Momentum Thickness

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TutorialsPoint

TutorialsPoint

Күн бұрын

Пікірлер: 34
@TutorialsPoint_
@TutorialsPoint_ Жыл бұрын
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@chandramoulisanthanam6964
@chandramoulisanthanam6964 6 жыл бұрын
The derivation shown here is what is given in most Indian textbooks and it is not correct!. It just leads to the same result. At 2:10, if the boundary is not considered why is the mass flow still (rho* 'u' *b*dy)? shouldn't it be (rho* 'U' *b*dy)?. The problem is that the ideas of boundary layer thickness, displacement thickness and momentum thickness are presented separately as if they are not connected but actually, they are very much related! For a correct explanation of these topics, please see the NPTEL video lecture on boundary layers kzbin.info/www/bejne/g6rOapqObZJ2m6s ( from 29:40)
@hemenkalita6582
@hemenkalita6582 6 жыл бұрын
thanx, the video u referred is great.
@DaniShmait
@DaniShmait 6 жыл бұрын
Thank you!! Oh and to reach momentum thickness directly it's 39:00
@Azzu974
@Azzu974 5 жыл бұрын
Same doubt i raise it bro
@prathameshdand4418
@prathameshdand4418 4 жыл бұрын
Yes u r right, same doubt here.
@pratik2886
@pratik2886 3 жыл бұрын
Thnx 👍👍 well done
@1023179152
@1023179152 5 жыл бұрын
At 2:08, why is the momentum flux p*u*b*dy*U , instead of p*U*b*dy*U. Don't we know that the velocity is U for uniform flow? Not u?
@anishdstar
@anishdstar 6 жыл бұрын
time: 2 min...how come the mass of no boundary layer has 'u' as velocity and not 'U'?
@giadaluppino2317
@giadaluppino2317 5 жыл бұрын
mass flow rate in boundary layer is the same as in the case with no boundary layer. is the evolution of the same flow that encounters a surface like a flat plate...
@shriharir6450
@shriharir6450 4 жыл бұрын
@@giadaluppino2317 how come its the same !? Its clear the the section with boundary layer is of velocity u nd without its U. So how can the massflow rate alone differ!?
@battlewing221
@battlewing221 4 жыл бұрын
same doubt bro any answer you got?
@shriharir6450
@shriharir6450 4 жыл бұрын
@@battlewing221 its actually wrong here... Nd its also wrong in many textbooks!!! Go to nptel videos and watch them... They teach the correct method.
@battlewing221
@battlewing221 4 жыл бұрын
@@shriharir6450 nice
@rifat6049
@rifat6049 Жыл бұрын
thanks.... long live India
@adarshthallapelly1942
@adarshthallapelly1942 4 жыл бұрын
While calculating momentum loss per second without considering boundary layer I thing it would be (rho*U^2*b*dy) bcz velocity is constant i, e U with no B.L condition
@rohannalawade3227
@rohannalawade3227 6 жыл бұрын
How is the mass for boundary less same as that of the case with the boundary. Shouldn't it be p×U×dy×b. ?
@giadaluppino2317
@giadaluppino2317 5 жыл бұрын
is the same for continuity equation... mass conservation!
@029mdsaif9
@029mdsaif9 4 жыл бұрын
@@giadaluppino2317 i did not think so, tell me in displacmenet thickness why their is no continutity equation?
@배병준-r2m
@배병준-r2m 2 жыл бұрын
Thank you sir
@Watersolutionhub
@Watersolutionhub 6 жыл бұрын
Sir thank you very easy explanation
@muhammadusmanarif5338
@muhammadusmanarif5338 5 жыл бұрын
Thanks.
@rumamahato5859
@rumamahato5859 4 жыл бұрын
If momentum thickness increases then velocity increase or decrease?
@santoshanand8237
@santoshanand8237 2 жыл бұрын
Increases
@98adityasingh
@98adityasingh 6 жыл бұрын
Brief and perfect!
@shivasmart967
@shivasmart967 3 жыл бұрын
tq sir
@shuklaacademy1138
@shuklaacademy1138 3 жыл бұрын
Thanks sir for the doubt clearing video
@vinodmalve7320
@vinodmalve7320 6 жыл бұрын
Perfect
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