Moment of Inertia of an Iron Beam's Cross Section

[@ManasPatnaikofficial]

Small correction guys: At timeline 05:10, I should have written Pi.r^2/2.... But the answer works out as 39.27 cm^2... Rest is fine...Not to worry...

[@suchithraperera]

What would be the changes will happen if we considering another reference axes rather than given reference axes/?

[@zubairmahmood1936]

i was just getting mad how come that the value is 39.27.

[@Mr_east_light]

A2=A3 = (pi * 25 )/2 = 39.2699

[@Mr_east_light]

x3 = 12-x2=12-2.12=9.88

[@Nkennedyyyy]

lmao i questioned my whole life existence for a moment there thanks G O A T

[@spritechz9044]

Super super easy explenation, thank u so much sir. 👏

[@nivedhinim5321]

sir,how to find out centroid of semicircle with axis tilted Is there any formula like finding out moment of inertia of semicircle..

[@vijayvamsi7324]

why don't you consider symmetric about x. axis or y. axis??? Sir. .

[@Urnbharat2047]

Excellent explanation. Just missed to write (2) while showing formula for area's of semicircle divided by 2. Also checked answer is matching. Thanks

[@saivyshnavigudipalli1827]

Sir... Upload some more problems on moment of inertia

[@vivekyadav-il2rx]

the way u teach sir,awesome and very easy to learn, thank you i got passed in mos because of ur videos

[@AmirHussain-rt3my]

two semicircle same distance from centroidal y axis

[@450shahnaz8]

Sir i, ve heard from my teacher dt if a body is symmetric about x_axis it's y bar is zero... How ❓❓ i, m getting confused... Wt is the right answer?

[@amaanrampath4100]

Hello.at 7:48 you explain iparallel=0.11r² and iperpendicular=0.393r²,I am confused because many textbooks say ix =iy for semicircle is 0.393r².they do not mention 0.11r².please explain why.thank you.

[@amaanrampath4100]

Even this lecturer says ix=iy in this link kzbin.info/www/bejne/n5WuiJ-hnLCLsK8 please skip 5:17.thank you.sorry to bother you

[@ManasPatnaikofficial]

Aman.... Come on FB messenger, lets have a quick chat......

[@amaanrampath4100]

Hi.i messaged you now.thank you again

[@faisalnazir9067]

I have same Question.......plz clear my doubt too

[@amaanrampath4100]

@@faisalnazir9067 in this video Mr.Manas takes MOI from center of semi-circle while many text books give you MOI from edge of semi-circle...BOTH ARE CORRECT, just check if you are at CENTER or EDGE

[@FatawYakubu-908]

Please what if the rectangle is labeled abcd and the question ask to find about ab axis

[@amirul-aj3925]

need help....!! where did you get the 0.11 and 0.393 on the semicircle..? I only saw these number in your video... thank you

[@janaranjania2537]

Thats a formula

[@ssss8619]

Thank your for your explanation, what about Ixy ? Is it Will always be 0?

[@kamugishaedison1944]

Thank you so much you have added alot to my knowledge of mechanics

[@ManasPatnaikofficial]

Thank u ......Keep learning and do share it with your friends.........aLL the best

[@Christian_904]

Thank you so much Manas Patnaik!

[@TutulBiswas-q2c]

For samicircle x=R and y =4r/3π .Quter circle x=y=4R/3π but sir you say that X2=2.12 i thik it may be 5 please describe it sir

[@cric_h8103]

Sir area of semicircle is wrong it is pi r^2/2 kk thank you sir

[@taukirsheikh9405]

just a doubt that is the formula (y-Ybar)square is applicable for all composite section in case of centroidal axis.

[@Mr_X_FIFA]

Thanks sir today was my paper and I read complete mechanics before from your videos itself and this was the last question which I saw before entering exam hall . Thanks a ton ❤️

[@ManasPatnaikofficial]

I am sure you will do well in exams. Good luck

[@Mr_X_FIFA]

@@ManasPatnaikofficial Yes sir sure.... thanks once again ❤️

[@dreamsosh9028]

how to calculate the moment of area for the singly reinforced beam?

[@GurtejSingh006]

Sir area of semi circle is pi r^2/2

[@ManasPatnaikofficial]

Yes u r right....I should have written Pi.r^2/2.... But the answer works out as 39.27 cm^2

[@GurtejSingh006]

Manas Patnaik yes sir

[@mohammedfareeduddin5527]

Can we apply direct method of finding centroid to I,Z,C section of rectangle??

[@riteshmandal7798]

Sir area pi r square by 2 hoga na

[@habeeljaveed6568]

Sir what is the moment of inertia of semi circle along y-axis

[@Nkennedyyyy]

1:39 X does not match 6 after verification

[@utkarshshukla3567]

sir does removing semicircles dont change the position of centroid?

[@artisticmaurya]

MOI OF semicircle ?? Is there any video ??plz reply

[@tessathomas554]

I like the way he speaks...

[@Hartel-eu3jr]

Kindly help us to find the polar moment of inertia and the radius of gyrations

[@janaranjania2537]

Great explanation video👍👍😊

[@KAMISETTYSATYASAKETH]

y the two semicircles are subtracted sir?

[@nahomdemelash291]

Thank you, u r a genius

[@mr.partha5829]

Great job Sir... keep uploading 😊😊

[@تمرآيےهہ]

Please, where can I find this question in the source?

[@yograjparajuli6506]

12:32 to 12:40

[@lakshmik9007]

sir can u pls explain moment of inertia of inverted T section

[@manishkhangar7333]

Pls tell about MoI of L section

[@rayanamatya]

I'm getting problem with M.O.I. OF SEMI CIRCLE ABOUT x-x & y-y axis Plse reply with clear concept hearty request 🙏🙏🙏

[@chhattisgarhtechhack7194]

Sir please upload a video on derovation of Moment of inertia of shapes like semicircle, quarter circle, triangle etc. Please sir

[@ManasPatnaikofficial]

Even i was thinking about that... till then u can watch stuff from these playlists. Topic-wise Playlist of Engineering Drawing / Engineering Graphics in English 1. Orthographic Projection: kzbin.info/www/bejne/jXiZeWWmfriIsLM 2. Projection of Point: kzbin.info/www/bejne/nHyXmWidgpxmrZo 3. Projection of Line: OLD: kzbin.info/aero/PLIhUrsYr8yHz_FkG5tGWXaNbIxVcibQvV NEW: kzbin.info/www/bejne/pquoYXdjfs-rmpY 4. Projection of Plane: kzbin.info/aero/PLIhUrsYr8yHx7TVB51jN3HZVyW3R6RiBg 5. Projection of Solid: kzbin.info/aero/PLIhUrsYr8yHxARPzEFz1nXgt8j6xF_tEm 6. Section of Solid: kzbin.info/aero/PLIhUrsYr8yHwAbiCATZUbzd_CpF0EHF3v 7. Development of Surface: kzbin.info/aero/PLIhUrsYr8yHwdB96ft6c0Uwc4SDCLuG1v 8. Auxiliary Plane: kzbin.info/aero/PLIhUrsYr8yHxHWk2TCg1SrphF1vKpHXoB 9. Interpenetration of Solids: kzbin.info/aero/PLIhUrsYr8yHyTGceE1TGhCSxxfHyFpnNM 10. Isometric Drawings: kzbin.info/aero/PLIhUrsYr8yHxVky7bfrnbRcdXcHjT_K83 11. Conic Sections: kzbin.info/aero/PLIhUrsYr8yHx0TuqsY0FUZ7Z24BbKxJoQ 12. Cycloidal Curves: kzbin.info/aero/PLIhUrsYr8yHwwA8eBea78pJW1lw9XAv6z 13. Involute: kzbin.info/aero/PLIhUrsYr8yHzu8pqYvGwQoJKVpuS1Jusa 14. Plain Scale and Diagonal Scale: kzbin.info/aero/PLIhUrsYr8yHwTgo_zu_ELqOC1ypcp5Gr9 15. Complete Engineering Drawing in one single Playlist: kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS Topic-wise Playlist of Engineering Drawing / Engineering Graphics in Hindi 1. Orthographic Projection in Hindi: kzbin.info/aero/PLIhUrsYr8yHy3chHVzYA4BMbY9DbhyYSY 2. Projection of Point in Hindi: kzbin.info/aero/PLIhUrsYr8yHwinNUxVA1NW0xxLRlDfINH 3. Projection of Line in Hindi: kzbin.info/aero/PLIhUrsYr8yHyvWb87YtG3A3jDEnChgzir 4. Projection of Plane in Hindi: kzbin.info/aero/PLIhUrsYr8yHxj9N5e1oZA0x_k5ZVssf3U 5. Projection of Solid in Hindi: kzbin.info/aero/PLIhUrsYr8yHylYPjrulRGm8DSPiimxP3P 6. Scales Hindi-Urdu: kzbin.info/aero/PLIhUrsYr8yHzJA426HjlEmiRqUkJTkozB Topic-wise Playlist of Engineering Mechanics / Applied Mechanics / Fundamentals of Mechanical Engineering in English 1. Forces: kzbin.info/aero/PLIhUrsYr8yHzoyUutEK57JzWy1n-vxIS0 2. Friction: kzbin.info/aero/PLIhUrsYr8yHwY1TDraJpyYkU8Zug-kM4m 3. Shear Force and Bending Moment: kzbin.info/aero/PLIhUrsYr8yHy1lc0hEhbpEAGsGwNmUWt7 4. Trusses: kzbin.info/aero/PLIhUrsYr8yHwIXEt9cqjEsEO8l83xcIf7 5. Centroid and Centre of Gravity: kzbin.info/aero/PLIhUrsYr8yHzZ52dVA3wQ_0IQVl7CKL7p 6. Moment of Inertia: kzbin.info/aero/PLIhUrsYr8yHw8qWxAVOx-5Y2XfGPOmcDy 7. Dynamics: kzbin.info/aero/PLIhUrsYr8yHwOZxmY63A_lURu6c-jNk-z 8. Complete Engineering Mechanics / Applied Mechanics in one single Playlist: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS

[@sengulseydaylmaz2637]

0.11 formula If we do not know how can we solve with 0.393

[@yograjparajuli6506]

09:40 to 10:00

[@AwolRedi]

Sorry I think that when you are calculating the area of semi-circle you made some eror that is πr square divided by 2 becouse it is semi-circle

[@sureshbabucheedella8147]

Sir small doubt ,can moment of inertia can be negative value ?

[@srinidhibhat]

No it will never be because area and distance will both always be positive themselves more or less on a plane it wont be negative. I think correct me if i am wrong

[@vamsikrishnakaki9828]

Nice explanation thank you very much sir

[@amitmishra958]

Very nice sir 👌👌👍

[@NathanPaku-u1p]

The area of circle should be divided by 2 since it's a semi-circle 😊

[@talhanadeem7593]

Amazing video :D

[@yograjparajuli6506]

09:40

[@thrivarn_arjun_9569]

In text book taking x1=-6 why

[@yashbhaigaming6204]

area of x2 and x3 is wrong and iyy3 is also wrong becoz of x3 has been changed

[@technicalstudyTEengineer]

Good concept

[@ssss8619]

Sir, can you explain how to get 0,11r⁴ for the Inertia of si circle?

[@MdHumayun-pm2kp]

Sir Thank you. Pass karwa diye.

[@54piyushkumare62]

Thanks sir its helps a lot

[@youfit5883]

I yy2 and I yy3 values will not be same

[@chikilerenukadevichikilerenuka]

Area of semi circle =pi r*2/2

[@dhiraj.govindvira]

Thank you very 😇 much.

[@tinkuji4040]

sir rolling ka video chahiye pls

[@rhshovan]

THANK YOU SO MUCH...........

[@satishmaddeshiya7457]

Area of semicircular is wrong

[@rahulnamdev9375]

Thank you

[@karishma.m8820]

Wonderful sir Tq u so much sir

[@sweetygadde5246]

Thanq sir

[@shivakumardodamani3178]

Thank you sir

[@vamsikrishna9876]

Problems on product of inertia

[@AmirHussain-rt3my]

a little bit mistake of figure 2

[@gamebredtv804]

sir pls upload derivation for moment of inertia for rectangle,semi circle,triangle,etc.,

[@kushalkhadka6707]

nice

[@sanjaybhargav1948]

First like

[@RamFitness-32]

All things are correct but addition is wrong.

[@mierdaa]

I think he subtracted the value of the rectangle from the values of two semicircles (since it's a hollow in the rect)

[@thenature1603]

Wasted my 3 hrs as u was not getting right answer because you had written Area of semi circle wrong..., rest is good..

[@ArshadKhan-dj7ce]

Yrr

[@SurajKumar-tf9iz]

Faltu