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@chandramoulisanthanam69646 жыл бұрын
The derivation shown here is what is given in most Indian textbooks and it is not correct!. It just leads to the same result. At 2:10, if the boundary is not considered why is the mass flow still (rho* 'u' *b*dy)? shouldn't it be (rho* 'U' *b*dy)?. The problem is that the ideas of boundary layer thickness, displacement thickness and momentum thickness are presented separately as if they are not connected but actually, they are very much related! For a correct explanation of these topics, please see the NPTEL video lecture on boundary layers kzbin.info/www/bejne/g6rOapqObZJ2m6s ( from 29:40)
@hemenkalita65826 жыл бұрын
thanx, the video u referred is great.
@DaniShmait6 жыл бұрын
Thank you!! Oh and to reach momentum thickness directly it's 39:00
@Azzu9745 жыл бұрын
Same doubt i raise it bro
@prathameshdand44184 жыл бұрын
Yes u r right, same doubt here.
@pratik28863 жыл бұрын
Thnx 👍👍 well done
@10231791525 жыл бұрын
At 2:08, why is the momentum flux p*u*b*dy*U , instead of p*U*b*dy*U. Don't we know that the velocity is U for uniform flow? Not u?
@anishdstar6 жыл бұрын
time: 2 min...how come the mass of no boundary layer has 'u' as velocity and not 'U'?
@giadaluppino23175 жыл бұрын
mass flow rate in boundary layer is the same as in the case with no boundary layer. is the evolution of the same flow that encounters a surface like a flat plate...
@shriharir64504 жыл бұрын
@@giadaluppino2317 how come its the same !? Its clear the the section with boundary layer is of velocity u nd without its U. So how can the massflow rate alone differ!?
@battlewing2214 жыл бұрын
same doubt bro any answer you got?
@shriharir64504 жыл бұрын
@@battlewing221 its actually wrong here... Nd its also wrong in many textbooks!!! Go to nptel videos and watch them... They teach the correct method.
@battlewing2214 жыл бұрын
@@shriharir6450 nice
@rifat6049 Жыл бұрын
thanks.... long live India
@adarshthallapelly19424 жыл бұрын
While calculating momentum loss per second without considering boundary layer I thing it would be (rho*U^2*b*dy) bcz velocity is constant i, e U with no B.L condition
@rohannalawade32276 жыл бұрын
How is the mass for boundary less same as that of the case with the boundary. Shouldn't it be p×U×dy×b. ?
@giadaluppino23175 жыл бұрын
is the same for continuity equation... mass conservation!
@029mdsaif94 жыл бұрын
@@giadaluppino2317 i did not think so, tell me in displacmenet thickness why their is no continutity equation?
@배병준-r2m2 жыл бұрын
Thank you sir
@Watersolutionhub6 жыл бұрын
Sir thank you very easy explanation
@muhammadusmanarif53385 жыл бұрын
Thanks.
@rumamahato58594 жыл бұрын
If momentum thickness increases then velocity increase or decrease?