Simple Lists

[@Sero-619]

this one really got me good i thought its [life, everything, 42, universe]

[@b088mohdzaid5]

I got it when the loops comes at the end and compare the IF condition If 0 == 0; (note that first “zero” is in our list) then it’s becomes true and then L[0] = “universe” applies, thus position at 0 is changed This is tricky cause in any other prog language we loop through indices like 1,2,3,4… but in python they loop through list elements.

[@chandlerzhu9735]

tricky, it uses "0" as an index

[@shahanahmed952]

So, Basically at Index thing= 3, it replaced the value at Index '0' not '3'

[@nishanthmaran4667]

It's shows the output as ['life','everything',42,0] Anyone please help me

[@akbarrauf2741]

thank you ,mit

[@sohrabgh5448]

we changed list.. why iteration does not stop?

[@klubotics]

sohrab gh We did not have a break statement or reach some sort of stop condition after the line which mutates the list. Thus, the for loop continues until there are no more elements.

[@brainstormingsharing1309]

👍👍👍👍👍

[@rachel_rexxx]

This problem requires noticeable deeper thought

[@날개달린_양]

tysm

[@abdulazizmukhamedov3553]

L = ["life", "answer", 42, 0] for thing in L: if thing == 0: L[thing] = "universe" elif thing == 42: L[1] == "everything" print(L) I got this answer: ['universe', 'answer', 42, 0]

[@muntaface]

You have a L[1] == 'everything, it should be L[1] = 'everything' (single '=' )

[@abdulazizmukhamedov3553]

@@muntaface Thank you very much! Got it