What FRQ #3 on the AP Precalculus Exam Will Look Like

[@vtyt9685]

Damn Its kinda funny to see how many people just like me are also watching these videos last minute too! Good luck to everyone on their exams and I know all of you are going to slay!

[@koushikyamsani6046]

watching this last second

[@adanaamun7921]

Test today, pray for me 😭

[@ohchelsea]

we got this 🙌

[@NerfAthena]

Honestly I need a 4 for this exam so idk if I am good or not cause this hard

[@tomatopatato20]

for Cii, can I also say the that the rate of change of h is increasing at a decreasing rate on the interval t1 and t2? is that sufficient or do I have to show

[@piggy5057]

do you need to use decimals or could i keep fractions as the variables

[@mporinchak]

Some problems specifically will say to give a decimal approximation. But if it doesn’t fractions are totally fine

[@nikhilapte4782]

For part C (i), if the question asked for the interval from J to K, would it be negative since it is below the midline, or do the y-values literally have to be negative numbers?

[@mporinchak]

No still positive. Ci is asking about the output values. The values are still positive even though below the midline. If the midline was y=0 then they would negative. But the values themselves are still positive in this problem.

[@mporinchak]

Check out this video for more How to Crush Free Response Question 3 on the AP Precalculus Exam kzbin.info/www/bejne/f2TVgGp9m56HpJI

[@adeolaadeyemo5249]

For Part Ci, the correct answer is b. I took the mock test and the answer key said b.

[@mporinchak]

Must have been a different question. Because from K to P in the graph the function values are positive and increasing which is choice A

[@AlexGold-wo7kh]

@@mporinchak But isn't graph decreasing because it concaves down? That's what you said in in part ii

[@mporinchak]

Part i (the multiple choice question) is asking about the function function values which are the outputs. They are increasing and positive from K to P. Part ii is asking about how the rates of changing are changing. Because concave down the rate of changing decreasing over the interval K to P. So it’s a matter of is the question asking about function values or rates of change over the interval.

[@eshokorat2994]

for B, would h(t) = 6sin(10pi(t+0.05))+20 also work?

[@mporinchak]

You would need the a value to be -6. If you start with a horizontal translation right 0.05 notice the sine curve goes down to its min first so that’s require a reflection across the midline. So you need the negative in front of the 6

[@hfdjsk9915]

@@mporinchakCould you do 6sin(10pi(t+0.15))+20?

[@nuhaibrahim7929]

for Cii how are the rates decreasing?

[@mporinchak]

In that interval the graph is concave down. The rate of change are getting less and less.

[@nuhaibrahim7929]

@@mporinchak what values show it getting less positive? so sorry, I might just not be seeing it correctly.

[@spicynoodlez9415]

@@nuhaibrahim7929 for me its easy just to see if its concave down the rates of change are always decreasing

[@AraPicasso]

Why would you consider points K to P as t1 and t2 and not points F and G?

[@mporinchak]

Because that is what the question stated were the two point to analyze. On the actual exam it could be another set of two points. But on this question it said K to P. Does that make sense?