Mod-01 Lec-13 Introduction to CDMA, Spread Spectrum and LFSR

[@chaitanyaprasad6924]

What an mind Blowing example to start CDMA with!!!!!!

[@lipsachhotray1021]

what a lucid explanation! thanks to such dedicated and enthusiastic teachers!

[@muralidhar40]

CDMA starts @ exactly 09:00. The explanation was crystal clear. Thank you sir. I believe it is not ‘chips’, but ‘chirps’ @ 30:10

[@yugeshkc851]

no its chips

[@amitchoudhary527]

Very clear explanation of CDMA and Spread Spectrum Modulation Sir.....

[@ishanverma]

go to settings and change speed to 2x , save time xD.

[@frivolous_wizard]

Wonderful lecture......easily understood what cdma is.....thanks a lot!!!

[@PrashantGoklani]

Awesome is the word...first tym really understood wat cdma exactly is...thank u very much sir :)

[@kunalchanda4854]

Excellent lectures.. Sir your explanation is just great. THANK YOU

[@prajanpradhan6089]

Perfect Explanation.....hats off to you sir...(Y)

[@AkhilDakur]

Thanks a lot. it is really a very good lecture with brief explanation. Thanks once again.

[@ecehoddr.b.venkateshulu7465]

very clear and nice presentation

[@padmapriyamadhavan1635]

Excellent and clear lecture sir...thank you so much Sir....

[@sagarakaraavan]

Beautifully explained... Thanks a lot nptel :)

[@humaunrashid3793]

Could you explain why there is less collision in CDMA with compare to other technology.

[@yashdodia8048]

best explanation sir but i have doubt that is in reference books it is mentioned that pn codes are non-orthogonal codes but you mentioned it has orthogonal code

[@nuwanatthanayake]

Great Sir...Thanks

[@suryanarayanavelamala3281]

Thank you sir nice explanation

[@flawsomenavs9190]

Great lecture

[@AnkushSingh007]

awesome sir :) very clear explanation :)

[@rivalaadil9051]

Thank u sir.... was really helpfull:.....

[@aakashkumar198726]

Grt sir......Thanks alot

[@EduardoRamirez-hi1vj]

awesome lecture, thanks

[@AdityaMehendale]

Hi, at 38:10, in codes C1 and C3, there is orthogonality *provided* that the encoders are synchronized. If you time-shift C1 by one bit-time, it will no longer be orthogonal with C3. How can this be worked around? Surprisingly, C0 C1 and C2 remain orthogonal even if time-shifted (i.e. with asynchronous clocks). Is this statement correct? Wouldn't it be smarter to forego C3 and stick with just C0 C1 and C2?

[@dhimanroy1671]

Here the bandwidth will be 500 Hertz. Because we must have to satisfy the Nyquist rate requirements!

[@agarvipul]

Super!

[@vedantjoshi1487]

How can we transmit 2 symbols at the same time and of same frequency? pls explain....

[@xinzhou8633]

I think the two symbols are added as one symbol to transmit, not transmitting two symbols

[@libraryofelectronics]

Thank you so much Sir🙏😇

[@ahmedal-haddad7425]

What a boss!

[@JCBATTAGLINI]

Hi!! Can you tell me how can i calculate the number of users using cdma th?

[@rudra9506]

Thank you :)

[@sukeshgoparaju318]

Thank you sir

[@manishakumari685]

Kota factory ke " jitu bhaiya "

[@justsomerandomguy933]

Thanks!

[@pvsanthosh]

great:)