Motion Graphs (6 of 8) Displacement from the Velocity vs. Time Graph

[@lika3002]

I’m came late to the lesson we learnt this in and didn’t understand it. Thank you so much for this clear explanation

[@stepbystepscience]

You are very welcome, thanks for watching and commenting.

[@sabeenamohammed7946]

9

[@dbuc4671]

@@sabeenamohammed7946 cool

[@beepbeeplettuce848]

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[@CH-gm6rl]

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[@aleccoburn6533]

Incredibly helpful. I go to a private high school and my AP Physics teacher couldn't explain this as clearly in 30 minutes as you did in 10.

[@stepbystepscience]

Thanks for the comment, great that you found the video helpful. Where do you go to school? I went to Riordan, also a private school, in San Francisco, but am now living in Berlin Germany.

[@aleccoburn6533]

I'm a senior at Bellarmine College Preparatory in San Jose. Definitely going to continue watching your videos - they explain in far more detail what my physics teacher just glances over during class.

[@stepbystepscience]

Great that you found the video help and thanks for the comment.

[@THEREASONIMHERE]

Thanks. I'm taking AP Physics this year without any Physics background because I had ap chem last year and now this makes much more sense!

[@rhiannonkandaris8506]

thank you so much!! i’m a freshman in high school and we’re learning this and it’s absolutely so hard to understand, my teacher couldn’t have explained it half as good as you did!!

[@stepbystepscience]

You are welcome, thanks for watching and commenting.

[@hmm_no]

Without you, I'd have fail in my physics exam. THANK YOU SO MUCH!

[@tdjhue]

Me as well!

[@adhesivespoons5786]

Awesome that you're still active on this channel after 7 years! Helping students then, helping students like me right now, in distance learning :D

[@stepbystepscience]

Happy to help, hope the distance learning goes well.

[@safaa9753]

Before watching this video I found it a perplexing method but you made it easy for me your way is incredible thanks alot

[@stepbystepscience]

Great to hear!

[@jakelineychavez]

All I can say is God bless you good sir! I understand!

[@vikramkulkarni3928]

Thank you so much! I'm taking AP Physics 1 this year and my teacher can't teach. I've learnt more from this video in ten mins then what we learnt in school for two weeks. So really appreciate this! :)

[@stepbystepscience]

Great that the videos are helpful!

[@stepbystepscience]

You are very welcome.

[@lonelychildrenoffici]

Thank you for elaborating on what my college professor skimmed through!

[@nicholasaragon4723]

I have been stuck on this for 2 weeks and its finals week next week for me THX SO MUCH!!!

[@stepbystepscience]

You are most welcome. Happy holidays!

[@Sophiemum]

Thank you! I was having problems with the exact method even though I knew the verbal explanation of what was happening. I know that sounds weird, but having a step by step visual representation was so helpful! Thank you!

[@stepbystepscience]

You're very welcome! And that is why I try to present everything step by step!

[@temotoes9182]

Thank you for all the help I can't understand my professor clearly in class so this really helps!

[@stepbystepscience]

Happy to help and thanks for the comment.

[@edgarfranco367]

So this what my professor didn’t explain clearly, the difference between distance and displacement. Thank you 🙏🏻

[@stepbystepscience]

Happy to help!

[@venispatel4809]

My exam is tmrw and this explanation made it so much easier for me to understand this concept thanks man keep up the good work :) THANK YOU, U REALLY HELPED ME THANKS

[@stepbystepscience]

Glad to hear that and thanks for the great comment.

[@yashdaryani8954]

Thanks a million. Helped a lot. My physics teacher cannot teach. I know that this is a very simple topic/concept, but still my teacher couldn't teach us properly . This was amazing. Good job!

[@stepbystepscience]

Great that you found the video help and thanks for the comment.

[@zedm1582]

Thank you very much this really helped me with my work sheet my teacher does not describe it like you did. Thank you again

[@stepbystepscience]

You're very welcome! I'm glad the video was helpful.

[@LolaOsos]

thank u so much u explain it much better than my teacher and ur way of solving it is much easier to understand

[@stepbystepscience]

Great, thanks for the comment.

[@iiheartemerald]

Yoo thank you so much i’ve been working on my homework for hours it is 1o’clock in the morning and this was the only video that help me solve the problem❤️!

[@stepbystepscience]

So glad I could help, thanks for the comment!

[@janmartinek5928]

Thank you, you saved my physics homework mark

[@stepbystepscience]

+Jan Martinek No problem, thanks for commenting!

[@selenahe2165]

thanks so much! this wasn't explained by my teacher so this really helped

[@stepbystepscience]

You're welcome. Glad it helped!

[@peasant3986]

My physics teacher never explains anything well. This video was incredibly helpful.

[@stepbystepscience]

Great that you found the video helpful. Thanks for commenting.

[@joyjustin2593]

really helpful and i easily understood the concept

[@mazhargreat2325]

Thank you sir, this video helped me a lot!

[@DetectiveConan990v3]

physics quiz coming up and this really did help

[@stepbystepscience]

Hope it goes well, let me know

[@JeNeComprendsPasAuRevoir]

This helped me a lot, I have a test today and I didn't understand how to do this but I do now. Thank you!

[@stepbystepscience]

Glad it helped! Hope the test went well.

[@fidanramazanli9784]

I am so thankful for this great explanation! You saved me

[@stepbystepscience]

You're welcome!

[@AliumMoAnn]

Thank you so much...you explained it much better than my book...it overcomplicated everything

[@stepbystepscience]

Awesome and thanks for the comment. You can see a listing of all my videos at my website,www.stepbystepscience.com

[@ChirsHunter]

So helpful, thank you so very much and have a nice day!

[@stepbystepscience]

You're very welcome. Glad it helped!

[@ahmedelwakeel225]

Awesome Explanation! Thanks

[@yvesnardlamisere4688]

Thank you..........It really help me to do my homework

[@Patience96.]

Thank you so much. This is the easiest solution for finding the displacement of a velocity vs time graph.

[@stepbystepscience]

You are very welcome.

[@adorableisa2732]

Nice Explanation!!I have a small doubt ....how r we finding both displacement and distance using velocity time graph with the SAME METHOD ? it would be amazing if u reply

[@stepbystepscience]

The area under the curve is the displacement of the object. This can be either negative or positive or zero depending on the direction that the object is moving. Practically speaking he the displacement will be negative if the velocity is negative. This would mean that the object was traveling in the negative direction. To find the distance that the object has traveled just use the positive values (drop the negative signs) for the displacements that you calculated and then add them up. Does that help?

[@adorableisa2732]

@@stepbystepscience Thank u soo much

[@adorableisa2732]

@@stepbystepscience Really helped !!

[@demanic2591]

So would it be 80m

[@demanic2591]

@@stepbystepscience so would it be 80m?

[@Willwrz]

Hi, for the first problem, can you use the area formula for a trapezoid to solve it?

[@stepbystepscience]

Yes you can but a lot of people are not familiar with that equation.

[@EthanBCWEntertainment]

Thanks so much! Before I was so confused but this makes so much sense!!

[@stepbystepscience]

Great that the video helped you clear it up.

[@rhodoraruiz530]

Thank you so much for such a clear explanation. I am your follower now.

[@stepbystepscience]

Awesome, thank you!

[@yasminehelen2942]

is the displacement of the velocity graph the same as the displacement of the original f(x) graph? if yes, would you also be able to find the displacement from the original f(x) graph or does that not work? I just don't understand why we are using the velocity graph to find displacement of the particle instead of using the original f(x) graph...

[@yashpalyadav4808]

I have one problem. How would you know that displacement = area enclosed between VT line/curve and time axis, can't we find area between VT line and velocity axis to know the displacement. I know that what I'm saying is wrong and it can be proved practically by thinking a constant velocity and finding both area one says some displacement and other says no displacement, but how theoratically you'll prove me wrong. We use this concept in many other field also like finding work done in pressure-volume graph. May be I asking a stupod question but please help me.

[@stepbystepscience]

+Yashpal Yadav I am not 100% sure what you are asking but….the area under the velocity vs. time graph is the displacement. If the area is a rectangle then….the area is height (velocity) x length (time). Area is then velocity (m/s) x time (s) = displacement (m). Does that answer your question? You can see a listing of all my videos at my website,www.stepbystepscience.com

[@grizzlybear7895]

Is displacement and velocity the same? What is the difference as they are both equal to the area under the curve?

[@stepbystepscience]

Displacement and velocity are not the same. Displacement is your change in position and velocity is your rate of change of position. Velocity is also often stated as how fast you are going and in what direction you are going. Speed with a direction. They are not both equal to the area under the curve. Only displacement is equal to the area under the velocity vs time graph. Does that help?

[@grizzlybear7895]

@@stepbystepscience yes thank you so much I'm doing my physics homework right now and am so lost as I just moved to a new school and they have learnt so much more than me

[@stepbystepscience]

@@grizzlybear7895 You are welcome, I hope you get it figured out. Let me know if you have any other questions.

[@amnarehan6852]

Thank u so much ! u r a great teacher!

[@stepbystepscience]

So nice of you, you are welcome!

[@anuradhasuresh3272]

Good explanation sir....

[@mohammadalyasi4071]

Thanks soo much, you earned a like.

[@stepbystepscience]

You're welcome!

[@adyy444]

tysmmm! you literally saved my life 😅

[@stepbystepscience]

Glad I could help Thanks for the comment.

[@fatimadelowar9106]

Can u also make a video about how to calculate free fall ...in negative types of graph ... i mean da second graph which u did....😣

[@lcv8525]

Thank you 🙏 now I’m going to pass my test tomorrow

[@stepbystepscience]

Best of luck!

[@marilynspikes]

Excellent. Thank you for explaining this so clearly.

[@dbuc4671]

7 years later

[@user-rd5nc1nb9f]

This video was pretty good thank you

[@stepbystepscience]

You are very welcome.

[@blitherwinner4955]

This helped a lot. Thanks!!!

[@stepbystepscience]

Glad it helped!

[@anasooyasree9156]

This was so useful! Thank you! ❤️❤️

[@stepbystepscience]

Glad it was helpful! You're welcome.

[@brian8529]

Ty my asian mum was going to spank me if I didn’t get this question

[@stepbystepscience]

ouch!

[@BaderElFarran]

Thank you so much :) Much appreciated !

[@cheesburgerlolcats]

Thank you so much for this tutorial! it was really helpful :)

[@stepbystepscience]

Great, thanks for commenting-

[@mikuculus3720]

Wait if it’s just the area under the curve can I just make it a definite integral with time regions?

[@johnhuffman921]

Why is the #2equation a positive 18m since the velocity is in a decline shouldn't it be negative?

[@stepbystepscience]

All of the velocities on the graph are positive (they are above the zero line on the graph) Yes, the velocity is decreasing but it is decreasing in the positive direction. If the motion line was below the zero line then the velocity would be negative. Remember the sign of the velocity does NOT tell you whether the object is speeding up or slowing down, the signs of the velocity tells you the direction of motion. Also, to get the displacement you need the height of the triangle and in number 2 the triangle is +18 m/s high. It does not matter whether it is speeding up or slowing down. Does that help?

[@jacob-jm2xp]

Super helpful.

[@stepbystepscience]

Super comment, thanks for watching.

[@shauryasingh7792]

thank you sir for explaining it helps me very much

[@stepbystepscience]

Glad to hear that, you're very welcome.

[@adventkent5904]

What if you have a graph where the velocity lands at 0 for 10 seconds having constant acceleration. How do you solve the area of such straight line ________ / \ / \________ \ / \_______/

[@adventkent5904]

Or the area is zero if it lands at 0 velocity? Please answer sir.

[@stepbystepscience]

If the velocity is zero then the acceleration is also zero.

[@adventkent5904]

Thanks

[@alok289]

Thank you for the video.

[@chittarlaalsingh]

so how do u find distance on velocity time graph?

[@wonderboyy000wondergirl7]

Thanks for thiss!!!...your amazing

[@stepbystepscience]

And thanks for the amazing comment.

[@ellene20]

Switch places with my physics teacher. PLEASE!

[@stepbystepscience]

Where is your physics teacher?

[@tianawarren2569]

Where did you get 8 seconds from???

[@tianawarren2569]

Wait nvm

[@stepbystepscience]

OK

[@purplepagic5361]

thank you so much i am streullging in physocs so slay

[@stepbystepscience]

You're welcome and best wishes!

[@cry_stalll]

thank you so much, you just saved a life :) also 4:27 I did guess it so yay

[@gloryodion672]

Thank you so much, God bless!!

[@stepbystepscience]

You're welcome and best wishes to you!

[@you_can_do_it.]

Thank you so much 🖤🌸

[@stepbystepscience]

You’re very welcome 😊

[@awwesomemoment4149]

If you find the equation of the lines then integrate to find the total displacement, oddly the answer will be wrong. Does anyone know why?

[@TheBugsification]

Is the area under the graph distance too?

[@stepbystepscience]

Smooches moose Good question, yes it can be. In the second example of this video all that you would need to do to get the distance is take the negative sign off of the second calculation. The displacement is zero because you start and end in the same place but the distance would be 80 meters.

[@TheBugsification]

Brian Swarthout Thank You :))))

[@ahmadbassel571]

Thank you so much ❤️

[@stepbystepscience]

Any time! Thanks for watching.

[@jackontwodirtwheels5138]

Thank you 👍👍👍

[@stepbystepscience]

Thank you too

[@jayantideshpande8459]

Sir how displacement is equal to area??

[@stepbystepscience]

The area under the curve is equal to the length x the height. The units are then s x m/s, the seconds (s) cancel and you are left with meters which is the units for displacement. Does that help?

[@zeeyangs.r9106]

Can anyone please explain to me why the area always equals to displacement? I only understand it when the area is a rectangle.

[@stepbystepscience]

Because it is the x-axis (time in s) times the y-axis (velocity in m/s) and s times m/s equals m (meters) or displacement and/or displacement.

[@zeeyangs.r9106]

Thank you for the reply. I can understand what you said, but only when the velocity is constant(i.e, the area is in a rectangle shape). When the velocity is changing in every interval of time, (e.g. the area is a triangle), it's impossible to just choose a y(velocity) value and time it with a x(time) value, because y is ALWAYS CHANGING as x gets bigger. What I want to know is, why the displacement is the area under the line when the object has change in velocity?

[@stepbystepscience]

Zeeyang S.R It also works when the velocity is not constant. Area of a triangle is 0.5 x base x height. It is really the same thing.

[@zeeyangs.r9106]

so how it works? why the displacement equals to area of triangle?

[@abdulalmasre3471]

thank you, Mr

[@stepbystepscience]

Welcome!

[@christinayolo9557]

Thank u very much !!! 😊😊

[@stepbystepscience]

You are very welcome.

[@muddathirkhan191]

how do you find velocity in a velocity time graph

[@muddathirkhan191]

+Muddathir Khan am doing mechanics as level the quetion says i should find velocity in the velocity time graph

[@stepbystepscience]

+Muddathir Khan Just read it off of the graph, it is the time vs velocity after all. You can a listing of all my videos from my website, www.stepbystepscience.com

[@ishakhatri169]

Hii guys , Anybody from India 🙄

[@stepbystepscience]

That is a great question, I am from the US but am currently living in Berlin, Germany. Thinking of adding Hindi subtitles to my video, do you think this would be helpful? I get a lot of views form India.

[@ishakhatri169]

Yeah sir definitely it would be very helpful for persons who are not able to understand English properly

[@Zerefk9]

Thank you so much helped a lot

[@stepbystepscience]

Great that it did and thanks for the comment.

[@michellelantmusic2343]

Thank you!!!

[@stepbystepscience]

You're welcome!

[@koreankuki2138]

Nice teach

[@stepbystepscience]

Thanks so much!

[@koreankuki2138]

Can I ask u teacher

[@SymphoColors]

Thank You :)

[@stepbystepscience]

+AmmaR K. You are very welcome, thanks for commenting!

[@AbhishekSingh-zn6lo]

savage understood everything sir

[@stepbystepscience]

savage???? Excellent You can see a listing of all my videos at my website,www.stepbystepscience.com

[@AbhishekSingh-zn6lo]

oops!! saviour😂 not savage!! my bad

[@stepbystepscience]

No problem

[@blackopsplayer1000]

Thank you

[@stepbystepscience]

+Mohammed Tofigh You are very welcome. You can see a listing of all my videos at my website,www.stepbystepscience.com

[@DoubleOhSquirtle]

Thanks a lot man!

[@dbuc4671]

7 years later

[@qriffis]

thank you so much for this!

[@stepbystepscience]

you are quite welcome. thanks for commenting.

[@azizkash286]

much thanks

[@adisomyeari6379]

it really help

[@jennymitchy]

thank you!

[@stepbystepscience]

You are very welcome. You can see a listing of all my videos at my website, www.stepbystepscience.com

[@707Menta]

6:12

[@sammied574]

THANK YOU!!

[@amychou8467]

Hi! Thank you soo much!

[@dbuc4671]

7 years later

[@arwa1168]

I wish that you’re my physics teacher :(

[@stepbystepscience]

That would be nice.

[@bradleysoutas2388]

really made it understandable! thanks a lot!

[@stepbystepscience]

+Bradley Soutas You are very welcome, thanks for commenting.

[@evelynsalas6634]

How did he get 8 on the last problem?

[@mahendrasingh134]

helpful

[@ishanchoudhary4179]

But why did you take 8s ?

[@increasingrain]

Thanks

[@akshayarao6089]

Thank you! helps

[@stepbystepscience]

You are of course very welcome. And don't forget, you can see a listing of all my videos at my website,www.stepbystepscience.com

[@devingraves8044]

Thank

[@stepbystepscience]

You are very welcome, thanks for commenting.