Integral of cos(ax)cos(bx) WITHOUT integration by parts

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Mu Prime Math

Mu Prime Math

Күн бұрын

Пікірлер: 16
@MuPrimeMath
@MuPrimeMath 5 жыл бұрын
Has anyone counted the number of times that I said "right here"?
@martinr3167
@martinr3167 5 жыл бұрын
import math print(math.floor(2*math.pi)) :v
@VibingMath
@VibingMath 5 жыл бұрын
Yes! Thank you for reminding! We can use this method to handle sinsin, sincos and coscos type integration
@alwaysuseless
@alwaysuseless Жыл бұрын
The math is great, and verbally the presentation is good. The one big improvement you could make in presentation is to AVOID erasing. Just move down and then eventually over to the right. The camera can follow you.
@hudyakovnick
@hudyakovnick 7 ай бұрын
Shouldn't "+C" be in the previous step? It is when we get rid of the integral, and then later in the end we simply calculate.
@MuPrimeMath
@MuPrimeMath 7 ай бұрын
Yes, there should be a +C in the penultimate step. I opted not to write it until the final answer because it doesn't affect the calculations.
@claireli88
@claireli88 5 жыл бұрын
We can do the same way for integration of product of two sines of different angles too.
@TheGiuse45
@TheGiuse45 Жыл бұрын
I never use trigonometric formulas, I use complex numbers like a real OG
@ShanBojack
@ShanBojack Жыл бұрын
Can you elaborate
@TheGiuse45
@TheGiuse45 Жыл бұрын
@@ShanBojack instead of remembering all the trig formulas you can derive them by using the equivalence e^(ix)= cos(x) + i*sin(x) with x a real number. you can use this to make the cosine or sine, for example cos(x)= (e^(ix) + e^(-ix))/2. you can derive any trig formula from this
@przemysawkwiatkowski2674
@przemysawkwiatkowski2674 5 жыл бұрын
How would you do it with integration by parts?
@MuPrimeMath
@MuPrimeMath 5 жыл бұрын
Choose one of the cosines to differentiate and one to integrate. After doing integration by parts twice, the resulting integral will be a constant multiple of the original. Then you can solve for the integral! This gives the result of b/(b^2-a^2)cos(ax)sin(bx) - a/(b^2-a^2)sin(ax)cos(bx) + C which is equivalent to the answer in the video.
@viktor-kolyadenko
@viktor-kolyadenko Жыл бұрын
a = b or a = -b (formally)?
@MuPrimeMath
@MuPrimeMath Жыл бұрын
Good point, those would be special cases!
@diegogallego9370
@diegogallego9370 2 жыл бұрын
Thank you
@ArifSolvesIt
@ArifSolvesIt Жыл бұрын
You could have presented a more complete solution by solving for the case a=b. You can still take the limit a goes to b in the final answer, but I think it is worth mentioning what happens when a=b.
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