Molecular Formula from Mass Spectrometry

[@wisp8957]

THANK YOU SOOOOOOOOOOOO MUCH FOR THIS VIDEO HONESTLY I DONT KNOW WHAT THE OTHERS WERE TRYING TO SAY ONE WAS TRYING TO USE THE HYDROCARBON FORMULA

[@samranadeem3405]

How can we find that there is nitrogen or oxygen in molecule?

[@ainatan572]

6:19 & 6:57 Sir, may I ask how did you get the ratio between the carbon and hydrogen? (6,4) & (9,1)

[@ochemlounge]

The m/z = 58 can have different constitutional isomers. Once we figure out the molecular formula and max number of carbons, there can be linear and branched isomers. The ratios stated as (6,4) are for the linear isomer butane with two methyl groups and two methylene groups. The (9,1) ratio is for the branched isomer 2-methlpropane that has three methyl groups and one methine.

[@rycarious]

Is there a specific reason you divided by 12 instead of 13 (C+H)?

[@ochemlounge]

Rycarious I guess it is just how I like to think about the process. To me I feel more comfortable thinking about each element separately. Nothing wrong with the CH strategy of 13. Equally as valid.

[@shayanabbasi6495]

Sir please tell if this can also help in finding the molecualr mass

[@tomato7453]

idk if u got your answer yet but mass spectrometry will tell you the mass. likewise if you use this to propose the molecular formula you can calculate that on your own with a periodic table

[@shayanabbasi6495]

Can this also help us to find the molecular mass

[@zoengu9535]

May I ask how to know the compound is hydrocarbon or not before the calculation?

[@DavisRyan12]

You can find that out with nmr

[@abdullahimusa3815]

Thank you very much Sir

[@megacitationx]

Hoo boy, thank you so much man

[@shayanabbasi6495]

Please tell me

[@hoor.a7242]

i dont understand

[@samranadeem3405]

Plz sir reply