I found this after PBS's latest Spacetime video mentioned using your index and middle fingers over your eye to see something similar.
@prof_hu4 жыл бұрын
Same for me.
@jakobberzins38552 жыл бұрын
The diffusion must occur at the edges of the slit, which makes diffraction occur for a single slit because of 2 edges. Not many sources explain this well.
@jakobberzins38552 жыл бұрын
I wonder if when physicists detect which slit in the double slit experiment if they are just destroying the coherence of the light. Hence no diffraction pattern.
@KartikSharma160711 жыл бұрын
relly nice. Helping me a lot in college. Thanks
@sidewaysfcs07189 жыл бұрын
when the distance between two null minimums is about 2.5 cm, the slit width is 50 micrometers
@samarthd99482 жыл бұрын
Yes sir, you're right
@thewanderers974 жыл бұрын
Enlightening
@sussusamogus88602 жыл бұрын
Brilliant
@shahramshahram4123 жыл бұрын
Light concentrators make the strips
@anupamsuman40378 жыл бұрын
is there any specific reason to use reflection of the laser light?
@jhyland877 жыл бұрын
I was wondering that as well.
@mielole7 жыл бұрын
I think the laser was too long to fit in front of the slit and, additionaly, was obstructing the slit. Thus, it was moved and a reflection system was put in place. It works just as well with direct light.
@trk32947 жыл бұрын
We use this technique generally to allow the laser beam to diverge and increase its spot size by allowing it to have a longer optical path. This technique is described by the far field radiation pattern which is a region of the electromagnetic field. And the parameters such as Power radiated, radiation intensity, Power pattern, Directivity, Gain etc are calculated from Far field.
@manavshetty44496 жыл бұрын
The reason is simple. It is to create a huge distance btw the slits and the source.... as for fraunhofer diffraction huge distances are required
@anshikapal88845 жыл бұрын
Laser light is more coherent than ordinary light .
@pranayreddy0079 жыл бұрын
fraunhofer diffraction means rays diffractio of ray by using converging lens and and usual diffraction means without any lens
@vishnoinigam16488 жыл бұрын
in second video with circular apertures when he vary the distance between pinhole and slit then why it happens so that when he reduces the distance there are larger fringes and when he increases it there are fewer fringes
@Sushil2k42 жыл бұрын
@anshukumar-yn4yn3 жыл бұрын
Is convex lens used for focussing wave front after passing through slit????
@rainbow1000ish10 жыл бұрын
Can anybody tell me what's the difference between Fraunhofer diffraction and the diffraction at a normal way??
@antiTamtaSquadLeader2 жыл бұрын
In the case of fraunhofer diffraction the wavefront is a plane wavefront that means the light source is at infinity. If the "normal" case is of diffraction of light of a source at infinity then it is fraunhofer but if there is a finite distance then it's fresnel diffraction
@rainbow1000ish2 жыл бұрын
@@antiTamtaSquadLeader oh God this comment is 7 years old
@1eV2 жыл бұрын
@@rainbow1000ish feeling old? XD
@rainbow1000ish2 жыл бұрын
@@1eV omg this is 7 years old Now i have no idea what i was even asking about 😂🤣🤣
@1eV2 жыл бұрын
@@rainbow1000ish understandable
@siddharthgandhi79377 жыл бұрын
Thanks
@zenvir16807 жыл бұрын
I did this experiment at home with a lazer and slit made by sticking two razor blades with tape.
@simranbaghla33817 жыл бұрын
Zen vir grt
@thorsten85545 жыл бұрын
Did this too today ! --> kzbin.info/www/bejne/fp3WhICof5eFfac
@puhbrox4 жыл бұрын
All I'm getting from this is that light is really powerful and it's bouncing off the slit in a way that makes it divide (but in reality it's just because the light is not a particle dividing but a wave dividing)
@alcatraz7662 жыл бұрын
Interesting theory but I'm afraid you're wrong, it actually due to the wave nature of light, the bright spots represent the spots with constructive interference and the blank ones representing the destructive interference.
@bellinivernon11 жыл бұрын
Exelente !
@NikitaNair3 жыл бұрын
Wow!!!
@jamesprince90419 жыл бұрын
How do we know that the interference pattern is not the result of quanta particles following the pattern of gravitational waves between the source and target. If gravitational waves exist, the duality of light quanta as both a wave and particle will be negated, a light particle would only appear as a wave as it traverses the valleys and crests of gravitational waves, because light is bound to gravity. Light is affected by gravity, gravity affects spacetime, and photons must follow a path in spacetime. As spacetime curves the path photons take is changed
@mortirius18 жыл бұрын
Im a little confused I thought it was only supposed to have two areas of light intensity when the double slit is observed but here I'm seeing a diffraction pattern thats only supposed to happen when there is no observer. Can someone explain why
@snehalsha64766 жыл бұрын
allan J this is not the quantum scale
@aditya_asundi Жыл бұрын
Aaditya sir if you're watching this, hi 👋
@parisian99332 жыл бұрын
No offense intended but he looks and speaks a bit like Howard Wolowitz xD Great Content btw :)
@jamesovenden38337 жыл бұрын
His voice reminds me of the european immigrants that aren't quite american on family guy
@ahmadmuaz53603 жыл бұрын
Boleh dh aq belajaq kat mit😤
@manjuldahal4404 жыл бұрын
n
@zenext77644 жыл бұрын
Improve video quality , guys.
@anoopkrishna200004 жыл бұрын
Vdeo ws 8 yrs ago
@SciD13 ай бұрын
We call that the single-slit experiment. 🙄
@leewilliam341711 ай бұрын
Mmmmm😊
@rainbow1000ish10 жыл бұрын
Can anybody tell me what's the difference between Fraunhofer diffraction and the diffraction at a normal way??
@coffeedence151110 жыл бұрын
I'm not sure, but I would say that the difference is in the approximation of Fresnel-Kirchoff equation. If I'm not wrong, the Fraunhofer diffraction is an approximation valid when the source (the incident waves are plane waves (in this case the Laser Beam)) and the screen (In this case 200 cm) are very far from the slit. If the screen is near to the slit and the incident waves are spherical, we've got Fresnel Diffraction.