thirteen. This increases the probability a lot. This approximately cancels out with the chance that the two formations (one with eight and one with five mines, and each having one blank) appear right next to each other.

[@NUSORCA]

I remembered setting the custom game to the hardest possible. First tile = 7. I’m out

[@User_K653]

You got 8 in Minesweeper? Well done. Now try to get 26 in 3D Minesweeper

[@blacklight683]

I love how the character's face doesn't move he's just😐 24/7

[@GamesComputersPlay]

That's actually modelled from the reality.

[@bkCheezburgor]

Riririeiieieieiririririttoir

[@Timmysthirdbirthday]

cool vidio my great grandpa stepped on a mine and was turned into 8 or mote chunks lol oops bye

[@jasontermini8487]

so i just have to play 108 million beginner boards to see an 8? welp off i go

[@doodeedah6409]

I think it makes sense that the chance of getting two 8s next to each other is relatively likely compared to getting two 8s anywhere. It’s because there are only a limited number of mines on the board - the fewer there are the more likely the two 8s will have to share mines. In fact, if you have few enough mines (e.g. 14) on any board size, the chance of the two 8s to be next to each other is 100%, i.e. they can’t physically form anywhere else.

[@RexVelde]

For the double 7, am I mistaken or is it pretty simple (without all this text) to solve with math on the begginer difficulty? In a 8×8 grid, there are obviously 64 cells. To get the desired formation of mines, there are exactly 10 mines used. By counting how many different positin the center can be in, it is 6 ways along the axis with the fewer mines and 5 ways with the more mines. Therefore there are (5×6)×2 positions for the formation to exist. Because there are exactly 10 cells we must fill, and each cell filled makes one less cell possible to fill, which gives: First mine: 10 availible cells in the grid (64 empty cells) Second mine given the first mine is correct: 9 availible cells int he grid which has now 63 empty cells Third 8 positions with 62 positions availible And so on. It may be written like 10!/(64!/(64-10)!) = 10!×54!/64! This gives the probability of the desired formation with a number between 0 and 1. To get it expressed by 1 in some number, simply inverse it. Because of the 60 positions the formation can take, multiply by 60. Final equation: 60 × 64!/(10!×54!) = 2.525 × 10^9 ≈ 2.5 × 10^9 Hope it was not too difficult, I recommend googling "nPr" and "nCr", which tells us about the number of combinations desired.

[@GamesComputersPlay]

That's exactly right.

[@theunknown4834]

This minesweeper is different from the original one. 0/10 lies were spouted out all jokes aside, wow, this is the sequel I needed