BCD Adder | Simple Explanation

[@AnshumanKumar007]

NESO ACADEMY ZINDABAD!!! I am passing this semester cause of you guys!!!!

[@SaisiddarthaPolusani]

Hey man did u passed ur semester What are u doing now

[@bikrantanand1811]

Ur explanation is great ...but u can believe that there is not a single soul in universe who watches ur video in normal speed🤣🤣🤣...#u r awesome

[@techvsfake6036]

i am that one... Even i am making notes of his presentation...

[@noobCoder7]

​@@techvsfake6036you will watch in normal speed if you are making notes. But not if you are reading

[@ImranALI-qh3je]

@@noobCoder7 i generally watch in 1.25x and take notes after finish. For easy topics, i watch in 1.5 or 1.75x.

[@noobCoder7]

@@ImranALI-qh3je i make rough notes and watch in 2x speed always

[@ImranALI-qh3je]

@@noobCoder7 good

[@lkls987]

This channel is highly trusted because I found some websites and other channels they don't take data accurate and also don't teach precisely but this channel teach everthing in precisely manner and whenever I study from this channel I don't take any tension for accuracy related problem....

[@layavanygoudanavar8956]

You are MY Online Guru where i can easily get all the things done thank you sir

[@maryammoghtaderi3456]

I love how I can learn all my subjects from Digital Design to Siganls and Systems, Programming, etc with your videos ❤️

[@Aryan-wv6qe]

Excellent explanation in all the tutorials. Easy to understand

[@rownitakhanam5013]

Thanks for all videos Neso Academy. Your videos are easy to understand and also clearly explain the basic concepts.

[@hikmathasanov]

Great explanation. I dont now why we added third case and then removed it through simplification. Even saying s3*(s2*+s1*), it was already covering number 10 - 15.

[@psibarpsi]

Don't forget + c*. But, yeah, what you're saying is ultimately correct.

[@optimisticfailure]

I find using the K-map to find the equation simpler.

[@biboswanroy6699]

one like is not enough ,if we could get such crystal clear concepts in all subjects

[@prathamtetgure2963]

Then give two.

[@thaynaemillycavalcantesant3687]

Omggg, thanks for existing!! Excellent video!

[@abhishekpawar5804]

You look very beautiful. Beauty with brain

[@RahulMadhavan]

(0) We are representing each decimal digit by 4 bits (1) We add 6 because 4 bit includes numbers till 15 and we only want numbers till 9. For the rest of numbers between 10 and 15, we wish to take a carry of 1 to the next set of 4 bits (by adding 6). (2) To identify numbers between 10 and 15, we can look at just the MSB = 1, unfortunately, this includes 8 and 9. So we want all 4 bit numbers such that MSB (S3) is 1, excluding 8 and 9. (3) 8 and 9 have S1 = 0 and S2 = 0. => S1+S2 = 0. For the rest, we want S1+S2 = 1, and also MSB bit as 1. This is S3.(S1+S2) (4) The sum of 2 numbers between 0-9 can also lead to 5 bit numbers, 16, 17 and 18. For these also we need to add 6 as 16 in binary is 1 0000, but we want 1 0110 (similarly for 17 and 18) (5) So the required expression for which we need to add 6 is C + S3.(S1+S2)

[@ikshvaku_allegiance4015]

can you tell why carry from or gate comes straight as is rather than coming from the second adder

[@RahulMadhavan]

​@@ikshvaku_allegiance4015 The 1st digit (MSB of the BCD representation) is explicitly calculated by the or gate. So this is correct. Your claim: the carry from the second adder is also correct. Let's check this. Say the sum of the two numbers is 17. Then the binary is 10001. The 0001 is taken and added to 0110 by the second adder to get 0111 = 7. This has no carry. Therefore by your method, the final output will be 00111 (which is wrong). If you use the carry from the or gate, the answer is 10111 (Which is the required answer. See @4:09)

[@ikshvaku_allegiance4015]

@@RahulMadhavan i have another doubt in video no. 143.Kindly resolve that as well.Thanks. I have posted it below as well. (@Rahul Madhavan .In very first question what happened to the carry outputs after subtraction of the first bit. Cin is 1 but then y0 + X0' must have given a carry which would have then propagated to next bit. How are we handling that?)

[@RahulMadhavan]

@@ikshvaku_allegiance4015 I'm sorry I don't have the context to this question as I don't have video numbers. Furthermore, I saw these videos 3 years back so I don't remember offhand. So maybe someone else can help on that.

[@ikshvaku_allegiance4015]

@@RahulMadhavan kzbin.info/www/bejne/pWOVgZh_ftKWgcU this is the video link.First question itself.Nobody else has been able to answer my doubt..kindly help

[@nickos6156]

Thank you ,you really saved someone's life. really helping

[@aarthiselvan1589]

Case 3 can be obtained from case 2 itself. Instead of eliminating s3*. s1* during simplification we can just have two cases.

[@VISHALHS-qw1hc]

Yes I thought the same I expect the creator to respond to this

[@thecodingdice3107]

case 3 is not required case 2 is valid for both and

[@rishikeshpisal6625]

Exactly.... Thanks for confirmation 🙌

[@saranyam5105]

Thank u so much sir, its really very clear and easy , millions of thank u sir

[@muttakinahmed2506]

Cases should be like 1. c*=1 (for 16-19) 2. s3*.s2* (for 12-15) 3. s3*.s1* (for 10-11)

[@ruturajjadhav8905]

Yes you are right.

[@creativestudio5761]

It doesn't matter either way, because when you take the sum of cases both answers are same.

[@gauravbhandari9304]

Yes

[@adibrashid4130]

@@creativestudio5761 If u take the sum of s2* and s1* then you don't need 3no case..Cause it also includes the case..But if you want to take 3 cases then the equations have to be as the comment..

[@kiran6042]

No one can explain such a complex method in one go,just understand his efforts

[@anshuleshpandey9042]

Hi @7:30 ------> In the (ii) case 12 to 15, instead of using " s*3.(s*2 + s*1)" we can use only "s*3 . s*2" Because 12 to 15 only s*3 and s*2 both is high(1).

[@AnythingGoesCodes]

agreed www.geeksforgeeks.org/digital-electronics-bcd-adder/

[@bubleedas9610]

I thought the same thing

[@shewynfernandes4240]

yes. you can use case two only. but to understand it better use condition 3.

[@vinaypant557]

Yes I agreed

[@otgateway]

I think you can group 10 and 11 in the group of 12,13,14,15 as well since their expression holds true for 10 and 11 as well

[@sravyag___6926]

Thanks for being our teacher

[@shannukichatpatikhabrein7867]

Neso Academy you are the best...

[@praveenkumarboddu6451]

the explanation is superb.All the contents are covered thanks a lot.

[@jxiongdevdiary]

Thanks for your explanation! It seems clear to me after listening to your lecture!

[@vidhiagrawal3]

Thanks for the awesome explanation otherwise its so hard to understand👍

[@sushantverma8694]

Excellent Sir!

[@user-ytuser]

thnx,earlier i memorized it but now i understand each component of bcd adder completely

[@mihirvora391]

Awesome explanation. Thank you. ❤

[@yashshah5469]

the lecture was very very helpful...thank you

[@pavansaijayanth156]

Clear explanation Tq sir I makes Me easy to understand the topic

[@satishmokkala620]

sir u r lecture is awesome !! I like it sir

[@deepsheth8005]

Explained very nicely😎

[@chengmengtan3286]

Such easy after your explanation...and how genius ppl who created this

[@egedoster2204]

can you also do videos about verilog there isnt much source, i follow your lectures, thank you , you really give us the best quality lectures and really helpful for all electronic students

[@mightygerman]

Soooooooooooo much great explanation sir...........

[@prempoudel8482]

just wow i got it within 1 view.great explanation .love from Nepal.Thank u

[@dhaisa]

nepaad

[@LalX77]

this was such a wonderful lecture, explaining each and every logic in simple and easy to understand way. Now I am safe to say that I will be able to do any question from this part. Thank You so much Sir!!

[@tunwaphantang4985]

Your videos are super easily understandable.

[@SahilSinhaArtStyle]

Nailed it buddy .....!!!

[@arjunprasadsarkhel7814]

Really helpful tomorrow is my exam and I got the logic from this

[@hassanmaqsood7696]

lol same here!

[@AnshumanMohanty95]

Really nice explanation

[@nidashaikh5317]

Excellent Explanation.

[@siddireddyvignesh]

Watching it first time i didn't understood. But later after three months i understood. First time i say is the time when my sir explained and second time i watched during my semester exam and i finally understood

[@yashkulshrestha4262]

awesome....extremely awesome...he made it so easy for me to understand...thanks

[@vidurbhardwaj4001]

Very well explained....sir

[@ravitejavaddi558]

at 7:45 u can say s3*.s2*=1,u can add 6(0110)

[@beivemotivation1454]

Excellent explanation thank you so much for making this video 😊😊😊

[@apumallick6274]

Sir, I really like your video. If you make a lot of videos like this, I would be very happy.

[@AS-nx9fu]

Nigga nobody cares about u

[@riseabovehate9476]

7:10 y r u considering 12-15 and not 10-15?

[@namansingla2009]

thanks a lot sir !!! you just made everything simple i think there are some problem with the subtitles.you are saying something(in the video) and subtitles are listing another

[@arogyaselvi5852]

Great and simple explanation sir, can u tell me which board are you using in the video for writing, It would be helpful for me to conduct online lectures for my students.

[@mohitmahajannetwork3223]

there is no need of taking a bit from the OR gate and giving it to final output, as we can directly get the 5 bit output from the second 4 bit full adder Thank you Good teaching

[@chhannupatel3981]

Awesome explanation....great

[@souravpodder2402]

You made it really easy

[@debaratighatak2211]

Thank you so much sir for posting such amazing videos !

[@monikasharma1184]

such a great teacher👍

[@ayanroy8757]

for these video lectures students are getting passed in the sem exams:) thanks a lot

[@llll308]

very nicely explained.

[@rutbamir7591]

Helped alot. Thanks

[@xxzeroxx8417]

Great explanation sir!!

[@abhishekdubey99]

lecture is awesome

[@mongya-hc6eu]

Superbb explanation..

[@arjungautam4542]

Good explained.

[@Nomnomnom165]

For 10-15, S3* is one and either S2* or S1* are one, that's how they're different from 8 and 9. That's enough as a single case, no need for the 3rd case. Outcome is still correct at the end

[@beingdealtwith]

Thank you, this helped quite a lot!

[@farhanrahman8327]

+Mohammad Sultan Khaja I know, watching it Porota!

[@beingdealtwith]

Farhan Waseehahahhahahahhahahahhah

[@dineshgowda1847]

Best teaching!!

[@bittu7502]

really,,it's very much helpful for me,thank you

[@millind69]

Thanks yaar bhai Maza aagya💙

[@shreyashetty372]

Why were 0&3 bits were called min term and maxterm ? Those terms are defined entirely different in some other video! Anyways excellent explanation. Thanks for that 👍

[@mohanmane1313]

super lecture salute u

[@mussabaheenmalik6814]

Very GOOD Keep it up! man

[@barsilgen120]

Thank you so much for the video!

[@prathamjagga5597]

Thank You so much for the great content !!! 😊

[@shehryarpwinx2653]

it was easy to understand.....ty

[@akarshsaxena7810]

sir in 8:37 m, (ii) case mei S2*=1 than 11 to 15 cover bhi hogye or 8 and 9 se disting bhi

[@excalibur1716]

thank you so much

[@shoaibmohammed3707]

Just for all the people wondering about Case 3, it's not required. Even if u do take Case 3, it will get eliminated since we find the minimum possible function. Case 3 is not required.

[@shishirmathur5855]

what's the need of case 3? 10 and 11 can be differentiated from 8 and 9 with help of case 2 only..then why go for case 3.

[@harshberiwal8420]

true..even i thought that

[@RandomMusingsOfLowMelanin]

He did eliminate that -_-

[@sanjay-thangaraj]

Exactly! Even I was thinking about that.

[@rishavrungta]

He could have done that but wanted everyone to understand so simplified the equation later.

[@invoker969]

Yea thinking the same thing

[@mashalname7685]

Thank u Its was a good help

[@saritaverma3890]

awesome sir.u are great

[@Harpreet-t5b]

🥳🥳🥳🥳 Thank you very much, sir.

[@Teenu]

Thnx for easy explanation

[@jaideeptiwari5855]

superb lecture sir

[@MohamedAli-rz1pp]

Thanks To You , It's Really Helpfull

[@Fr0stPhe0nix]

who's here one day before exam at 1.75x

[@frostywalker2108]

HAHA me

[@pupper6044]

Very well explain sir. But how do you write this is verilog code?

[@sarfarajansari4484]

love you sir

[@verkilagautaminath5396]

thank you nice explanation

[@rubayetkhusbu3752]

Excellent 👌 thanks

[@swapnilg.5996]

Thanks you are awesome :D

[@soumik9876]

Thanks,that was really helpful

[@UjjwalOjhaNepal]

Nicely explained!

[@RamKumar-pn3od]

Nice explanation

[@harshberiwal8420]

In my college we are expected to solve the sums using k-map. Your videos are really helpful but none of your videos are solved using kmap....it would be great if you can help by uploading videos in which you have used kmap

[@md.mahedihasan5716]

Thank You So Much

[@kshitijvengurlekar1192]

Thanks a lot. I am still clueless about what my stupid professor taught us in class. This was so simple.

[@muhammadahmed8933]

Hi! your video is very informative and easily understandable so I always see the videos related to the digital logic design on your channel. thank you! But I have a question related to this video, what is the previous carry?

[@gayathriswaminathan4929]

Is there any video in ur series for serial adder?

[@sashkale777]

Thanks a lot for the explanation!!!! but i do not get one thing: why C (carry of BCD sum) is output of OR gate, is it the output of Cout of the second FULL ADDER?

[@gauravav1635]

See the truth table, from 0-9, C is 0 . But for 10-19, C is always 1. 10-19, is when we add 6 to the sum. So for 10-19, the o/p of the or gate will always be 1 and for 0-9, it'll always be 0, which is the case with truth table too. So o/p of or gate is actually C

[@tusharsingh5825]

@@gauravav1635 so technically the final carry can be drawn from the 2nd adder too. it will still always be automatically 1. and what is done in the video is also correct.

[@khaledal-jehani1623]

Great Job!! When will you complete your videos?

[@hudahasan6140]

you're the best!!

[@massiouanebenagdi478]

There is no requirement for case 3 from the first place But great explanation ,thankss