Mohr's Circle Principal and MAX SHEARING ANGLES in 2 Minutes!

[@justsomeguy2918]

Thanks bro, I hate having to go back to my books to find information, having condensed recaps like this makes life so easy you are a legend!

[@lukelamagna7175]

This cleared it up. Thank you.

[@naveenwanigasundara2206]

Really well explained! Keep it up!

[@RajaRecover]

keep up the good work!

[@wajihaqureshi-p2b]

How to find the complementary angles

[@ericgerard1648]

After you draw the Mohr's circle to scale and have sigma 1&3, is it necessary to do the "blocks" at the end to check? - Studying for the FE.

[@EMEngi4ALL]

perfect

[@wasimahussain657]

danke

[@EUSHAASWAD]

best

[@m.abubakrarqam4278]

why did you rotated 8.15 below the axis?

[@ethanboba5262]

Bc to get to t_max you have to rotate 8.15 clockwise. Moving the cube clockwise puts it under the x-axis

[@johnfitzgerald1552]

@@ethanboba5262could u rotate to 81.9 above the x axis instead

[@2foldmusicuk]

You've said that 2*Txy = 12? Shouldn't this be 24

[@kvnyang]

ye true but he skipped over that, the answer is right eitherway since 2Txy/(σx-σy) = Txy/((σx-σy)/2) , (σx-σy)=12-5=7

[@2foldmusicuk]

@ took my exam anyway 😂 hopefully dont need this shit anymore

[@AbreMaldwyn-sh7kf]

The explanation is good but too fast🤦🏽‍♂️

[@WASTE_7]

.75x

[@balajiraghavndra3886]

Wrong answer ra waste fellow

[@S..u..n..i..l]

Hahahaha Indian bro.