Conversion of Regular Expression to Finite Automata - Examples (Part 1)

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@mohammadfaisal3649
@mohammadfaisal3649 2 жыл бұрын
dear neso academy , you have always helped me in my engineering journey. I am so grateful that we have teachers like you. Thanking you from the core of my heart🥰🥰
@mukesh5652
@mukesh5652 10 ай бұрын
💯
@ziliestarrive
@ziliestarrive 5 жыл бұрын
Thank you so much for this. My lecturer makes the material super confusing and while the textbook(Hopcroft) is good, it's really wordy and takes forever to get to the working knowledge, given that it uses proofs to introduce new concepts. This is perfect.
@grassroots99
@grassroots99 2 жыл бұрын
I'm jealous that you've long been done with this course haha
@Soulhunter17
@Soulhunter17 5 жыл бұрын
This video has a pretty good quality to show the very basic steps on how to do it with good explanation. Exactly what I was looking for. Thank you! =)
@HabiburRahamaniit
@HabiburRahamaniit 3 жыл бұрын
You are a saviour . I am from IIT KGP, I follow your lectures from the very first year. Thanks .
@mrsmurf911
@mrsmurf911 2 жыл бұрын
bahut harami ho beta
@goutamshaw4225
@goutamshaw4225 Жыл бұрын
😅F gg for free ho o; hj
@poojakatiyar7380
@poojakatiyar7380 Жыл бұрын
Hy
@yashtripathi9079
@yashtripathi9079 Жыл бұрын
heyyy@@poojakatiyar7380
@poojakatiyar7380
@poojakatiyar7380 Жыл бұрын
@@KaushikcraftAI give your insta id
@bishalmohari8748
@bishalmohari8748 4 жыл бұрын
Your explanations are just so concise . Love your work
@visheshkumar15
@visheshkumar15 Жыл бұрын
00:01 Converting regular expressions to equivalent finite automata 01:11 Conversion of Regular Expression to Finite Automata - Examples (Part 1) 02:12 Conversion of Regular Expression to Finite Automata - Examples (Part 1) 03:20 Conversion of Regular Expression to Finite Automata - Examples (Part 1) 04:23 Finite Automata accepts strings based on the given regular expression 05:30 Design finite automaton for a BC closure 06:41 Finite Automata Closure 07:47 Conversion of Regular Expression to Finite Automata Crafted by Merlin AI.
@vectrex28
@vectrex28 5 жыл бұрын
Thanks for the videos, I might just ace my exam tomorrow thanks to them :)
@grizzthekid
@grizzthekid Жыл бұрын
I literally sing along to the intro song because that’s how great the lectures are.
@JD_Mapes
@JD_Mapes 3 жыл бұрын
Pretty sure I need to be paying you instead of my school
@mohtrz5759
@mohtrz5759 3 жыл бұрын
i can agree for this :)
@eyramakahoho9303
@eyramakahoho9303 2 жыл бұрын
I agree
@habbometin2csocapb
@habbometin2csocapb 2 жыл бұрын
Same thing
@nihalwaseem7106
@nihalwaseem7106 Жыл бұрын
Totally agree bro🔥
@lucknawi_ladka62
@lucknawi_ladka62 Жыл бұрын
Which country are u from?
@missecah1731
@missecah1731 3 жыл бұрын
Thank you very much. I'm having trouble understanding regular expression in automata
@chabotaluputa7665
@chabotaluputa7665 7 ай бұрын
Awesome,for the last one I made only two states,it still worked
@trollerninja4356
@trollerninja4356 6 жыл бұрын
I have to say this....thanks a fucking ton.....I despised this subject...it sucked for me......and I have my midterm in 2 hrs...started watching yur videos few hrs back...and I absolutely love solving these problems....its about how one is taught that changes the student's approach towards the subject....thanks a lot again...!!!
@swatiaryaa9268
@swatiaryaa9268 2 жыл бұрын
Thank you so much sir ,,love from India✌️✨🥰
@utsavbudathoki2384
@utsavbudathoki2384 6 жыл бұрын
thank you sir ..all my doubt are clear now
@shahzadafathurrahmanbscs-2773
@shahzadafathurrahmanbscs-2773 2 жыл бұрын
for question 3. if you have string ac or ab as there is star over bc, so one can pick any number of b or any number of c, so by doing that we won't reach the final state?
@adityaaryan2412
@adityaaryan2412 Жыл бұрын
We won't reach final like that as we always need 'b' and 'c' together and also at the end of the string.
@sebastianarturoobandomayor1554
@sebastianarturoobandomayor1554 7 жыл бұрын
Thank You Thank YOU !! Thank YOU !!! for ALL the videos !! :D Really Thank YOU
@SasiKumar-pk5uf
@SasiKumar-pk5uf Жыл бұрын
I am sure because I spent a useful time for this video
@pallavikavalipati1431
@pallavikavalipati1431 3 жыл бұрын
for a(bc)* can we return both bc to final state b instead of another state c?
@shantanujoshi290
@shantanujoshi290 3 жыл бұрын
same doubt
@latalabatagoshu5341
@latalabatagoshu5341 2 жыл бұрын
I was thinging that too.
@collegematerial5348
@collegematerial5348 2 жыл бұрын
Bc we should make one transition fir B and another for C
@arshitaanchaliya1583
@arshitaanchaliya1583 2 жыл бұрын
I think no because if u make b,c on b only it means that it accept the string abbb, ACCC, also but here we have bc repeating not b or c ....
@pkm2520
@pkm2520 11 ай бұрын
@@arshitaanchaliya1583 when a self loop is given to B for b,c, when b is given self loop happens ab when c is given self loop happens abc will work na?
@chavaligangadevi8663
@chavaligangadevi8663 Жыл бұрын
good explanation sir
@studywithme4599
@studywithme4599 8 ай бұрын
Thanks for the video best video on finite automata
@rrsc07
@rrsc07 7 ай бұрын
ee bc bc bc bc😂😂😂😂..... I started laughing in the library lol
@tharindumarapana6670
@tharindumarapana6670 2 жыл бұрын
Very clear explanation. Thanks much
@ilmnafi3
@ilmnafi3 4 ай бұрын
thanks great explination 😊
@divinesoul3311
@divinesoul3311 Жыл бұрын
in the third question can we add a self loop to b for inputs b,c instead ?
@marianeziade1997
@marianeziade1997 Жыл бұрын
I did the samee and it make more sence cause b ans c should be togheter not like he did but im not sure if its right
@stardust3511
@stardust3511 10 ай бұрын
nope, in that case, after 'a' if you only read 'b', it ends up at a final state though "ab" is not an accepted string
@martinriedl4139
@martinriedl4139 2 жыл бұрын
Great explanation! 👍
@whysoserious8806
@whysoserious8806 2 жыл бұрын
found this channel just a day before my exam damn I'm unlucky🙂
@piyushmishra860
@piyushmishra860 2 жыл бұрын
Tq so muchh sir ♥️
@buzzfeedRED
@buzzfeedRED 6 жыл бұрын
+Neso Academy Please give the answers when students asked to , You always said in your video if U have a doubt then Comment it , i will answer
@manindermanish3843
@manindermanish3843 7 жыл бұрын
Sir ,Is there no need to show the dead state or trap state in making the dfa of these examples
@emrekara369
@emrekara369 4 жыл бұрын
you are right
@manindermanish3843
@manindermanish3843 3 жыл бұрын
@Shivansh Thapliyal its none of my use now i use these lectures when i was doing MCA and neso academy is the only academy at that time which help me alot to pass these subjects anyway thanks for your reply work hard play hard
@pkm2520
@pkm2520 11 ай бұрын
@@manindermanish3843 what are you doing now g
@darkblack9958
@darkblack9958 Жыл бұрын
Thank you teacher!
@shahzadafathurrahmanbscs-2773
@shahzadafathurrahmanbscs-2773 2 жыл бұрын
To my little knowledge , in finite automata every state and transition should be determined, as there is no trap state after the final state so its more of an NFA.
@akashchoudhary8162
@akashchoudhary8162 2 жыл бұрын
That's for DFA. In the qn it was just mentioned FA. DFA and NFA are both FA
@shweta7362
@shweta7362 3 жыл бұрын
Very helpful🙌😄
@meghanareddy9642
@meghanareddy9642 5 жыл бұрын
Super explanation sir
@sadikabdullahi288
@sadikabdullahi288 3 жыл бұрын
Tomorrow I have a theory of computing exam:
@harshekka6089
@harshekka6089 9 ай бұрын
Same bro
@GOLDENBOYRICHIE
@GOLDENBOYRICHIE 5 ай бұрын
Same here on Monday
@rajeshmedia0.2
@rajeshmedia0.2 5 ай бұрын
Yes​@@GOLDENBOYRICHIE
@fadelcmd9969
@fadelcmd9969 5 жыл бұрын
Sir please make a video about Regular expression to Epsilon NFA Conversion, thankyou
@NOLAMarathon2010
@NOLAMarathon2010 5 жыл бұрын
Worth noting that none of these conversions were to DFA's. All the conversions were to NFA's.
@tavasoli
@tavasoli 2 жыл бұрын
I know it's been 2 years but could you elaborate more? Here, there are no epsilon-transitions and no two identically labeled transitions out of the same state. So, it is fine with the definition of DFA.
@prohightension2000
@prohightension2000 2 жыл бұрын
@@tavasoli no a DFA has to have all the inputs and their outputs which means all the state has to have all the inputs
@AadeshingaleOfficial-zl5fd
@AadeshingaleOfficial-zl5fd 4 ай бұрын
Nice Sir 😊
@vinayaddagatla1569
@vinayaddagatla1569 6 жыл бұрын
in 3rd example if input given is only a then it goes to final state but according to regular expression it should go to final state only if input is like abc abcbc abcbc..... please explain if my doubt is correct.
@chinmaysingh513
@chinmaysingh513 6 жыл бұрын
a is also a valid expression since it is (bc)* so it can be epsilon as well so a or a followed by any number of (bc)
@vinayaddagatla1569
@vinayaddagatla1569 6 жыл бұрын
@@chinmaysingh513 thanks got it
@amirsuhel7184
@amirsuhel7184 Жыл бұрын
My exam is day after tomorrow. I guess you will make me pass.
@nikhilreddy719
@nikhilreddy719 2 жыл бұрын
Thank you, sir
@AnuRajpoot-h4u
@AnuRajpoot-h4u 7 ай бұрын
Thanku sir ❤
@saisreenivas8875
@saisreenivas8875 6 жыл бұрын
In the 2nd example,string aac is also accepted right?Then how is that correct?
@shahinshaikh07
@shahinshaikh07 5 жыл бұрын
The string "aac" will not be accepted. (a+b) means either a or b will be read before 'c'..... It will read only one from 'a' and 'b'
@rezaarian237
@rezaarian237 2 жыл бұрын
on c part bc can produce lamda right ?
@swm7f137
@swm7f137 7 жыл бұрын
you are the best thanks alots
@stealth50k
@stealth50k 7 жыл бұрын
Great videos :)
@vaggelismanousakis6147
@vaggelismanousakis6147 5 жыл бұрын
Is there a diffrence between NFA and DFA regarding their automata design ? Is there any video related to that with examples? Thanks in advance
@ayushanand18
@ayushanand18 Жыл бұрын
The difference lies in the rules for it. DFA cannot have two different transitions on the same symbol from a state or a null transition, but NFA can. We ought to implement a deterministic machine and so every NFA must be converted to DFA before implementation (physically). So design perspective they are different because of the transitions that are allowed.
@mridulanand10
@mridulanand10 2 жыл бұрын
sir in 3rd part why didn't you go for more than 3bc's?
@saravana___
@saravana___ 6 ай бұрын
for closure in last example, do we need to give a self loop sir
@mohdluai1808
@mohdluai1808 5 ай бұрын
for the 2nd example (a+c)b why is the + operator considered or rather than one or more 'a'?
@johnyhawkahsan
@johnyhawkahsan 7 жыл бұрын
Thank you so much
@pp-xc8kb
@pp-xc8kb 2 жыл бұрын
can anyone tell me briefly what is the useage of this? I just learn it from my university but don´t know still what does it imply
@ajaypratapsingh9626
@ajaypratapsingh9626 2 жыл бұрын
Are we converting it into nfa Because we are not showing all transitions?
@rohitippili3834
@rohitippili3834 6 жыл бұрын
Thank you 🙏🏼
@jyothijyo6409
@jyothijyo6409 3 жыл бұрын
Sir can't we put the self loop for final state in the example 3
@adityaaryan2412
@adityaaryan2412 Жыл бұрын
We can't as if we end the string with a 'b' that string would still get accepted which is wrong
@Birabhadra1234.
@Birabhadra1234. 3 жыл бұрын
As we know that for n, no. Of input alphabet there are nth no. Of ways from one state to another
@dhanushsivajaya1356
@dhanushsivajaya1356 4 жыл бұрын
Thankyou sir
@afraimlevi9871
@afraimlevi9871 3 жыл бұрын
Thanks Alot
@gedelasivakrishna
@gedelasivakrishna 3 ай бұрын
Thankyou !!
@tarekrahaman9321
@tarekrahaman9321 Жыл бұрын
Design DFA over an alphabet = (a,b), so every string accepted must end with 'aa,bb,aba' Please solve the question
@jamilafathima
@jamilafathima 5 жыл бұрын
Hello sir Good explanation video Thank you so much, kindly do videos for database , im preparing for gate exam (self preparation) do the needful sir
@elishauppalapati
@elishauppalapati 10 ай бұрын
In 3rd example at B state we can loop bc?
@koteswaripeddinti7089
@koteswaripeddinti7089 5 ай бұрын
construct a nfa-epsilon either a or abb or a* b+ Sir can you solve it
@deekshudeekshitha9835
@deekshudeekshitha9835 10 ай бұрын
for RE 2 why "abbc" is not accepted by that machine?
@AhamedKabeer-wn1jb
@AhamedKabeer-wn1jb 4 жыл бұрын
Thank you..
@mechanicalengineering7554
@mechanicalengineering7554 Жыл бұрын
what is the fa if the expression is like "a/b" please explain this
@yas-sinesl9105
@yas-sinesl9105 Жыл бұрын
If (a+b) is a or b , then what does (a|b) means ?
@aakash9579
@aakash9579 4 жыл бұрын
can't the third case can be done with the help of two state as 2nd state having loop
@aakash9579
@aakash9579 4 жыл бұрын
got it concatenation introduce a new state
@taibamalik8114
@taibamalik8114 Жыл бұрын
Why we don't use self loop for bs in a(bc)*
@macromed2023
@macromed2023 2 ай бұрын
I won't be a dfa
@theonlyarjun
@theonlyarjun 7 жыл бұрын
in 3rd example. can't we self loop on state b with b,c ?
@TheKrish207
@TheKrish207 7 жыл бұрын
Arjun Manoj same doubt
@sotsnein3873
@sotsnein3873 7 жыл бұрын
No, you can't use a self loop with b, c as b,c stands for b+c. In this case, there is a concatenation of b and c(b.c).
@ChristianBurnsShafer
@ChristianBurnsShafer 6 жыл бұрын
No, that would accept the string 'ab' for instance.
@ChristianBurnsShafer
@ChristianBurnsShafer 6 жыл бұрын
GeishaTheSerpantClan is an idiot that wets their pants at night.
@joydeepmukherjee8263
@joydeepmukherjee8263 6 жыл бұрын
Self loop will accept these strings: abcc, abbc, abcbbc, .... so on. The point is that, self loop can't impose the sequence b->c
@maryamriaz9001
@maryamriaz9001 Жыл бұрын
why we didnt apply the loop to bc?in last example
@arpanasingh9959
@arpanasingh9959 7 жыл бұрын
Can u solve this solution (11+110)*0
@utkarshhh7
@utkarshhh7 3 жыл бұрын
Very tough
@buzzfeedRED
@buzzfeedRED 6 жыл бұрын
My doubt is Can we take a self loop over state B as (bc) as one input Because we have (bc)* , so we can do it ?????????? Reply PLease
@RahulMadhavan
@RahulMadhavan 6 жыл бұрын
the alphabet doesn't contain bc, only {a,b,c} so you need to keep a new state to transition through
@suvenduhatua_1754
@suvenduhatua_1754 4 жыл бұрын
@@RahulMadhavan if i only give b,c as an inputs to State B as a self Loop....then what is the problem???... Please reply.
@RahulMadhavan
@RahulMadhavan 4 жыл бұрын
@@suvenduhatua_1754 I don't think i understand your question because i've lost context. Any case, here's my understanding of the question. For the third question in the video, you are proposing a state A and a state B. State A transitions to state B on input 'a', and state B self loops on the inputs 'b', or 'c'? You then propose B as the terminal state. Is this understanding correct? If so, then it has a clear disproof. Your automaton would accept input ab, which it should not.
@ektasrivastava8651
@ektasrivastava8651 5 жыл бұрын
sir , is this thompson's construcion method ?
@scaldbox7442
@scaldbox7442 7 жыл бұрын
I thought(a+b)c meant, one or more occurrences of 'a' followed by 'b', followed by 'c'
@ChristianBurnsShafer
@ChristianBurnsShafer 6 жыл бұрын
Only if the '+' is superscript. At least, in the context of this lecture series.
@mohanmahanty9619
@mohanmahanty9619 6 жыл бұрын
Hello Scald Box,if it is (a+b)c,means there is a path from one state to another by a or b and then we can reach to next state by c,that means (a or b) followed by c
@aryandeshpande1241
@aryandeshpande1241 2 жыл бұрын
dont you have to define every state transition over every state? in Q1, you defined over state a only transition 'b'
@Karim-nq1be
@Karim-nq1be Жыл бұрын
Its says Finite Automata not Deterministic Finite Automata.
@kingzai1314
@kingzai1314 7 жыл бұрын
thanks
@mdashamimad7728
@mdashamimad7728 Жыл бұрын
For the second expression if the input is ca thn????
@sudhanshupal4427
@sudhanshupal4427 6 жыл бұрын
Thanks a lot!!!!!!!
@5430amit
@5430amit 6 жыл бұрын
Thanks from IIIT_Kalyani :)
@CSELTADEPALLIDATTASRISAIRAM
@CSELTADEPALLIDATTASRISAIRAM 4 жыл бұрын
why cannot we put b,c in self loop to B??
@Sabidha-xv6lp
@Sabidha-xv6lp Ай бұрын
How to take a state as final state
@kartikaymehrotra6697
@kartikaymehrotra6697 Жыл бұрын
can we have a self loop at B for input a,b?
@kartikaymehrotra6697
@kartikaymehrotra6697 Жыл бұрын
in q c
@manikanta-oh3qy
@manikanta-oh3qy 7 жыл бұрын
sir why r u not upload the design of amplifier in analog electronics
@sidreign3095
@sidreign3095 6 жыл бұрын
can you self loop B with bc as input?? 3rd example
@biswarupchakraborty5608
@biswarupchakraborty5608 6 жыл бұрын
Buddha_ reincarnated No that will accept ab or ac too.
@arpanasingh9959
@arpanasingh9959 7 жыл бұрын
In third example were is ur self loop for closure?
@ChristianBurnsShafer
@ChristianBurnsShafer 6 жыл бұрын
Close of a concatenation requires (at least) two states.
@GOLDENBOYRICHIE
@GOLDENBOYRICHIE 5 ай бұрын
Where do you get the c from
@endone3661
@endone3661 Жыл бұрын
what does this use for ?
@mubashirayub6630
@mubashirayub6630 4 жыл бұрын
can you please make DFA of my RE which is: a ( ab + b )* bba ( a + b )
@chetanyasaini3899
@chetanyasaini3899 3 жыл бұрын
Kaise kiya 1 saal hogya ab
@tanmayphalke6251
@tanmayphalke6251 Жыл бұрын
Kaise kiya 3 saal hogaya ab aur@@chetanyasaini3899 apko 2 saal...🤣🤣
@iconicillustrations6853
@iconicillustrations6853 Жыл бұрын
8:15
@sumitgaur2010
@sumitgaur2010 2 жыл бұрын
please help creatin dfa for "a*a" or how we can simplify the RE
@birajpaul4060
@birajpaul4060 2 жыл бұрын
self loop with input 'a' on state A and out transition with input 'a'-> towards final state B
@sonit9707
@sonit9707 Жыл бұрын
@@birajpaul4060 That's not a dfa.
@sonit9707
@sonit9707 Жыл бұрын
@@birajpaul4060 Just the self loop should work.
@thewaveclasses7740
@thewaveclasses7740 7 жыл бұрын
please sir signal and system ka aur video uplod ker dijiye
@nanitechinfo6188
@nanitechinfo6188 7 жыл бұрын
write regular expression that derives all strings if a's and b's where every string contains substring ab as substring?
@nikhilnambiar7160
@nikhilnambiar7160 7 жыл бұрын
(a+b)^*ab(a+b)^*
@ViralVideoCreator
@ViralVideoCreator 5 жыл бұрын
Where is prvious lecture
@sheerazamushtaq368
@sheerazamushtaq368 6 жыл бұрын
Where r rules for this sir?...in which lecture
@kalpesh7668
@kalpesh7668 6 жыл бұрын
prior to this video , #54 video
@Birabhadra1234.
@Birabhadra1234. 3 жыл бұрын
1st finite automata graph is wrong because there are only one path from A to B not the other path for going a, alphabet fromA to B
@MohamedOsman-xk3xe
@MohamedOsman-xk3xe 6 жыл бұрын
if my input became what happen in example one
@alimoosawi4301
@alimoosawi4301 2 жыл бұрын
i love u
@muskansrivastav6023
@muskansrivastav6023 3 жыл бұрын
Can anyone solve this....(alb)l(ab)*(bla)*(bb)*..... urgent please
@GOLDEN-wq8uz
@GOLDEN-wq8uz 2 жыл бұрын
2 is incorrect, + means 1 or more times, what if we wanted to put in more than 1 a or b
@nonbeliever5027
@nonbeliever5027 4 ай бұрын
It is correct
@sireesharani6314
@sireesharani6314 3 жыл бұрын
There is no keypoints for how to solve those sums ...he just solved the particular sums ...there is no subject foro how to solve any problem in regular expression..
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