Moment Diagram by Parts (Simplified)

This discusses the basic concepts to use in constructing the moment diagram by parts as well as the shortcut formulas for areas and centroids.
‪@GillesaniaEngineeringVideos‬ ‪@MATHalino1‬ ‪@cebox‬ ‪@eboratutorials‬ ‪@structurefree‬ ‪@engrjayc‬

[@nightskyalarcs]

Ito yung best explanation kung bakit magiiba yung MDBP basta from the right yung load the same concept lang pala sa moment equation from the right

[@engrclidez]

yes po kasi 'pag from the right iba yung lalabas na moment reaction. It's good na you were able to relate it sa previous discussions

[@mmrida_]

thank you po! may tanong po ako, bakit po dun sa part ng triangular load lang po mismo nung ang moment center ay A, di nyo po inextend? yung may 15 kN/m po

[@engrclidez]

@@mmrida_ helloo, need po sya iextend I forgot to edit it out.. kaya po merong separate video sa load extension.. pasenya po ✌️✌️

[@engrclidez]

cinut ko nalang po yung segment na yon to avoid confusion hehe

[@mmrida_]

thank you so much po!! very helpful mga videos nyo 💌💌💌

[@engrclidez]

@@mmrida_ ur welcome and thanks for expressing!

[@KhimLeonard]

Engr., okay lang po ba pa expound nung sa 13:30 onwards regarding sa continuity ng loads? Medyo nabilisan lang po ako (aka di mavisualize)

[@KhimLeonard]

Tama po ba pagkakagets ko, (1) Not ideal sa mag moment center about A since yung height ng triangular load is dapat onto A not away from it (since nasa B yung max height ng loading). (2) Not ideal about C since kelangan continuous papuntang C yung triangular load; eh ang kaso naputol at B. So, ang tendency is magdadagdag bawas pa. Speaking of dagdag-bawas method, pwede rin bang atake here is gawing unformly distrbuted (downwards) and mag add ng upwards na triangular load na continuous towards A? Bale dalawang loading pa rin, isang uniformly dist. load na sakop buong beam span at isang triangular load na continuous towards A. Naisip ko kasi na given this, possible na rin mag moment center about A. pavalidate po sana Engr. salamat po!

[@engrclidez]

@@KhimLeonard yes tama po. To make it continuous about A, add ka ng triangular load then counteract mo with an upward triangular force. If about C po, add ka ng trapezoidal load tapos icounteract. Mas mahirap yung dagdag-bawas method kung about C po kasi masyadong madami na yung forces. To summarize, sa continuity po always height ng spandrel or triangle nasa moment center dapat then distributed loads hindi pwede maputol patungo sa moment center. Baka sa future po pwede kong gawan yan ng additional video about A saka C. Bago pa lang po kasi ako nagYT noong time na 'yan nahirapan pa talaga ako mag-edit dati tas 2nd language ko lang Filipino kaya di ko nainclude and then dinagdag ko nalang as comment. Mas holistic po sana kung pinakita hehe. Salamat po sa mga tanong mo, makakatulong 'to sa ibang viewers din po!

[@KhimLeonard]

@@engrclidez Yung sa about C po, I think hindi po trapezoid idadagdag-bawas (?). I think need po malaman lang yung height ng additional triangular load na idadagdag-bawas using right triangle similarity. Correct me if I'm wrong po huhu. Refer to this link po to visualize (Gdrive link): drive.google.com/file/d/12f8CAe8TACkGBKYr97z1pr7VBbz0Hlha/view?usp=sharing Anyways, super appreciated ko tong channel mo Engr! Dito ko nagets yung MDBP :>

[@engrclidez]

Sa link mo yung nasa ilalim ng beam po dapat trapezoidal din, counteract yung in-add sa taas. Gawan ko nalang din po ng video + checking hehe

[@KhimLeonard]

@@engrclidez Triangle lang po inadd ko sa taas kaya triangle lang din po dinagdag ko sa baba. Pero sige po looking forward po sa video nyo

[@engrclidez]

Check this video out for a more in-depth discussion kzbin.info/www/bejne/a6KoaYZ6pMhnq5Y