Moment of Inertia of a Composite Section_Problem 1

[@abassmobolaji9809]

For the semi circle. It’s not meant to be 0.11*(4)^4. It should be pi over 8 then multiply be 4^4.

[@kjeevan9945]

I could have never passed my sem exam(bem)without this knowledge ,thank u for this wonderful lecture

[@ManasPatnaikofficial]

Hi Mr. Techy......Thanks for appreciating my work…and all the best for your examI am sure this channel is helping you learn…You can support my channel by donating and do watch this video: kzbin.info/www/bejne/jZfchnierc2dkLd8ave a nice day.

[@johnfrancis6413]

for semi circle we can use (pi/8 x r^4) where r = 4 directly ... also for circle we can use(pi/4 x r^4) where r = 2 directly

[@brillamariyamsunny1706]

Sir ...I am very thankful to you.....last semester I studied the whole engineering graphics from ur videos.....I suggested it to my frnds........they really helped us......I scored good marks too.......this semester ur engineering mechanics lectures are really helpful ......thanks a lot sir

[@ManasPatnaikofficial]

I wish u all the very best in life....

[@GreatThoughts36]

How did you get the semicircle MOI and Circle MOI That semi circle = (3.1415)4^4 /8 +ad^2 for that Circle MOcm=pi*r^4/4+0=201.061

[@advaitharun6072]

Why didn't we calculate centroid for this question ?as we do for all until now

[@pramoddiwate6404]

Here we are asked to calculate moi abt AB so......but if we asked to calculate moi abt centroidal axus then we have to calculate it. Correct me if m wrong

[@swatisahay7150]

how do we understand whether we have to take the x distance or y distance from the given line? like in the previous video we got the x component and the y component, we dont have to do that in this?

[@mierdaa]

i have the same concern...

[@pradnyakharade3718]

Sir you have literally helped me to infinity cz I was not knowing anything i.e. how to calculate it as I missed my mechanics lacture But got a great social tutor.

[@nagulananantharaman3302]

A very clear and good teaching! Thanks a lot for this sir

[@ManasPatnaikofficial]

Glad it was helpful

[@polankirajulu1183]

Please tell me more about Moi of composite sections (about semicircle problems)

[@sebtodd97]

WHY IS IT THAT INDIAN GUYS ON KZbin ARE BETTER TEACHERS/EXPLAINERS THAN ANY OF MY PROFS WITH PHD'S AT A TOP SCHOOL IN CANADA

[@manishadhikari1429]

Smart way of teaching sir ..❤ It cleared my dbt

[@shubhashyadav9092]

Sir, for the same figure how to find MOI about its centroidal x-axis?

[@DasariKartik13]

For semi circle and quarter circle you have taken radius instead of diameter in your formula. Please correct it or else people get confuse. remaining good explanation

[@Carlo-hm8jo]

you are a life savior, holy macaroni

[@julieanneamar9886]

Do you also know how to solve the polar and radius of gyration? And where is the y axis. Thank you

[@ZainKhan-cy4sp]

sir the semicircle is in 3 4 quadarant and in 3 4 quadarant the y values is negative ,then sir why you should not represent the y distance in (-) form

[@imtiaz91]

Sir, in your previous videos (eg. I beam), the "y" value was (value of centroid "y" - y1/y2/y3) but in this video you directly took y1/y2/y3 value. I couldn't understand.

[@cosmophile6657]

Same question

[@ntegral7306]

Sir, how did u get the 0.11 in IAB2? How to calculate? Plss help!

[@akashmondal8181]

The MI through its C.G = MI through its base - A×y^2 =0.393r^4 - A×y^2, (y= 4r/3 pi) & ( A= pi× r^2/2) . calculate this you will get 0.11r^4.

[@bhargavareddy8399]

Moi of semi circle is not mentioned and how did we get that 0.11*4^4

[@shriramparab4879]

Sir , for semicircle how did you get that 0.11*(4)^4

[@ManasPatnaikofficial]

Hi Sriram... thats just the aplication of formula in the right sense... Welcome to the "The Library of Manas Patnaik" Topic-wise Playlist of Engineering Drawing / Engineering Graphics in English 1. Orthographic Projection: kzbin.info/www/bejne/jXiZeWWmfriIsLM 2. Projection of Point: kzbin.info/www/bejne/nHyXmWidgpxmrZo 3. Projection of Line: OLD: kzbin.info/aero/PLIhUrsYr8yHz_FkG5tGWXaNbIxVcibQvV NEW: kzbin.info/www/bejne/pquoYXdjfs-rmpY 4. Projection of Plane: kzbin.info/aero/PLIhUrsYr8yHx7TVB51jN3HZVyW3R6RiBg 5. Projection of Solid: kzbin.info/aero/PLIhUrsYr8yHxARPzEFz1nXgt8j6xF_tEm 6. Section of Solid: kzbin.info/aero/PLIhUrsYr8yHwAbiCATZUbzd_CpF0EHF3v 7. Development of Surface: kzbin.info/aero/PLIhUrsYr8yHwdB96ft6c0Uwc4SDCLuG1v 8. Auxiliary Plane: kzbin.info/aero/PLIhUrsYr8yHxHWk2TCg1SrphF1vKpHXoB 9. Interpenetration of Solids: kzbin.info/aero/PLIhUrsYr8yHyTGceE1TGhCSxxfHyFpnNM 10. Isometric Drawings: kzbin.info/aero/PLIhUrsYr8yHxVky7bfrnbRcdXcHjT_K83 11. Conic Sections: kzbin.info/aero/PLIhUrsYr8yHx0TuqsY0FUZ7Z24BbKxJoQ 12. Cycloidal Curves: kzbin.info/aero/PLIhUrsYr8yHwwA8eBea78pJW1lw9XAv6z 13. Involute: kzbin.info/aero/PLIhUrsYr8yHzu8pqYvGwQoJKVpuS1Jusa 14. Plain Scale and Diagonal Scale: kzbin.info/aero/PLIhUrsYr8yHwTgo_zu_ELqOC1ypcp5Gr9 15. Complete Engineering Drawing in one single Playlist: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS Topic-wise Playlist of Engineering Drawing / Engineering Graphics in Hindi 1. Orthographic Projection in Hindi: kzbin.info/aero/PLIhUrsYr8yHy3chHVzYA4BMbY9DbhyYSY 2. Projection of Point in Hindi: kzbin.info/aero/PLIhUrsYr8yHwinNUxVA1NW0xxLRlDfINH 3. Projection of Line in Hindi: kzbin.info/aero/PLIhUrsYr8yHyvWb87YtG3A3jDEnChgzir 4. Projection of Plane in Hindi: kzbin.info/aero/PLIhUrsYr8yHxj9N5e1oZA0x_k5ZVssf3U 5. Projection of Solid in Hindi: kzbin.info/aero/PLIhUrsYr8yHylYPjrulRGm8DSPiimxP3P 6. Scales Hindi-Urdu: kzbin.info/aero/PLIhUrsYr8yHzJA426HjlEmiRqUkJTkozB Topic-wise Playlist of Engineering Mechanics / Applied Mechanics / Fundamentals of Mechanical Engineering in English 1. Forces: kzbin.info/aero/PLIhUrsYr8yHzoyUutEK57JzWy1n-vxIS0 2. Friction: kzbin.info/aero/PLIhUrsYr8yHwY1TDraJpyYkU8Zug-kM4m 3. Shear Force and Bending Moment: kzbin.info/aero/PLIhUrsYr8yHy1lc0hEhbpEAGsGwNmUWt7 4. Trusses: kzbin.info/aero/PLIhUrsYr8yHwIXEt9cqjEsEO8l83xcIf7 5. Centroid and Centre of Gravity: kzbin.info/aero/PLIhUrsYr8yHzZ52dVA3wQ_0IQVl7CKL7p 6. Moment of Inertia: kzbin.info/aero/PLIhUrsYr8yHw8qWxAVOx-5Y2XfGPOmcDy 7. Dynamics: kzbin.info/aero/PLIhUrsYr8yHwOZxmY63A_lURu6c-jNk-z 8. Complete Engineering Mechanics / Applied Mechanics in one single Playlist: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS Complete Playlist of ENGINEERING SERVICES EXAMINATION: kzbin.info/www/bejne/mZKYeqqep6iBmLM Complete Playlist of Machine Drawing: kzbin.info/www/bejne/n3emn3mLh556msU Complete Playlist of Theory of Machines / Kinematics of Machines / Dynamics of Machines: kzbin.info/www/bejne/eaCXip-Xq6ijm7M

[@arinzeanthony7447]

I was asking the exact same question.

[@abassmobolaji9809]

It’s not meant to be 0.11*(4)^4. It should be pi over 8 then multiply be 4^4

[@saketpandey18]

Thanks a lot sir this explanation helped me a lot in my CA.

[@HashemAljifri515]

Hello, usually in a moment of inertia problem do I have to determine the centroid first or it will be given?

[@harikanune901]

Sir same problem in vertical centroidal axis, for circle x distance how much sir

[@theworldofall287]

is the line not passing throough the base not center to make the moment of inertia bh3/12 not bh3/36

[@arinzeanthony7447]

Please, I have a couple of questions, isn't Ix of a semicircle meant to be equal to Iy? what of quarter circles, if we were to find Ixx and Iyy when parrallel and perpendicular to a quarter circle, what values do we use? Also, for semicircles, I know how they obtained that 0.393r^4 =(pi.r^4/8). But how did you get 0.11r^4?

[@j.v.c.maliackal3169]

can we take MOI of semi circle about the base formula in this problem ie pi * r^4/8 directly

[@pramoddiwate6404]

What will be the solutuon if we want to find moi about centroidal axis parallel to AB?

[@ntegral7306]

Sir, how did u get the 0.11 in IAB2? How to calculate?

[@abhishekprajwal5691]

It's a formula for a semicircle

[@arinzeanthony7447]

@@abhishekprajwal5691 can you please type how it was obtained? that's my major problem right now.

[@parveshqaiser9840]

Sir, why did u take MOI of triangle as bh 3/36 instead of bh3/12 ? In some other videos they have taken bh3/12. Totally confused .

[@hamdanahmedbarlaskar7977]

the MOI of Triangle is bh^3/36 & MOI of Rectangle is bh^3/12

[@Ankitc7]

Very nice video and very helpful , with Explanation

[@tadigadapasarath0009]

Sir Iab2 =0.11×4 to the power of 4..why

[@shivamsaini4281]

why you did NOT CALCULATE X AND Y BAR PLEASE TELL DONT IGNORE

[@sanskratigupta9454]

Because we don't have to calculate moi about centroidal axis

[@NiggasinGTAVI]

Bro it's wrt to AB

[@v747p3]

Brilliant explanation of and hour long concept in 10 min

[@memoonajamil951]

Which book are you using? Tell me the name please.

[@TarunKumar-ym1is]

Thanku for ur wonderful lectures . I am watching both ed and mechanics ur videos

[@RSaran-mt5tl]

Some time y2 is (y-ybar)... Some time y2 is directly substitute.... Please tell the answer sir...

[@cosmophile6657]

Same question

[@aravindaswamynamani1588]

Sir,Cetroid of right angled triangle is (2*8÷3 , 8÷3)

[@johnfrancis6413]

correct but look at the distance marked in video its from opposite side so the distance from opposite side is (8-(2*8)/3)=8/3

[@ManasPatnaikofficial]

I will check it John in just a moment..... If there is an error...... I will make a comment and pin it at the top of comment section. Because I can't make alterations to the video..... I am sure that this video has helped you gain some insight into calculating moment of inertias......

[@johnfrancis6413]

@@ManasPatnaikofficial no the video is correct but you dint mention the origin direction thats why some people have this confusion

[@eduardojrisideriodecatoria4999]

I would like to correct that this is not a right triangle but actually an iscoceles triangle. indicating it as a "Right Angled Triangle" is totally wrong because an isosceles triangle has a summation of 180° inside. Also take note that a right triangle has 90° only. Anyway, the solution still correct.

[@havudamusic]

Moi of the triangle is this correct formula ? sir

[@janaranjania2537]

Hindi peoples are too good in teaching👍👍😊😊☺️

[@erickmwangi1136]

Why is the distance of the centroid in respect to the y axis divided by 3

[@nwejigilbert6529]

Please sir, is there differences between Engineers and Engineering Technologist. Please sir help me out in the distinction.

[@jagadeeshwarrao3491]

Fabulous one sir....love you so much sir....

[@ManasPatnaikofficial]

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[@julieanneamar9886]

Thank you for that helpful explaination. But why did you come up to that formula of an area?

[@TarunKumar-ym1is]

Gd evening sir.can I know the ix and iy values of a triangle other than right angle triangle

[@stppavankumar1346]

sir same problem how to find centroid

[@kanaksinghal4552]

Sir hum isme kisi axis ke respect m hi nikalte h either x axis or y axis

[@021alwinthomas.j9]

really awesome

[@0501245]

Why you keep using b/3 instead of 2/3*b?

[@ifesinachiekeneme1304]

Pls, I want to know how this is going to help us future engineers??

[@VanZam]

Ixx=(bh^3)/36 Where is 36 come from?

[@sheherbano9487]

you wrote value of r of triangle 8/3 how? can you explain plz

[@kmlfunny817]

Why don't we calculate directly I.e.., bd^3/12+pid^4/128_pid^4/64

[@rakeshvarma4944]

Sir is it possible to use direct formula about it's base instead of parallel axis..

[@ManasPatnaikofficial]

Absolutely Rakesh

[@awaismajeed7302]

Why you have not applied parallel axis theorem to using y-axis...?

[@awaismajeed7302]

Sorry , I Got it

[@bhaswatiborah4345]

For right angle triangle formula if bh^3/12 .. Why u have used 36 instead of 12 ?

[@shubhojeetcl]

36 is from the Centroidal axis & 12 is from the XX axis(directly)

[@prafulkumarmandal5771]

in same question about centroidal axes?

[@giftasiana]

thank u so much sir it helped me a lot tomorrow is my exam😀

[@ManasPatnaikofficial]

All the best..... Rock it tomorrow

[@omamababar5587]

area of circle is A=πr2 then wht divided by 2

[@padmanabanr5424]

How ur taking ,only Inertia of XX axis

[@n0rth_219]

When u took the moi of circle why did u use radius 4 instead 2?

[@karanpratap7077]

Bro, that's ''Diameter'' not the ''Radius''. Sir said that the formula is pi/64 X D^4.

[@drcommondrate12]

I thought that the moment of inertia of right triangle is bh^3/12 And why are you using diameters if you can use the radii.

[@ManasPatnaikofficial]

Yes it is but it is about its own centroidal axis and then you can apply the parallel axis theorem to calculate the moment of inertia with respect to any axis

[@drcommondrate12]

Manas Patnaik okay. I got it now. Thanks lmao good luck for my exam later.

[@DineshKumar-cn8hi]

Thank you for neat explanation

[@shamanths9724]

Sir u are simply awesome!!!

[@manipoosanam3508]

How to find y value?

[@ArunBabu-i2j]

Sir in case of semicircle the radius is 2 cm but you write it as 4.How?

[@aalokydv8310]

he took the formula in diameter form.

[@madhuk2276]

Sir plz send finding moment of inertia of circle , semicircle and quarter circle video

[@ManasPatnaikofficial]

Ok MAdhu...that will be uploaded soon

[@freakedout922]

sir may I get more composite figures

[@NKShahariar]

Sir, whats the MOI of a quarter circle?

[@kmlfunny817]

4r/3pi

[@arinzeanthony7447]

@@kmlfunny817 what you wrote is centroid and not moment of inertia.

[@411archanabejjanki3]

Sir Iyy also have to calculate

[@-Shahbaz]

Sir for the triangle moment of inertia is bh^3/12 about base ab but y did u consider bh^3/36

[@ajitabhverma4434]

U teach very well, sir

[@hayagrivapoornabl2158]

Like Igxx is we need to calculate Igyy

[@prajwalbhattjoshi6136]

Thank you sir Mai apka abhari hu 😄😄😄😄😄

[@rharshith25]

Sir why did u take 8/3 for triangle

[@bhagwad_gita_daily]

CENTROID OF A TRIANGLE IS B/3

[@anuragkk373]

Thank you soo much sirr

[@عليبورقيه-ق4غ]

Thank you very much, man, you have saved me.

[@janaranjania2537]

This sum is slightly different y u not find out y square

[@HarshaVardhan-zg5qc]

SIR please make a video on moment of inertIa of builtup sections

[@UECAshutoshKumar]

Thank you sir ❤️

[@dnchco3295]

Thank u!! Helped a lot 🧡

[@cece_Dominic]

Can you assist me with a question am really struggling and I was using your method

[@varshilshah6679]

Please add the archimedian spiral

[@sriguruskandha9920]

Can you please upload mass moment of inertia,it's our need to know them.Please upload as soon as possible......🙏

[@ManasPatnaikofficial]

It's in the planning already.

[@sriguruskandha9920]

Ok sir👍

[@akashmondal8181]

you slove the problem with long process. it can be slove easily , as we have a formula of find MI through its base (for triangle ) is (bh^3/12) & for semicircle is 0.393 r^4 ( though you say that ) , then why will go in long process?.

[@sbahlenontobeko5844]

Thanks for the shot cut

[@manojwarthi6686]

How take 0.11 value in IAB

[@AnkitTiwari-005]

That is the formula

[@eddyr978]

It is 12 rather than 36

[@mutiyasani3564]

Air i have a question

[@ManasPatnaikofficial]

Then write it down.....🙂

[@AbdellaMahmud]

Thank a lot.

[@halfengineer8476]

thank you very much sir ,, ur videos r clearly understable

[@krishnaprasath10]

Thank you very much sir

[@thanzeelas.r9971]

Ufffff tq u sir

[@SAKI-fm6rz]

Thank you for speaking in English

[@ManasPatnaikofficial]

All the best

[@parvezreza818]

thanks borthers

[@kamalpandey3229]

Sir couple ke video please.......

[@sahilsingh892]

Wrong formula of MOI of triangle

[@kiranswamy8097]

S

[@kiranswamy8097]

It is not b \3 it is 2b/3

[@eduardojrisideriodecatoria4999]

lol. The video is correct. look at the location of the two 8/3. both of them located at the 1/3 position of C.G. take note that the 2/3 is located from the vertex of the triangle to the C.G. the vertices I'm saying base to the triangle in the video is located at the top and the left of the triangle. The distance he indicated there is located at the 1/3. He didn't use 2/3. If you still didn't get it then try to focus your eyes at the distances at triangle from B to X and B to Y. If still didn't get then you really an idiot. I'd better suggest you to quit learning Inertia. LOL

[@tinkuji4040]

sir rolling and collision ke video kB banoge sir btao naa pls

[@ManasPatnaikofficial]

Abhishek...that will take sometime.. I cannot promise anything as of now......

[@tinkuji4040]

Manas Patnaik thanks for information..I will wait for your videos because your videos are highly understandable and conceptual...

[@pacifiersemtexff5655]

G fad diya exam ne toh

[@eslavathchintu9482]

Its a shortcut dude.Incomplete tbh