Surely Id3 >Id1 >Id2 because of increment in no. Of e- , charge carrier +creses and hence i +creses.
@VishalGupta-vr2ly7 жыл бұрын
the best explanation i had gone through many videos but this one is amazing
@shubhamjaiswal4963 Жыл бұрын
watching 2 day before the exam and it is the best content of electronics
@tsheringongmu12998 ай бұрын
mera exam kl h aur me aaj dekh rhi hu
@AliRaza-be1bj7 ай бұрын
@@tsheringongmu1299mera bhi kal hai 😭
@SachinMishra-i2l Жыл бұрын
its a saviour for end semester exam thank you sir
@shreyasn30786 жыл бұрын
Thanks a lot for the lectures sir!! Very nice explanations. Could you please teach field theory also? It would help us a lot....
@AwesomeMinds6 жыл бұрын
id3>id2>id1 because in case 3: when we apply Vgs>0v since gate is at +ve voltage it will attract electrons from the p-substrate thus making more electrons for the conduction.
@mukutthakuria2687 Жыл бұрын
id3 > id1 > id2
@nasrinriya42425 жыл бұрын
Amazing Sir thank you so much...Tomorrow is my xm..this is very helpful
@varunrawat5994 жыл бұрын
Your welcome
@mohammadzahidulislam39773 жыл бұрын
You’ve watched this video 1 year ago. I'm watching 1 year later because of that LOG 🙃 @Nasrin Riya
@nasrinriya42423 жыл бұрын
@Mohammad Zahidul Islam bro chill..you will nail the exam this year.💙💙💙
@mohammadzahidulislam39773 жыл бұрын
@@nasrinriya4242 in sha Allah 💜 keep me in your prayers 🥰
@kamranali66455 жыл бұрын
Sir! why the pinch off voltage is same for all the values of Vgs? As we've seen that it changes in emosfet or jfet
@picturization39146 ай бұрын
In case III where VGS>0, wouldn't it increase the depletion layer in the middle section of the N channel for the same reason, i.e. more reversed biased? If so, is it restricting the current ID in any way?
@abhibham25887 жыл бұрын
Id3 is (increase rapidaly & high ) as compare to Id2 & id1 Thank u sir
@debapriyadasgupta65348 жыл бұрын
why didn't we have recombination in case of enhancement-type MOSFET?
@rajgandhi40426 жыл бұрын
Because in that case channel is not their from the beginning
@kilarisreenivasprasad80303 жыл бұрын
@@rajgandhi4042 THERE WE ASSUMED THAT WE MAINTAIN CHARGE NEUTRALITY...SO REMEMBER DEAR BROTHER
@siddharthkshirsagar25457 жыл бұрын
sir at 6:09 you said with increasing reverse voltage the deplition region becomes narrow but actually it should be broad
@Aman-Verma7 жыл бұрын
he said width of depletion region will increase and channel will become narrower .
@swapnildesai56227 жыл бұрын
reverse bias ,so depletion region is broad but channel of conduction is less ,like in jfet in reverse bias depltion increses and channel is dreaseses
@sonikashyap48046 жыл бұрын
right
@chandrakanti38045 жыл бұрын
He said that depletion region will become more thicker and channel through which current will flow will become more narrower
@koppulapremsagar2 жыл бұрын
@@swapnildesai5622Firstly go and learn the spellings of "Depletion , Increase and Decrease" plz.!!
@hemkumarpatel46147 жыл бұрын
siddharth you are right, it was wrong. by increasing reverse bias voltage, depletion width is going to increase.
@riteshraj72866 жыл бұрын
what is the difference between N-channel D-MOSFET and E-MOSFET, explain with their transfer function and output characteristic.
@Travelwithranveer6 жыл бұрын
Nice one!!!👌👌👌
@jeetendra15786 жыл бұрын
id3 > id1 > id2
@anirudhmuthuswamy80915 жыл бұрын
you said if we increase V(DS), after a point I(D) becomes constant due to reverse bias in the n-region under the drain. Why does I(D) increase in the first place if a reverse bias is present in the drain?
@clutterphobic5 жыл бұрын
Same doubt I have... But nobody reply
@juturubharathi85105 жыл бұрын
Intially it has less depletion region but when we increase vds then depletion region also increases the hen id becomes constant and at the same time while keep on increasing vds at particular point there is a drastic change in the current.
@ahanray3 жыл бұрын
I think that the reason for the increase in id is because of the fact that there is a potential difference between the Drain and the Source. Since the source is doped, we find an abundance of carriers willing to go to the drain causing a current id. Now, extending this logic, when we further increase Vds the current increases but due to the decrease in conducting path, the resistance of the channel increases hence the current decreases. The assumption is that the rate of change of voltage is smaller than the rate of change of the height of the depletion region. I hope this helps.
@fardeenahmed11477 жыл бұрын
Thanks.... hope we will see some more tutorials
@MrJojija7 жыл бұрын
Id3 > Id1 > Id2
@changliu487 жыл бұрын
May I know why with negative V_GS both electrons and holes are attracted and that was called recombination, but with positive V_GS only electrons are attracted and that was called collision?
@ashimdas22076 жыл бұрын
Electrons and hole attraction is called as recombination. And electron and electron repulsion is called collision... I hope you understand my point
@rashitasingla99405 жыл бұрын
same is my doubt
@prashankbhardwaj57747 жыл бұрын
Ty sir 4 it.this is awesome.keep doing this work.
@Learner-lq3vu Жыл бұрын
03:50 Isnt the current direction in depletion mosfet from drain to source
@v.kfunstudio51953 жыл бұрын
at VGs >0 minority carriers i.e, electrons will be accelerated ? With whom it will collide? electrons in the n channel or between themselves?
@vijetasarswat96107 жыл бұрын
Best explaination
@agstechnicalsupport7 жыл бұрын
Clear and to the point.
@PoliticsWithAkhil7 жыл бұрын
If gate terminal is insulated from channel how do the negative charge on gate repel conduction ē from channel (when Vgs=-ve)
@santhoshrapolu40677 жыл бұрын
Actually an oxide is between the gate terminal and the channel, so it's operates same like a capacitor, so there generates a conventional current.
@PoliticsWithAkhil7 жыл бұрын
Santhosh Rapolu tanq
@saritaverma39747 жыл бұрын
Best explanation
@domithangeo8767 жыл бұрын
Can anyone know the general working and construction of D-MOSFET...AM LOOKING FORWARD TO IT...THIS ARE ALL N-type and P-type working
@abhibham25887 жыл бұрын
Domi Thangeo it will be not a passible for forward baised
@bestcakesdesign5 жыл бұрын
Why we start study only by keeping V(GS)=0v not starting from V(DS)=0v
@jyothikorupuri29367 жыл бұрын
sir should we take an insulator inplace of p type substrate
@puneetpandey54517 жыл бұрын
what is Vdd in case of n channel depletion mosfet
@bubunmazumder7 жыл бұрын
Sir,why inversion isn't occured in the case of case-2,i.e.,when Vgs is negative?
@swapnildesai56227 жыл бұрын
inversion will not occured becaause electrons attract posistive ions, and when Vgs is negative due to Sio2 layer positive ions occurs opposite side and dey is already positive charge becuz of p substrate , inversion will occurs only wen we apply Vgs.
@vinayvinnu1282 Жыл бұрын
when vgs =0 how does the e- moving from n region through p substrate
@venkateshpolisetty56246 жыл бұрын
id1>id2
@hanumantha18176 жыл бұрын
Thanks bro...
@saisumanth80647 жыл бұрын
it is so simple (ID1ID3)
@SurajSingh-jc7hc5 жыл бұрын
Why did we short circuited gate and source here?
@n.m28514 жыл бұрын
how does pinch off occur at VGS = zero? in DE-MOSFET? nobody explains that
@artibisht3705 жыл бұрын
one more question...gate is connected through dielectric... metal (gate)/dielectric/ Metal.. its making capacitor right?so when we apply -ve voltage to the gate other side it must induce +ve voltage..so how canit repels electrons......am i right or wrong please clear..
@dhirajkumarmewal40263 жыл бұрын
Now make construction again with source and body terminal connected. what would you found, you must found that if V(gs) is negative then body terminal should positive, which is connected to p type substrate now holes will repel and electron will attract. try it, If you read it carefully you would surely find your answer. By the way, Very good Question.
@alterguy43277 жыл бұрын
Id3 >Id1>id2
@Alokkumar-tf8jq6 жыл бұрын
sir PN junction se to current flow hona hi nhi h..... to Depletion layer ki width increase hone se ID kaise level off ho sakta h.... clear kre jra
@GauravGupta-pb8mk4 жыл бұрын
Thank you sir
@parthmodi41818 жыл бұрын
id3 is highest
@deeprobardhan34115 жыл бұрын
Why gain source voltage of jfet cannot be positive? If positive .. it will produce more current in jfet ...
@parthmodi41818 жыл бұрын
thankyouu so much sir
@sameershirodkar30886 жыл бұрын
Sir what about the p type depletion mosfet ... How is it different. . pls respond asap i have exams🙏🙏🙏
@rakeshkota75318 жыл бұрын
hai..sir her sio2 is insulator...then how gate adding and attract the hole and elections..?
@arpitgupta67105 жыл бұрын
okay
@MobinSyd6 жыл бұрын
Please explain IGBTs
@rahulsannigrahi85505 жыл бұрын
Why Id current after increase become const why not it will decrease as the channel becomes narrow
@jefferyaustin15717 жыл бұрын
I am not sure what you try to do that you define Vg and Vd and place them in front of Vgs and Vds then take a loop without explaining how and what. Even though I took circuit analysis courses, but still could not understand what you try to do. Hope you can explain different ways and better. In fact, I understand why the channel becomes pinch-off.
@bpallavi86155 жыл бұрын
Sir,in case-3 their will be a drastic or rapid increase in drain current as comparing to case-1 and case-2.
@swastikapremanandh61573 жыл бұрын
what is Vdd here?
@susheelapatgar36403 жыл бұрын
Thank u sir
@prashankbhardwaj57747 жыл бұрын
Anyone plz tell me that what is the work of silicon di oxide layer in this??
@furqanmughal34627 жыл бұрын
Prashank Bhardwaj due to silicon dioxide the input impedance of mosfet becomes very high
@riyarajput87985 жыл бұрын
Due to this input impedence will high and as well as we can say that sio2 also provides better isolation and it also behave as a good dielectric material that's why we use sio2
@ahmedfrazafzal52396 жыл бұрын
nice sir
@अखिलेशअक्की7 жыл бұрын
thanks
@VishalSharma-ri3ih4 жыл бұрын
Id 3 > Id 1 >Id 2
@venkatrao4047 жыл бұрын
thanks sir
@varunrawat5994 жыл бұрын
It's ok
@mikeejohnbaesa6987 жыл бұрын
thankyou so much. :)
@SachinSingh-gg9md4 жыл бұрын
nice...
@hamzazahid77687 жыл бұрын
nice
@hemanthgooty8 жыл бұрын
great
@sufyanch58537 жыл бұрын
level (Y)
@anassaifi76135 жыл бұрын
Saviour
@saikumar-zw7bj3 жыл бұрын
Classes on 4G
@sourabhrathour5080 Жыл бұрын
obviously... Id3>Id1>Id2...
@lawrenceopoku61637 жыл бұрын
great video.great work neso academy.God bless you.Jesus is Lord and he is coming soon.make him Lord of your life if you havent.
@bishnupriyarout37306 жыл бұрын
I want p channel d mosfet
@sonushaik12186 жыл бұрын
Just change the substrate and wells
@vishwajeetyadav8106 жыл бұрын
Same to
@sonushaik12186 жыл бұрын
Once go-to learning of electronics
@ideapadgaming-b9q Жыл бұрын
i3 is higher than the rest two
@Rakshi_36 ай бұрын
👍
@leeeknowerrr168411 ай бұрын
❤
@phoenixop46733 жыл бұрын
❤️🤝
@vibhorbhatnagar70745 жыл бұрын
you keep on repeting same point again and again... from the begining from the begining.. u said it four times here and two times in last video... thats completly useless... cover main pouint rather than this