3. Friction | Complete Concept & Problem#1 | Most Important Problem

[@Exploreepic1987]

Nice explanation but I don’t understand directly calculations if u calculate step by step with out through the equation calculation

[@himanshusharma1066]

Thank you so much sir you help me alot and you are working very well and d'not think about likes and share you are doing great job.u providing best way of online learning . Your way of teaching is very beneficial to all btech,bsc students. Thanks alot sir😍😍😍😍

[@sahil_more7306]

Thanks sir pura step wise he perfect samj me aaya

[@saniyamansuri9607]

Easy explaination 👍🏻

[@AnkitKumar-sc7pm]

Sir you superb explain everything thanks a lot

[@Khushbu-es7ej]

Nice way of explain sir thank you

[@Sindhuja-cs7wm]

Thank you sir for good explanation

[@motivationalasraful2517]

Very very nice ... Thank You so much...Sir

[@aparnamajumder5683]

You explained it really well

[@AKHILDS-j3v]

Nice xplanation......😍😍

[@kamalakc6344]

Nice bro👍👍

[@sivamech20]

NICE sir...

[@trex1756]

Very helpful, thank you

[@nikhildubey4216]

Great job Sir u helped me a lot ✌

[@rachanabharati8845]

Sir..if the motion of the lower block is in forward direction then the motion of upper block would seems to be in backward direction bcos it's tied to a string. so, the frictional force acting on the upper block would be in forward direction this is wht i think...plz do clear my doubt

[@sanketbhagat7155]

since the string AB is pulling the upper block in the backward direction ....the friction force will act in the opposite direction to it...i.e forward

[@anupamkumar915]

great video

[@srikantasahoo5030]

thank u sir ji

[@paythetrader]

like toh banta hai

[@rameshjvr7288]

Very nice

[@sanatansahoolifestory2083]

Nicely explained

[@kamleshjadhav5700]

Best que for exam

[@abhimanyuraj2719]

Thx sir

[@tejasvishwanath4141]

Sir, i think the weight of the 1 block should be 1250N becoz, the weight of the upper block (250N)

[@Rohit-qp1ye]

Guys if you view the videos and you find helpful then please like it

[@sanketpatil6084]

FX component Mai toh uN2 hai aur FY component Mai N2 do no alag hai na equation Mai kyu consider Kiya as a X ...

[@sharvarikurudi]

Sir reaction forces ke direction kaise likhe??

[@momentofinertia4198]

sir iss ka equation casio fx82 mai solve kaise kare?kiu ki mere pass fx82 hai

[@godofroasts]

Sir very nice explanation. But please explain last step by elimination method and not by scientific calculator

[@kishankoyani5793]

reaction force is always opposite to the weight but how N2 is downside weight of w2 is downside so reaction force will be upword plz explain it

[@akashdubey9132]

Yess even I was thinking that

[@shubhankarsingh4065]

that is the case when object is on a surface but when two objects are in contact they exert equal and opposite normal forces on each other

[@kjahnavi3043]

Yes N2 is acting opposite to N2 in the diagram

[@ManjunathManju-er8xd]

Why not we don't consider W2 weight on W1

[@pov920]

We considered thats what N2 is

[@machi925]

Explain IN English

[@manikantareddyreddy2352]

please explain in english

[@janvichhabra750]

Can u specify the name of this calculator?

[@Ketan-kw4xb]

Scientific calculator

[@saptarshasarkar4545]

Casio fx-991ES model

[@ankamallaharishkumar8108]

Sir please .explain in english

[@deepaksundaresan7684]

Ankamalla Harish Kumar Ditto

[@vallapureddysyamaladevi9598]

it is still more better if you explain in english

[@shivanikakade4360]

Sir thank you