MOSFET Solved Problems (Part 1)

[@picturization3914]

Thanks for all these tutorials. They are very good. In this video, I think it may be confusing to say the rate of change of Id and Vgs are the same for the obvious reason that it depends on the values of those constant K, Vt, Vp and Idss. My interpretation of the Maths in this video would be this. Both enhancement type and Depletion type share a linear relationship between the variables d(Id)/d(Vgs) and Vgs because it's equivalent to a straight line y=mx + c. Where y=d(Id)/d(Vgs) and x=Vgs. The slope of the lines m are with different constant values and the constant c too. Hence, the rate of change Id per unit change of Vgs is not the same.

[@sinanemresenem4009]

thank you, the lectures are really helpful and perfect, one thing how do we say that the constants are the same at the end?

[@nilliusinverba6517]

As far as i understand, we are not actually saying that the final results imply the same thing. Since the question is asking the 'rate' we can say that the rates are same no matter what the constants are. It has been quite a while since you ask the question but I thought it might be useful for those who will watch the video recently :)

[@neerajhebbar7313]

in the equation if we put -ve value of Vgs then Id is increasing its exactly opposite you explained in the mosfet working depletin region

[@TechnicallyExplained]

congratulations on one million subscribers...

[@Hrcian]

now two million

[@helloUser12373]

GREAT VIDEOS BY YOU . THANKS VERY MUCH. But I have a doubt, how can the rates be same when constants are different.

[@yallaskate]

the constants are given in the question, if theres a higher order term then the rate of change will change significantly

[@vaideshshankar9899]

+yallaskate same doubt

[@student6830]

@Other comments: He didn't say all the constants are the same. He said that because they're all constants, the rates of change would be APPROXIMATELY the same. It's like saying y = 1.4x is similar to y = 1.5x

[@satyamchauhan9775]

but how ypu can say they are nearly same

[@23sivenkat]

@@satyamchauhan9775 Put x=1 in both equation , we get y=1.4 from first equation and y=1.5 from second, which are nearly same values.

[@bruhbruh4137]

@@23sivenkat put x=0, y=0 and x=0 bruhhhhhhhhhhhhhhhhhhhhhhhhh

[@23sivenkat]

@@bruhbruh4137 Thank you for replying.You are saying if we put x=0 in both equations then y becomes zero in both which is fine.But to prove they are nearly same, i put x=1.

[@StrengthThroughWisdom]

Sir why did you differentiated wrt to Vgs and not Vds.??

[@ramkrishnaverma5694]

How you assume all constant is c??

[@amitYouTubee]

good question. +1

[@94D33M]

nice question, +2

[@anirbanghosh6328]

@@94D33M i came into the comment section for this only

[@demetriusdemarcusbartholom8063]

Thank you

[@pinkichoudhary6637]

its so gud sir nd very useful thanku so much

[@vinaykumarkarri2702]

@@amitKZbine what happened to u bro.. If she is appreciating

[@abhishekdasgupta4786]

Good Evening Sir What is the relation Between Vt and Vp?

[@GeekyKidz]

thank you very helpful

[@tejapedapati8277]

why have u taken the change in ids w.r.t to vgs ? the rate of ids is more dependent on vds than vgs..

[@ritukumari7968]

why Idss is constant as explained in the previous video it changes as Vgs changes

[@satyamchauhan9775]

idss is the current when vgs is zero

[@VanshikaBansal-k4n]

but sir what if the constants that we have taken are not same for both then there must be factor by which one of them increases faster than the other sir please explain why you took them all as the same constants

[@StrengthThroughWisdom]

Sir what is Idss in case of depletion type MOSFET.

[@Sidd-rb4ec]

In depletion type mosfet doesn't Idss depend on Vgs and is not constant?

[@saadarshad8973]

how derivative of -1/vp is positive?

[@amitYouTubee]

when you differentiate using pen and copy then u no need to ask. on differentiating u find one times '--' --(Vp-Vgs)==(Vgs-Vp)

[@rahulsannigrahi8550]

How u can take c const for both Vt and Vp

[@sherlly3168]

sir please upload mosfets other features such as amplification ,small signal models and also frequency response

[@architsharma8071]

+1

[@amitYouTubee]

first understand this, Q. rate of increment or decrement will be same only slope will also same but here how can we assume 2k=(2IDSS/VPP2)? clear my doubts please u understand well, because u wish to another video on mosfets other features such as amplification ,small signal models and also frequency response.

[@janataroy2293]

Wow

[@divnoorsinghchugh4416]

Enhancement wale equation mein jo c liya hai aur Depletion type wale mein jo c liya woh dono alag alag hain toh same rate se kaise ghat rahe

[@bhupeshbhatt4334]

Wtf! Why all constants are taken same?

[@satyamchauhan9775]

exactly i am also in shock